pride3310 发表于 2006-3-8 21:18

请高手帮忙解解一个非线性方程组!

请问下面的方程组如何解？(其中A1,A2,A3,A4,A5,A6为常数) x1*x1*cos(x2)*cos(x3)+x4*x4*cos(x5)*cos(x6)=A1 x1*x1*cos(x2)*sin(x3)+x4*x4*cos(x5)*sin(x6)=A2 -x1*x1*sin(x2) -x4*x4*sin(x5) =A3 x1*cos(x2)*cos(x3)+x4*cos(x5)*cos(x6)=A4 x1*cos(x2)*sin(x3)+x4*cos(x5)*sin(x6)=A5 -x1*sin(x2) -x4*sin(x5) =A6

pride3310 发表于 2006-3-8 21:19

<p>x1*x1*cos(x2)*cos(x3)+x4*x4*cos(x5)*cos(x6)=A1 </p><p>x1*x1*cos(x2)*sin(x3)+x4*x4*cos(x5)*sin(x6)=A2 </p><p>-x1*x1*sin(x2) -x4*x4*sin(x5) =A3 </p><p>x1*cos(x2)*cos(x3)+x4*cos(x5)*cos(x6)=A4 </p><p>x1*cos(x2)*sin(x3)+x4*cos(x5)*sin(x6)=A5 </p><p>-x1*sin(x2) -x4*sin(x5) =A6</p>

pride3310 发表于 2006-3-8 21:19

<p>开始发的没换行，抱歉!</p>

Iron_001 发表于 2006-9-1 13:44

<p>这里A1-A6全取为0，给出了方程的一组数值解</p><p>&nbsp;X= -4.401511704233166E-003&nbsp;&nbsp; 2.37848808715067&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 4.00211757466643<br/>&nbsp; 4.394757557655542E-003&nbsp;&nbsp; 2.37691000701559&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 3.99544008799962</p><p>误差：4.516939107748084E-005（得到的各方程误差的范数）</p><p>若还有其他线性方程组请发上，或者加QQ：290936988，本人将给予解答。</p>

llsfdyz 发表于 2006-11-16 23:48

qiang

kangyujie 发表于 2010-5-5 19:33

有程序可以用来求解非线性方程组吗？最好是c或c++，非常感谢
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