数学建模社区-数学中国
标题:
求助,代码第二段啥意思
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作者:
魏关亭侯
时间:
2012-7-25 10:30
标题:
求助,代码第二段啥意思
背包问题,12件物品质量为2,5,18,3,2,5,10,4,11,7,14,6,价值为5,10,13,4,3,11,13,10,8,16.7.4,包的最大重量是46
! W: F T8 o4 [* p# ~, R5 ?* y
求最优方案
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代码如下,第二段看不懂,从那个=~开始,那符号啥意思
4 R, `, w% B8 [( K8 Z N0 `' e9 g
a=0.95
, @. d; L: I: M0 v4 J2 x( h
k=[5;10;13;4;3;11;13;10;8;16;7;4];
: ?2 \# X2 E$ \' F5 W
k=-k;
( b( ^% W4 U9 X2 l& ]7 ^/ T% x! i3 d
d=[2;5;18;3;2;5;10;4;11;7;14;6];
, [4 t8 i) \) N: o4 P1 c
restriction=46;
$ P& C8 L7 P Y2 W
num=12;
7 [9 R7 A/ B* [4 \/ e5 @6 N0 E
sol_new=ones(1,num);
$ \5 [7 ~) w4 D6 ?$ M
E_current=inf;E_best=inf;
$ s$ L; p" o' ~0 {
sol_current=sol_new; sol_best=sol_new;
, ~2 Y, B3 ~4 M- X+ L$ y
t0=97;tf=3;t=t0;
. Y. }4 A" p- L) u
p=1;
1 P3 f3 ~! c$ d, K
/ L6 D4 @8 k0 }8 x* r8 Z
while t>=tf
7 y: u- `0 i4 p
for r=1:100
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tmp=ceil(rand.*num);
; Z; t# E' k* G" [7 D; G, s! z
sol_new(1,tmp)=~sol_new(1,tmp);
# P9 k. b Q! Z# m) W
while 1
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q=(sol_new*d<=restriction)
+ O% [. F. l1 ?& G4 A: v1 Y; H8 f( ^
if ~q
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p=~p
_# H+ F t' m0 I
tmp=find(sol_new==1);
1 W2 \7 ]$ u m3 q. [1 E6 r: `# Z
if p
3 a( E4 [( X( \/ ]# I7 A
sol_new(1,tmp)=0;
) T! n* t! l% X6 ~+ A6 `
else
0 k7 S1 k/ P9 U- N; w6 H
sol_new(1,tmp(end))=0;
- T" S5 M2 ?. h9 d7 y2 w; s
end
1 ~& v0 d" q! H8 }2 u1 q5 v
else
9 e. L: x6 l# c4 P5 \- U
break
3 ?( I6 [6 W' o4 q' o
end
: ?# `$ `' P7 z
end
/ q5 W- O* B5 @. I0 s
作者:
赵煜星
时间:
2012-7-25 21:01
好啊 我喜欢
作者:
梦天涯M
时间:
2012-8-5 11:54
model:
* ~5 x) P* [( Q) k" _+ l
sets:
" z G2 b5 t, m' z
beibao/1..12/:zhiliang,jiazhi,x;
2 o! y; x6 s1 Z. N4 x8 l, C1 V$ ?
endsets
9 q- N: D+ L) J
data:
' G* `; q& O/ o6 [
zhiliang=2 5 18 3 2 5 10 4 11 7 14 6;
* H' y) }3 N0 V8 z! t4 I
jiazhi=5 10 13 4 3 11 13 10 8 16 7 4;
% Y$ t5 G3 ^$ s. y" l0 {! @
enddata
# a1 {$ W$ R( t5 t3 L
max=@sum(beibao(i):jiazhi(i)*x(i));
& W$ \& ^5 D; u
@sum(beibao(i):zhiliang(i)*x(i))<46;
# n& f: {# t/ ~; W% f7 D
@for(beibao(i):
, ~, z2 C+ K, H1 Y( r
@bin(x(i)));
7 k3 f5 M; p/ Y' _; B: I6 p0 V9 ]
1 F: d/ i% w" e- z v& }$ I* U2 z
结果:
: {- }& V( {% K: S0 C. |
Global optimal solution found.
% `* S& p3 p1 R4 E5 R9 M
Objective value: 76.00000
r' j- w' ?. u5 ~9 j9 G K
Objective bound: 76.00000
; `; \: G# o' w' j; A* U
Infeasibilities: 0.000000
. S5 I; d1 y9 ~6 h
Extended solver steps: 0
) d( D7 x, w4 @; H) J! f
Total solver iterations: 0
: I" ^# ]9 b6 S# D* u
5 G& H. ?& s o- l" {1 u
Model Class: PILP
6 t. l( [) ?1 d/ @- I$ V
$ ]% ^/ r, R3 @( y7 i
Total variables: 12
3 V% Y) P* c- ^( z& v6 |
Nonlinear variables: 0
' q( l7 c1 X9 b+ t! ^8 Y, [
Integer variables: 12
1 J2 ?: g, n T1 Y0 W
8 p% x+ y" o" T
Total constraints: 2
* U) H9 K8 e2 T
Nonlinear constraints: 0
" a( Z. P. c* W) U
- @8 ^9 s4 K* J. Y, G; t; v
Total nonzeros: 24
" z$ C. P. W: g9 D
Nonlinear nonzeros: 0
1 U9 |2 m" ^$ f+ G# g. ^$ U& P. N C
+ z6 u4 u @6 E4 k0 T* n
3 K. q0 E8 n; q7 t0 K9 W
Variable Value Reduced Cost
( |2 A# O7 [8 x; \8 b, j4 n
ZHILIANG( 1) 2.000000 0.000000
5 K( { g& A$ s4 g) d
ZHILIANG( 2) 5.000000 0.000000
1 V# N4 y1 a3 M7 J$ z
ZHILIANG( 3) 18.00000 0.000000
- n# X; i, u* q& S+ ]; L6 i
ZHILIANG( 4) 3.000000 0.000000
5 `) C7 s& f+ `' C' N
ZHILIANG( 5) 2.000000 0.000000
. d1 d' F5 w) \+ d( |3 n
ZHILIANG( 6) 5.000000 0.000000
2 q4 x" `% {# g$ Q4 s9 D. W
ZHILIANG( 7) 10.00000 0.000000
+ r* C! b5 r) k$ D$ N
ZHILIANG( 8) 4.000000 0.000000
+ G! _$ D: l1 P8 j
ZHILIANG( 9) 11.00000 0.000000
+ y: [- b8 u. D1 n# S/ Z" E
ZHILIANG( 10) 7.000000 0.000000
8 ^2 R. s3 A N2 A
ZHILIANG( 11) 14.00000 0.000000
- q6 J: C0 t3 c0 c/ P5 ~
ZHILIANG( 12) 6.000000 0.000000
& H) m5 y z5 x$ e" @3 L
JIAZHI( 1) 5.000000 0.000000
% J N! G; g( O
JIAZHI( 2) 10.00000 0.000000
& g3 b4 {5 ?5 _$ \" e' v
JIAZHI( 3) 13.00000 0.000000
, y0 {% V) N& y
JIAZHI( 4) 4.000000 0.000000
2 L7 v1 {4 ~! N6 K. d
JIAZHI( 5) 3.000000 0.000000
! i( t6 j& y" Z b2 D
JIAZHI( 6) 11.00000 0.000000
" q% |: q6 z; M6 U7 x
JIAZHI( 7) 13.00000 0.000000
- S+ |: b: g# Q8 j% U
JIAZHI( 8) 10.00000 0.000000
( H' D+ K( Y4 D( ?
JIAZHI( 9) 8.000000 0.000000
% S6 m f; X" J$ X
JIAZHI( 10) 16.00000 0.000000
) Z5 n- l4 {( s. _+ d
JIAZHI( 11) 7.000000 0.000000
: r/ }+ G& ~' @) h3 r" m
JIAZHI( 12) 4.000000 0.000000
5 b5 a4 Y' v. U9 z0 r% Q9 y
X( 1) 1.000000 -5.000000
4 O3 _* _* @! m) }' x6 U' Q7 h
X( 2) 1.000000 -10.00000
( S. f0 C$ x& d: ~" ]# D% n
X( 3) 0.000000 -13.00000
0 H4 l9 \/ _5 ]1 M- [# X A5 T
X( 4) 1.000000 -4.000000
$ e9 x% V* y: P
X( 5) 1.000000 -3.000000
+ M5 I# v4 C0 W
X( 6) 1.000000 -11.00000
7 {9 t4 F8 K1 C) c7 l v! A2 g/ |) H
X( 7) 1.000000 -13.00000
" s1 h& a7 K1 D0 O) u
X( 8) 1.000000 -10.00000
+ w) D& A" L7 R& c
X( 9) 0.000000 -8.000000
# g- f" b! m4 t" w
X( 10) 1.000000 -16.00000
' `; `& p! }7 p
X( 11) 0.000000 -7.000000
# A: Z {; @0 U: X$ Q( c
X( 12) 1.000000 -4.000000
# n( A: O4 P% C! e( q
! o' j3 _' I" [! G
Row Slack or Surplus Dual Price
) n" M9 B; v: a7 m
1 76.00000 1.000000
6 ]; k9 s& J' b( U, c) a* R/ C |
2 2.000000 0.000000
, U9 D$ R2 e* i2 u$ V3 s
9 G9 I1 ^$ c7 l7 ?
作者:
梦天涯M
时间:
2012-8-5 11:56
不好意思,上边写成bin了,应该是gin
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正确程序:
, g. `: p' {; y! f
model:
( j6 x1 \( d3 n2 P. ?% Q
sets:
6 m* v: r3 { h/ R8 T; q9 I
beibao/1..12/:zhiliang,jiazhi,x;
1 m9 g' E3 P. [" Y% S ?0 O% U+ t% y
endsets
$ A: P$ L0 G! D' r& g
data:
" [0 h! f& v$ i, L3 f L5 Y
zhiliang=2 5 18 3 2 5 10 4 11 7 14 6;
; C1 z/ X7 N5 N7 E- @1 L. A0 s: U$ p% E
jiazhi=5 10 13 4 3 11 13 10 8 16 7 4;
8 k8 @9 W+ L' T0 N) D
enddata
# K7 _+ j- D/ N# h4 }
max=@sum(beibao(i):jiazhi(i)*x(i));
1 e4 x& Q, e% F9 i2 D
@sum(beibao(i):zhiliang(i)*x(i))<46;
( r( O/ u5 Q! }' i
@for(beibao(i):
) h, ]/ N6 e0 @
@gin(x(i)));
作者:
梦天涯M
时间:
2012-8-5 11:58
Global optimal solution found.
* E3 E* @1 R8 Q! V+ _# C
Objective value: 115.0000
3 b5 L& }& f; G9 }, Z
Objective bound: 115.0000
) [1 t, I0 }5 I7 F3 C
Infeasibilities: 0.000000
/ \4 Z, V( r; M. p% C6 m
Extended solver steps: 0
/ q5 @, o, u% `0 @
Total solver iterations: 0
. v" w4 b5 }. `5 i$ G: q# }
3 U9 q2 F1 c' i: Y5 B
Model Class: PILP
f6 [' y* k: |$ C5 f I- Y9 j
# a) r: i$ y2 A5 D1 F' `* r
Total variables: 12
* ^" K1 n: i! Z: l( D# u
Nonlinear variables: 0
* v/ e8 H. ?. X
Integer variables: 12
1 [( Y, X* U" i# t; r4 Q |7 H
8 W- f, B# Z7 P0 d& ?" e
Total constraints: 2
) ]7 O \# e! `
Nonlinear constraints: 0
" ^ c8 q- Q6 R4 f$ G; h
$ C/ z- F1 M" [9 O- g9 t+ h+ f- Y' A
Total nonzeros: 24
! w& S4 \7 F7 Y. t! ]7 D4 ~8 _6 P# y
Nonlinear nonzeros: 0
) x5 m! E2 S& H% i G+ `8 d0 d
/ t% r/ b3 d( W4 ?: G: \3 `! N" f
3 ] n6 `+ w. j7 g
Variable Value Reduced Cost
" e9 H% Y& z' F# E: S/ d4 B
ZHILIANG( 1) 2.000000 0.000000
# p! Q# S6 M; t1 p
ZHILIANG( 2) 5.000000 0.000000
6 ^ W5 W0 a% f+ d
ZHILIANG( 3) 18.00000 0.000000
) w; L! T2 Q/ K; [( s% Y9 h% _
ZHILIANG( 4) 3.000000 0.000000
5 p" G. g! ?0 |0 t3 ?* e
ZHILIANG( 5) 2.000000 0.000000
9 V1 Z! c1 f }7 d+ K
ZHILIANG( 6) 5.000000 0.000000
5 ^+ Q/ v. c, I3 g3 h* ~
ZHILIANG( 7) 10.00000 0.000000
U+ w( U! f) f: z8 h" y5 _3 @
ZHILIANG( 8) 4.000000 0.000000
4 A% ]' z0 b* t6 c0 D
ZHILIANG( 9) 11.00000 0.000000
; n3 j' C& d7 |" {0 u
ZHILIANG( 10) 7.000000 0.000000
8 {5 I" C- s. P2 x# _ ]& Z8 s; Q
ZHILIANG( 11) 14.00000 0.000000
* ~/ r3 }& G8 g9 Q2 _& D
ZHILIANG( 12) 6.000000 0.000000
" a- y2 P& P, q
JIAZHI( 1) 5.000000 0.000000
5 K, B W$ W2 h! Q8 S* D# e5 n
JIAZHI( 2) 10.00000 0.000000
' `7 d$ v) G0 F! Y" D" F
JIAZHI( 3) 13.00000 0.000000
* ]7 N+ A, C9 z' O) w9 o, g" K! t
JIAZHI( 4) 4.000000 0.000000
$ ^5 M8 W8 Y& ]: b( J: J
JIAZHI( 5) 3.000000 0.000000
3 x! p- E$ p5 ?7 _' S
JIAZHI( 6) 11.00000 0.000000
5 G0 O# Q y! `
JIAZHI( 7) 13.00000 0.000000
p/ e' {" I3 p9 o/ ~ W
JIAZHI( 8) 10.00000 0.000000
3 U5 i+ |, f* M8 g' r8 H8 r
JIAZHI( 9) 8.000000 0.000000
2 `3 M; ?. W [
JIAZHI( 10) 16.00000 0.000000
9 X, Q& v1 ]- \2 ]. _
JIAZHI( 11) 7.000000 0.000000
! ~; N4 q7 l) d; [" w
JIAZHI( 12) 4.000000 0.000000
4 y- `/ c6 d+ L; f( j
X( 1) 1.000000 -5.000000
# _# I' Q( Q+ _; X
X( 2) 0.000000 -10.00000
+ M* Q3 w( a" f
X( 3) 0.000000 -13.00000
% T0 q3 l3 t1 C: o
X( 4) 0.000000 -4.000000
% B/ [9 }$ i R& O' [" }
X( 5) 0.000000 -3.000000
* J0 \6 X3 e* |5 ~: u9 R3 H1 O/ k
X( 6) 0.000000 -11.00000
2 C$ ] M# M, D3 \- M, G' D
X( 7) 0.000000 -13.00000
/ V: H/ y" O- y8 [
X( 8) 11.00000 -10.00000
0 T: ^* d* r$ a3 o: p w! z" F
X( 9) 0.000000 -8.000000
% G }/ X8 G- K! ?/ w/ [
X( 10) 0.000000 -16.00000
6 C4 u- Q! v, a% A! p3 r" t0 o' M" M
X( 11) 0.000000 -7.000000
3 a; M; c% F: ^+ B1 A7 T! H( b
X( 12) 0.000000 -4.000000
2 A: [) P3 @/ `! I: @. J7 X
4 S7 J4 @ n) T8 V
Row Slack or Surplus Dual Price
; H/ L+ }- s) s9 f6 j3 W) K+ U
1 115.0000 1.000000
9 r' F7 ]: Q0 q3 s1 }
2 0.000000 0.000000
6 ^0 p4 z& l4 J' b* t' c" B. N
作者:
梦天涯M
时间:
2012-8-5 11:59
第一件物品取1件,第8件物品取11件,最大价值115
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