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标题: Mathematica 能否完全替代Lingo？ [打印本页]

作者: 入戏太深丶 时间: 2015-4-15 14:24
标题: Mathematica 能否完全替代Lingo？

要求从1开始，最终回到1，且路径有方向，要求所有路径都经过。 ! k5 B1 A" a  I, I8 g( a7 @
以下是lingo的代码) F) z* a! v9 P7 M3 r! G  Y3 E/ o
sets:8 @3 t$ X7 Z( L  a" L
nodes/A,B,C,D,E,F,G,H,I,J,K,L/;4 n- y: L  r/ j% W# n) X1 F% p. }! c
arcs(nodes,nodes)/: y3 T. [1 o  a" z  W: Q5 l$ }
A,B A,E- g- x2 n( z2 t
B,C B,E B,F6 y6 Z9 E! r+ Z$ l; f) j
C,B C,D
$ t5 z* F/ [8 K) W' p% `D,C D,H7 E  [2 k8 Y- g$ Q: q# m
E,A E,F
7 j0 H/ h& F3 m3 oF,B F,E F,G F,I F,J
/ C; o! n8 l' h* UG,C G,F G,H G,K
9 t9 H& y: w4 N: y4 eH,D H,K H,L
3 G$ o+ b) a1 s2 P1 |  @" PI,E I,J4 `. [2 B, @) @
J,F J,G; i7 S* Q. {. Y) O
K,G K,J
: ?. k) {8 `, V$ J7 t& A1 |& CL,K" r7 u2 N, ?  M; e8 Z
/: c, x;# ]9 j& M& l$ z1 H/ p
endsets
- V  ?( S) ^$ L/ e: x4 z! Jdata:
/ G+ @% K$ `8 G, _, ^& M) wc=- c( k9 P0 ]5 Y0 K1 |6 u+ G
150 165  _8 o; o* G$ w4 t3 h2 X" L+ g
130 230 160% a5 b( u1 x8 t0 n, b' y  n
140 100+ b8 F9 m' @& e4 g) y
100 190, w  y* K8 y6 W0 b
165 1441 F; `6 j9 f' s8 ]5 ]
170 144 128 218 174
# r9 o. b8 e7 A& o" S( X200 122 109 185, |* G0 U2 Q, o3 }
180 141 1902 K$ F8 K8 S5 I+ e3 x
194 148$ e4 H5 U# ~; X7 R  r
174 233
& Z# L, @5 ]& K  _9 F185 135
) H$ L& q! q: b110;
; C$ E1 O* y6 V6 h) W6 Tenddata: c9 S$ N. t7 F7 p
n = @size(nodes);5 i: I- q( v& g4 P4 o6 E+ J$ i
min = @sum(arcs: c * x);( C, I: b' s, z. Q
@for(nodes(i):
/ k- M: k* z4 G, J@sum(arcs(i,j):x(i,j))=@sum(arcs(k,i):x(k,i))2 W% H7 g8 n. ]3 T$ i4 M
);
2 R# h8 n# K, J; T@for(arcs: @bnd(1,x,9)); 5 Q, Q: O& e" I* q/ X
" `5 c; j* C1 a; `. W; y8 ~
它只能算出路径的步数和路程，并不能得到线路。希望能用mma解决这个问题。

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自己用mma写的程序对于四点还可以，但是扩展到12点实在繁琐：

P11 = {2, 5}; P12 = {150, 165};

P21 = {5, 6}; P22 = {230, 160};

P51 = {1, 6}; P52 = {165, 144};

P61 = {2, 5}; P62 = {170, 144};(*只考虑1、2、5、6四点，P11为第一点“可去往的点”，P12表述对应的路程*)

open[q_] :=

Module[{i = 1, randomD, randomP, D, randomreal, p1, p2, p5, p6, c, u,

Df = 80000, uf, path = {1}, pathf = {1}, pb},(*随机搜索*)

For[r = 0, r < q, r++,

{p1 = {}; p2 = {}; p5 = {}; p6 = {}; u = 0; D = 0; i = 1;

randomP = P11; randomD = P12;

While[

Length[p1] != 2 || Length[p2] != 2 || Length[p5] != 2 ||

Length[p6] != 2 || i != 1,

randomreal = RandomInteger[{1, Length[randomP]}];

c = randomP[[randomreal]]; AppendTo[path, c];(*Print[path];*)

Which[

i == 1 &&

Product[If[p1[] != c, 1, 0], {i, 1, Length[p1]}] ==

1, {AppendTo[p1, c]},

i == 2 &&

Product[If[p2[] != c, 1, 0], {i, 1, Length[p2]}] ==

1, {AppendTo[p2, c]},

i == 5 &&

Product[If[p5[] != c, 1, 0], {i, 1, Length[p5]}] ==

1, {AppendTo[p5, c]},

i == 6 &&

Product[If[p6[] != c, 1, 0], {i, 1, Length[p6]}] ==

1, {AppendTo[p6, c]}];

i = c;

D = D + randomD[[randomreal]];

Which[i == 1, {randomP = P11, randomD = P12},

i == 2, {randomP = P21, randomD = P22},

i == 5, {randomP = P51, randomD = P52},

i == 6, {randomP = P61, randomD = P62}];

u = u + 1; If[u > 11, Break[]];

If[Df > D, {Df = D, uf = u, pathf = path, path = {1}},

path = {1}];

}

];

Print[Df, ",", uf, ",", pathf];

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open[1000]
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