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标题: 求帮忙啊，一个程序的小问题啊！ [打印本页]

作者: 相思枕畔 时间: 2013-1-16 18:11
标题: 求帮忙啊，一个程序的小问题啊！
MODEL:
title economic pipe;
sets:
tubulation/1..9/

,Q,A,EK;
      caliber/1,2,3,4,5/;
      LINK(tubulation,caliber):C,X,D;
ENDSETS
DATA:
!各段管长;
L=700,700,700,500,500,500,500,500,500;
!各段流量;
Q=0.135,0.060,0.015,0.015,0.045,0.015,0.015,0.015,0.015;
!节点服务水压标高;
EK=47,46,44,46,44,43,45,46,43;
!水源到节点的管段数;
A=1,2,3,2,2,3,3,3,3;
!标准管径单价;
C=42.0 55.2 64.0 83.2 103.2
   38.7 42.0 55.2 64.0 0.00
   25.0 30.8 0.00 0.00 0.00
   25.0 30.8 0.00 0.00 0.00
   30.8 38.7 42.0 55.2 0.00
   25.0 30.8 0.00 0.00 0.00
   25.0 30.8 0.00 0.00 0.00
   25.0 30.8 0.00 0.00 0.00
   25.0 30.8 0.00 0.00 0.00;
!标准管径;
D=0.25 0.30 0.35 0.40 0.50
   0.20 0.25 0.30 0.35 0.00
   0.10 0.15 0.00 0.00 0.00
   0.10 0.15 0.00 0.00 0.00
   0.15 0.20 0.25 0.30 0.00
   0.10 0.15 0.00 0.00 0.00
   0.10 0.15 0.00 0.00 0.00
   0.10 0.15 0.00 0.00 0.00
   0.10 0.15 0.00 0.00 0.00;
ENDDATA
!OBJECTIVE FUNCTION(目标函数);
[OBJ]MIN=@SUM(LINK(I,J):C(I,J)*X(I,J));
!pipe range CONSTRAINTE(管长约束);
@FOR(tubulation(I):[RANGE_CON]@SUM(caliber(J):X(I,J))=L(I););
!Stress constraint(压力约束);
@FOR(caliber(J)

@SUM(tubulation(I)

0.135^2*X(1,J)/D(1,J)^5.342))*(1.942*10^-3))<(60-47));
@FOR(CALIBER(J)

@SUM(TUBULATION(I)

0.135^2*X(1,J)/D(1,J)^5.342+0.060^2*X(2,J)/D(2,J)^5.342))*(1.942*10^-3))<(60-46));
@for(caliber(j)

@SUM(TUBULATION(I)

0.135^2*X(1,J)/D(1,J)^5.342+0.060^2*X(2,J)/D(2,J)^5.342+0.015^2*X(3,J)/D(3,J)^5.342))*(1.942*10^-3))<(60-44));
@for(caliber(j)

@SUM(TUBULATION(I)

0.135^2*X(1,J)/D(1,J)^5.342+0.015^2*X(4,J)/D(4,J)^5.342))*(1.942*10^-3))<(60-46));
@FOR(CALIBER(J)

@SUM(TUBULATION(I)

0.135^2*X(1,J)/D(1,J)^5.342+0.045^2*X(5,J)/D(5,J)^5.342))*(1.942*10^-3))<(60-44));
@for(caliber(j)

@SUM(TUBULATION(I)

0.135^2*X(1,J)/D(1,J)^5.342+0.045^2*X(5,J)/D(5,J)^5.342+0.015^2*X(6,J)/D(6,J)^5.342))*(1.942*10^-3))<(60-43));
@for(caliber(j)

@SUM(TUBULATION(I)

0.135^2*X(1,J)/D(1,J)^5.342+0.045^2*X(5,J)/D(5,J)^5.342+0.015^2*X(7,J)/D(7,J)^5.342))*(1.942*10^-3))<(60-45));
@for(caliber(j)

@SUM(TUBULATION(I)

0.135^2*X(1,J)/D(1,J)^5.342+0.060^2*X(2,J)/D(2,J)^5.342+0.015^2*X(8,J)/D(8,J)^5.342))*(1.942*10^-3))<(60-46));
@for(caliber(j)

@SUM(TUBULATION(I)

0.135^2*X(1,J)/D(1,J)^5.342+0.060^2*X(2,J)/D(2,J)^5.342+0.015^2*X(9,J)/D(9,J)^5.342))*(1.942*10^-3))<(60-43));
!速度要求;
!非负假定;
@FOR(LINK(I,J):X(I,J)>0;);
END

这个程序能运行，但是有些问题，能不能把数组d中的0剔除，下面d是做分母的，或者其他的方法，也可以，求大神指导！！

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