数学建模社区-数学中国
标题:
求助,代码第二段啥意思
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作者:
魏关亭侯
时间:
2012-7-25 10:30
标题:
求助,代码第二段啥意思
背包问题,12件物品质量为2,5,18,3,2,5,10,4,11,7,14,6,价值为5,10,13,4,3,11,13,10,8,16.7.4,包的最大重量是46
L% u5 t8 K" ]% D3 M
求最优方案
, ^2 }0 j* _7 W) G' u- n4 _
代码如下,第二段看不懂,从那个=~开始,那符号啥意思
) C& k! I% s' A: X
a=0.95
0 c$ j6 m* w3 X+ ]$ o: g
k=[5;10;13;4;3;11;13;10;8;16;7;4];
8 g( G% I) z1 C( V
k=-k;
. U' W! P7 O4 N; b$ B
d=[2;5;18;3;2;5;10;4;11;7;14;6];
/ H3 v& e3 x7 b( _1 e6 ?
restriction=46;
& ^3 F6 e _5 y
num=12;
! V/ t! V2 `. ]( N1 [3 U$ ~
sol_new=ones(1,num);
2 r/ t; A. T' A, _8 e# D3 [, v
E_current=inf;E_best=inf;
8 z3 |1 k0 E& y9 A& f; F4 j+ J# S! O
sol_current=sol_new; sol_best=sol_new;
1 i' f: F' s( t9 c" R
t0=97;tf=3;t=t0;
% Z, V7 }8 l o
p=1;
7 K$ ` |& B1 q5 c
1 S+ f8 D+ U2 [& u
while t>=tf
4 c' f( ` F" ?
for r=1:100
* } u! j7 W' x- E3 m" `( |
tmp=ceil(rand.*num);
8 x- x/ N# u2 ^1 ?$ Y; [7 ]. r* P
sol_new(1,tmp)=~sol_new(1,tmp);
: ~ \# D. n! E; c [
while 1
1 |( T3 D0 B1 J4 z* w3 N9 h, f- e# k
q=(sol_new*d<=restriction)
' [# f3 M( i: W c( |* h+ s
if ~q
1 D! |, y& C' ~5 p& a( W
p=~p
, U$ I X d8 A& J
tmp=find(sol_new==1);
/ N! H( v' t3 a2 c
if p
/ D% M! g% B% g% k! p
sol_new(1,tmp)=0;
( ]3 R- a0 r( e2 C9 o" u( {
else
& A" {# s& F# A4 q% U" y" P
sol_new(1,tmp(end))=0;
! D6 [5 Z8 a1 M( F* K/ q
end
* z# A9 j2 |& W8 q
else
- J% V9 S: S: I @) Z4 }' R, V
break
+ \/ p1 n/ u# a. A# x7 }/ |! z
end
7 N5 \& t: l6 D( \$ w
end
: L3 g& Z O4 [3 F& q
作者:
赵煜星
时间:
2012-7-25 21:01
好啊 我喜欢
作者:
梦天涯M
时间:
2012-8-5 11:54
model:
' e* I( T% C C
sets:
. {: Q6 V9 U1 D0 n9 h5 X+ M7 s
beibao/1..12/:zhiliang,jiazhi,x;
2 c3 g) G4 h0 `
endsets
`2 y# }) s9 M9 T u! X7 V* I; K
data:
$ W$ G n2 H+ \# }6 Q" {& J7 b
zhiliang=2 5 18 3 2 5 10 4 11 7 14 6;
! V6 h3 @6 s( b! T. o
jiazhi=5 10 13 4 3 11 13 10 8 16 7 4;
- o' ^" w+ U' ]
enddata
- j3 {6 z6 y9 h8 V9 E) n5 ^
max=@sum(beibao(i):jiazhi(i)*x(i));
- ]3 f7 T2 l; y+ l4 ]( B( Y
@sum(beibao(i):zhiliang(i)*x(i))<46;
4 ^- O$ v7 j4 K, [) c
@for(beibao(i):
; k' w. a$ F! M0 w4 c0 q- r) G
@bin(x(i)));
1 S6 ]( j8 N* i. j9 \! ^, a
( q4 h P4 _4 q9 I2 ?
结果:
# ]0 N$ d( Y* V6 _( N+ l; O
Global optimal solution found.
: q% h: s$ M% ^& m
Objective value: 76.00000
4 h. A" f% i8 _# ]- z# n q; }1 e
Objective bound: 76.00000
* r! ]. h) D- h
Infeasibilities: 0.000000
" I/ B$ n+ m) _) w
Extended solver steps: 0
6 `. v) W( E+ v/ {% O( b
Total solver iterations: 0
+ o& P. O3 q2 I9 ?( z/ Q: M
' Z. z `: Z. R7 p5 P2 ?3 E$ W
Model Class: PILP
: [! D1 n- ~/ ?
9 H4 l8 W' Z0 q
Total variables: 12
3 f5 c$ Z$ X9 i* ~/ f: ~
Nonlinear variables: 0
+ I4 p/ e' }' L* {. A
Integer variables: 12
3 r6 h0 \2 g9 Z* r X0 I5 t4 y
. y% F9 J& n* e. [
Total constraints: 2
5 F: {. V' ` L6 a. e# ?8 U7 a. J
Nonlinear constraints: 0
/ j+ G4 K' ]# z. c6 O
4 |8 X0 G7 F. l- ]8 B9 r
Total nonzeros: 24
& z* U: ]$ Y1 v' n
Nonlinear nonzeros: 0
1 ~* }, @: _; ~3 l) ]
' `$ F: f" ?) D0 I$ Q8 M8 g
1 |" [1 D, R( `6 E# R
Variable Value Reduced Cost
# a! K" p6 f) w1 @
ZHILIANG( 1) 2.000000 0.000000
: [$ g# D# S5 ?7 m0 K" I4 @' @: _$ U
ZHILIANG( 2) 5.000000 0.000000
5 h& R+ Y) e" v, [: G! f% W& l
ZHILIANG( 3) 18.00000 0.000000
1 B% {4 F) w5 ]% D# X6 h
ZHILIANG( 4) 3.000000 0.000000
7 T! Z% O0 o% W! w, h9 d/ Z0 k
ZHILIANG( 5) 2.000000 0.000000
; G$ N* t+ x0 ?) |+ u
ZHILIANG( 6) 5.000000 0.000000
, S1 ]. |7 A* P1 }
ZHILIANG( 7) 10.00000 0.000000
3 Q" `$ e) d% k6 [9 R! t
ZHILIANG( 8) 4.000000 0.000000
9 P. U1 m8 z/ s7 w0 R8 D
ZHILIANG( 9) 11.00000 0.000000
* y4 s$ u$ i m$ m8 h& @
ZHILIANG( 10) 7.000000 0.000000
& [9 h4 i" o6 a
ZHILIANG( 11) 14.00000 0.000000
8 E( ]5 w$ Q$ c) D
ZHILIANG( 12) 6.000000 0.000000
Y) l1 Y3 L9 ^3 |, s9 F0 [. q( i+ |
JIAZHI( 1) 5.000000 0.000000
$ P" e# U. ^! w3 \( J9 o( C
JIAZHI( 2) 10.00000 0.000000
) ~* o$ B M$ @9 z' h' S
JIAZHI( 3) 13.00000 0.000000
% N8 T: J3 j M1 e4 G
JIAZHI( 4) 4.000000 0.000000
5 f5 u% H1 e0 A
JIAZHI( 5) 3.000000 0.000000
, d. {" M3 d {
JIAZHI( 6) 11.00000 0.000000
; C7 t9 V( C+ v, c3 H* Y& _4 q
JIAZHI( 7) 13.00000 0.000000
1 s/ u8 _5 S( a5 c* w- _# R8 ?. D
JIAZHI( 8) 10.00000 0.000000
' r- F& C$ ^! u; F
JIAZHI( 9) 8.000000 0.000000
9 s7 ]. C, I( ?1 C$ c
JIAZHI( 10) 16.00000 0.000000
* @( O* {: `/ U! Y9 S
JIAZHI( 11) 7.000000 0.000000
3 Q$ \. q* n6 F6 x8 {( s- b
JIAZHI( 12) 4.000000 0.000000
$ z3 H# q2 I! `6 H4 y
X( 1) 1.000000 -5.000000
8 J/ O+ [0 J( r1 Z5 g
X( 2) 1.000000 -10.00000
% C5 h7 z9 N% I4 a3 B! k% Y6 ]
X( 3) 0.000000 -13.00000
" }/ q* g" \" D& X: p" o5 V
X( 4) 1.000000 -4.000000
' e# n1 t% v/ P4 ]9 x2 l" y+ X
X( 5) 1.000000 -3.000000
5 [ \! }" f+ Z3 a+ M r, U
X( 6) 1.000000 -11.00000
( x( |; a# j: f' c( x9 U
X( 7) 1.000000 -13.00000
/ u# R# f3 k6 b; ]; Q
X( 8) 1.000000 -10.00000
! Z+ l" s% y* e8 I
X( 9) 0.000000 -8.000000
- A% Q4 T/ h7 z4 f7 D9 p A5 r0 v
X( 10) 1.000000 -16.00000
' N/ l1 J+ J0 q) l, U/ c g% O' @+ A
X( 11) 0.000000 -7.000000
* w: v% h, f& ^
X( 12) 1.000000 -4.000000
! L# N* Q7 [6 T/ v- X' D6 M" \
9 u; E- o( I) ] p* a3 J1 _
Row Slack or Surplus Dual Price
1 I1 m* R/ a/ g3 l1 P0 v
1 76.00000 1.000000
* E) H/ O6 M3 d9 p1 }& a$ E! d# I
2 2.000000 0.000000
6 {" ^; r7 o; l3 Y' E- }
7 l+ Y, w& U1 J8 U( s9 \
作者:
梦天涯M
时间:
2012-8-5 11:56
不好意思,上边写成bin了,应该是gin
6 q3 s' Q7 q; u
正确程序:
. T- z/ [, W" D; O
model:
3 z/ b/ `$ P# e& |& V. T" p
sets:
4 A3 B. R. {3 [( D" ]" k5 Q& ^
beibao/1..12/:zhiliang,jiazhi,x;
% P) F" x4 [) o9 r
endsets
b- y- [ u+ D' a4 B7 a7 G- T
data:
$ Y4 n, Z, B$ H: f( N
zhiliang=2 5 18 3 2 5 10 4 11 7 14 6;
8 b$ @% o. q& q% j a
jiazhi=5 10 13 4 3 11 13 10 8 16 7 4;
: A, }4 q4 K& E
enddata
0 U1 T3 i& T, |' N- _
max=@sum(beibao(i):jiazhi(i)*x(i));
* f* G# f4 M4 H W1 F7 J2 x
@sum(beibao(i):zhiliang(i)*x(i))<46;
8 W4 x7 g! K- o( D- s: w1 ]( z1 ~7 f
@for(beibao(i):
9 J& P8 |4 Q( U) [( g, D
@gin(x(i)));
作者:
梦天涯M
时间:
2012-8-5 11:58
Global optimal solution found.
0 W, y1 b1 ?7 T4 ^( ]5 X8 A3 K, x
Objective value: 115.0000
& t9 K! M3 H; k* y( b
Objective bound: 115.0000
) w' F% r0 V7 S' I8 `2 |* b5 q# f3 c
Infeasibilities: 0.000000
' p0 p9 |. u. f, V
Extended solver steps: 0
9 _+ X. \7 i9 |$ r0 g! I/ P! U9 Y
Total solver iterations: 0
( d7 y0 U+ W" P* x" Z
2 `% R9 E9 b4 B, z' |9 J3 D
Model Class: PILP
" j+ ^( v! n4 o
, g, K9 w+ G2 Y g1 @) O' F
Total variables: 12
% P) c$ R) f; |% ~$ p: Z* Q: S! u% }0 S
Nonlinear variables: 0
2 ~, k' ^) c- w- R, N5 u: G" l
Integer variables: 12
, S5 y& T5 f% z6 |
! k, t. B$ L0 k* ^8 }: Z3 \
Total constraints: 2
+ d% t3 P% p* p M8 V3 C
Nonlinear constraints: 0
) F7 W* F& k( R6 S' A. @
# ]1 c( r# S' k% P. V' v& P
Total nonzeros: 24
, |$ G1 ]* N4 P3 D. G
Nonlinear nonzeros: 0
& p0 p8 q( c! g& w) X
, X* c* f8 S7 V8 o3 J. \( ?. _
7 K& l, L3 [) ? p% [; P: h
Variable Value Reduced Cost
- L; Y- c R) `
ZHILIANG( 1) 2.000000 0.000000
0 S0 h! H+ f! q# S: C( V) m) ]
ZHILIANG( 2) 5.000000 0.000000
( ^& W) b3 [$ Y" L) H: X3 n
ZHILIANG( 3) 18.00000 0.000000
& q! z2 }8 r, ]* }' o3 y1 f6 v" [2 Q/ w
ZHILIANG( 4) 3.000000 0.000000
. H& {5 ~/ v3 E! R% N2 F( T2 t
ZHILIANG( 5) 2.000000 0.000000
4 |0 S7 w$ f( }/ g1 f
ZHILIANG( 6) 5.000000 0.000000
% I8 d4 W6 H u- o# T' x1 u% E0 e
ZHILIANG( 7) 10.00000 0.000000
3 q; ?) S" }$ u# p. W( O4 z. m
ZHILIANG( 8) 4.000000 0.000000
" p. T- l. C8 j: F8 j% H0 t
ZHILIANG( 9) 11.00000 0.000000
+ s, R( B9 S. O
ZHILIANG( 10) 7.000000 0.000000
* Q/ z2 S8 q) v& `2 c: e, U
ZHILIANG( 11) 14.00000 0.000000
! ]/ D1 G" V5 e# G8 X2 x
ZHILIANG( 12) 6.000000 0.000000
9 ?7 x- x) _- z: O; y- w. V
JIAZHI( 1) 5.000000 0.000000
9 D5 c' F5 x& @
JIAZHI( 2) 10.00000 0.000000
! P* v* O- h' P) t. Z# P8 O z
JIAZHI( 3) 13.00000 0.000000
b% W. |/ h* }4 T
JIAZHI( 4) 4.000000 0.000000
; c9 F4 _8 M) P, ~* i# l0 P
JIAZHI( 5) 3.000000 0.000000
: o9 F/ o# i1 M' z7 Q
JIAZHI( 6) 11.00000 0.000000
0 g' P4 y6 J+ l+ [& M" K8 @, T
JIAZHI( 7) 13.00000 0.000000
2 |0 \' x. t3 v
JIAZHI( 8) 10.00000 0.000000
+ \5 K& F8 w/ S" [
JIAZHI( 9) 8.000000 0.000000
7 f2 }/ t% T) S! ^3 b
JIAZHI( 10) 16.00000 0.000000
h9 r$ |; [1 P" a. H+ \8 I& C
JIAZHI( 11) 7.000000 0.000000
9 \2 S _( J' |: G9 Y* r. B4 M7 I
JIAZHI( 12) 4.000000 0.000000
1 d0 X! G- L1 L0 J
X( 1) 1.000000 -5.000000
( w6 T; Q$ E' c2 S& A6 G8 H
X( 2) 0.000000 -10.00000
7 C4 c1 I. N5 _7 n7 g& B$ g8 k3 ^: s
X( 3) 0.000000 -13.00000
8 R, L0 X# [) ^ M3 f2 M( q
X( 4) 0.000000 -4.000000
9 N* _0 n' Q% U' T, G
X( 5) 0.000000 -3.000000
+ v b9 r9 N7 N& f# b1 N, \
X( 6) 0.000000 -11.00000
, Y) ^# G3 @5 V, [% V7 ?0 \
X( 7) 0.000000 -13.00000
F2 N1 t# i9 d9 `0 ?* Q
X( 8) 11.00000 -10.00000
, r4 I* x9 r* q4 q$ O) a1 @
X( 9) 0.000000 -8.000000
) U) ^: l) d9 Y. L! i5 j0 I% B" S
X( 10) 0.000000 -16.00000
4 {) v% i, ]# o" Y! L6 N" y
X( 11) 0.000000 -7.000000
! ^/ r8 z$ }& z1 m
X( 12) 0.000000 -4.000000
! s# D; V" j3 ?* t
; \/ v. G- W) A5 d/ U# D- ~& g
Row Slack or Surplus Dual Price
" U* g( l# c/ F6 f9 x& J! r* s. x
1 115.0000 1.000000
1 t# s" F6 c7 p, l5 F ?" ], B1 b
2 0.000000 0.000000
]3 W5 q) H' o
作者:
梦天涯M
时间:
2012-8-5 11:59
第一件物品取1件,第8件物品取11件,最大价值115
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