谁有多元回归的程序，急需啊！
谁有多元回归的程序，急需啊！ 我也 急需，有的请发 29897815@QQ.COM 多谢{:3_41:} zhenc 发表于 2012-8-26 09:49 static/image/common/back.gif我也 急需，有的请发 多谢
现在找到了没 多元线性回归的就是简单的矩阵计算，matlab中有现成regress函数可以调用，你要程序干什么？
根据最小二乘原理，
Y=XB+E中系数向量的估计值为b=inv(x'x)*x'y
matlab中的源代码是：function = regress(y,X,alpha)
%REGRESS Multiple linear regression using least squares.
% B = REGRESS(Y,X) returns the vector B of regression coefficients in the
% linear model Y = X*B. X is an n-by-p design matrix, with rows
% corresponding to observations and columns to predictor variables. Y is
% an n-by-1 vector of response observations.
%
% = REGRESS(Y,X) returns a matrix BINT of 95% confidence
% intervals for B.
%
% = REGRESS(Y,X) returns a vector R of residuals.
%
% = REGRESS(Y,X) returns a matrix RINT of intervals that
% can be used to diagnose outliers. If RINT(i,:) does not contain zero,
% then the i-th residual is larger than would be expected, at the 5%
% significance level. This is evidence that the I-th observation is an
% outlier.
%
% = REGRESS(Y,X) returns a vector STATS containing, in
% the following order, the R-square statistic, the F statistic and p value
% for the full model, and an estimate of the error variance.
%
% [...] = REGRESS(Y,X,ALPHA) uses a 100*(1-ALPHA)% confidence level to
% compute BINT, and a (100*ALPHA)% significance level to compute RINT.
%
% X should include a column of ones so that the model contains a constant
% term. The F statistic and p value are computed under the assumption
% that the model contains a constant term, and they are not correct for
% models without a constant. The R-square value is one minus the ratio of
% the error sum of squares to the total sum of squares. This value can
% be negative for models without a constant, which indicates that the
% model is not appropriate for the data.
%
% If columns of X are linearly dependent, REGRESS sets the maximum
% possible number of elements of B to zero to obtain a "basic solution",
% and returns zeros in elements of BINT corresponding to the zero
% elements of B.
%
% REGRESS treats NaNs in X or Y as missing values, and removes them.
%
% See also LSCOV, POLYFIT, REGSTATS, ROBUSTFIT, STEPWISE.
% References:
% Chatterjee, S. and A.S. Hadi (1986) "Influential Observations,
% High Leverage Points, and Outliers in Linear Regression",
% Statistical Science 1(3):379-416.
% Draper N. and H. Smith (1981) Applied Regression Analysis, 2nd
% ed., Wiley.
% Copyright 1993-2009 The MathWorks, Inc.
% $Revision: 1.1.8.3 $ $Date: 2011/05/09 01:26:41 $
if nargin < 2
error(message('stats:regress:TooFewInputs'));
elseif nargin == 2
alpha = 0.05;
end
% Check that matrix (X) and left hand side (y) have compatible dimensions
= size(X);
if ~isvector(y) || numel(y) ~= n
error(message('stats:regress:InvalidData'));
end
% Remove missing values, if any
wasnan = (isnan(y) | any(isnan(X),2));
havenans = any(wasnan);
if havenans
y(wasnan) = [];
X(wasnan,:) = [];
n = length(y);
end
% Use the rank-revealing QR to remove dependent columns of X.
= qr(X,0);
p = sum(abs(diag(R)) > max(n,ncolX)*eps(R(1)));
if p < ncolX
warning(message('stats:regress:RankDefDesignMat'));
R = R(1:p,1:p);
Q = Q(:,1:p);
perm = perm(1:p);
end
% Compute the LS coefficients, filling in zeros in elements corresponding
% to rows of X that were thrown out.
b = zeros(ncolX,1);
b(perm) = R \ (Q'*y);
if nargout >= 2
% Find a confidence interval for each component of x
% Draper and Smith, equation 2.6.15, page 94
RI = R\eye(p);
nu = max(0,n-p); % Residual degrees of freedom
yhat = X*b; % Predicted responses at each data point.
r = y-yhat; % Residuals.
normr = norm(r);
if nu ~= 0
rmse = normr/sqrt(nu); % Root mean square error.
tval = tinv((1-alpha/2),nu);
else
rmse = NaN;
tval = 0;
end
s2 = rmse^2; % Estimator of error variance.
se = zeros(ncolX,1);
se(perm,:) = rmse*sqrt(sum(abs(RI).^2,2));
bint = ;
% Find the standard errors of the residuals.
% Get the diagonal elements of the "Hat" matrix.
% Calculate the variance estimate obtained by removing each case (i.e. sigmai)
% see Chatterjee and Hadi p. 380 equation 14.
if nargout >= 4
hatdiag = sum(abs(Q).^2,2);
ok = ((1-hatdiag) > sqrt(eps(class(hatdiag))));
hatdiag(~ok) = 1;
if nu > 1
denom = (nu-1) .* (1-hatdiag);
sigmai = zeros(length(denom),1);
sigmai(ok) = sqrt(max(0,(nu*s2/(nu-1)) - (r(ok) .^2 ./ denom(ok))));
ser = sqrt(1-hatdiag) .* sigmai;
ser(~ok) = Inf;
elseif nu == 1
ser = sqrt(1-hatdiag) .* rmse;
ser(~ok) = Inf;
else % if nu == 0
ser = rmse*ones(length(y),1); % == Inf
end
% Create confidence intervals for residuals.
rint = [(r-tval*ser) (r+tval*ser)];
end
% Calculate R-squared and the other statistics.
if nargout == 5
% There are several ways to compute R^2, all equivalent for a
% linear model where X includes a constant term, but not equivalent
% otherwise. R^2 can be negative for models without an intercept.
% This indicates that the model is inappropriate.
SSE = normr.^2; % Error sum of squares.
RSS = norm(yhat-mean(y))^2; % Regression sum of squares.
TSS = norm(y-mean(y))^2; % Total sum of squares.
r2 = 1 - SSE/TSS; % R-square statistic.
if p > 1
F = (RSS/(p-1))/s2; % F statistic for regression
else
F = NaN;
end
prob = fpval(F,p-1,nu); % Significance probability for regression
stats = ;
% All that requires a constant. Do we have one?
if ~any(all(X==1,1))
% Apparently not, but look for an implied constant.
b0 = R\(Q'*ones(n,1));
if (sum(abs(1-X(:,perm)*b0))>n*sqrt(eps(class(X))))
warning(message('stats:regress:NoConst'));
end
end
end
% Restore NaN so inputs and outputs conform
if havenans
if nargout >= 3
tmp = NaN(length(wasnan),1);
tmp(~wasnan) = r;
r = tmp;
if nargout >= 4
tmp = NaN(length(wasnan),2);
tmp(~wasnan,:) = rint;
rint = tmp;
end
end
end
end % nargout >= 2 {:3_55:}，程序中怎么会出现笑脸呢？ 程序非常好。。。 liwenhui 发表于 2012-8-28 10:10 static/image/common/back.gif
，程序中怎么会出现笑脸呢？
您编辑完之后全部选中，之后点击编辑器上面的这个符号“<>”,之后所有代码就正常显示了。 liwenhui 发表于 2012-8-28 10:10 static/image/common/back.gif
，程序中怎么会出现笑脸呢？
帮你编辑之后就会像上面的这样的显示了！ darker50 发表于 2012-8-28 14:14 static/image/common/back.gif
帮你编辑之后就会像上面的这样的显示了！
原来如此，明白了。 liwenhui 发表于 2012-8-28 10:09 static/image/common/back.gif
多元线性回归的就是简单的矩阵计算，matlab中有现成regress函数可以调用，你要程序干什么？
根据最小二乘原 ...
:)非常感谢~
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