2019第十届蓝桥杯B组决赛题解第一题
2019第十届蓝桥杯B组决赛题解第一题题意: 求2019<X<Y ,使2019*2019,X*X,Y*Y组成等差数列且X+Y最小.
结果: 7020
代码:
#include<bits/stdc++.h>
#define mem(a,b) memset(a,b,sizeof(a))
using namespace std;
typedef long long ll;
const int inf = 0x3f3f3f3f;
const int maxn = 3e5+55555;
const ll mod = 998244353;
const double eps = 1e-7;
int main() {
int w = 2019*2019,x,y;
for(int i = 2020;i<= 10000;i++) {
x = i*i;
y = i*i+i*i-w;
int tmp = sqrt(y);
if(tmp*tmp == y) break;
}
cout<<sqrt(x)+sqrt(y)<<endl;
return 0;
}
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作者：nka_kun
来源：CSDN
页:
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