标题: 谁来帮忙看一下这个题错在哪里？ [打印本页] 作者: Winter_moon 时间: 2011-3-19 15:26 标题: 谁来帮忙看一下这个题错在哪里？ Cryptoquote & k- Q$ n4 _( u' ~$ A' n4 f + i# E3 a, X6 R" E# U 6 I5 u& s: c( Y; n1 Q( jTime Limit: 1000 ms Memory Limit: 65536 kB ; S% K" u7 R. }( N0 vSolved: 79 Tried: 281 9 Y$ A* D9 ^( Z( a" h
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Description 4 w! L1 K* b7 l$ V% K/ f
A cryptoquote is a ** encoded message where one letter is simply replaced by another throughout the message. For example: 8 U6 o' P# ?: I& @- @- s5 Q6 n ' x( M! Z7 t6 M! NEncoded: HPC PJVYMIY 8 r) }) ?) _; w
Decoded: ACM CONTEST : o- ?' [, {4 r0 M& A u% a& ^8 c6 o- G
In the example above, H=A, P=C, C=M, J=O, V=N, Y=T, M=E and I=S. For this problem, you will decode messages. # [( d, W) P+ H5 G
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4 o. l/ e4 z! B$ A) ~" J! P. cInput ; |1 E f9 D5 g6 BThe first line of input contains a single integer N,(1<=N<=1000) which is the number of data sets that follow. Each data set consists of two lines of input. The first line is the encoded message. The second line is a 26 character string of upper case letters giving the character mapping for each letter of the alphabet: the first character gives the mapping for A, the second for B and so on. Only upper case letters will be used. Spaces may appear in the encoded message, and should be preserved in the output string. 6 Y: r8 e: Y1 O9 ~7 m H# P. ` . l) y! t7 n1 g- T( e" T( T( x& v( Z: G. W* |! c
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Output ' v3 I' e2 o7 y- h
For each data set, you should generate one line of output with the following values: The data set number as a decimal integer (start counting at one), a space and the decoded message. * V* i0 O8 H+ B; \8 k2 W . W/ L7 {! J5 ^ . z( Q u. i9 N4 a2 Y) |Sample Input * t" A9 v$ K7 x4 T# b9 v: `2 3 k! _8 J. ~! |) b1 THPC PJVYMIY ( s- s0 S; y4 C6 k/ ^- t7 m% H2 ?+ DBLMRGJIASOPZEFDCKWYHUNXQTV ' n! E0 v# j& T1 @FDY GAI BG UKMY 6 a7 F, F) w+ p7 s' i6 r
KIMHOTSQYRLCUZPAGWJNBVDXEF : s+ H* B2 @, U6 F; k3 J, E+ `8 ~/ k$ Y! z4 {9 r4 r" F
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Sample Output E/ J+ X& |' I2 M3 X; W$ g) b1 ACM CONTEST 5 C2 Q1 Y. t2 p S# D5 J2 THE SKY IS BLUE % a' x, T6 g: E. J4 c6 j" Q1 a+ _; i 3 r0 B, |- P. M! m+ K2 w1 c& \. O) B
0 c' z$ E4 f* K! a我的代码是： @( J* O0 B5 k A- d3 r
#include<stdio.h>: P. p) |7 w+ B: s
#include<string.h>7 B6 L, p. A, A: y
int main() $ c/ _) J9 N. s6 }/ J/ o2 {{ 7 ^+ c8 e/ v+ \0 E: P9 y/ `& h int N,i,j,k;1 h* j$ A0 q9 B' C
char c;3 i( q) e% v$ q T8 K
char code[1000];- k4 j+ D. D/ o3 e k6 X' [
char map[27];0 p5 e1 q0 m$ ~* W& r8 ~$ D% `* e! h
char trans[1000]; 0 n- g; ?2 ~2 ?2 b" B! Y S. s! K" N char wrong[3]; % X C5 h$ d( [% U# ~ scanf("%d",&N);2 x" v5 l' ?$ K4 X: l' Y# s
gets(wrong);. d) j; l) W+ Q9 z1 m6 U
int h=1;: z5 x1 h5 J0 P8 D
while(N--) / @( b) e1 P3 b! {7 P { $ d* Y# o, n; p3 B gets(code);: O* J2 R0 F7 }0 l
gets(map); 7 x5 {2 r+ |! s) t/ D for(i=0;((c=code[i])!='\0');i++) % B* I' a2 B* |& Z, i9 h { 9 r& D3 {/ n$ E" c& s6 s1 o8 ` if(c==' ')trans[i]=' '; , n t8 ]# A: j# H9 j5 [ else {j=code[i]-'A';+ j0 B Y* V$ `
trans[i]=map[j];} }( ^0 ^ k. P9 p; \$ ?9 E
printf("%d ",h); & R% s1 ^8 U6 o7 N. c' Z for(i=0;((k=trans[i]<=90)&&(k=trans[i]>=65)||(k=trans[i]==' '));i++)8 D1 w6 l, Y" Z5 g, l0 w
printf("%c",trans[i]);8 j/ \7 F/ I# \# \0 c5 D
h++; 8 ~) k2 o/ [* R8 @) } printf("\n");0 Z5 y1 s- c6 E) E
} ! \& h Z+ x9 k7 U6 t: s! F# L return 0; ; l+ f l1 c, g% ~7 R} 0 S4 H- w: r) w' R* ` ' |! h5 k- B6 y$ x , j. i# b8 i' l9 _. }1 Y样例过了，但是提交答案的时候还是wrong answer。是哪里有陷阱？( \& X O {6 d$ g 作者: zjqylcy 时间: 2011-3-19 22:26
把答案也附上来吗。。。 - g: z7 G& q; X% o是不是k是int型？作者: 葉_浅浅 时间: 2011-3-20 16:45
.....................作者: linmatsas 时间: 2011-3-20 23:27
C………………………………作者: _我还活着 时间: 2011-4-29 18:56
没有看懂.....作者: huangliao6252 时间: 2011-5-6 00:49
int h=1;这个定义应该在 scanf("%d",&N);前面。