求教大神！关于用lingo计算一个物流中心选址的模型
这个软件我一窍不通。。。但是老师要求要我用lingo把那个模型的计算步骤做出来。下面是截图
这是原文；
求教怎么用软件算它的步骤啊。。。有大神能给个答案呗 π_ππ_ππ_ππ_π π_ππ_ππ_ππ_π 共同学习~~
原论文论述并不清晰，对模型中关键变量解释不清楚，按照它的思路，编制的LINGO如下：MODEL:
SETS:
SUPPLY/1..3/:SX,SY,CL,FL;
DEMAND/1..5/:DX,DY,DQ;
PATH(SUPPLY,DEMAND):B,L;
ENDSETS
DATA:
SX,SY,CL,FL=
40,20,150,30
40,60,200,50
60,60,100,18;
DX,DY,DQ=
20,20,50
20,60,40
60,80,60
80,40,20
60,20,30;
THETA=0.01;
OMIGA=5;
ENDDATA
MIN=@SUM(SUPPLY(J):@SUM(DEMAND(I):B(J,I)*(DQ(I)*(L(J,I)+OMIGA*DQ(I))/(1-THETA)^l(J,I))));
@FOR(SUPPLY(I):@FOR(DEMAND(J):L(I,J)=@SQRT((SX(I)-DX(J))^2+(SY(I)-DY(J))^2)));
@FOR(SUPPLY(J):@SUM(DEMAND(I):DQ(I)*B(J,I))<CL(J));
@FOR(SUPPLY(J):@SUM(DEMAND(I):DQ(I)*B(J,I)/5)<FL(J));
@FOR(PATH(I,J):@BIN(B(I,J)));
@FOR(DEMAND(I):@SUM(SUPPLY(J):B(J,I))=1);
@FOR(SUPPLY(J):@SUM(DEMAND(I):B(J,I))<2);
END运行后得到的结果并不是论文提供的结果： Global optimal solution found.
Objective value: 60383.95
Objective bound: 60383.95
Infeasibilities: 0.000000
Extended solver steps: 0
Total solver iterations: 0
Model Class: PILP
Total variables: 15
Nonlinear variables: 0
Integer variables: 15
Total constraints: 15
Nonlinear constraints: 0
Total nonzeros: 75
Nonlinear nonzeros: 0
Variable Value Reduced Cost
THETA 0.1000000E-01 0.000000
OMIGA 5.000000 0.000000
SX( 1) 40.00000 0.000000
SX( 2) 40.00000 0.000000
SX( 3) 60.00000 0.000000
SY( 1) 20.00000 0.000000
SY( 2) 60.00000 0.000000
SY( 3) 60.00000 0.000000
CL( 1) 150.0000 0.000000
CL( 2) 200.0000 0.000000
CL( 3) 100.0000 0.000000
FL( 1) 30.00000 0.000000
FL( 2) 50.00000 0.000000
FL( 3) 18.00000 0.000000
DX( 1) 20.00000 0.000000
DX( 2) 20.00000 0.000000
DX( 3) 60.00000 0.000000
DX( 4) 80.00000 0.000000
DX( 5) 60.00000 0.000000
DY( 1) 20.00000 0.000000
DY( 2) 60.00000 0.000000
DY( 3) 80.00000 0.000000
DY( 4) 40.00000 0.000000
DY( 5) 20.00000 0.000000
DQ( 1) 50.00000 0.000000
DQ( 2) 40.00000 0.000000
DQ( 3) 60.00000 0.000000
DQ( 4) 20.00000 0.000000
DQ( 5) 30.00000 0.000000
B( 1, 1) 1.000000 16505.55
B( 1, 2) 0.000000 15343.76
B( 1, 3) 0.000000 41153.43
B( 1, 4) 0.000000 4536.936
B( 1, 5) 1.000000 6235.428
B( 2, 1) 0.000000 23098.39
B( 2, 2) 1.000000 10759.17
B( 2, 3) 0.000000 26173.19
B( 2, 4) 0.000000 4536.936
B( 2, 5) 0.000000 9156.613
B( 3, 1) 0.000000 27065.02
B( 3, 2) 0.000000 14350.38
B( 3, 3) 1.000000 23474.55
B( 3, 4) 1.000000 3409.249
B( 3, 5) 0.000000 8520.539
L( 1, 1) 20.00000 0.000000
L( 1, 2) 44.72136 0.000000
L( 1, 3) 63.24555 0.000000
L( 1, 4) 44.72136 0.000000
L( 1, 5) 20.00000 0.000000
L( 2, 1) 44.72136 0.000000
L( 2, 2) 20.00000 0.000000
L( 2, 3) 28.28427 0.000000
L( 2, 4) 44.72136 0.000000
L( 2, 5) 44.72136 0.000000
L( 3, 1) 56.56854 0.000000
L( 3, 2) 40.00000 0.000000
L( 3, 3) 20.00000 0.000000
L( 3, 4) 28.28427 0.000000
L( 3, 5) 40.00000 0.000000
Row Slack or Surplus Dual Price
OBJ 60383.95 -1.000000
2 0.000000 -227.0183
3 0.000000 0.2980232E-07
4 0.000000 0.2980232E-07
5 0.000000 0.2980232E-07
6 0.000000 -99.34730
7 0.000000 0.2980232E-07
8 0.000000 -157.0388
9 0.000000 0.2980232E-07
10 0.000000 0.2980232E-07
11 0.000000 0.2980232E-07
12 0.000000 0.2980232E-07
13 0.000000 0.2980232E-07
14 0.000000 -309.2856
15 0.000000 -60.83994
16 0.000000 0.2980232E-07
17 70.00000 0.000000
18 160.0000 0.000000
19 20.00000 0.000000
20 14.00000 0.000000
21 42.00000 0.000000
22 2.000000 0.000000
23 0.000000 0.000000
24 0.000000 0.000000
25 0.000000 0.000000
26 0.000000 0.000000
27 0.000000 0.000000
28 0.000000 0.000000
29 1.000000 0.000000
30 0.000000 0.000000
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