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#include<iostream.h>
& {, R9 G9 [, w1 s; `& z* |6 g+ i* {#include<fstream.h>
" X) y% w9 |% @" R#include<math.h>( r, r6 J8 |1 \# [/ b* B
#include<time.h>7 v8 R* F" J% S' D* v( h
7 D# x# W$ D6 j3 t//============随机数类=================
2 b) j) i+ ~+ | m4 E; Mconst unsigned long maxshort=65536L;4 w( a- J( z0 k1 `" f J
const unsigned long multiplier=1194211693L;2 v' }' B, R: e0 O/ X! e
const unsigned long adder=12345L;
1 ~) q: b+ i5 ? {; w) [; I9 |$ @7 A" d$ ~
class RandomNumber: V6 E7 u4 y# w4 s5 h0 G0 |
{( j+ p# ^1 f$ S& V, ^( h2 d
private:7 Q. h" S* h4 V8 ~
unsigned long randSeed; //当前种子 D4 o6 v8 I: i$ l( i
public:3 P$ J' X% l. T/ y% ]% o
RandomNumber(unsigned long s=0); //构造函数，缺省值0表示有系统自动产生种子
4 a$ Y; A+ a1 r0 | T/ _, {( D: F! R unsigned short Random(unsigned long n); //产生0:n-1之间的随机整数+ X/ c" V% Y7 B v1 Q/ e$ g8 c' y
double fRandom(void); //产生[0，1)之间的随机实数
! N& v" ? O% q& {6 y+ J1 f};' N' p2 B/ Y% p$ N- I
3 c/ b: ]8 P( [RandomNumber::RandomNumber(unsigned long s), f/ H: v$ F; D* ?6 R8 r
{//产生种子
' |, {% c4 J) {4 q' k if(s==0)
; @: Q, U q$ X3 v8 A# ]* e randSeed=time(0); //用系统时间产生种子
$ l6 H2 W* c, J else
, {7 }4 C( }- ^7 t- ? randSeed=s; //由用户提供种子
9 Q; z: W- ]0 U' u; ]}. ^6 n; H8 x6 n" N1 Y& L
2 V8 ?3 {- o0 t# }6 t5 F9 i
unsigned short RandomNumber::Random(unsigned long n)
1 _" \7 u8 z5 W! T; Q{//产生0:n-1之间的随机整数
6 C. Q; f* [4 _6 x randSeed = multiplier * randSeed + adder;" F, E; P1 T c( @* ^' v% h
return(unsigned short)((randSeed>>16) % n);
+ k' o3 q' t+ {' I- J8 J}
3 r5 I# Z$ M$ t/ e3 F9 U _# l: U! v2 f+ ]: j# K: q, h, {4 p
double RandomNumber::fRandom(void)5 S7 m; C) z5 L( P
{//产生[0，1)之间的随机实数1 `* A/ U9 n* c1 \
return Random(maxshort)/double(maxshort);
* [1 ^* o, q$ h4 a' x" l}
- l% P1 Z! A( K4 l5 J! J$ T//===================================================9 o( {/ o M/ ?8 `, j
2 z. ]1 n1 J- u
& K& Q7 ~# ?& Q0 b% L& T
//=============合并排序算法====================: @1 j. C8 B4 w) u
template <class T>
* m j2 Y; L% d X* ]7 e9 Pvoid Merge(T *c,T *d,int l,int m,int r)
$ H* N$ q6 o- i# M' z$ ^/ [' m{! K+ c0 ^ d; R: s5 A
int i=l,4 L0 D8 {9 s1 E$ L% @0 y; U( v* B8 O4 E
j=m+1,
, B3 X r) ?, A* b' ]3 p: J _ k=l;3 K/ D) m: A. E& }3 h1 C
while((i<=m)&&(j<=r)), a' k% x9 o% j# e$ e+ j5 T! I
if (c <=c[j]) d[k++]=c[i++];
: N) }/ m4 z3 t else d[k++]=c[j++];
2 u# X3 c# A! G* o# s if(i>m) for (int q=j;q<=r;q++)
! {6 G; C& N8 a$ m# U d[k++]=c[q];
- t6 m+ S! N5 z2 i! ? else for(int q=i;q<=m;q++)
5 I% o( J* l8 b8 n b& K7 d6 h d[k++]=c[q];
$ f' u) F$ ~: a- C( Z. i} N p4 y' z$ D4 l: T/ N
6 j, R0 f( p) M1 D, t6 j% Utemplate <class T>4 z% T+ H/ d/ M; h" }
void MergePass(T *x,T *y,int s,int n)1 }. s* p0 b z1 D7 O
{; A6 c, ^1 ~5 U
int i=0;
; E0 O# }, ~# A9 x while(i<=n-2*s)
4 L9 s# z' x; J' P; M0 u/ B {
5 k. U; Y# F% a. M Merge(x,y,i,i+s-1,i+2*s-1);
" Y* R/ l7 }" f% T' M4 m! Z5 P* l! m i=i+2*s;9 P( E* }9 y9 m3 C1 s
}# K, ?2 f2 J& F/ K5 e
if (i+s<n) Merge(x,y,i,i+s-1,n-1);5 R" h/ \9 e, [7 t9 v1 k
else for(int j=i;j<=n-1;j++). {- h8 D; Q9 ]5 D% n
y[j]=x[j];
* f, e4 F+ ` R& ~}
" t1 ?' f1 Q: Z# T9 k2 T! A4 v6 [' G; N/ Z6 u/ {
+ p( W# v+ _& }
# l7 Y8 \1 R2 B% x7 @% @! j# h9 }6 c
template <class T>7 E% O6 U1 z$ O, K3 {
void MergeSort(T *a,int n)
3 l! N/ D3 u# X9 H2 h& \& F{- ]4 l( V& R$ y) D i+ O
T * b = new T[n];$ Y, S$ Y& I3 R, b% N# I
int s=1;
& J6 K2 M0 v/ E; h! v8 n5 I while (s<n)
8 r% J7 ^% B* {0 G* h! o" o {7 h9 A9 N9 o+ Y
MergePass(a,b,s,n);
' P ?! l' P! @7 L3 `6 S/ [! t# L s+=s;
5 |; e, M/ Z% u! z) [- _' w MergePass(b,a,s,n);
' i5 |, k' b! ^- g8 H, u s+=s;) f* a5 S' ^) s2 b/ T: u4 F
}
# {& Y& {% R& j& [ K1 q}
7 \ \7 ]5 f& k/ s7 }! U8 @
( o) V: o: Q9 R% v& Z//==============二分查找算法==================. r( m* T. q6 R2 ~# }! W4 l! f, t
template <class T>
0 U( ~; T1 D; E: w4 O1 ]/ K' z, Yint BinarySearch(T *a, const T & x,int n)% G Y9 q1 `3 `, M* @% L8 A1 }
{//在a[0]<=a[1]<= ... <=a[n-1]中搜索x,找到返回其位置，否则返回-1
( \! G' `- P) J int left=0;int right=n-1;1 J" b& ~! b' _* _' i" S
while(left <=right)- O3 {( O- ^1 G
{
! h. |6 Z/ Y c! w5 J7 U" x9 O int middle=(left+right)/2;
5 h6 H7 W- N' f" b6 a8 S/ I4 G if(x == a[middle]) return middle;
' A& O' M9 \+ R9 |3 p if(x > a[middle]) 0 V% ~$ _" r, E
left=middle+1;* o" M2 L! |' M7 O' p- m
else9 E, K8 U: p" K/ a( j
right=middle-1;
" ? n+ [% X( t& D* [ }
) k4 X& V/ _. E% t1 m+ _ return -1;//未找到x- j) |6 h7 b+ N4 j6 t+ d1 f/ ^3 n
}) Y. a' D- N5 E# H; z) s( |
) V$ x& T' J9 x4 l9 b
* \- v5 }0 s& K( Q//=========判断两个集合相等的蒙特卡罗算法==============0 t& Z( F; {( d% a3 _
bool Equal(int *S,int *T,int n); ~+ f) A& E1 i7 e
{//判断两个集合相等的蒙特卡罗算法
8 p8 w: `& O5 i% i. c$ z- ?8 p Y, z static RandomNumber rnd;
' m+ S$ [, b5 V2 z+ W8 X int i= rnd.Random(n); //从集合T中随机选择一个元素，判断它是否在集合S中，
1 [9 f, g s& o" c// cout << T <<endl;
: d$ c( u6 I- F1 D2 k if (BinarySearch(S,T,n)==-1) return false; //不在,返回false,即集合不相等
, K* x* U. X" F return true; //在,返回true，即集合相等+ Z( Z. C% u' k6 {; f6 ~
}$ A. z8 I, c; x: v7 T
& p6 V. @/ Q! xbool EqualMC(int *S,int *T,int n,double e)- K! z% ]# p5 j2 p/ I/ p
{//重复多次调用算法Equal,确保错误率小于e
+ \* a% H$ o4 m; ?/ O W( O int k= int(ceil(log(e)/log(double(n-1)/double(n))));8 [: R+ {, s( o( w5 k
// cout <<"k="<< k<<endl;/ k3 Z& G& M9 z; d1 I" K" G8 ]7 c+ i
for(int i=1;i<=k;i++)4 _: C8 g, a& S' B. X0 ]& c
{) i$ O V* X5 X, Q. k$ z' F
// cout <<i<<" -> ";* C* v7 ]7 ^$ |/ u
if (!Equal(S,T,n))
( a% {8 n) {/ j6 Z {% t2 j2 [+ l1 ~
// cout <<i<<endl;7 }8 z: H* ?* `6 E* O* Z4 }/ L; k
return false;
2 L7 o$ e4 S, L2 G: W }
" w5 B3 w! s' s* k0 r6 v }8 X8 L- X1 d3 n3 I" e+ N. M
return true;& l' u0 S# j6 {# f. m: l
}) G+ o8 a% m: W! W: t h+ }5 ~6 S2 N
int main() h! w9 p! O3 F& E$ s6 F& y
{
5 h4 T* i. e! w1 [+ f int n; //集合的元素的个数
- G' w* h" O: s( {9 g4 S, D int * S,*T; //待比较的两个集合$ ?0 ?7 o6 B4 f1 C; G
int i;
# y$ @1 \; ]& {- F
( ?# V: P+ ~! h ifstream InFile("input.txt",ios::nocreate); //读取input.txt
5 N+ z" z4 \$ @4 }
. j7 C, p7 p! D1 q8 h% a1 V! o/ `9 R/ P if(InFile.fail()) //读取文件失败: I/ s. `3 [7 C2 ]9 |' c4 g
{
$ U& H- ]5 |+ U4 ~! S cout<<"the input.txt is not exist!"<<endl;
) ~0 r. p+ I* D X return(1);' V: h1 F+ |/ z( {4 q2 ?
}
0 L. k+ ~7 y1 W& e/ n" ?9 G InFile >> n ; //集合的元素的个数
1 A# K4 n! W7 q9 x% j0 e S=new int [n];
: }+ L; h$ {# B* a9 N* y3 y/ e for( i=0; i<n; i++) InFile >> S; //集合S的各元素1 k$ a, _! k; X7 L. P$ ]# N
T=new int [n];% [# L- C9 ?+ w8 A* l
for( i=0; i<n; i++) InFile >> T; //集合T的各元素/ S$ B% j' C7 p, q
' O. b5 l5 V* `1 c9 ]' @ InFile.close();
* `. {; ~, y/ G0 Z0 F6 G& @. E2 k, C& s8 }% f8 g E8 X
//将集合S的元素进行排序预处理- p2 k/ y E$ X. @$ q8 Z1 K
MergeSort(S,n);
: W) w( I9 m" j* b) t7 t. S9 g' n- G& g0 }
//cout <<"OK Sort"<<endl;
, E! |& ]7 X/ p6 b, k// for (i=0;i<n;i++) cout<<S<<" ";
0 H2 P, ^# F; E- @% _) C7 L// cout <<endl;
1 ~- P* s* ^; I$ i' d. q* N$ I* `
; [. V, Z& I) ]( n a; k///*
- R& U9 g+ M: @: }9 K. k ofstream OutFile("output.txt");3 ]: r1 n9 B4 Z9 z% R8 d
double e=0.001; //错误的概率
2 F' X9 m# M6 B* ]0 [ if (EqualMC(S,T,n,e))4 Z8 G+ S" h8 ^6 `: n
OutFile <<"YES";
r1 C' L& }! B6 [% K7 R4 W. W else
8 i4 J& o8 k8 f1 S0 u/ p( B& }% N2 Y OutFile <<"NO";
5 x* M: S) [$ ?6 w1 n& Y3 H delete []S;
7 `+ O& Q0 m4 R+ [ J delete []T;
2 `: L; c/ O2 H% X3 T return 0;
- t3 ?- K* t: A K//*/
; x! Q7 C$ T9 |* S9 t+ Z5 s/ j- x) j: e9 o+ G$ Y
/*
; X8 a) ?% J6 H9 V: q//=========测试用，连续判断m次，看得到的结果正确的次数和错误的次数6 b" c4 |' B N7 X5 A! k* d
int a=0,b=0,m=1;2 D( j. _. Q1 j3 I" m
doub集合相等的蒙特卡罗算法
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| | 发表日期：2006年1月12日 已经有66位读者读过此文 | |
#include<iostream.h>
x6 i$ b; s# t* d, H% [/ u#include<fstream.h>
o" |! p+ o0 x: r; q#include<math.h>
# Q& ~* g+ A' p: p3 V; s/ \# l#include<time.h>/ I% m& f+ K @2 f% e/ Z
/ j% H+ w0 }6 L1 x5 L$ A
//============随机数类=================
" ?2 {, u4 C) a- lconst unsigned long maxshort=65536L;
/ |; O# p" l* \; l3 \const unsigned long multiplier=1194211693L;6 k) q6 c$ X# H$ N8 k+ ?& |) o
const unsigned long adder=12345L;$ o& Y9 L2 p0 m7 m6 g; ?
* K6 ?, Q+ h4 }# z! J, d
class RandomNumber
: B% D5 Z/ `) l# C% \6 r/ B{
5 ]6 l: W) u9 V) S; _+ j! n: I private:/ b5 m, K: h- L1 O: A3 x
unsigned long randSeed; //当前种子5 e, X' {2 P# X$ J- @. R
public:! N" B5 M9 N: C4 b G3 }6 P
RandomNumber(unsigned long s=0); //构造函数，缺省值0表示有系统自动产生种子$ t0 S! w# T$ Z' r, x# c( X! N9 z
unsigned short Random(unsigned long n); //产生0:n-1之间的随机整数
' G6 c- P( O" y/ `/ r6 O, C double fRandom(void); //产生[0，1)之间的随机实数! W+ i0 h$ Q# p. b) n
};
/ v9 c; l# v4 ]7 O
! {, n! b% V' J! ?9 n; BRandomNumber::RandomNumber(unsigned long s)2 _ ^- l# A0 w& X0 ]# A
{//产生种子
1 {8 ]6 @# h7 l if(s==0)
. @) U) q8 K: h) V randSeed=time(0); //用系统时间产生种子7 V1 T r2 p, `0 n: Q
else
7 j8 J. R( ^* {- v2 f randSeed=s; //由用户提供种子! F% J' G. r4 E3 M% G$ t
}
K4 a+ V+ a1 v( X4 i' V! e8 d1 N9 ]0 g" q- L. x# l* K
unsigned short RandomNumber::Random(unsigned long n)
" f% _0 L4 D# J' z2 C& @{//产生0:n-1之间的随机整数
. ]4 C, _/ g4 } A# W$ [ randSeed = multiplier * randSeed + adder;
6 u' d3 c2 \$ b- O* x; S, ` return(unsigned short)((randSeed>>16) % n);
4 T# a$ ^) D* }/ V* X9 e}2 @( W- T4 }; L# U* t/ ^
* Z/ h1 [! I; cdouble RandomNumber::fRandom(void)0 N5 V( |$ {( H- v
{//产生[0，1)之间的随机实数# S1 e0 c$ W$ K Q3 R4 O
return Random(maxshort)/double(maxshort);
8 u6 h( [; \$ G}/ u) x( Y2 d: f; f
//=================================================== J1 A+ b" m0 l) i
$ M+ ^% s! }. g) b2 I: ?9 N( F. P- e9 `( i+ u
//=============合并排序算法====================
9 I- V3 r1 s/ d. c3 btemplate <class T>8 ~" y2 g3 y- ~9 ]
void Merge(T *c,T *d,int l,int m,int r)
) Z% g4 W' W# F5 X4 L) @4 d( Q+ @1 {{- a/ E: ?1 D5 c7 K; }; C
int i=l,: L: T: r% h: ^, K: |/ [' B/ W
j=m+1,( j' E9 e: G7 g9 q
k=l;0 q, u$ T% ^& Z8 E3 o8 H* Z
while((i<=m)&&(j<=r))
& ~- N- u& X) n. G5 q/ D# C6 a if (c <=c[j]) d[k++]=c[i++];: R: {) Z/ Z7 y5 @' e$ ~ E
else d[k++]=c[j++];
, P& z w+ B5 T% |) t; w7 F if(i>m) for (int q=j;q<=r;q++)! g* Q) O; L7 |7 b7 G0 {8 E1 J
d[k++]=c[q];& \4 t8 N, Z8 D6 f
else for(int q=i;q<=m;q++)9 a0 b S( ]. Z5 H1 I+ ^
d[k++]=c[q];
$ Z* ]6 p& _3 V: _" q}
6 [2 F- l5 x1 z! u' q( h. y
5 f8 y1 E! E W% ~template <class T>. A( f t9 d5 u6 n$ _- ?
void MergePass(T *x,T *y,int s,int n)
% Z9 _! Y3 C/ r, Q0 R( M' o4 r{. a j% t% o/ Z& y% U
int i=0;$ N' G/ I2 L( O- A' s' K! B7 s
while(i<=n-2*s)
: k* |& K0 m2 U! V9 N {
2 U t5 S1 Y5 C$ C+ V Merge(x,y,i,i+s-1,i+2*s-1);
( F0 j% Z0 A/ Y; c/ O' \" Z i=i+2*s;
" i: c, I6 p2 c& `$ ^ }: G$ Q" O+ D# q: P) V4 t
if (i+s<n) Merge(x,y,i,i+s-1,n-1);
& G" K: f" A1 l" n `/ L) d- d5 A6 g8 b else for(int j=i;j<=n-1;j++)
9 X* m. ]! J# N D1 Z1 F y[j]=x[j];0 x2 @6 _0 r/ l$ F
}
$ u) L" _# S# @% B2 [# J$ `
* b( M L# w8 `# g% r9 ]: b1 K. V: I- E% X% P1 M2 G2 Z ~
- W) \9 H5 H0 O. rtemplate <class T>
3 Z: S) q* I$ ?* Ovoid MergeSort(T *a,int n)
" n' {* {' i* ^/ H{
5 ?1 O0 T7 _; ] T * b = new T[n];2 E4 X& H3 n1 d
int s=1;
2 [% }4 u' q' }, O while (s<n)0 \* R _: U) {7 T
{
. _8 F* n, _6 @! {" ^6 P# b4 C MergePass(a,b,s,n);
, ^) F3 P; w+ B) c" T s+=s;
+ k0 y% s1 k1 r MergePass(b,a,s,n);4 U s9 |0 x3 a; p" z! `7 O: X
s+=s;: |8 ?: k- }5 X* V D. j$ H
}- _4 ]- X$ f4 M2 g" ^
}9 H, C5 O9 J$ s% d
$ L4 E2 t! z7 U
//==============二分查找算法==================* t" {% o2 O( p) M5 g. [
template <class T>, }: M6 e7 j$ w+ i5 f
int BinarySearch(T *a, const T & x,int n)
4 y4 s+ G: \( L. p{//在a[0]<=a[1]<= ... <=a[n-1]中搜索x,找到返回其位置，否则返回-1# m+ v' C/ a; P
int left=0;int right=n-1; d+ l: g4 `6 e/ K1 V% s
while(left <=right)5 g9 Z7 G E) |
{% a2 U( u" o; A" a# r6 f5 X z5 i
int middle=(left+right)/2;
+ N9 i, c/ V/ ] if(x == a[middle]) return middle;' i8 B& Q! s/ [8 q# ]% { B
if(x > a[middle]) 8 P9 S$ v. v6 e2 o
left=middle+1;
( F' l- T# H: W else0 F8 @; G6 {2 V, \8 f" N
right=middle-1;
- `8 t: B5 u0 q8 O }
0 c: \' s7 P0 v1 [4 \ return -1;//未找到x& _% ~8 `- T, y2 T
}- v. ^* p6 j. w4 ?* W! X
+ `7 F# a% O7 @2 y3 y0 \7 e5 k6 y; |& _0 s# V
//=========判断两个集合相等的蒙特卡罗算法==============4 J4 W. |7 _" L; d: a% F, W
bool Equal(int *S,int *T,int n)+ [/ R% e! O& I) K# O1 X3 c
{//判断两个集合相等的蒙特卡罗算法 T" A8 Z# K6 }3 @, y! G
static RandomNumber rnd;
* e, \' k5 i/ r ` int i= rnd.Random(n); //从集合T中随机选择一个元素，判断它是否在集合S中，
9 k& N6 @" C* Z9 i/ g1 `// cout << T <<endl;
& W% b& |: o1 G' f if (BinarySearch(S,T,n)==-1) return false; //不在,返回false,即集合不相等8 t/ A- ]& l3 z$ M
return true; //在,返回true，即集合相等3 Z6 n6 D; l2 o. B! @
}! r& J$ @3 m2 p2 n# A
2 t! `$ u1 a9 h; z j
bool EqualMC(int *S,int *T,int n,double e)
7 `% T$ b% ~% q7 ^7 o/ s) U. |7 [- Q{//重复多次调用算法Equal,确保错误率小于e
8 @, h0 f& C. l- Q' W8 F int k= int(ceil(log(e)/log(double(n-1)/double(n))));
* m4 O4 K3 r/ x7 r4 @// cout <<"k="<< k<<endl;1 e2 c, i: P- R1 s
for(int i=1;i<=k;i++)) v/ ^& f) V: p( |) z
{9 v8 r& B* w" F; u5 `% S
// cout <<i<<" -> ";
5 O. A2 q9 ?. e% o, Q if (!Equal(S,T,n))
/ s) q8 a2 d0 [0 Y/ l {# _" z! }. M" g4 {
// cout <<i<<endl;
; [8 A4 F! e* r% [ return false;
' v8 ^, A& y/ O8 a5 M }
) z' G4 L6 q2 ?( P. y# d }
& n8 ^( n2 K& k9 r( N/ @/ |; ~ return true;5 d( p) q' {/ R% _3 I
}
& O" ^" Y9 t' W# @- [7 O# L2 I! nint main()
# k# J, d7 N# U1 V{ r9 v$ Y- a+ g! R
int n; //集合的元素的个数
& ?: p& a1 F' j% Q/ v int * S,*T; //待比较的两个集合
5 W* k; D i+ i6 n# h int i;3 A' n! q( q' x; B7 b7 U
! g+ H. {4 D% m5 v1 q ifstream InFile("input.txt",ios::nocreate); //读取input.txt
0 W7 |$ ^2 A% i, z7 e; q0 P' \$ [5 m3 t1 K4 o: ^2 M
if(InFile.fail()) //读取文件失败
, z4 b* P( y: r* F3 E {3 v% O- U3 y/ }" a% a( ^: _" A# A% t
cout<<"the input.txt is not exist!"<<endl;3 s% [5 X$ `& O% Q3 W$ e# @) ]) ]1 [ B
return(1);( b; W s! W S6 }
}
( |* [! P% y/ e( J" w InFile >> n ; //集合的元素的个数) `8 i" a/ Q9 ]7 G; k5 J; c
S=new int [n];: w8 L3 T$ i! V5 q5 H
for( i=0; i<n; i++) InFile >> S; //集合S的各元素! K8 j; E2 }# y- j/ p
T=new int [n];
4 b" Q4 a* q5 Q5 e for( i=0; i<n; i++) InFile >> T; //集合T的各元素
% _1 w/ V' c$ ^0 ^: B) C, s, p$ R* I) B3 v+ r) [6 o& `( U
InFile.close(); E( |0 d% q) c0 I( A M2 k* Q& K
3 X2 ~/ u& @" @ //将集合S的元素进行排序预处理- Q4 i+ A4 n- }. M0 k8 k& T; d
MergeSort(S,n);
, z2 c; x3 @6 `1 \, [& O% e+ M
/ }) |- c+ O* F7 U' J" N" k. `* w //cout <<"OK Sort"<<endl;2 L' o/ V$ a! T' j) F& Q5 K. T
// for (i=0;i<n;i++) cout<<S<<" ";
, n& B6 `) I* P5 ^; {+ e2 v3 G: v& J// cout <<endl;
, v0 h" C" k/ B( [ e
* A4 K- c. Z8 S/ N1 R///* 3 f/ R, `/ U: C3 E* I6 _( E
ofstream OutFile("output.txt");" L/ z) F: C4 R; e
double e=0.001; //错误的概率
2 ]8 g9 a/ Y0 V0 ~ if (EqualMC(S,T,n,e))4 n9 v- D3 q& u3 g0 H
OutFile <<"YES";9 b( T0 Z5 k, U4 c- v& |
else ?1 B/ R! F& ~& ~. ?$ B. C
OutFile <<"NO";/ Q' }; i0 @: v0 V2 }
delete []S;& j% ]* k* `& m% c2 `* k5 i
delete []T;
: |* u* e) x; e- z' x o return 0;
7 A% H Z" Q$ K. [ W1 Q* i3 _# j//*/
; ?. T7 z3 [: u, t- v
& T: g: v1 A1 s/*
1 K) E. q! h8 h: r3 R//=========测试用，连续判断m次，看得到的结果正确的次数和错误的次数
' p4 T6 h9 R0 }# p int a=0,b=0,m=1;$ T$ ^8 V. {9 x# c6 Z5 G' u# r
double e=0.01;
7 o _9 @ C# @: O, t$ M3 y) H for(i=1;i<=m;i++). r! |& k& _% J) f
{* {1 |- I- n0 z+ a, \ {
if (EqualMC(S,T,n,e))
+ o( B/ j: m: K" a" d2 G a++;
8 t0 p4 C, v% H6 ?! R5 V else% e3 T9 r% J" ]2 r) K4 {$ k7 y
b++;, @ o2 d* r0 i" M: f7 ~
}
5 m* I% Q: M+ L) I* C; m cout <<"Yes " <<a<<endl;
8 s+ l) c8 T: F$ i8 f* j' N cout <<"NO " <<b<<endl;
+ v3 ] [! G* a//==============================================================
2 y% E6 f! ]# t% R*/& h) B; h \0 K: ]2 q5 V( ]6 P
- e2 V8 y- a$ y& }( c! V+ }1 l
/*
; g; x5 G0 @5 [+ l9 v//==========产生测试用数据===================8 ~/ A! B: a( Y: S
ofstream OutFile("input.txt");
* j7 k$ s# y+ v# Q1 u/ c9 v2 ?; x n=10000;& u# L" _; n; Z& a
OutFile<< n<<endl;
" d. c. A e& n& D3 T for( i= 0 ;i<n;i++) OutFile<< i<<" ";
# u( R4 W% W* S OutFile<<endl;- [* i, ^0 g3 J6 m
for( i= 0 ;i<n;i++) OutFile<< i<<" ";
* ^( W) e7 }4 Y OutFile<<endl;# r5 x. A0 [+ e# V$ ~$ O" X8 x
//=========================================$ z8 k8 K# N3 n6 T6 w( d1 y) {" c
*/
' R( K' C) M$ l, l0 B9 @% ~ D$ Z5 d7 H# r& L' M( u" @+ v
}
% j& ^) H4 o4 _9 y3 @6 ~+ R
|
|
le e=0.01;
) J" l3 E% ]2 w for(i=1;i<=m;i++)* M3 m9 f& f0 u& L; q) z3 z
{
4 f0 l4 [ Q" P. V R, u! @ if (EqualMC(S,T,n,e))
; w2 e: x9 M c Z a++;
3 ]7 l9 x1 o9 j& v2 U v$ e; i else3 j9 y& b! O7 F8 G+ C
b++;
/ {8 u1 F/ a6 Y7 o( J }% y+ B0 q2 H" z, b- b
cout <<"Yes " <<a<<endl;! A9 E. _5 b% {9 m5 W T7 {1 @
cout <<"NO " <<b<<endl;1 N" Q# M3 x3 t2 P) B2 u: W
//============================================================== . Y$ ]8 l% j. G
*/$ Y8 H6 F0 Y2 r/ \; |4 Q
- g- D6 u3 I2 b3 x; F
/*7 y& M% }1 K! @* R$ i
//==========产生测试用数据===================0 M; g1 z6 P" H& {; H
ofstream OutFile("input.txt");
$ e5 ]( z4 a% [4 X9 y# U4 s; f1 V n=10000;
4 @; A& n! l9 o9 q- a; t OutFile<< n<<endl;
1 X+ L: U# w; p/ L, p/ \ for( i= 0 ;i<n;i++) OutFile<< i<<" ";6 |! c: M' }7 I+ n
OutFile<<endl;4 d- E4 R& l _8 \
for( i= 0 ;i<n;i++) OutFile<< i<<" ";
2 p) f# _ A& H+ f! q OutFile<<endl;" D! B9 |$ V& s4 z! g* D
//=========================================
' _; f9 V9 C O) T4 Z+ B- N" H*/5 p0 ~& I% h2 [2 M# l6 |6 C
* m9 o! P5 L6 a( L0 s/ {+ N4 n
}
3 g1 N2 v* x; |6 q- H
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