lingo模型在评价版显示超限制，但在12 API破解版，请大家帮忙分析！
LINGO/WIN32 12.0.2.21 (20 Oct 10)LINDO API 6.1.1.515 (Oct 20 2010 20:14:13)
Copyright (C) 2005-2009 LINDO Systems Inc. Licensed material,
all rights reserved. Copying except as authorized in license
agreement is prohibited.
License location: F:\TDDownload\LINDO Document\lingo12破解\lndlng12.lic
License location: F:\TDDownload\LINDO Document\lingo12破解\lndlng12.lic
Eval Use Only
License expires: 23 Nov 2029
Licensed for commercial use.
Branch-and-bound solver enabled.
Nonlinear solver enabled.
Barrier solver enabled.
Global solver enabled.
Integer solver enabled.
Stochastic solver enabled.
Parameter Old Value New Value
ECHOIN 0 1
: take EnergyPlan.lng
: model:
? Title EnergyPlanModel By HuBingQing in 20140720;
? sets:
? District/@FILE('cDistrict.LDT')/: GDP0, GRateMin, GRateMax, EPG0, EPGRateMin, EP
? endsets
? data:
? T = 8;
? TGDP = 98500;
? TEPG = 0.75;
? ! GDP0;
? GDP0 = @pointer(1);
? ! Min Increase Rate of GDP;
? GRateMin = @pointer(2);
? ! Max Increase Rate of GDP;
? GRateMax = @pointer(3);
? ! EPG0=Energy Consumption Percent GDP in Base
? EPG0 = @pointer(4);
? ! Min Decrease Rate of EPG;
? EPGRateMin = @pointer(5);
? ! Max Decrease Rate of EPG;
? EPGRateMax = @pointer(6);
? ! Forcast Years
? T = @pointer(7);
? ! Total GDP Lower Demand
? TGDP = @pointer(8);
? ! Total GDP Lower Demand
? TEPG = @pointer(9);
? !Output File
? @Text('InputData.txt')=GDP0,GRateMin,GRateMax,EPG0,EPGRateMin,EPGRateMax,T,TGDP,
? enddata
? !Real EPGt;
? !@for (District(i) : EPGt(i) = EPG0(i) * ( 1-EPGRate(i) ) );
? !Real GDPt;
? !@for (District(i) : GDPt(i) = GDP0(i) * (1 + GRate(i))^T);
? !Real Energy Consumption Now
? !@for (District(i) : E0(i) = GDP0(i)*EPG0(i));
? !Real Energy Consumption
? !@for (District(i) : Et(i) = GDPt(i)*EPGt(i));
? !Minimize Total Energy Consumption;
? min = @sum(District(i) : (GDP0(i) * (1 + GRate(i))^T)*(EPG0(i) * (1-EPGRa
? !TE = @Sum (District(i) : Et(i));
? ! min = TE;
? !GDP Increase limit for Minimun or Maximun Rate of GDP;
? !@for (District(i) : GRate(i) >= GRateMin(i) , GRate(i) <= GRateMax(i));
? @for(District(i) : @bnd(GRateMin(i),GRate(i),GRateMax(i)));
? !EPG Decrease limit for Minimun or Maximun Rate of EPG;
? !@for (District(i) : EPGRate(i) >= EPGRateMin(i) , EPGRate(i) <= EPGRateMax(i));
? @for(District(i) : @bnd(EPGRateMin(i),EPGRate(i),EPGRateMax(i)));
? !Real GDPt;
? @for(District(i) : GDPt(i) = GDP0(i) * (1 + GRate(i))^T);
? !Real EPGt;
? @for(District(i) : EPGt(i) = EPG0(i) * (1-EPGRate(i)));
? !Real Energy Consumption
? @for(District(i) : Et(i) = GDPt(i)*EPGt(i));
? !Region Total GDP Lower Demand;
? CurTGDP = @sum (District(i) : GDPt(i));
? CurTGDP >= TGDP;
? !Region Total EPG Higher Demand
? TE = @sum (District(i) : Et(i));
? CurTEPG = TE/CurTGDP ;
? !CurTEPG >= TEPG;
? data:
? @pointer(10) = GDPt;
? @pointer(11) = EPGt;
? @pointer(12) = Et;
? @pointer(13) = GRate;
? @pointer(14) = EPGRate;
? @pointer(15) = rObj;
? @pointer(16) = @status();
? @pointer(17) = CurTGDP;
? @pointer(18) = CurTEPG;
? enddata
? end
: go
Compiling model ...
Structural analysis, pass 1 ...
Reading API parameters from: LINDO.PAR
Scalarizing model ...
Generating nonzero matrix ...
Solving ...
The LINDO API returned the following error code: 2026
LINDO API routine: LSsolve
License is too small for the given problem.
A solution is not available for this model.
Running output operations ...
: quit
没有人遇到过2026错误？请高手帮助！ LINDO API 12破解不完全，LINGO 11 Crack对应的API也不能调用，Team zwt的LINGO 9好像也有问题，你试试LINGO 10看看。主要是我不怎么熟悉C这些编程语言，LINGO使用这块关于API的调用了解得比较少，连用个mxLINDO我都差点看吐，也没有什么时间去静下去看，你要是急的话告诉我如何调用，我有真正无限制的API，可以帮你试试，不过不能分享。
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