数学建模社区-数学中国
标题:
matlab做数学建模，有这么段代码，这有错么？
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作者:
杨利霞
时间:
2019-7-22 14:44
标题:
matlab做数学建模，有这么段代码，这有错么？
matlab做数学建模，有这么段代码，这有错么？
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结果实在是跑不对
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selftimeform = [14.7:0.05:15.7];
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x=[1.03650000000000,1.06990000000000,1.10380000000000,1.13830000000000,1.17320000000000,1.20870000000000,1.24480000000000,1.28150000000000,1.31890000000000,1.35680000000000,1.39550000000000,1.43490000000000,1.47510000000000,1.51600000000000,1.55770000000000,1.60030000000000,1.64380000000000,1.68820000000000,1.73370000000000,1.78010000000000,1.82770000000000]
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y=[0.497300000000000,0.502900000000000,0.508500000000000,0.514200000000000,0.519800000000000,0.525500000000000,0.531100000000000,0.536800000000000,0.542600000000000,0.548300000000000,0.554100000000000,0.559800000000000,0.565700000000000,0.571500000000000,0.577400000000000,0.583300000000000,0.589200000000000,0.595200000000000,0.601300000000000,0.607400000000000,0.613500000000000]
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yingchang = sqrt(x.^2+y.^2)
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N=107; %N为15年4月18日与1月1日的日期之差
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derta=23.45*sin(360*(284+N)/365)*pi/180; %赤纬角
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omiga=15*(selftimeform-(120-111.02)/15-12)*pi/180; %计算时角
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for j=1:21
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for fai=1:90
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fenzi = sin(derta)*(sin(fai*pi/180)*sin(fai*pi/180))+cos(derta)*cos(fai*pi/180)*sin(fai*pi/180)*cos(omiga(j))-sin(derta)
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fenmu = sqrt(1-(sin(derta)*sin(fai*pi/180)+cos(derta)*cos(omiga(j))*cos(fai*pi/180))*(sin(derta)*sin(fai*pi/180)+cos(derta)*cos(omiga(j))*cos(fai*pi/180)))*cos(fai*pi/180)
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f(j,fai) = fenzi/fenmu - x(j)/yingchang(j)
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end
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end
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fai = 1:1:90
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plot(fai,f(1,fai))
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haha = f(1,fai)
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求大神指点一二
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作者:
KarryAndTomato
时间:
2019-7-22 21:59
有点难 是有乱码么哈哈 试着运行下
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