[讨论]大哥大姐帮忙看一下这个LINGO程序
<P>执行结果：</P><P>Error Code:<BR> 94</P>
<P>Error Text:<BR> Unexpected fall through Newton Loop: Contact LINDO Systems<BR> for patch availability.</P>
<P>附上源程序：后面大量的都是数据输入，烦请帮帮忙，谢谢啦</P>
<P>model:<BR> sets:<BR> from/1..7/:supply,p,S;<BR> to/1..15/:get,allQR,allQL;<BR> fromto(from,to):Q,F,QR,QL;<BR> distance/1..14/:len;<BR> endsets<BR> min = @sum(from(i):p(i)*supply(i))+@sum(fromtF*Q)+0.1/2*@sum(to(j):allQR(j)^2+allQL(j)^2-allQR(j)-allQL(j));<BR> @for(from(i):<BR> @sum(to(j):Q(i,j))=supply(i););<BR> @for(to(j):<BR> @sum(from(i):Q(i,j))=get(j);<BR> @sum(from(i):QR(i,j))=allQR(j);<BR> @sum(from(i):QL(i,j))=allQL(j);<BR> );<BR> @sum(from(i):supply(i))=@sum(to(j):get(j));<BR> @for(to(j)|j #ge# 2 :allQR(j-1)+allQL(j)=len(j-1);); <BR> allQL(1)=0;<BR> allQR(1)=0; <BR> @for(from(i):supply(i)>=500;supply(i)<=S(i););<BR> data:<BR> F= 170.7000 160.3000 141.2000 98.6000 38.0000 20.5000 3.1000 21.2000 64.2000 94.0000 96.0000 108.0000 125.2000 130.0000 143.1000<BR> 210.7000 200.3000 191.2000 172.6000 112.0000 95.5000 87.0000 71.2000 115.2000 144.0000 150.0000 158.0000 175.2000 180.00 194.0000<BR> 225.7000 215.3000 202.2000 182.6000 122.0000 106.5000 97.0000 86.2000 48.2000 82.0000 89.0000 96.0000 114.2000 119.0000 132.0000<BR> 255.7000 245.3000 236.2000 217.6000 157.0000 140.5000 132.0000 116.2000 88.2000 62.0000 51.0000 61.0000 79.2000 84.0000 98.0000<BR> 253.7000 243.3000 229.2000 210.6000 150.0000 133.5000 125.0000 114.2000 81.2000 57.0000 33.0000 51.0000 72.0000 77.0000 91.0000<BR> 254.7000 244.3000 230.2000 211.6000 151.0000 134.5000 126.0000 115.2000 82.2000 62.0000 51.0000 45.0000 26.2000 11.0000 28.0000<BR> 266.7000 256.3000 243.2000 223.6000 163.0000 147.5000 138.0000 127.2000 94.2000 78.0000 68.0000 56.0000 38.2000 26.0000 2.0000;<BR> p = 160 155 155 160 155 150 160;<BR> S= 800 800 1000 2000 2000 2000 3000 ; <BR> len=104 301 750 606 194 205 201 680 480 300 220 210 420 500 ; <BR> enddata<BR>end</P>
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