7 Z& K( @3 L" Q' M& \0 M% p" D- d答案 : ) r, Q# k8 E0 x工人2指派给城市1,工人7指派给城市2,工人4指派给城市3,工人9指派给城市4,工人8指派给城市5,工人5指派给城市6,工人6指派给城市7,工人3指派给城市8,工人1指派给城市9,工人10指派给城市10时,可取得最小费用每月1142.00元。' M/ ~* x) w$ O# N# x0 f/ T/ |9 ~
matlab源程序: 1 V- ~! {) a! t" h%遗传算法 k# h U; d# g" M m%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%) K; g* V% j& S
M=[0 5 3 7 9 3 9 2 9 0; ! U5 W: g; |1 o5 _$ \; F 7 0 7 8 3 2 3 3 5 7;( V1 Q' u) f, e
4 8 0 9 3 5 3 3 9 3;8 o5 f W' G) X) j' [" @
6 2 10 0 8 4 1 8 0 4;: R4 l" ^: \ g$ h* i
8 6 4 6 0 8 8 7 5 9;$ ~+ l( k! x" m2 z6 z- v, k4 E
8 5 4 6 6 0 4 8 0 3; $ J( p' M. S R7 q: Z' \ 8 6 7 9 4 3 0 7 9 5;9 ~: y6 `2 [$ v/ ~4 i" O1 `
6 8 2 3 8 8 6 0 5 5;6 p9 g' `) }/ ^# E# N
6 3 6 2 8 3 7 8 0 5; & K8 x: C: y& j* S! u# a. w, j0 u 5 6 7 6 6 2 8 8 9 0;]; & i2 ^: u* R% K0 W3 J7 Y0 YM1=M; %员工间每月通话时间矩阵+ w7 b) _& Q( m5 N# x: H6 E1 |! v
for i=1:10 " k1 g- T$ N& |( P9 E% K for j=i+1:10# |/ l& L& `/ z( V# T. }
M1(j,i)=M(i,j);% t8 `; [: k3 n
end " d2 \1 B1 V8 V6 f- P: S: V" Bend8 A7 a7 k3 X( X I `6 k* ~. n0 e, E
M2=M; %两地间通话费率矩阵 * b) n, c) ]9 z) Pfor i=1:10 ! k# j' [' y: Y/ a for j=i+1:10; J+ ^6 v4 N, S( a. r$ I
M2(i,j)=M(j,i);( T6 ~, Q3 v& m' U/ n
end b" N# k8 H/ q$ W5 M# M% B
end % b. L5 @3 p! G' q+ Q8 ]%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% 7 v: x8 F( y& _4 h; Q+ R%初始化种群 0 c/ d& G: \% }2 w% Onum=10; %种群数量 - u8 r) ]; v2 G/ _, M1 l6 \8 acode=10; %染色体长 9 Z2 k' R3 g; [0 n5 ldai=100; %遗传代数 2 n. V+ ~/ @1 i* ~4 Hinter=0.8; %交叉率 - B- k) o }5 n0 e* x1 @5 L2 C7 h$ Ibyl=0.8; $ F) Y3 w) n% i: d%A=randperm(num*code); 9 A+ L; X+ h6 n i9 bfor i=1:num+ Y. ?( S7 l" G1 I% @; K& |8 ]
V(i,:)=randperm(10);: X0 B/ f! ]3 b7 m F2 {* R
end5 O* t/ a8 X$ m4 y
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% ] S) |. {5 c# E* Z, \) b1 x. nfor gen=1:dai( p) _' |' p V- X+ Z
' Q( ]8 m6 O2 l6 x/ ~ %评估 ! X- Y- s, U) [. q* f/ f [num1,lin]=size(V);8 E& P5 ^2 L" v- e
eval=zeros(num1,1);/ ?- X; U r: s/ R; ~ O
for i=1:num1( I( @% {! x& |' L2 f& N2 Z& Z. H# ~, u
for j=1:code-1: r( s! \6 P& {% n
for k=j+1:code' g A! N& f z( H
eval(i)=M1(V(i,j),V(i,k))*M2(j,k)+eval(i);: w9 M4 R" O( S0 y8 m0 }
end ) n4 G* g9 {* V' I end ' {; Y/ x( u% i7 ~* m8 S) {; j end! I& p$ k H. |1 Q# L- r8 X: g
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%) z) K# q! {' ~( o0 \
%选择- q4 L5 i6 W$ n
[eval1,ind]=sort(eval); O6 U- B( D( \# g4 t6 j
V1=V;( L0 ]/ P: e5 R, q5 `0 d
V=zeros(num,code);' d/ L4 L* k* \) b: J% b. _ l
for i=1:num : o* d" V: e! z' A- U) A6 p V(i,:)=V1(ind(i),:); $ m; a) a/ M# A H' V3 G/ Y8 q& Q8 M end" [& x7 E* m U
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% & \/ u3 I' Z" I, K7 y: Y5 q( K4 C
%交叉2 B* [1 o) w2 V2 f( ?
V1=V;9 s$ m5 w' M; }% e7 \& _+ a
panduan=rand(fix(num),1); %判断是否进行交叉. g# R$ T0 w; d$ r/ D+ s7 T& j! G7 D8 V
for i=1:fix(num);( E0 s* O! o' C9 \1 S
if panduan(i)<inter %在交叉概率内进行交叉$ W6 y$ z* I p2 h' m& y( [! C6 A( q
V2=zeros(1,code); %记录交叉后的染色体 . m) P% b6 {# t2 e% w) p/ X h=randperm(num); %随机取两个做交叉h(1)h(2)% S* `4 c, ~* [0 A8 M
a=zeros(code,1); %记录未使用的位置3 {# Z- ]$ V u8 F( y: J
b=zeros(code,1); %记录未使用的数字 V6 Y4 G/ M6 g& B
%在双亲中随机选择基因 ' E6 O( l8 J4 a# r% d1 p t. g for i=1:code " N$ j7 Z: R; O h2=randperm(2); %在双亲中随机选择& I, j& l6 A1 m" m7 H' v5 P* ~7 i# g
if b(V1(h(h2(1)),i))==0 8 X* L. _! A' ~# w! z, O: L V2(i)=V1(h(h2(1)),i); b(V1(h(h2(1)),i))=1; a(i)=1;9 m; r1 r5 t y
end: R( W9 j! W8 ~4 f% `
end. N7 ~) c8 O7 c# \& E8 W
# z& c) Y* p. c% G! } %随机分配未使用数字和位置 o! F- c3 n4 P- u h1=randperm(code); %记录未使用的数字4 i" o0 Y, b% _& z% |3 M, I
for i=1:code3 }2 y, C$ K1 d7 i7 @, p5 _
for j=1:code8 q) v- ^3 l! a( Y" v9 w$ {1 D
if b(i)==1&&h1(j)==i & ?* q, i% C' B; M# ~5 X0 b h1(j)=0;break$ A6 t: k9 J0 w( b4 I4 Q( t7 V
end t% J B: t, F
end . q# C) f4 F* E1 Z/ f f end6 b! s6 U; j J u. j, H5 p
/ Y7 t: B1 _$ _( c4 Y6 V" i7 n
for i=1:code4 L2 K% {- z+ ^5 Q, @, T% u/ Z
if V2(i)==0 T( d0 S. s% O5 u/ H# K T' o
for j=1:code! I+ |" t) [" B8 J3 z% \0 |4 M
if h1(j)~=0 ! `: H ~- z. s$ h2 P' x V2(i)=h1(j);h1(j)=0;break 9 W1 T3 B( I; r$ m; x end7 d6 }2 K! k7 C( y2 k0 M: t6 t
end + m3 d+ a6 [6 u9 f; r0 A' r end* _; T5 H1 C+ J6 C- W
end * h, k; J, u, F% {5 d V=[V;V2];, P/ l# E9 R3 y& T1 z7 `
end' |1 r" |3 U! T K& ~3 c! j% i
end 1 F2 ~ y( ?( ]2 |8 S/ \2 W Q3 @& \# S/ c% B u6 v %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5 s5 K% P! r! u" D
%变异 * ~4 h+ ^! r0 R0 `( F5 y8 W1 L V1=V;( H: H7 c( W" E; [& \
[num1,lin]=size(V); 9 P& M/ m, a& F7 q- z/ g x3=rand(num1,1); % w: N: P3 R+ y8 f; [ for i=num1 : a9 [/ z T& Q( `# B if x3(i)<byl %变异率( _$ z1 E q+ S
h2=randperm(code);' K1 w2 X) ~- w2 ?8 [" ] I. a
V(i,h2(1))=V1(i,h2(2)); & P" n2 v. v$ i( I2 W3 ~8 p+ q V(i,h2(2))=V1(i,h2(1));1 P% ?) d' s* ~; h, P; D
end 9 B9 f3 l3 o4 R) [# A end 2 v, D. B$ _0 ^3 {/ xend , H, C# a* }" k; v! z/ ]%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%/ v2 z4 b* T3 F1 T3 H5 E
7 F8 R* V" ~9 A; i: Y3 R
%对最终种群进行评估" o5 G- y: I/ W. [$ r" y& V
[num1,lin]=size(V);3 i$ z' [7 o: |* K! {: N* e
eval=zeros(num1,1);* m$ i" O/ Q7 a& Q% k( s
for i=1:num1 ) r# c5 T: Q7 k: K8 d for j=1:code-1% h; H- I, D; f' q& z* y
for k=j+1:code" O) i3 Z3 ]& L8 e' B/ `
eval(i)=M1(V(i,j),V(i,k))*M2(j,k)+eval(i); 4 N V B4 B" q7 N U2 E end3 f [4 q, U% h' c
end, A7 }+ g9 I5 T, L- _% I0 v6 m
end# _2 F. g6 ?6 b' p( ~# Z