数学建模社区-数学中国

标题: 谁有多元回归的程序,急需啊! [打印本页]

作者: 小瑞儿    时间: 2012-8-25 08:29
标题: 谁有多元回归的程序,急需啊!
谁有多元回归的程序,急需啊!
作者: zhenc    时间: 2012-8-26 09:49
我也 急需,有的请发  29897815@QQ.COM    多谢
作者: 小瑞儿    时间: 2012-8-27 08:44
zhenc 发表于 2012-8-26 09:49
我也 急需,有的请发      多谢

现在找到了没
作者: liwenhui    时间: 2012-8-28 10:09
多元线性回归的就是简单的矩阵计算,matlab中有现成regress函数可以调用,你要程序干什么?
根据最小二乘原理,
Y=XB+E中系数向量的估计值为b=inv(x'x)*x'y

matlab中的源代码是:
  1. function [b,bint,r,rint,stats] = regress(y,X,alpha)
  2. %REGRESS Multiple linear regression using least squares.
  3. %   B = REGRESS(Y,X) returns the vector B of regression coefficients in the
  4. %   linear model Y = X*B.  X is an n-by-p design matrix, with rows
  5. %   corresponding to observations and columns to predictor variables.  Y is
  6. %   an n-by-1 vector of response observations.
  7. %
  8. %   [B,BINT] = REGRESS(Y,X) returns a matrix BINT of 95% confidence
  9. %   intervals for B.
  10. %
  11. %   [B,BINT,R] = REGRESS(Y,X) returns a vector R of residuals.
  12. %
  13. %   [B,BINT,R,RINT] = REGRESS(Y,X) returns a matrix RINT of intervals that
  14. %   can be used to diagnose outliers.  If RINT(i,:) does not contain zero,
  15. %   then the i-th residual is larger than would be expected, at the 5%
  16. %   significance level.  This is evidence that the I-th observation is an
  17. %   outlier.
  18. %
  19. %   [B,BINT,R,RINT,STATS] = REGRESS(Y,X) returns a vector STATS containing, in
  20. %   the following order, the R-square statistic, the F statistic and p value
  21. %   for the full model, and an estimate of the error variance.
  22. %
  23. %   [...] = REGRESS(Y,X,ALPHA) uses a 100*(1-ALPHA)% confidence level to
  24. %   compute BINT, and a (100*ALPHA)% significance level to compute RINT.
  25. %
  26. %   X should include a column of ones so that the model contains a constant
  27. %   term.  The F statistic and p value are computed under the assumption
  28. %   that the model contains a constant term, and they are not correct for
  29. %   models without a constant.  The R-square value is one minus the ratio of
  30. %   the error sum of squares to the total sum of squares.  This value can
  31. %   be negative for models without a constant, which indicates that the
  32. %   model is not appropriate for the data.
  33. %
  34. %   If columns of X are linearly dependent, REGRESS sets the maximum
  35. %   possible number of elements of B to zero to obtain a "basic solution",
  36. %   and returns zeros in elements of BINT corresponding to the zero
  37. %   elements of B.
  38. %
  39. %   REGRESS treats NaNs in X or Y as missing values, and removes them.
  40. %
  41. %   See also LSCOV, POLYFIT, REGSTATS, ROBUSTFIT, STEPWISE.

  42. %   References:
  43. %      [1] Chatterjee, S. and A.S. Hadi (1986) "Influential Observations,
  44. %          High Leverage Points, and Outliers in Linear Regression",
  45. %          Statistical Science 1(3):379-416.
  46. %      [2] Draper N. and H. Smith (1981) Applied Regression Analysis, 2nd
  47. %          ed., Wiley.

  48. %   Copyright 1993-2009 The MathWorks, Inc.
  49. %   $Revision: 1.1.8.3 $  $Date: 2011/05/09 01:26:41 $

  50. if  nargin < 2
  51.     error(message('stats:regress:TooFewInputs'));
  52. elseif nargin == 2
  53.     alpha = 0.05;
  54. end

  55. % Check that matrix (X) and left hand side (y) have compatible dimensions
  56. [n,ncolX] = size(X);
  57. if ~isvector(y) || numel(y) ~= n
  58.     error(message('stats:regress:InvalidData'));
  59. end

  60. % Remove missing values, if any
  61. wasnan = (isnan(y) | any(isnan(X),2));
  62. havenans = any(wasnan);
  63. if havenans
  64.    y(wasnan) = [];
  65.    X(wasnan,:) = [];
  66.    n = length(y);
  67. end

  68. % Use the rank-revealing QR to remove dependent columns of X.
  69. [Q,R,perm] = qr(X,0);
  70. p = sum(abs(diag(R)) > max(n,ncolX)*eps(R(1)));
  71. if p < ncolX
  72.     warning(message('stats:regress:RankDefDesignMat'));
  73.     R = R(1:p,1:p);
  74.     Q = Q(:,1:p);
  75.     perm = perm(1:p);
  76. end

  77. % Compute the LS coefficients, filling in zeros in elements corresponding
  78. % to rows of X that were thrown out.
  79. b = zeros(ncolX,1);
  80. b(perm) = R \ (Q'*y);

  81. if nargout >= 2
  82.     % Find a confidence interval for each component of x
  83.     % Draper and Smith, equation 2.6.15, page 94
  84.     RI = R\eye(p);
  85.     nu = max(0,n-p);                % Residual degrees of freedom
  86.     yhat = X*b;                     % Predicted responses at each data point.
  87.     r = y-yhat;                     % Residuals.
  88.     normr = norm(r);
  89.     if nu ~= 0
  90.         rmse = normr/sqrt(nu);      % Root mean square error.
  91.         tval = tinv((1-alpha/2),nu);
  92.     else
  93.         rmse = NaN;
  94.         tval = 0;
  95.     end
  96.     s2 = rmse^2;                    % Estimator of error variance.
  97.     se = zeros(ncolX,1);
  98.     se(perm,:) = rmse*sqrt(sum(abs(RI).^2,2));
  99.     bint = [b-tval*se, b+tval*se];

  100.     % Find the standard errors of the residuals.
  101.     % Get the diagonal elements of the "Hat" matrix.
  102.     % Calculate the variance estimate obtained by removing each case (i.e. sigmai)
  103.     % see Chatterjee and Hadi p. 380 equation 14.
  104.     if nargout >= 4
  105.         hatdiag = sum(abs(Q).^2,2);
  106.         ok = ((1-hatdiag) > sqrt(eps(class(hatdiag))));
  107.         hatdiag(~ok) = 1;
  108.         if nu > 1
  109.             denom = (nu-1) .* (1-hatdiag);
  110.             sigmai = zeros(length(denom),1);
  111.             sigmai(ok) = sqrt(max(0,(nu*s2/(nu-1)) - (r(ok) .^2 ./ denom(ok))));
  112.             ser = sqrt(1-hatdiag) .* sigmai;
  113.             ser(~ok) = Inf;
  114.         elseif nu == 1
  115.             ser = sqrt(1-hatdiag) .* rmse;
  116.             ser(~ok) = Inf;
  117.         else % if nu == 0
  118.             ser = rmse*ones(length(y),1); % == Inf
  119.         end

  120.         % Create confidence intervals for residuals.
  121.         rint = [(r-tval*ser) (r+tval*ser)];
  122.     end

  123.     % Calculate R-squared and the other statistics.
  124.     if nargout == 5
  125.         % There are several ways to compute R^2, all equivalent for a
  126.         % linear model where X includes a constant term, but not equivalent
  127.         % otherwise.  R^2 can be negative for models without an intercept.
  128.         % This indicates that the model is inappropriate.
  129.         SSE = normr.^2;              % Error sum of squares.
  130.         RSS = norm(yhat-mean(y))^2;  % Regression sum of squares.
  131.         TSS = norm(y-mean(y))^2;     % Total sum of squares.
  132.         r2 = 1 - SSE/TSS;            % R-square statistic.
  133.         if p > 1
  134.             F = (RSS/(p-1))/s2;      % F statistic for regression
  135.         else
  136.             F = NaN;
  137.         end
  138.         prob = fpval(F,p-1,nu); % Significance probability for regression
  139.         stats = [r2 F prob s2];

  140.         % All that requires a constant.  Do we have one?
  141.         if ~any(all(X==1,1))
  142.             % Apparently not, but look for an implied constant.
  143.             b0 = R\(Q'*ones(n,1));
  144.             if (sum(abs(1-X(:,perm)*b0))>n*sqrt(eps(class(X))))
  145.                 warning(message('stats:regress:NoConst'));
  146.             end
  147.         end
  148.     end

  149.     % Restore NaN so inputs and outputs conform
  150.     if havenans
  151.         if nargout >= 3
  152.             tmp = NaN(length(wasnan),1);
  153.             tmp(~wasnan) = r;
  154.             r = tmp;
  155.             if nargout >= 4
  156.                 tmp = NaN(length(wasnan),2);
  157.                 tmp(~wasnan,:) = rint;
  158.                 rint = tmp;
  159.             end
  160.         end
  161.     end

  162. end % nargout >= 2
复制代码

作者: liwenhui    时间: 2012-8-28 10:10
,程序中怎么会出现笑脸呢?
作者: yangfuzhi    时间: 2012-8-28 10:38
程序非常好。。。
作者: darker50    时间: 2012-8-28 14:08
liwenhui 发表于 2012-8-28 10:10
,程序中怎么会出现笑脸呢?

  您编辑完之后全部选中,之后点击编辑器上面的这个符号“<>”,之后所有代码就正常显示了。
作者: darker50    时间: 2012-8-28 14:14
liwenhui 发表于 2012-8-28 10:10
,程序中怎么会出现笑脸呢?

帮你编辑之后就会像上面的这样的显示了!
作者: liwenhui    时间: 2012-8-28 15:06
darker50 发表于 2012-8-28 14:14
帮你编辑之后就会像上面的这样的显示了!

原来如此,明白了。
作者: 小瑞儿    时间: 2012-8-29 11:29
liwenhui 发表于 2012-8-28 10:09
多元线性回归的就是简单的矩阵计算,matlab中有现成regress函数可以调用,你要程序干什么?
根据最小二乘原 ...

非常感谢~




欢迎光临 数学建模社区-数学中国 (http://www.madio.net/) Powered by Discuz! X2.5