求助 帮忙转化为lingo的语言求解 感谢
<p>...刚学两天 什么都还不懂..</p><p>要求min=<span style="FONT-FAMILY: 宋体; mso-ascii-font-family: "Times New Roman"; mso-hansi-font-family: "Times New Roman";">∑</span><span lang="EN-US"><font face="Times New Roman">xi*pi i从1到45 pi是长度为45的已知的向量 </font></span></p><p><span lang="EN-US"><font face="Times New Roman">约束条件有1, xi为0 , 1 </font></span></p><p><span lang="EN-US"><font face="Times New Roman"> 2 , 80% <= (5750*0.95)/(<span style="FONT-FAMILY: 宋体; mso-ascii-font-family: "Times New Roman"; mso-hansi-font-family: "Times New Roman";">∑</span><span lang="EN-US">xi*ni) <= 90% ni为长45的已知向量;</span></font></span></p><p><span lang="EN-US"><font face="Times New Roman"><span lang="EN-US"></span></font></span></p><p><span lang="EN-US"><font face="Times New Roman"><span lang="EN-US"></span></font></span></p><p><span lang="EN-US"><font face="Times New Roman"><span lang="EN-US">感谢了 </span></font></span></p><p><span lang="EN-US"><font face="Times New Roman"><span lang="EN-US"><br/><br/></span></font></span></p>
[此贴子已经被作者于2008-5-1 13:16:17编辑过] model:<br/>sets:<br/>jihe/1..45/:x,p,n;<br/>endsets<br/>data:<br/>p=?;<br/>enddata<br/>@for(jihe:@bin(x));<br/>@sum(jihe:x*p)<=5750*0.95/90;<br/>@sum(jihe:x*p)>=5750*0.95/80;<br/>min=@sum(jihe:x*p);<br/>end <p>不好意思,范围给弄反了,下面的可用:</p><p>model:<br/>sets:<br/>jihe/1..45/:x,p,n;<br/>endsets<br/>data:<br/>p=?;<br/>enddata<br/>@for(jihe:@bin(x));<br/>@sum(jihe:x*p)<=5750*0.95/0.8;<br/>@sum(jihe:x*p)>=5750*0.95/0.9;<br/>min=@sum(jihe:x*p);<br/>end<br/></p> 谢谢了
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