数学建模社区-数学中国
标题: [求助]谁能帮我翻译一下这篇文章?~ [打印本页]
作者: angel_lys 时间: 2007-11-23 22:16
标题: [求助]谁能帮我翻译一下这篇文章?~
文章是讲一致收敛和微分的~我英语不好看不明白~请大家帮帮忙啊~~~~
Theorem 9.13. Assume that each term of is a real-valued function having a finite derivative at each point of an open interval
4 L `) y7 h2 H) l . Assume that for at least one point9 v# j7 \$ u8 M
in
; J1 I5 C9 O w; [$ B( s7 e- ~5 p the sequence converges. Assume further that there exists a function g such that% h# j y5 t" J9 I2 @ @8 n
uniformly on8 j! b) w) [5 G9 d& m
. Then:
$ b+ y W" P/ b; S8 y
a) There exists a function f such that C4 _7 {! n" D: K2 l3 B
uniformly on' e# A6 W4 Y% B) A C% h ]$ U1 s& K5 K9 b
.
b) For each x in
/ i/ |/ n% { P! a# q5 X+ L the derivative$ r6 W1 X6 V: M' D% \' ^9 ^
exists and equal
# x2 a) C) |; ]: B+ e .
Proof. Assume that
! g! e: z4 {4 g' C and define a new sequence
8 J0 m4 H, j7 S7 `7 o4 A8 t as follows:
8 V' w) [6 I3 @
' V$ v6 g8 q5 a+ C* u6 k0 n W (8)
5 t9 D! m& j- }7 G
The sequence4 W& k8 u5 n- T, B
so formed depends on the choice of c. Convergence of follows from the hypothesis, since
( g9 g4 O; F: \2 z6 E4 B . We will prove next that( a8 H( }9 f( g( ?& s
converges uniformly on$ p2 n: X) d. ~- s& C) B
. If , we have
% c5 V$ R/ d9 Y& R
,
3 W; g; j9 }/ z3 X& y/ M (9)
& H, d, X0 {8 }2 p; v
where
% }7 U0 \$ O+ `4 _! s . Now
3 c! O# B5 P. f) Z0 G5 \) F exists for each x in
( o$ ~9 Z' A6 L% o a4 d+ c" { and has the value( f5 j& v% j9 x C
. Applying the Mean-Value Theorem in (9), we get
,
; O8 }' D' `( I8 P3 @- Y7 D$ I8 J; E
4 g+ I! \# w0 H! K (10)
where7 \2 o- [8 r* e9 E- x% L& x
lies between x and c. Since
/ O1 q; ~& l- i! w p& h converges uniformly on0 t6 j. Q% D# u. J1 z
(by hypothesis), we can use (10), together with the Cauthy condition, to deduce that& K' m, n0 J# S* l% v
converges uniformly on7 J0 {( s( J* J8 C
.
Now we can show that3 O' N+ |- A+ |3 P) k. r. N
converges uniformly on
' }4 F3 H+ V8 l . Let us form the particular sequence5 e- t8 O# j6 m7 Q2 J% d
corresponding to the special point
9 t2 F3 B4 y4 y5 ?. d for which
3 N& A/ W9 r$ T- W is assumed to converge. Form (8) we can write
an equation which holds for every x in
" V0 j; d$ O$ I% `& ]7 x0 K1 m . Hence we have
This equation, with the help of the Cauthy condition, establishes the uniform convergence of on% N# N* M( c% y! E8 R2 x
. This proves (a).
To prove (b), return to the sequence3 k8 a0 v @+ D8 e+ u3 x
defined by (8) for an arbitrary point c in& B, c ]1 H) t$ a
and let8 b% h$ [& V( g
. The hypothesis that
# j$ R; L) d& }; a exists means that . In other words, each
. Q7 C% o6 J4 q% L- l" Z8 P1 J is continuous at c. Since
( W( U0 K: @5 Y( O/ M! d uniformly on
- j9 S& S1 b: Q& {% x/ m , the limit function G is also continuous at c. This means that
4 h# O. E- O! q; T9 Y( }( N8 u
(11)
the existence of the limit being part of the conclusion. But for
+ ?( x+ L: G' c* U0 E# g , we have
Hence, (11) states that the derivative8 ?* V/ I ^9 }: o! V+ x$ Z
exists and equals i& }( g" k b, v
. But
hence k, I$ m: N! l0 o4 @5 k4 h4 V
. Since c is an arbitrary point of
% e& {# X" z2 q/ A# v/ p4 E , this proves (b).
When we reformulate Theorem 9.13 in terms of series, we obtain
) h$ u, |$ d! z0 Q# m. Q
Theorem 9.14. Assume that each
\0 F6 ^( e( f; Y* |1 T2 A% H, J is a real-valued function defined on0 D0 O2 g; I: v( F' W
such that the derivative
2 r) s; V7 D2 L( ^1 C! b/ c6 s: } exists for each x in. C; J! l% r6 s. l3 U
. Assume that, for at least one point
- w* f9 ^. S/ f' C$ n in
. T( z9 x% q8 u: @# V( O/ B , the series% y: ?# O$ f6 I# p$ z1 F
converges. Assume further that there exists a function g such that (uniformly on
" ]' M8 v( m) T4 p$ a: M ). Then:
a)) p. q7 Q! v" S" |" p, S
There exists a function f such that
2 @" \7 j2 k3 n8 h6 M- k" q (uniformly on
& y) K3 o" m1 b ).
b)
7 h9 M+ {5 L' |) u If , the derivative; ?5 Q2 r$ B. x9 U0 e
exists and equals j% @& F" s. K" |/ ~. l
.
作者: lzh0601 时间: 2008-4-19 13:22
我怎么只看到脚本文件呢?
作者: tinkertinker 时间: 2008-7-28 14:22
“Theorem 9.13. Assume that each term of is a。。。。。” 这里面有没有漏了字?
# O! V" u* P' m* C( B, c( ]& Z+ w
[此贴子已经被作者于2008-7-28 14:24:38编辑过]
作者: rao 时间: 2009-1-13 21:47
看不清楚。。。。。
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