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标题: 美赛数模论文之公式写作 [打印本页]

作者: zhangtt123    时间: 2020-2-12 17:14
标题: 美赛数模论文之公式写作
由假设得到公式7 u" E! i. ]( f
1.We assume laminar flow and use Bernoulli's equation:(由假设得到的公式)
; A$ H1 T: b, i) Y; @- M
! J* M+ [4 N* L  L+ R" S( w公式+ a9 _: G& ^7 `& `
1 W+ l3 D& [, W5 o# u1 G; v: h
Where: x3 J! P. M1 a4 g

2 w% n) a9 v( \  y8 R符号解释* N2 B8 `1 R3 w- }4 h
3 |+ ?( O, _9 g
According to the assumptions, at every junction we have (由于假设)
" b: W  H0 ~# i
' n* G' P8 l  Y; X" L. w0 J6 [8 d公式
, F. B$ t, x* \) W$ b: J: U  c8 e; r: ], U' b' d$ J6 u
由原因得到公式
9 `5 I# M# i! i0 _3 w2.Because our field is flat, we have公式, so the height of our source relative to our sprinklers does not affect the exit speed v2 (由原因得到的公式);
& K/ C1 C# m- A2 u" ^' P+ L
. p) Y, [% {3 A+ G8 A公式
5 N. o; C* i8 ]
% ~6 g9 O; ^) a& T! gSince the fluid is incompressible(由于液体是不可压缩的), we have/ s, ~" U& _# o

0 P4 f: D: A5 `2 v公式, o+ K% v. q; K7 I: ?
6 Q1 o) `  M; u& P6 [" j$ \
Where( n; h& q' D9 b1 A# E; y. f: @( P: t

7 T6 z" l( H  Z& n, H9 K( [公式
: N. ?" Z5 ~$ v3 g( h3 |: K. X& E# g6 w" R- t4 f+ u
用原来的公式推出公式6 \' g& r! ?3 s, ~+ _# ~+ ?" w
3.Plugging v1 into the equation for v2 ,we obtain (将公式1代入公式2中得到)$ q: ?- j) G* H4 p$ {& J

" x* L9 g  c2 |) P) s. ?* a, B公式/ A* Q9 t0 q2 M/ a' ^( ^

* F5 z# i9 i7 g9 \: }11.Putting these together(把公式放在一起), because of the law of conservation of energy, yields:
: Z+ c/ Y& V& C* M
2 ?! K9 d( B! [' A9 Y8 d公式$ U2 b4 i  S4 `2 Z2 G0 m, f

$ N! K+ |* t+ ~" m0 M% M+ x12.Therefore, from (2),(3),(5), we have the ith junction(由前几个公式得)
- K# ?2 g6 a% n  C& `; S& K4 g
公式
9 O4 _0 X# [& N& N* n/ n+ E6 v9 [) ^) y" N* D' j; H9 |( z
Putting (1)-(5) together, we can obtain pup at every junction . in fact, at the last junction, we have/ T& E, V, B8 F

* E8 o( r& {/ H$ l7 E公式
# O2 j- ]  Q) V6 f; C! L2 m& d2 c5 b' i9 D/ T
Putting these into (1) ,we get(把这些公式代入1中)4 A7 h* o! j& x, d1 P3 J! P

4 o1 e" y% T  D! ^- Q8 ?0 p# U公式  r9 i% M! ~( m% S- A4 e
1 k3 F3 J' c) e5 z/ l
Which means that the
' q  c  m' n2 [) k
5 ^: p8 f1 s8 a2 j# j. X+ W; C! VCommonly, h is about
& ^- I7 h, e* S. s/ J; z5 x- Q$ U3 R
From these equations, (从这个公式中我们知道)we know that ………
8 g8 ]: [9 N+ |. |! U8 C$ Q5 Q
. `0 {( x" f3 M# H" ` 2 r) p1 n+ K8 _/ T4 C; e7 e* z# a

4 J$ S+ O" a- B% I& r引出约束条件. ~$ Y5 ?2 H$ G; x; I7 t$ V9 I3 i
4.Using pressure and discharge data from Rain Bird 结果,
$ J0 B, d8 b  _# D# C4 ?4 [  `0 p4 }
We find the attenuation factor (得到衰减因子,常数,系数) to be- w: z9 ^* Z( S: h# g4 y" A1 L
4 E0 y# y6 n9 l" }- N. R
公式; c+ ^$ b8 R* _' Q) [

2 P: e6 @$ f( u计算结果5 P- N8 W6 |$ H1 Z6 q7 X
6.To find the new pressure ,we use the ( 0 0),which states that the volume of water flowing in equals the volume of water flowing out : (为了找到新值,我们用什么方程)2 W4 b0 R  _9 k5 a
5 H0 p: V6 H- s' C% m
公式
5 j* h7 \7 F8 G2 R0 c9 h
8 Z% j8 g5 l: L3 I0 O' R5 w: \+ W" VWhere3 |: ?! e' o$ R5 O0 I
! s- s2 T  }$ l0 m
() is ;;: N+ y$ J8 h1 p/ W5 Z
$ U( E/ M5 a3 d; v: M8 h: u
7.Solving for VN we obtain (公式的解)1 I7 Z; ?1 {* L/ K: M8 k3 I1 H
% l2 K" ]5 }% y# i9 E1 a% e
公式
' D$ m3 U3 T5 [6 C" D
4 v) F6 ]9 {6 \3 Q3 i1 D0 |Where n is the …..3 a  b: V# s; _4 z: p3 g& O3 i

( k7 t& G7 d9 ^' C( D" a) [ 0 y1 v4 `" @& r; J: H9 K7 K
3 W3 q$ p9 z; C$ i! X9 Z# n+ G4 {  c. b
8.We have the following differential equations for speeds in the x- and y- directions:& s, J7 F; E7 n8 a. R
( k9 |+ ^/ m: T
公式
- h+ P+ J% ]: E" R3 G! b: M  r2 `1 s' ^1 O3 E$ q( x' |% R
Whose solutions are (解)
6 J/ e1 J. m/ b$ p9 v7 U5 ]! c- s0 B5 E
公式, d. ?; B2 n) n* X

5 s! Y" E) I. J* V/ `9.We use the following initial conditions ( 使用初值 ) to determine the drag constant:
0 J) n6 r! f6 F$ v: N
- W) q& k8 W8 [4 T公式
& e) q- q% H1 v' X% {
* T3 D' r) T. ^根据原有公式
0 q9 N: C) I6 f* @1 R9 E, x0 }; N10.We apply the law of conservation of energy(根据能量守恒定律). The work done by the forces is1 h* ?4 _3 z$ @6 i

4 g, m- d1 y8 ]% P& ?4 C公式
5 G6 l- {1 {" i+ Z
$ K# m0 R# ?+ |0 aThe decrease in potential energy is (势能的减少)2 z/ V! n% h$ h
( t/ B& b4 i. j. J; c
公式
; h- ~4 m# L# ~# O& o  c
! A9 R" O$ B  J. j; XThe increase in kinetic energy is (动能的增加)# ^8 m1 z  B$ u; ^* t

. D+ z4 @1 i* U; T. v9 ~7 ?公式# T) W2 f. G. n+ `1 i5 l% n2 S2 F& b

; y4 t8 n9 x0 W8 L, Q: f3 iDrug acts directly against velocity, so the acceleration vector from drag can be found Newton's law F=ma as : (牛顿第二定律): D' N6 _" c  _
- o- z3 W2 B# _" _- q& |1 s
Where a is the acceleration vector and m is mass
: w, [" |; X8 k; f. L( v# `( W) j. B3 x: j# ?2 V  A! z  ^
 
; d8 O- ]: N+ g7 k9 u! z1 n+ x
% ^% v9 R; b* m$ a. o4 p3 Q+ lUsing the Newton's Second Law, we have that F/m=a and
& P* a: U0 y9 x/ Z0 D  A- n2 p4 r
( B/ Y% {! @- R/ l4 o+ u公式. L3 h0 W; I( s! [
$ f& m7 n, Z9 P# q4 r) ]
So that$ h" i* I8 G5 v5 T  {

: }, g8 n+ ]7 m8 i3 w公式3 e# L* j8 n5 g. U$ B7 B' V% N
4 e$ H* H5 q6 `6 c- T( q. I8 N6 w
Setting the two expressions for t1/t2 equal and cross-multiplying gives
3 M* K" N8 i0 J4 A# t; s0 A8 @. |8 T( m& G
公式9 w# ?0 F8 L( A& n7 l* Z1 z, I2 W( U2 m

6 o8 g: N* h' a+ s- s22.We approximate the binomial distribution of contenders with a normal distribution:2 U0 ?9 Q$ V9 b! ~: h1 R3 H

' E$ [9 L/ {) w公式# P$ Q* ^) e0 Z& @+ H% h2 g

+ ~/ O, O% G" L: zWhere x is the cumulative distribution function of the standard normal distribution. Clearing denominators and solving the resulting quadratic in B gives$ y: E! O% Q! ^# C: Q; I
+ K- P7 T: T" z8 Q. C! ~+ [
公式* R( S0 U4 I5 j6 ~" w( `  e' X% r+ M

, m3 Z' r  O# Z4 Z. [# O/ B) ]As an analytic approximation to . for k=1, we get B=c
+ ?4 E6 J: T! r" a7 H- O, U& P9 O( |- E# W7 ~# y6 c
 3 e2 ~: N7 \2 H8 _
7 i4 [0 D- U! ]8 D
26.Integrating, (使结合)we get PVT=constant, where
3 w8 l9 o. v1 J9 c7 Q! X' Z
' m- X( P. l2 |( ^$ G公式
& w; {# N, |1 j& [" {+ H" _: H; a1 a' p+ m8 F  x
The main composition of the air is nitrogen and oxygen, so i=5 and r=1.4, so6 Q5 y! L& S$ q: j. V5 @
7 m9 t' U% @7 C' ]8 v. E
 
" k+ a% P# i5 ?2 C4 j1 X# d
1 R  |5 D4 H+ j4 i, r$ M23.According to First Law of Thermodynamics, we get
2 T9 o9 j; d1 d
3 [: N  s/ U: Y) x3 r9 r公式9 o# U1 z; F6 D+ {5 H" K# w, B
. }, q; {6 A8 @7 U
Where ( ) . we also then have
( K0 y* N( q5 T% E/ W' b0 m; c* E' g' e- e4 U7 p
公式& x6 t2 I" x4 D

8 D' s" T; z4 a! M! I$ O! P0 R. TWhere P is the pressure of the gas and V is the volume. We put them into the Ideal Gas Internal Formula:1 ]/ g/ Q, }  u/ c* V
1 a/ Y* a8 c) p1 _+ l: t% u
公式
' q7 a0 O% A  g; z; y
1 j& U) K/ D* i- D3 N  X6 X6 D$ [, S2 }Where2 k: I) t  I0 c) S
! J" P* G( z( g8 v, U
 
  I, q" P2 @& P: ?1 M. ]( n1 Y; F! T3 \& L
对公式变形
6 a  f# j( Q# `8 T  B2 w3 `13.Define A=nlw to be the ( )(定义); rearranging (1) produces (将公式变形得到)+ \; P. @' ~$ v

6 W0 Q( v5 s. h' O4 k公式# I& n! \  O3 b$ G
& T: `+ O% g: t' z; a) @  `) Z
We maximize E for each layer, subject to the constraint (2). The calculations are easier if we minimize 1/E.(为了得到最大值,求他倒数的最小值) Neglecting constant factors (忽略常数), we minimize
$ d0 R, q( A. r1 x* v
6 s+ l9 V% X: r$ Q2 |公式
- l" Y  J) q% [- g7 l/ z2 a( `! Y- c1 [8 n
使服从约束条件
8 {! F  {  r; B5 d4 o0 Q- x. F/ P14.Subject to the constraint (使服从约束条件)
$ p. y4 g9 T, N- x- o" H1 h( a. M6 \4 r, n
公式
  R! \0 U: D: |" s) ?. ~; H) @
' \' d1 K/ Y. a$ m; u- n  xWhere B is constant defined in (2). However, as long as we are obeying this constraint, we can write (根据约束条件我们得到)
: a( h: S. {' a
% x* e# O* j' y公式
% J: R6 s' T! l4 G
8 |' A, k: T  Z6 i& IAnd thus f depends only on h , the function f is minimized at (求最小值)
2 m* R4 j% A# a8 a7 a  v5 a4 X* x0 T3 t5 z& l: A8 {
公式$ f- W0 f1 M# J: k. D0 y

# U2 O* y# x8 m: s, LAt this value of h, the constraint reduces to
7 K/ V5 X: E4 v, H
" }& d. V  t6 V' F! [; k2 X公式6 S+ ?- q3 g/ b2 e# e

+ A; g' o% k$ V3 [+ M结果说明* T3 S/ u2 U4 K2 T! ~7 q
15.This implies(暗示) that the harmonic mean of l and w should be
8 H$ d. `/ z' K# Q) e4 v) P; f% C# E# C' `4 I) D6 X6 ]
公式
( h$ T: r9 f7 d; N* S1 w* ~9 b5 `2 }3 G: S- K4 p
So , in the optimal situation. ………
* t0 D" s3 V. c$ H( d+ C: v
) e" R. J: k) h5.This value shows very little loss due to friction.(结果说明) The escape speed with friction is, w! n$ _7 u% _, z! h

* g( l, {8 [, U; z3 K公式
! y0 }& o- ]2 G; H: Q' t" t
1 J) v5 P, n- i& O- r16. We use a similar process to find the position of the droplet, resulting in  E/ t; D! d: P

' z( r1 N4 G+ W) n公式$ J+ V; Z2 B* E5 }
3 Y  c4 z% ?$ E6 h4 v+ R/ X2 D
With t=0.0001 s, error from the approximation is virtually zero.
2 }; ]- N* C# |+ N# a1 _' J! A0 g! y
 1 B" o8 T- e; e

7 J( u6 t" w. M- y17.We calculated its trajectory(轨道) using2 ^5 C, l6 M* R, i, n! P4 {
7 J8 A1 c% f0 V8 N7 z
公式
' `' `$ s6 Z; z9 p: F( W$ P  g& {9 J# J7 q
18.For that case, using the same expansion for e as above,
; g  l& L3 z/ Y2 e0 c# @, K7 q5 D. Q" k9 y3 n
公式
2 w0 N2 }+ B( ^% w' g8 r4 k+ G- @/ V! [7 [0 t& A4 I+ T
19.Solving for t and equating it to the earlier expression for t, we get2 ?7 @% n" y5 O' `4 L
  }& ]. i  I; }, O4 {3 T6 v" m8 X
公式
0 M* r! I4 s6 G/ @1 f5 G5 U% U# z& M) Z8 o
20.Recalling that in this equality only n is a function of f, we substitute for n and solve for f. the result is+ g! o$ \; O' c: B) X/ l

  G. E3 X! [% y! j4 Q% V公式+ n! v, N9 s* u7 {) C) u+ s* B
7 y: }" ~' P# [! m9 c: t; p' D
As v=…, this equation becomes singular (单数的).1 J( E0 m3 U' E* F

( z/ b6 H2 G7 _- L* p& [ ; ^# E8 ]  R  b& R* |5 e6 H
# {+ R# B% ^7 n1 F
由语句得到公式; K; x$ x( q0 t& ?7 z. {
21.The revenue generated by the flight is. [+ j0 b& ]5 p: W' l+ v8 Q3 r

; h+ A/ t9 ^, Y; |公式. R1 @% _) {: B

1 Z- \$ q# B/ u" {3 N$ e  H/ h - g% o7 |* r% |8 J

' w  I+ h  ~2 U24.Then we have
( S0 W9 f0 F4 y1 ]  ]8 P$ i' ^0 H) F+ i: i! t" d
公式
( o: H2 j5 W1 }: c  H. F8 X* J' D% {( j% |; S" \4 L
We differentiate the ideal-gas state equation: s/ r: W, h( k& M

, M3 d1 I* y5 H  r& D* T9 K1 G5 @3 S公式
( B( r% E1 P) x6 _# T2 S: ~" t* `
# `4 B* K& a9 U4 D4 nGetting# l: z0 y7 W9 I  U; H
! M0 k0 ?0 v0 S
公式
+ b& s2 B/ }  }7 \
& X9 h; \3 X" l- n2 H0 H25.We eliminate dT from the last two equations to get (排除因素得到)
) W" ]- M: T  P3 K( |$ b. I6 L
# ?) \, a( n1 J2 q: X公式
/ n( }+ K; I9 j4 F/ Q- k$ D6 P; Q% \6 M% }9 r3 b8 X0 `9 j
 
! T2 \, h1 w, A: V  i0 n* [) }8 J, y" C5 @- c; U/ l& u( x
22.We fist examine the path that the motorcycle follows. Taking the air resistance into account, we get two differential equations6 b9 S! {0 Y# y& {2 f5 U3 ]

; k* S$ `0 X* v. V" `公式
4 }3 \( g/ |* L9 K
& p# \( X7 M. z3 F8 Y6 jWhere P is the relative pressure. We must first find the speed v1 of water at our source: (找初值)
: d: e# `0 _; G: X% ~" K& o2 f# E% K3 @# H1 z5 S
公式6 ~' r8 D- q' \- F' b! _
————————————————
6 O' e# \; b, B2 K+ I版权声明:本文为CSDN博主「闪闪亮亮」的原创文章。8 P( N+ o; p  U: f  g
原文链接:https://blog.csdn.net/u011692048/article/details/774743862 d* A) y" M' F" V& m3 q4 E* Q# i

作者: 1369728843    时间: 2020-2-12 18:25
感谢+++++++++++++++- C3 B9 K8 @4 S3 y

作者: chace    时间: 2020-2-17 15:19
学习学习学习 谢谢  L! ^7 c$ P/ K& r; Y/ h# V( w0 B





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