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标题: Mathematica 能否完全替代Lingo？ [打印本页]

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作者: 入戏太深丶    时间: 2015-4-15 14:24
标题: Mathematica 能否完全替代Lingo？

要求从1开始，最终回到1，且路径有方向，要求所有路径都经过。
以下是lingo的代码
9 q, y, T3 `" P2 |7 `$ ?1 y( {1 asets:
" a* T. k4 _6 L: Q& R) Y! Snodes/A,B,C,D,E,F,G,H,I,J,K,L/;
/ t$ ^! W( S, E' Q, ?8 a( Warcs(nodes,nodes)/
A,B A,E
B,C B,E B,F
C,B C,D
D,C D,H
+ d' o2 v) \+ }/ b# l* D7 O4 FE,A E,F
F,B F,E F,G F,I F,J
G,C G,F G,H G,K
  g. u$ t# y0 I2 \! GH,D H,K H,L
I,E I,J
J,F J,G
0 J% Y( N5 x" F, F1 A( @1 }6 q; cK,G K,J
L,K
- g9 D5 V6 ]) w& t0 m/: c, x;
endsets
data:
c=
# R6 j! E5 [6 L. S150 165
130 230 160
! q4 W7 B. e. R9 K6 B140 100
100 190
165 144
- N( E$ z, b* u) v$ K170 144 128 218 174
+ C1 l6 j9 e, S! d! J$ k5 w) {3 _200 122 109 185
180 141 190
194 148
+ g9 e# o/ }! k7 f. q174 233
. \* N4 o# }) G" [, u185 135
110;
! W0 u& {' o7 n3 V/ a) [0 Penddata
n = @size(nodes);
( ^  ~: J# R( Nmin = @sum(arcs: c * x);
@for(nodes(i):
8 Q* `* c; z3 M0 O; L/ g, s@sum(arcs(i,j):x(i,j))=@sum(arcs(k,i):x(k,i))
5 h- c% w6 L9 h! S);
@for(arcs: @bnd(1,x,9));
5 F0 d0 t# P  a; z. A
% u# e. ]2 X- d6 E& u# v它只能算出路径的步数和路程，并不能得到线路。希望能用mma解决这个问题。

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自己用mma写的程序对于四点还可以，但是扩展到12点实在繁琐：

P11 = {2, 5}; P12 = {150, 165};

P21 = {5, 6}; P22 = {230, 160};

P51 = {1, 6}; P52 = {165, 144};

P61 = {2, 5}; P62 = {170, 144};(*只考虑1、2、5、6四点，P11为第一点“可去往的点”，P12表述对应的路程*)

open[q_] :=

Module[{i = 1, randomD, randomP, D, randomreal, p1, p2, p5, p6, c, u,

Df = 80000, uf, path = {1}, pathf = {1}, pb},(*随机搜索*)

For[r = 0, r < q, r++,

{p1 = {}; p2 = {}; p5 = {}; p6 = {}; u = 0; D = 0; i = 1;

randomP = P11; randomD = P12;

While[

Length[p1] != 2 || Length[p2] != 2 || Length[p5] != 2 ||

Length[p6] != 2 || i != 1,

randomreal = RandomInteger[{1, Length[randomP]}];

c = randomP[[randomreal]]; AppendTo[path, c];(*Print[path];*)

Which[

i == 1 &&

Product[If[p1[] != c, 1, 0], {i, 1, Length[p1]}] ==

1, {AppendTo[p1, c]},

i == 2 &&

Product[If[p2[] != c, 1, 0], {i, 1, Length[p2]}] ==

1, {AppendTo[p2, c]},

i == 5 &&

Product[If[p5[] != c, 1, 0], {i, 1, Length[p5]}] ==

1, {AppendTo[p5, c]},

i == 6 &&

Product[If[p6[] != c, 1, 0], {i, 1, Length[p6]}] ==

1, {AppendTo[p6, c]}];

i = c;

D = D + randomD[[randomreal]];

Which[i == 1, {randomP = P11, randomD = P12},

i == 2, {randomP = P21, randomD = P22},

i == 5, {randomP = P51, randomD = P52},

i == 6, {randomP = P61, randomD = P62}];

u = u + 1; If[u > 11, Break[]];

If[Df > D, {Df = D, uf = u, pathf = path, path = {1}},

path = {1}];

}

];

Print[Df, ",", uf, ",", pathf];

open[1000]

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