数学建模社区-数学中国
标题:
求助,代码第二段啥意思
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作者:
魏关亭侯
时间:
2012-7-25 10:30
标题:
求助,代码第二段啥意思
背包问题,12件物品质量为2,5,18,3,2,5,10,4,11,7,14,6,价值为5,10,13,4,3,11,13,10,8,16.7.4,包的最大重量是46
9 j6 |* J3 d8 t) Z- E2 ^3 n+ e
求最优方案
, t4 D5 Y$ O- E2 I0 G2 i
代码如下,第二段看不懂,从那个=~开始,那符号啥意思
: ]( q3 Q. B( C# ~5 d+ @
a=0.95
' i8 ^) c# c& B, z6 b
k=[5;10;13;4;3;11;13;10;8;16;7;4];
/ b7 k' h$ P7 G- y
k=-k;
/ Z4 Y. u3 \, h9 X- N" M/ K/ d
d=[2;5;18;3;2;5;10;4;11;7;14;6];
/ q; I' U9 p$ p. j3 [4 x* @% p/ \
restriction=46;
, p. B" B! R' g: K: O
num=12;
# [7 @8 ]! A, Y; T( r4 _9 A3 i
sol_new=ones(1,num);
. k3 V/ c+ d$ L( K2 m
E_current=inf;E_best=inf;
+ V' K, l# Q7 e) S( l
sol_current=sol_new; sol_best=sol_new;
) J! L) D1 i4 ` t* m
t0=97;tf=3;t=t0;
. v( i, O6 Q) e. A4 w
p=1;
/ G0 o0 r0 E* P
7 W* G# Y2 W- ^/ `" \
while t>=tf
9 |/ m, u- o2 h4 y) D& a$ m+ [6 ~& K
for r=1:100
" J0 e4 T; _: U# w- k' G5 x
tmp=ceil(rand.*num);
" c7 B! P8 v0 t3 F; c6 @
sol_new(1,tmp)=~sol_new(1,tmp);
9 r! v% {- ?3 [, H- D, r, d0 O$ C
while 1
4 g% d" g `, ^; y
q=(sol_new*d<=restriction)
1 x8 S6 D+ n+ a: d3 B4 E1 l+ j! i* \
if ~q
, Q6 L$ p; N9 x* E+ b8 |6 i
p=~p
2 W* d, G& I0 b" v; A; I7 y7 k
tmp=find(sol_new==1);
2 x# K7 B9 J) R/ v
if p
9 Q, `& }+ m' m3 g: K& i+ a
sol_new(1,tmp)=0;
' h0 Q0 B) c' p! g9 E
else
/ W z( |- F* N8 d4 U. X
sol_new(1,tmp(end))=0;
0 d9 z" J8 C# `$ G; m: t: E
end
/ B/ n) e" t& C( t( n$ l
else
& [; n G; Y d# Y" X
break
9 s! J' B3 d7 u' f5 H3 j2 o! N
end
% X4 d. i- F- K' Z
end
/ | P+ V/ ^6 `( \2 g0 ^2 K
作者:
赵煜星
时间:
2012-7-25 21:01
好啊 我喜欢
作者:
梦天涯M
时间:
2012-8-5 11:54
model:
2 K( e/ X% M2 ~8 A2 m
sets:
/ G$ r$ Q& _5 W) ]
beibao/1..12/:zhiliang,jiazhi,x;
; T, H$ ^- q) Y, E. N: V4 F
endsets
, ^3 }) k# r; @4 b% {/ B4 v
data:
0 [2 {# w1 U; Q8 x& Z6 D
zhiliang=2 5 18 3 2 5 10 4 11 7 14 6;
; B. R. p) T$ A5 |# w3 X/ ~
jiazhi=5 10 13 4 3 11 13 10 8 16 7 4;
2 k' k4 E1 ^4 M2 F, z ?( ^2 ^8 n
enddata
/ ?$ f6 @; W8 h3 {, J2 S$ K
max=@sum(beibao(i):jiazhi(i)*x(i));
$ t0 K# j- w% ^9 c* F7 H
@sum(beibao(i):zhiliang(i)*x(i))<46;
4 y8 {' }) U) I8 Z! h% u2 a
@for(beibao(i):
/ U% ^! b1 a. Z$ o; [
@bin(x(i)));
+ Q3 F+ j: n4 e& o, e8 \
7 c& T2 @; P$ D R+ x7 S
结果:
: d! g( H! f. @# v5 u
Global optimal solution found.
, L" P9 b0 `2 L9 _7 {, ?
Objective value: 76.00000
5 P/ g9 z: y5 g5 H
Objective bound: 76.00000
9 M' l2 I: ^5 n! R/ _
Infeasibilities: 0.000000
5 R9 k6 `1 W5 k( L k( C5 d
Extended solver steps: 0
7 g9 T5 t* T5 [
Total solver iterations: 0
# K I9 `# o; E( e( A7 X; B u. U- S
{& d0 D( I/ W; g1 g9 ]
Model Class: PILP
/ n# @/ w; H+ x1 k5 M* K4 }
0 }0 H$ ?) h; C" P
Total variables: 12
3 }+ \$ I: |5 x) |, d* s
Nonlinear variables: 0
3 ]' L5 o, o ?1 V, z* n* H) l
Integer variables: 12
9 P2 e) p) F4 ~) @) A# X2 g
% B4 U/ N4 r# l) {
Total constraints: 2
, e6 |- \- {" x: V# U) d
Nonlinear constraints: 0
/ _+ W4 V$ d; ]
( R) H$ K, }: V) c* s
Total nonzeros: 24
, }- [7 b. K7 B
Nonlinear nonzeros: 0
* O" i- Q+ T+ W) ]2 f
% U* P' V; o. \3 v9 E
3 u+ Y) W& [/ g
Variable Value Reduced Cost
! B" a, L2 r' z; K
ZHILIANG( 1) 2.000000 0.000000
9 C8 i7 \) k- O4 J, P" Z9 Z
ZHILIANG( 2) 5.000000 0.000000
. U) E' G- F6 S R6 ^7 I
ZHILIANG( 3) 18.00000 0.000000
6 t4 G0 n$ [- k$ k; O
ZHILIANG( 4) 3.000000 0.000000
: f7 M8 |0 B8 e
ZHILIANG( 5) 2.000000 0.000000
; w2 K' l1 q5 o* A% i
ZHILIANG( 6) 5.000000 0.000000
5 U( D9 B* ^- v: r$ o- D5 t
ZHILIANG( 7) 10.00000 0.000000
! Z/ o; F0 O( V; I/ H9 C9 A6 D
ZHILIANG( 8) 4.000000 0.000000
! l6 B' z6 g7 [- a: l; I8 E
ZHILIANG( 9) 11.00000 0.000000
5 M; g" t, e6 D. _) k5 F( I" f: x0 O
ZHILIANG( 10) 7.000000 0.000000
( I- f( A. q1 P% u7 ~. `) v
ZHILIANG( 11) 14.00000 0.000000
5 d6 f7 l: O* b# U( f
ZHILIANG( 12) 6.000000 0.000000
8 m$ d9 ]* i8 s
JIAZHI( 1) 5.000000 0.000000
. f* Y$ W: t) e9 a0 l, I! G8 }. B
JIAZHI( 2) 10.00000 0.000000
3 e3 G4 X+ E4 F" i( `; s, A' a
JIAZHI( 3) 13.00000 0.000000
( x8 U3 I4 D E$ U0 i8 T2 Z, f
JIAZHI( 4) 4.000000 0.000000
. l+ Q) _, r9 d8 K; s
JIAZHI( 5) 3.000000 0.000000
" Y; n+ ?. [ X/ l( k
JIAZHI( 6) 11.00000 0.000000
7 C" A+ f9 s7 e
JIAZHI( 7) 13.00000 0.000000
' Z" @4 |6 R: [$ ]9 p
JIAZHI( 8) 10.00000 0.000000
1 l% ]9 F0 V7 `' a& w
JIAZHI( 9) 8.000000 0.000000
2 M p/ Z6 j ]+ Y$ n
JIAZHI( 10) 16.00000 0.000000
, B# ?: l8 u- |# ^2 P$ x
JIAZHI( 11) 7.000000 0.000000
: Z2 Q( k+ ]2 T1 j
JIAZHI( 12) 4.000000 0.000000
9 A& J3 C6 N- A! ~
X( 1) 1.000000 -5.000000
6 e: ~. f% Z. n# b* e
X( 2) 1.000000 -10.00000
1 _2 Y, |' C9 j7 s- n9 ^; K
X( 3) 0.000000 -13.00000
. F" @$ _; |* W: w# I8 {8 D/ e
X( 4) 1.000000 -4.000000
5 F6 i0 F5 {2 I* a( r8 ]% ?
X( 5) 1.000000 -3.000000
; {2 g1 l+ r `, q- s, S
X( 6) 1.000000 -11.00000
" A1 D6 a r+ [% F& k; `
X( 7) 1.000000 -13.00000
8 q; [+ a& _& s8 m( M" ^/ m
X( 8) 1.000000 -10.00000
5 r* ` F/ ^: H2 ^# m4 b8 n$ q! k
X( 9) 0.000000 -8.000000
" h) H- Q L5 y4 m
X( 10) 1.000000 -16.00000
0 p$ f7 ?& }/ ~* p: O
X( 11) 0.000000 -7.000000
+ F' M9 o- y3 M1 _
X( 12) 1.000000 -4.000000
, ]7 ~* W: B2 m
9 q. e# W2 `! p* H) s; [ n
Row Slack or Surplus Dual Price
/ ]; Z$ s1 ~0 a# m+ Q; b
1 76.00000 1.000000
; k: C) g3 h2 F8 B1 x7 ]0 {
2 2.000000 0.000000
m) a# `* D/ e; E( ?1 Q
2 f" m' R- W* l3 }6 S
作者:
梦天涯M
时间:
2012-8-5 11:56
不好意思,上边写成bin了,应该是gin
# b0 R% ~9 M0 `3 l* [
正确程序:
! B' g/ T2 ~9 k
model:
. j, C. R5 X4 M1 w' k
sets:
3 q9 j8 T4 x" K4 g
beibao/1..12/:zhiliang,jiazhi,x;
8 W5 b, n) y8 L3 N4 l- ]" v
endsets
: h. }0 o( Q- v4 o, D
data:
# ~6 h$ k: ~4 ~- z* \" u: y
zhiliang=2 5 18 3 2 5 10 4 11 7 14 6;
! S3 u8 Q y. Q
jiazhi=5 10 13 4 3 11 13 10 8 16 7 4;
9 `) N0 \$ y9 _
enddata
% D; @8 I8 `! {* z4 F4 r8 k5 q" {
max=@sum(beibao(i):jiazhi(i)*x(i));
" p: h! L, [6 Y& L5 W
@sum(beibao(i):zhiliang(i)*x(i))<46;
. X( f! l# }/ }4 W$ L
@for(beibao(i):
- Y7 s9 I3 k# i
@gin(x(i)));
作者:
梦天涯M
时间:
2012-8-5 11:58
Global optimal solution found.
( `: T# q# h$ D% q+ Q' f, {
Objective value: 115.0000
0 w' J: N# @7 N O
Objective bound: 115.0000
5 Z8 G6 O' S* n$ R8 h. B8 o7 I
Infeasibilities: 0.000000
r% ~. L6 V. J. v' w+ m) e1 z
Extended solver steps: 0
% P, l8 w% Z# [8 M
Total solver iterations: 0
( |4 e: }9 j# N) x+ w
* s3 \6 e8 i. x8 c3 X
Model Class: PILP
! ]6 v) |& \6 f! D+ x6 x
& o1 f1 d( S( ?5 Y. M
Total variables: 12
' v6 _3 L3 y" h2 ^
Nonlinear variables: 0
, ?' Z& y" S' T% H
Integer variables: 12
`. K4 [: A: B0 l) B8 g) g9 j( O3 w8 s
" u% e: G p7 \4 Z
Total constraints: 2
# b8 U1 G1 }- W1 X: X+ H6 o
Nonlinear constraints: 0
% }+ A( [" r# F0 ]+ S
8 i) ]! `& j) b, D7 w8 J
Total nonzeros: 24
( A/ b* b5 c9 S/ }
Nonlinear nonzeros: 0
: |- f1 J; z$ h8 I
R0 t4 @+ k& F6 s$ l* H# [
" O+ m2 L* N% z' p
Variable Value Reduced Cost
$ |/ p; ^$ ~/ j, X8 |
ZHILIANG( 1) 2.000000 0.000000
5 C* ]4 `1 H7 ]7 a3 h
ZHILIANG( 2) 5.000000 0.000000
) s7 C4 t. x. f; Y1 _
ZHILIANG( 3) 18.00000 0.000000
9 R' h* T8 L& P6 m, B |% g: m! j9 d
ZHILIANG( 4) 3.000000 0.000000
% l# z- H g% _+ g0 Y( `4 \
ZHILIANG( 5) 2.000000 0.000000
- ]/ \. n" w+ i% P( ]( d6 U. D
ZHILIANG( 6) 5.000000 0.000000
( F8 v) s' K/ J- R9 D3 y, o, B& V
ZHILIANG( 7) 10.00000 0.000000
- `, w. f9 m. R" _7 F
ZHILIANG( 8) 4.000000 0.000000
" @5 N, N v4 B+ p$ L- a' X e
ZHILIANG( 9) 11.00000 0.000000
) G2 ~: X* Z6 w7 _. _
ZHILIANG( 10) 7.000000 0.000000
! e# x7 `- P1 p/ u: H/ R" N
ZHILIANG( 11) 14.00000 0.000000
* @4 b% [& R0 o$ a* g7 @
ZHILIANG( 12) 6.000000 0.000000
* m/ N. p7 v0 a4 R
JIAZHI( 1) 5.000000 0.000000
" o' J% l% {3 _& ^- N" c5 q( K
JIAZHI( 2) 10.00000 0.000000
) ^; \ _: ~4 X1 c8 z3 G
JIAZHI( 3) 13.00000 0.000000
, f0 M& O1 @8 h4 F
JIAZHI( 4) 4.000000 0.000000
& \; ]) l# b% w* H* @7 B
JIAZHI( 5) 3.000000 0.000000
O$ _5 u8 `0 v) e( M8 N" R& n
JIAZHI( 6) 11.00000 0.000000
+ C7 K( w, D3 ]9 @! L( g ^ @
JIAZHI( 7) 13.00000 0.000000
; @0 h3 n Z/ t# l$ q2 k: Z' q
JIAZHI( 8) 10.00000 0.000000
* p- r: i" w3 |4 |0 G1 z$ [6 R2 a+ c
JIAZHI( 9) 8.000000 0.000000
2 U" i {, i p& M. i0 r7 Q5 T! W
JIAZHI( 10) 16.00000 0.000000
0 _( f ]) h/ m+ h8 {9 p2 ?! a
JIAZHI( 11) 7.000000 0.000000
, p7 C! Y5 w8 @$ [+ P* f
JIAZHI( 12) 4.000000 0.000000
0 c& b3 E6 G" p( q
X( 1) 1.000000 -5.000000
- e/ H/ n1 W, U
X( 2) 0.000000 -10.00000
# B. ~, k! X8 j' o9 m" A. z
X( 3) 0.000000 -13.00000
: u# d i- W9 e& M/ Y) W g
X( 4) 0.000000 -4.000000
( j, A$ Z0 C; }8 K4 y x
X( 5) 0.000000 -3.000000
/ i; c" N: ~) |; m v2 m% X
X( 6) 0.000000 -11.00000
5 f4 X- s8 P( V7 J. e& i! i
X( 7) 0.000000 -13.00000
+ p( L( L' _8 X' j
X( 8) 11.00000 -10.00000
0 x l8 y/ k2 r5 `( m) O* `
X( 9) 0.000000 -8.000000
1 ]& V. ^- w$ e: q' p$ r
X( 10) 0.000000 -16.00000
$ H' F% s$ I7 h3 A; b
X( 11) 0.000000 -7.000000
/ s( y: ]$ ]/ I
X( 12) 0.000000 -4.000000
6 N h3 ]& y8 B
2 G/ s: L o( Q
Row Slack or Surplus Dual Price
/ c4 ]! O" f$ i6 ?, x, [
1 115.0000 1.000000
( F. \' U, }9 ^
2 0.000000 0.000000
3 H& \/ s6 j2 C9 D( n
作者:
梦天涯M
时间:
2012-8-5 11:59
第一件物品取1件,第8件物品取11件,最大价值115
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