关于一道题的解法疑惑（高手请指教！） - 数学建模社区-数学中国

model:0 @5 A) `/ A# b8 x
!n个货车8收点运输问题;- K% t6 l5 y/ g# D4 r: e6 n
sets:, n0 w1 Y6 Z, Z8 ?3 ?" y- Y
place/place1..place10/:time1,time2,timexie;
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car/car1..car3/:time;
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jiu/1..9/;& b1 E' j+ w1 |. m
er/1..2/;
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lc(car,jiu):lucheng,ct; W% z/ [+ T5 w5 K( E
plan(place,place,car):a;% Y0 ~" H/ W1 c# K# R& f& b. T
distance(place,place):dd,dt,which;! ?: R; J* l! U, F5 _
endsets
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!这里是数据;7 }0 L L* L+ n! Y' a
data:
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s=1;9 m2 r" Z; r; v
time1=-10 1 4 1 4 3.5 2 5 1.5 1; $ l8 Z* o5 p1 @. K
time2=7 4 6 2 7 5 5 8 4 10 ;: Z# [6 T" k& K {+ Z4 H$ \
timexie=0 1 2 1 3 2 2.5 3 0.8 0;# o4 M2 F2 u% b) G: z- Q
B% Z( e8 ^3 L z
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dd=: W! W, q+ \1 H8 {! q8 @0 L6 f
0 40 60 75 90 90 100 135 80 0& D& W" z7 S U- K$ V2 x: E% r1 _
40 0 65 40 100 50 75 110 100 40" D- [# F+ n9 P- T
60 65 0 75 100 100 75 75 75 60
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75 40 75 0 100 50 90 90 125 75
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90 100 100 100 0 100 75 75 100 90 F0 v/ y/ b* d& t8 Z
90 50 100 50 100 0 70 90 75 90! U6 d. D4 }5 r1 T' N. `2 G% ]& z: ?
100 75 75 90 75 70 0 70 100 100! U; P- s& j6 r. ~$ M
135 110 75 90 75 90 70 0 100 135
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80 100 75 125 100 75 100 100 0 80
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0 40 60 75 90 90 100 135 80 0 ;
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dt= 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0
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0.8000 0 1.3000 0.8000 2.0000 1.0000 1.5000 2.2000 2.0000 0.8000, Y! k5 i$ m% K
1.2000 1.3000 0 1.5000 2.0000 2.0000 1.5000 1.5000 1.5000 1.2000. H' S3 u$ Y( h$ y
1.5000 0.8000 1.5000 0 2.0000 1.0000 1.8000 1.8000 2.5000 1.5000( G3 R. r2 l+ c; W
1.8000 2.0000 2.0000 2.0000 0 2.0000 1.5000 1.5000 2.0000 1.8000
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1.8000 1.0000 2.0000 1.0000 2.0000 0 1.4000 1.8000 1.5000 1.8000
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2.0000 1.5000 1.5000 1.8000 1.5000 1.4000 0 1.4000 2.0000 2.0000& w1 L8 Y0 U" J9 D
2.7000 2.2000 1.5000 1.8000 1.5000 1.8000 1.4000 0 2.0000 2.7000; b) q- S* Y& l+ y. ~
1.6000 2.0000 1.5000 2.5000 2.0000 1.5000 2.0000 2.0000 0 1.60007 \& Q8 z7 x1 ^5 _4 X+ G
0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0;
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enddata
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!目标函数;& u N8 T) ]3 \, `/ c8 o, z
min=@sum(lc(I,J): lucheng(I,J));
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!整数约束;7 Z1 r$ y, ?8 `3 k2 j) S
@for(plan:@bin(a));, q: m! I# W5 N; @" ]$ b
@for(car(I):@free(time(I)) ;
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!从零点开始最终回来;7 t y6 a9 u1 ~, H+ r
@for(car(I):; L6 \: G- O3 o% u; m9 Q0 s8 {5 R
a(1,1,I)=1;a(10,10,I)=1);
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!每个任务只能有一个;) x5 Y$ D0 U9 w9 Q; R6 a+ Z
@sum(car(I):5 T1 X3 l, S/ M+ }! z: B
@sum(place(K):4 Z1 [2 k( W) ^* a' N
@sum(place(J): a(J,K,I))))=1;
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!每个车的任务最多有四个;7 G$ Q C. C5 E0 J0 n
@for(car(I):
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@sum(plan(J,K,I):a(J,k,I))<=6); W1 r6 A. U. f& _
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!前一辆车任务大于等于后一辆车;) q9 X8 O l% u. |8 z" r
@for(car(I)|I#lt#1:
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@sum(plan:a(J,K,I))>=@sum(plan:a(J,K,I+1) );! m3 v2 _" p& s; i) ]* H
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!求which 例子若a（1，：）=[1 0 0 1 0 1 0 0 0 1];6 s0 ^+ k. r1 |) |
! 则 which（1，：）=[1 1 1 4 4 6 6 6 6 10] ;( @8 x3 Z! D* F4 }4 l# Y) a. z @+ w, t
@for(car(I):8 ?- d. Q: z1 k' a/ |3 g7 D6 g
@for(place(kk)|@sum(place(jj):a(kk,jj,I)) #eq#1:/ h( z) T4 L0 r# j
@for(place(jj)|a(kk,jj,I) #eq#1:
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which(I,kk)=jj ););
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@for(place(kk)|@sum(place(kk):a(kk,jj,I)) #ne#1:8 P. Y" Y$ Z( \0 I
which(I,kk)=which(I,kk-1));: ?3 ~( d; A+ g) f4 A' i* R; t
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!时间限制;
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@for(car(jjj):3 |; p6 R; G$ N% @; j- }
time(jjj)>=-10;time(jjj)<=7);
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@for(jiu(jjj):9 }9 l5 d2 E) S$ r
ct(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dt(which(I,jjj),which(I,jjj+1))+timexie(which(I,jjj)),0));
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@for(jiu(jjj):. z+ m, s- o1 y
time(I)+ct(I,jjj)>=time1(jjj+1);time(I)+ct(I,jjj)<=time2(jjj+1));
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!求每辆车行驶的距离;: U# ]1 ~% W6 X. b9 m6 C7 R m
@for(jiu(jjj):4 w @2 j8 M+ i% p) y' ^
lucheng(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dd(which(I,jjj),which(I,jjj+1)),0) );
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);););0 D) j+ \4 p/ {6 u/ y
end
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