关于3边的证明

tianpuke 发表于 2006-10-2 16:31

求解 如下<shapetype id="_x0000_t202" path="m0,0l0,21600,21600,21600,21600,0xe" ospt="202" coordsize="21600,21600"><stroke joinstyle="miter"></stroke><path gradientshapeok="t"></path></shapetype><shape id="_x0000_s1040" stroked="f" fillcolor="#0c9" filled="f" type="#_x0000_t202" style="MARGIN-TOP: -12.35pt; Z-INDEX: 15; LEFT: 0px; MARGIN-LEFT: 364.75pt; WIDTH: 29.15pt; POSITION: absolute; HEIGHT: 36pt; TEXT-ALIGN: left; mso-wrap-style: none; v-text-anchor: top-baseline;"><textbox style="mso-fit-shape-to-text: t;"></textbox></shape><table cellspacing="0" cellpadding="0" width="100%"><tbody><tr><td style="BORDER-RIGHT: #ece9d8; BORDER-TOP: #ece9d8; BORDER-LEFT: #ece9d8; BORDER-BOTTOM: #ece9d8; BACKGROUND-COLOR: transparent;"><div class="shape" vshape="_x0000_s1040" style="PADDING-RIGHT: 7.2pt; PADDING-LEFT: 7.2pt; PADDING-BOTTOM: 3.6pt; PADDING-TOP: 3.6pt;">E</div></td></tr></tbody></table><shape id="_x0000_s1039" stroked="f" fillcolor="#0c9" filled="f" type="#_x0000_t202" style="MARGIN-TOP: 29.65pt; Z-INDEX: 14; LEFT: 0px; MARGIN-LEFT: 160.75pt; WIDTH: 31.9pt; POSITION: absolute; HEIGHT: 36pt; TEXT-ALIGN: left; mso-wrap-style: none; v-text-anchor: top-baseline;"><textbox style="mso-fit-shape-to-text: t;"></textbox></shape><table cellspacing="0" cellpadding="0" width="100%"><tbody><tr><td style="BORDER-RIGHT: #ece9d8; BORDER-TOP: #ece9d8; BORDER-LEFT: #ece9d8; BORDER-BOTTOM: #ece9d8; BACKGROUND-COLOR: transparent;"><div class="shape" vshape="_x0000_s1039" style="PADDING-RIGHT: 7.2pt; PADDING-LEFT: 7.2pt; PADDING-BOTTOM: 3.6pt; PADDING-TOP: 3.6pt;">D</div></td></tr></tbody></table><line id="_x0000_s1038" to="282pt,116.4pt" from="258pt,32.4pt" style="Z-INDEX: 13; LEFT: 0px; POSITION: absolute; TEXT-ALIGN: left; flip: x;"><stroke endarrow="block"></stroke></line><line id="_x0000_s1037" to="258pt,116.4pt" from="252pt,44.4pt" style="Z-INDEX: 12; LEFT: 0px; POSITION: absolute; TEXT-ALIGN: left; flip: x y;"></line><shape id="_x0000_s1036" stroked="f" fillcolor="#0c9" filled="f" type="#_x0000_t202" style="MARGIN-TOP: 5.65pt; Z-INDEX: 11; LEFT: 0px; MARGIN-LEFT: 274.75pt; WIDTH: 30.5pt; POSITION: absolute; HEIGHT: 36pt; TEXT-ALIGN: left; mso-wrap-style: none; v-text-anchor: top-baseline;"><textbox style="mso-fit-shape-to-text: t;"></textbox></shape><table cellspacing="0" cellpadding="0" width="100%"><tbody><tr><td style="BORDER-RIGHT: #ece9d8; BORDER-TOP: #ece9d8; BORDER-LEFT: #ece9d8; BORDER-BOTTOM: #ece9d8; BACKGROUND-COLOR: transparent;"><div class="shape" vshape="_x0000_s1036" style="PADDING-RIGHT: 7.2pt; PADDING-LEFT: 7.2pt; PADDING-BOTTOM: 3.6pt; PADDING-TOP: 3.6pt;">C</div></td></tr></tbody></table><shape id="_x0000_s1035" stroked="f" fillcolor="#0c9" filled="f" type="#_x0000_t202" style="MARGIN-TOP: 20.4pt; Z-INDEX: 10; LEFT: 0px; MARGIN-LEFT: 228pt; WIDTH: 30pt; POSITION: absolute; HEIGHT: 36pt; TEXT-ALIGN: left;"><textbox style="mso-fit-shape-to-text: t;"></textbox></shape><table cellspacing="0" cellpadding="0" width="100%"><tbody><tr><td style="BORDER-RIGHT: #ece9d8; BORDER-TOP: #ece9d8; BORDER-LEFT: #ece9d8; BORDER-BOTTOM: #ece9d8; BACKGROUND-COLOR: transparent;"><div class="shape" vshape="_x0000_s1035" style="PADDING-RIGHT: 7.2pt; PADDING-LEFT: 7.2pt; PADDING-BOTTOM: 3.6pt; PADDING-TOP: 3.6pt;">B</div></td></tr></tbody></table><shape id="_x0000_s1034" stroked="f" fillcolor="#0c9" filled="f" type="#_x0000_t202" style="MARGIN-TOP: 134.4pt; Z-INDEX: 9; LEFT: 0px; MARGIN-LEFT: 240pt; WIDTH: 30pt; POSITION: absolute; HEIGHT: 36pt; TEXT-ALIGN: left;"><textbox style="mso-fit-shape-to-text: t;"></textbox></shape><table cellspacing="0" cellpadding="0" width="100%"><tbody><tr><td style="BORDER-RIGHT: #ece9d8; BORDER-TOP: #ece9d8; BORDER-LEFT: #ece9d8; BORDER-BOTTOM: #ece9d8; BACKGROUND-COLOR: transparent;"><div class="shape" vshape="_x0000_s1034" style="PADDING-RIGHT: 7.2pt; PADDING-LEFT: 7.2pt; PADDING-BOTTOM: 3.6pt; PADDING-TOP: 3.6pt;">A</div></td></tr></tbody></table><line id="_x0000_s1033" to="366pt,56.4pt" from="174pt,14.4pt" style="Z-INDEX: 8; LEFT: 0px; POSITION: absolute; TEXT-ALIGN: left; flip: y;"></line><line id="_x0000_s1032" to="366pt,116.4pt" from="258pt,14.4pt" style="Z-INDEX: 7; LEFT: 0px; POSITION: absolute; TEXT-ALIGN: left; flip: y;"></line><line id="_x0000_s1031" to="210pt,86.4pt" from="174pt,56.4pt" style="Z-INDEX: 6; LEFT: 0px; POSITION: absolute; TEXT-ALIGN: left; flip: x y;"></line><line id="_x0000_s1030" to="258pt,122.4pt" from="210pt,86.4pt" style="Z-INDEX: 5; LEFT: 0px; POSITION: absolute; TEXT-ALIGN: left;"></line><shapetype id="_x0000_t120" path="m10800,0qx0,10800,10800,21600,21600,10800,10800,0xe" ospt="120" coordsize="21600,21600"><path gradientshapeok="t" textboxrect="3163,3163,18437,18437"></path></shapetype><shape id="_x0000_s1029" fillcolor="#0c9" type="#_x0000_t120" style="MARGIN-TOP: 116.4pt; Z-INDEX: 4; LEFT: 0px; MARGIN-LEFT: 252pt; WIDTH: 6pt; POSITION: absolute; HEIGHT: 6pt; TEXT-ALIGN: left; mso-wrap-style: none; v-text-anchor: middle;"></shape><line id="_x0000_s1028" to="384pt,116.4pt" from="270pt,20.4pt" style="Z-INDEX: 3; LEFT: 0px; POSITION: absolute; TEXT-ALIGN: left;"></line><line id="_x0000_s1027" to="378pt,122.4pt" from="180pt,116.4pt" style="Z-INDEX: 2; LEFT: 0px; POSITION: absolute; TEXT-ALIGN: left; flip: y;"></line><line id="_x0000_s1026" to="276pt,116.4pt" from="186pt,14.4pt" style="Z-INDEX: 1; LEFT: 0px; POSITION: absolute; TEXT-ALIGN: left; flip: x;"></line> 如图假如小球从A点出发,做A的对称点D,再做A的另一边的对称点E联结DE 交点BC则三角形ABC就是运动轨迹。经过严、验证 A—>B—>C的过程遵守反射定律由于DE不能超过上面的顶点由此范围可以得到

zxpyxcn 发表于 2006-10-8 10:13

明白了

tolana 发表于 2006-11-24 18:02

en

qilongzhu 发表于 2006-11-24 11:24

我不明白啊

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数学建模社区-数学中国's Archiver

关于3边的证明