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#include<iostream.h>
- q1 Z# a+ ^! C#include<fstream.h>
6 U7 X8 C: I! _* c/ v" u; E+ \#include<math.h>( _6 _$ h g7 D! o
#include<time.h>
& H7 N4 R) b/ X0 N2 ^; U8 d( o9 s% N0 [& f
//============随机数类=================, g3 B1 i. B. L8 S' V" e
const unsigned long maxshort=65536L;
$ @: a; c, G; F4 {8 E2 |9 M4 ~0 aconst unsigned long multiplier=1194211693L;
1 h& _- h! v! Q6 _9 W6 @+ s6 rconst unsigned long adder=12345L;2 b: D. g+ [& y, c6 e
2 o6 B3 e% J2 A) `& ]1 T/ ]class RandomNumber
5 w* \' n) e6 e% m( K{
* m4 g% w3 }, F- V3 Z private:
( U( h$ Y& E ~2 Z/ c3 n unsigned long randSeed; //当前种子
$ W4 [+ x% h. Y! d% u/ g public:
, H* a3 o' @ ~1 S- V RandomNumber(unsigned long s=0); //构造函数，缺省值0表示有系统自动产生种子3 F1 `: @+ r; P3 q, @
unsigned short Random(unsigned long n); //产生0:n-1之间的随机整数
! K X1 k% f8 ^ double fRandom(void); //产生[0，1)之间的随机实数
3 R# S# P; W4 D0 h3 W. `. Y9 T};6 l6 u% w2 o/ |4 k$ r3 b6 w6 j+ P
F; ?: d3 g. V4 C
RandomNumber::RandomNumber(unsigned long s)
$ \6 a, e4 D7 O$ V* V{//产生种子4 c& v. d u( \ O' p" B
if(s==0)
* _5 G/ N( [# ~. x. } randSeed=time(0); //用系统时间产生种子
; v; V# _+ E9 }5 K else
2 C6 e4 U$ A$ ]) X, o randSeed=s; //由用户提供种子9 i0 u S& i2 E5 a8 s/ Q1 S
}
6 B) K' I. V: h5 \5 G9 F2 P4 u( [1 p [: f" E
unsigned short RandomNumber::Random(unsigned long n): T/ i) s, U g! u( S4 u& G& G( E n
{//产生0:n-1之间的随机整数- z1 V+ F# S; ~. D2 l3 ~# `0 Y
randSeed = multiplier * randSeed + adder;
3 ^! g8 ]2 A( I" j) ^9 Y* m return(unsigned short)((randSeed>>16) % n);
% J; ]& I& U6 d x6 P}
# D" }, Y& l: \6 s* M, r# }2 J' ]" Z2 U
double RandomNumber::fRandom(void)' j; y3 `9 o8 {. `' N; R( I
{//产生[0，1)之间的随机实数
: M b0 h g) X6 ] return Random(maxshort)/double(maxshort);0 p: d3 a C! O5 f) \" X; J& M
}; y) U1 r# m# Q z! U
//===================================================
! g( M$ @3 }0 {% W' S" e2 X
0 W% J# f$ Q2 G7 O# b/ O* }, _6 l! }. C9 v0 }
//=============合并排序算法====================
/ L+ ?0 x2 V& H1 ^* f3 f# jtemplate <class T> V, O( W; u; t$ q$ }3 u
void Merge(T *c,T *d,int l,int m,int r)
! j# T' r% G8 T$ v6 W U{3 X# X: k" R" E1 k8 Z# ^2 F
int i=l,
8 D8 d/ |# x, d V* D7 @, @! o$ C7 K j=m+1,
+ X+ w7 L: C; q) X0 l k=l;- Z6 z- w/ d2 r4 r! l
while((i<=m)&&(j<=r))" u* u$ }3 g# a& C4 {* R; n
if (c <=c[j]) d[k++]=c[i++];
3 B4 J% ?9 n9 c0 W U6 U else d[k++]=c[j++];
" J2 w3 {7 f6 |1 l3 { if(i>m) for (int q=j;q<=r;q++)
% C9 z* ^& w# ]) M# W+ ` d[k++]=c[q];
1 t* m, W& u. G) n( o1 _ else for(int q=i;q<=m;q++)
' D5 g3 D" B. D6 z, M3 a+ N d[k++]=c[q];
$ Y2 o' I& D4 N% k}
7 z2 u2 z# R/ z" n+ w7 J4 p/ O& E8 V! Q f3 i. I( F C! p
template <class T>! I+ S% M, ?* t! d8 p+ z" g
void MergePass(T *x,T *y,int s,int n)
" z) w9 k4 k7 }, m! F* B6 D8 a2 i{1 k" O x5 h& ^( q, C; a [: J% R
int i=0;( |8 j- t5 Z& U8 F3 x
while(i<=n-2*s), P+ X+ L' N: T- P2 p2 S0 j
{( N- ^5 N" D$ W2 l! p" \
Merge(x,y,i,i+s-1,i+2*s-1);
9 T1 J& B1 I( f" g i=i+2*s;, S& I* A4 z) z5 r) c7 ?6 v
}
' U; u1 n, s7 H5 M# W if (i+s<n) Merge(x,y,i,i+s-1,n-1);- {5 p; J! J% v, v7 k
else for(int j=i;j<=n-1;j++)
2 _3 G7 k* [4 O y[j]=x[j];
3 U7 Z( P2 O) L1 s9 g}; v! c& X' a! O# c' X
" F0 G' }4 ^% Q4 D, X& J4 T1 j7 |% J# B% s3 `
% P# `6 v. B# E' T
template <class T>& f3 O) R, ^0 a
void MergeSort(T *a,int n)
9 {9 h2 @' y9 d, S! g2 A& Q{$ `* K- c0 }- U/ f, G. k$ Y9 |
T * b = new T[n];% \3 [4 l8 b6 d3 P. M8 {9 m
int s=1;
; x( O+ W& w& X1 x8 @$ K- e: u while (s<n)
. k. s6 {3 M% c7 ^% z. t7 i$ l+ m+ V {
2 k P3 J. x0 V& ^ MergePass(a,b,s,n);
\5 g# L: I6 n: F" F D s+=s;
+ F8 R+ q3 x, k( ~ MergePass(b,a,s,n);
. K& `7 E# ~$ f+ V( @+ X) c8 H! Z s+=s;' i3 I$ x' L7 O5 M
}# Y" N5 B8 |0 y, Y' G5 L3 U6 R' G
}
J8 B/ Y6 N2 u0 [6 b. [0 @7 |+ Z# W' o5 y5 ?" D7 O1 T5 J: a
//==============二分查找算法==================8 I9 f% ~4 S9 j. D7 p
template <class T>
8 f! n: R' ^9 S% z) kint BinarySearch(T *a, const T & x,int n)! E5 ^% u9 G7 }4 K
{//在a[0]<=a[1]<= ... <=a[n-1]中搜索x,找到返回其位置，否则返回-1
" q' X/ a$ ^- _% P o int left=0;int right=n-1;
. Q9 |) M5 s: j0 U4 ] while(left <=right) A$ ]. \+ j7 l7 _
{" u% K9 F2 _8 u( v* U1 g1 S
int middle=(left+right)/2;
* ~5 s9 q3 g2 Y: }+ \/ g2 u7 q$ f& J if(x == a[middle]) return middle;
( d( A6 t2 b4 U- C( h# G/ s" |) y6 w* D if(x > a[middle]) 8 W {- ?: O7 _+ k d- }5 B
left=middle+1;1 }8 T3 G+ r( z9 @) w" G
else
& Z, W, |- U; ? right=middle-1;. Z r$ e7 Q' f# R% _! k- m% _; O/ C
}
6 G- z! y0 `9 k return -1;//未找到x
+ l; z9 @; r6 N}2 G9 E( } H# C+ h2 b
3 s* J( ^, v3 p0 e* x2 z, _
0 d) t% P: a( |: {3 C7 z1 H//=========判断两个集合相等的蒙特卡罗算法==============
7 n8 D6 y1 Y& Kbool Equal(int *S,int *T,int n) i5 z% E$ X! s) ?. |& e# A8 z
{//判断两个集合相等的蒙特卡罗算法- q" t) R, c4 \% ?6 w" S
static RandomNumber rnd;
* L/ D' k) E: s6 o( j int i= rnd.Random(n); //从集合T中随机选择一个元素，判断它是否在集合S中，' H) g* z, q# e& D/ U" f
// cout << T <<endl;
+ l1 ]8 u: B$ x+ w) ]; ]4 W$ u if (BinarySearch(S,T,n)==-1) return false; //不在,返回false,即集合不相等* j# C3 D; j$ z: w" a6 V, L( E
return true; //在,返回true，即集合相等
" Q) Q3 a& _0 R}4 x6 a1 E( C+ [' B* T
: z* D9 z h4 V( y( V: ebool EqualMC(int *S,int *T,int n,double e) S/ M+ M/ ?1 v
{//重复多次调用算法Equal,确保错误率小于e3 O2 i* B) U" c" q
int k= int(ceil(log(e)/log(double(n-1)/double(n))));6 W8 M- V- x, y) q- \; S
// cout <<"k="<< k<<endl;- x1 C: H1 a6 k6 q' H+ G$ \
for(int i=1;i<=k;i++)# w2 p6 z# r: M6 Z# B
{
, k% {" M, B% j1 `4 ^// cout <<i<<" -> ";8 M- ~0 H9 X+ w3 B8 G6 p
if (!Equal(S,T,n))
7 g' w" M; j4 w: T, o, y: R {
& U1 U) y0 A8 f$ L: L# K1 n// cout <<i<<endl;+ b, O# T: V1 w/ y4 a$ z! q! \+ F
return false;
) `( T' k0 T7 h5 _( [6 I9 b8 W }) |4 o, i# I4 v* P p) ]) r% o2 Y6 u+ r
}) R8 E, n, D2 }+ i8 P9 B' `& t
return true;
- S7 \0 R2 I r1 d& L} [2 f5 e5 y' X( L4 Z0 R E: ?
int main()
6 A8 D6 o/ P$ _# s8 X/ k& n" Y7 q{
% _+ m- ^ x0 s3 s1 e" H int n; //集合的元素的个数; ?) L! V# `9 d" t: T4 T9 P1 V
int * S,*T; //待比较的两个集合
' k) `4 ?* E) A+ k int i;
{ c- F9 k N: A& y" y4 n9 T/ a1 E
ifstream InFile("input.txt",ios::nocreate); //读取input.txt
# C$ f9 a6 D' b' {6 S" n; |# `4 g& K* \4 D5 i0 J( n/ `
if(InFile.fail()) //读取文件失败8 @! F7 S( f, v# ?
{/ F# }. [1 T6 w/ M8 p% P
cout<<"the input.txt is not exist!"<<endl;
7 T. N8 v" a, R3 W return(1);' e. O) X0 Q; x) U4 d/ v1 a
}! t) K2 J6 t9 \7 b0 c" E) `
InFile >> n ; //集合的元素的个数
+ ~/ l" F3 r4 h, F: l S=new int [n];
( \* c; l6 k$ q8 E! V for( i=0; i<n; i++) InFile >> S; //集合S的各元素
1 L: v. ^8 q% v# L T=new int [n];
7 U5 S5 W4 B1 A3 y for( i=0; i<n; i++) InFile >> T; //集合T的各元素* n& S: {& \/ | d) J* ]8 b3 |
, F: d1 m. T; j$ W0 s InFile.close();
# M& l5 d3 g% l$ P" x
5 O1 ]7 [( U o) W% @% f //将集合S的元素进行排序预处理$ e7 ^: ^- ~* Z5 E# E2 M
MergeSort(S,n);& E; O9 ^1 _8 `# O2 ~& o
& f* p2 |+ {# ^. f. b9 h //cout <<"OK Sort"<<endl;- s+ k" b+ ^ p+ J* j
// for (i=0;i<n;i++) cout<<S<<" ";: ?# @( S2 Y+ ?
// cout <<endl;; y. r7 ~8 Q$ L& D0 a: j/ f
/ j5 K1 w7 a p. o `& |///*
5 |6 J3 q$ Q1 U. [/ I$ G3 d ofstream OutFile("output.txt");8 f, |: e: j- o* G
double e=0.001; //错误的概率
, t3 ^5 ]" z) ^! f9 E8 `/ g if (EqualMC(S,T,n,e))
; {( V$ ~; E( I: S5 ~" I2 p OutFile <<"YES";
% w9 C3 f9 t5 c' ]8 m8 v5 y else8 D$ I8 X8 |6 ?$ M9 h+ F: ~
OutFile <<"NO";& I2 @0 W$ M, B: E; p# U# c
delete []S;
5 W; D6 {2 ^; p1 D delete []T;( T2 A. d8 g" O+ m
return 0;) S0 s# I, k' A9 b. T' K- M! c
//*/
8 V5 V0 a1 T: n Y& W5 V7 l) }. m4 |. { \; _2 ~( i0 n; o
/*
. k" z6 l. T% A/ W6 |# ~5 U//=========测试用，连续判断m次，看得到的结果正确的次数和错误的次数
- \8 r# X3 @/ ?' i" n' O8 d, C int a=0,b=0,m=1;" Q6 u7 \- z' P" ?
doub集合相等的蒙特卡罗算法
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| | 发表日期：2006年1月12日 已经有66位读者读过此文 | |
#include<iostream.h>
4 P7 h7 S# ^1 _! b#include<fstream.h>. [- r2 }( `7 r- S
#include<math.h>+ C+ R& M( M: r1 x5 A
#include<time.h>
% \+ z4 K T, [
6 y3 a+ H, A# `; i. l7 T$ B//============随机数类=================# ^( b4 y& |0 @, Y/ T
const unsigned long maxshort=65536L;
( I" g; O0 E8 q) i7 j! jconst unsigned long multiplier=1194211693L;
* w: K) R% l# B' s4 F. Y2 {const unsigned long adder=12345L;# W6 q2 h8 p1 }6 a
/ [# O2 u. g6 @class RandomNumber
/ o$ F3 c5 m. [/ v* ?. _/ s/ V{
' |8 s+ ~# ~/ S' ` private:" n% A6 [6 v0 D# ]' j
unsigned long randSeed; //当前种子
& l) \; r. w( g* a% Q public: }/ S* N, S$ K1 T* {+ D: c
RandomNumber(unsigned long s=0); //构造函数，缺省值0表示有系统自动产生种子
; a1 D8 d4 M" C/ t unsigned short Random(unsigned long n); //产生0:n-1之间的随机整数
" m* K* P v( D9 `9 B* [" d double fRandom(void); //产生[0，1)之间的随机实数
: L5 w8 R/ ?+ i, D9 [+ G( u f0 I};6 @9 M! T% m$ D6 ?" S
9 z+ b- b: I+ y! e6 zRandomNumber::RandomNumber(unsigned long s)' ~1 \; @8 e" h
{//产生种子* ]3 Q& O( ?2 Z- _
if(s==0)
* n/ s ^' M! L9 _ randSeed=time(0); //用系统时间产生种子
" p8 K" k9 F7 f* l else- S+ `+ E! r- D j: s* z
randSeed=s; //由用户提供种子
+ }% a7 ]6 V$ K2 B}. u2 _/ N7 H9 d# i" l
. M x Z) Q+ a& s6 Uunsigned short RandomNumber::Random(unsigned long n)# x% V( N8 C# x: B+ A4 y" ~9 J8 @* c
{//产生0:n-1之间的随机整数 l. s$ h# ?1 [# f; `+ }4 s
randSeed = multiplier * randSeed + adder;( u; G/ @. l4 a$ p8 ]
return(unsigned short)((randSeed>>16) % n);
$ R8 ^3 W- m& n2 L+ h: ]9 `* e}
% k' J5 S+ N7 E- l9 g
) u2 C9 Q/ c( Rdouble RandomNumber::fRandom(void)
/ A1 y0 x' B: A0 l+ o. L+ F{//产生[0，1)之间的随机实数( D4 B3 g7 v4 r% a
return Random(maxshort)/double(maxshort);
; \# @# f& c8 N1 F9 @}0 m6 _9 v1 R* r! z+ a
//===================================================& i d1 x8 n4 D1 e- a
' S( R/ w9 b# O2 X2 R3 J3 W/ O( V( L* `9 e: _! }& w
//=============合并排序算法====================
# v1 i, `; e- ]0 H; wtemplate <class T>
M: j3 z; g7 r% w) j4 dvoid Merge(T *c,T *d,int l,int m,int r)
8 N$ l8 o. |0 M* }; N& k) e- r{3 ~' v9 A- S4 U: R* A
int i=l,
( H* y% n `- u0 R4 C% f$ I j=m+1,$ L3 ?1 X2 g& e* f' r3 ?
k=l;7 K" }5 _. X4 k0 c( Q! A c
while((i<=m)&&(j<=r)); M! z8 g! A# l( Q$ ^3 {' i; e
if (c <=c[j]) d[k++]=c[i++];. I# U3 Q. [2 d l, c. s' G
else d[k++]=c[j++];
. K, ~( G; b$ h. W4 W if(i>m) for (int q=j;q<=r;q++)
+ w( o: A% E8 z: l- m4 q% W+ ] T" n d[k++]=c[q];! V* A0 H1 g* c2 n
else for(int q=i;q<=m;q++)& s9 k" l# r8 c( K4 o# x7 j
d[k++]=c[q];
, ~. }/ x% H6 B! d ]}$ N C9 i- W2 v4 t: T
' c+ a; G6 Z) r4 x% u
template <class T>
% ~- ?9 ~* O5 `; hvoid MergePass(T *x,T *y,int s,int n)0 D0 n1 \+ ?( g+ G* F. V
{
' @$ l5 A$ S& V0 O% }( P0 Q0 } int i=0;
2 {1 E4 U# x+ z& H$ } while(i<=n-2*s)
, f! V7 x( D0 W- ?3 N" Z {1 X' d8 {1 i7 Q8 r& z' @6 a4 n
Merge(x,y,i,i+s-1,i+2*s-1);
! W. e5 J2 T' N3 {* ? i=i+2*s;
; r8 |( _1 O9 d* j9 c; O, d. ^* P) r/ e }, y# i5 A. b( f- s# D9 b! M5 t
if (i+s<n) Merge(x,y,i,i+s-1,n-1);) q# Z3 A# U( Z. n9 F
else for(int j=i;j<=n-1;j++)
& l8 r) Q8 H, b, W7 ` y[j]=x[j];# ^# D) R6 v; p6 V7 P& t0 j
}, {8 \/ O- q! ]! M7 p
. ~+ s9 T# P5 `/ ?5 Y. v" s( R: I$ L4 y5 p5 }* h, w; V1 n- m
9 b7 w3 b) \' ftemplate <class T>) H& L2 V8 R3 o1 ~" g6 z& o
void MergeSort(T *a,int n)8 t4 j( S6 _) @! w
{
7 k" }& v0 p: L T * b = new T[n];
" n' @- B1 C' X# V3 ` int s=1;
% N) r. s; Q; p$ k while (s<n)
1 g" [) i/ A1 x9 I {
Q$ o$ v# }; F9 R, S MergePass(a,b,s,n);) B8 ~) d* {/ O" g4 K
s+=s;
1 I6 W9 A; D1 \# \4 f4 R9 D MergePass(b,a,s,n);6 M7 v/ \+ e/ b
s+=s;# U% a7 D; {! O7 Y9 A7 o& X9 u0 `8 E
}. }: e* G" C% ]. F% U; w( V0 K) d
}# L, x6 z1 ^9 b) x- P; [# s
: I+ B2 |3 M6 W! ~& X
//==============二分查找算法==================, x; a% D9 P) I7 o
template <class T>
# c8 P$ Q" h. Aint BinarySearch(T *a, const T & x,int n)/ j9 I' ]9 p/ c; x. t
{//在a[0]<=a[1]<= ... <=a[n-1]中搜索x,找到返回其位置，否则返回-1
- @, i/ T3 [' G, x2 R0 O int left=0;int right=n-1;
E0 C, a0 {7 N, w3 ~' y" ^9 N, q while(left <=right)
/ D( r2 e9 ~+ U3 ]$ `0 ~7 X {& u3 {4 |0 H4 m4 I
int middle=(left+right)/2;4 H! ]) E, T; m2 \' V4 t3 Y
if(x == a[middle]) return middle;
( H, ~/ s5 Y* z0 \+ ~1 p& X if(x > a[middle]) $ z0 N) d# k6 @
left=middle+1;% T$ H/ G# l, ^7 h& k% A" J
else
]+ S7 q, }' T1 u2 ` [ right=middle-1;
$ ~# _% ]" M/ N2 `2 R" G, H% D }
Y5 i7 V e8 B. C6 w5 i* x return -1;//未找到x/ \6 v2 y; D. ~5 G
}
5 l7 o) u, J/ `6 C' x
& f3 _' p; J T$ X1 r
* }! L+ w% o1 z) e/ H- }//=========判断两个集合相等的蒙特卡罗算法==============
3 j6 J; H5 M2 Obool Equal(int *S,int *T,int n)
j( {- k5 ^7 {, h3 i" K{//判断两个集合相等的蒙特卡罗算法
( K4 ^! J7 C c static RandomNumber rnd;4 P2 u1 A& K3 W
int i= rnd.Random(n); //从集合T中随机选择一个元素，判断它是否在集合S中，
+ W N3 e9 H/ O, A// cout << T <<endl; 4 O5 B: s' z: Y1 \; S
if (BinarySearch(S,T,n)==-1) return false; //不在,返回false,即集合不相等
1 Y0 \5 C% V/ Y% i return true; //在,返回true，即集合相等$ q0 u( e1 e% r8 |) q5 ]
}
( X! ]2 {; v' B7 C z( p4 ~: |1 s$ z1 N% q8 M1 b4 T/ J" C
bool EqualMC(int *S,int *T,int n,double e)# `% y: E& V/ F* f/ N6 z/ d
{//重复多次调用算法Equal,确保错误率小于e* O# w* @* W/ }# I5 M s# P
int k= int(ceil(log(e)/log(double(n-1)/double(n))));1 L# p2 r) T- m6 v+ n0 S
// cout <<"k="<< k<<endl;
/ G- M4 M" X; }* O- h- i for(int i=1;i<=k;i++)
' c2 l. Y$ x0 o- w) V$ B {6 Z3 h4 o( z" U+ G, p0 K' S
// cout <<i<<" -> ";
+ @/ e% J" P1 A$ G, E if (!Equal(S,T,n))
" e4 t& `( x8 Z7 \* X8 [2 z7 g {) F8 F$ Y! i4 t) o9 Q+ W* Q
// cout <<i<<endl;+ d& v# U, X% W
return false;6 t) U; C$ ?% K
}: t( \% a$ q% X1 b
}/ o" X3 m, f7 [6 Q+ g
return true;5 w% ~" D4 Z( a2 b* p0 k
}
* B) Z9 H; u# O* v/ r ?9 V& uint main()
6 r( G, r& x1 m6 H3 p7 d{
* j- p3 C3 j6 b; P$ p int n; //集合的元素的个数
# ^& O, ?" v5 C# } int * S,*T; //待比较的两个集合
( H7 \- L7 U+ P V4 f int i;
7 Z1 f/ C. i$ L; j' E o
- b7 z' V. _( d# X k& a ifstream InFile("input.txt",ios::nocreate); //读取input.txt
6 l E. Q; N1 \, g9 H& i3 \
' g2 W3 s) e% V+ f if(InFile.fail()) //读取文件失败
! w+ D; F% h3 q% L3 z0 V {$ v, |1 D# v/ A9 R
cout<<"the input.txt is not exist!"<<endl;& ?2 j- l1 V. ~0 `8 i) R$ \5 \2 Y
return(1);; z$ V" ]8 V& q) M J: |, e
}
3 \. w) S/ e- J8 q/ ^+ p* ^ InFile >> n ; //集合的元素的个数( S! u o/ T% e6 k
S=new int [n];4 E. c, f. N l4 `9 |
for( i=0; i<n; i++) InFile >> S; //集合S的各元素
* b" x$ k- b1 {+ P2 X4 { T=new int [n];. B# T! k& W0 t2 a4 o9 ?( {
for( i=0; i<n; i++) InFile >> T; //集合T的各元素
4 e; o1 N7 U$ m. a" y) w1 P" H3 q R
InFile.close();/ o9 F& ~. I6 k+ ~, N _+ _
& o6 ]) V, v6 f v" a; m
//将集合S的元素进行排序预处理& M) \! M1 }8 e
MergeSort(S,n);3 d* G' q( D0 J( E& A) v
: s6 N1 n ]" s8 o( x, c
//cout <<"OK Sort"<<endl;
2 v( `) U1 E" r& Y4 F9 A |// for (i=0;i<n;i++) cout<<S<<" ";% o% o# s7 p# t, ]5 C7 R j- i
// cout <<endl;
' m6 ?. a9 y O( C) ?! F5 f1 a" o' |1 M F! L! A3 c+ O: ]
///* ( J* W* f6 A: \; N: s3 t
ofstream OutFile("output.txt");1 m, U2 l/ r4 U# n. E" S
double e=0.001; //错误的概率& b e3 u& [- ^9 w' J+ C9 j
if (EqualMC(S,T,n,e)), M' S# q3 s/ p, @9 \
OutFile <<"YES";
% V# O3 G% e3 T" u. t0 Z6 F else
2 I1 l6 e; t. u8 K/ t+ | OutFile <<"NO";
1 j4 I* \2 @* } f delete []S;
0 Y' N! y, T F n0 q6 Z0 P4 } delete []T;! V4 L3 y; Q% e, G, Y
return 0;
' V% ^2 I# i% T1 J3 Z. E% C//*/
4 O! b; x- e" T9 T" G- [% I7 j+ L' P/ ^, j
/*
4 o" Q9 P; r3 B- z* q! L//=========测试用，连续判断m次，看得到的结果正确的次数和错误的次数; R/ b- j, D/ ~" b( d
int a=0,b=0,m=1;
- ?6 N$ j' R) [$ e double e=0.01;+ C8 `) Q; g8 a7 ^3 a
for(i=1;i<=m;i++)6 `6 M, w. B5 }# ~# R
{6 `" k, i' P, _4 E: y% i
if (EqualMC(S,T,n,e))& i4 W3 {0 o+ D" W
a++;$ \2 r6 J1 @3 Z
else
# @2 a) s* j% W3 ? b++;
3 y& v6 p0 X0 P$ d# v# ` }1 q r7 y9 @1 H& I+ m9 I0 X' |
cout <<"Yes " <<a<<endl;7 ~; g$ G* a2 R$ ?$ j F
cout <<"NO " <<b<<endl;/ n) h+ l9 S0 r8 T# f
//==============================================================
- J3 G: K9 @3 G' |& n6 h6 y*/' o" ]# @ F `' b: B, G- S" j4 h6 |( {
R% H q* J# v3 B) W! M- O
/*
. ^3 j l# x8 l//==========产生测试用数据===================
& c1 B! Q# b8 x0 o0 b ofstream OutFile("input.txt");; i& a& _1 u& z9 g0 Z* p: q
n=10000;( u% u( u& A2 k1 c! W
OutFile<< n<<endl;
% W( X6 y0 T1 f: @6 A for( i= 0 ;i<n;i++) OutFile<< i<<" ";$ e% ] x! }6 O% G' _
OutFile<<endl;
/ z U% k9 Q/ Q* h/ F for( i= 0 ;i<n;i++) OutFile<< i<<" ";& K( J2 {; g$ t2 H) c# c
OutFile<<endl;3 h# [# `+ h1 l
//========================================= ] K1 }; E( y' \( K
*/# i7 ]. [6 f+ c: j+ z) H
: w9 C5 j0 h$ d/ _2 E}# O" B" C) }2 u# K" R5 f( n% v
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le e=0.01; G0 {; X# q" X) z- {" r
for(i=1;i<=m;i++)
3 [# ]7 ?9 c2 v% F2 }# `, v% b7 ~' z {
$ h- w& l6 g, C# g if (EqualMC(S,T,n,e)) @1 w- @, [, x, K* a
a++;8 @' `* V) H+ @1 q( M$ p p' S
else H4 C' h G( r/ b
b++;
" W* V G1 W3 J. X1 v( f }
' T! T; ?& h! q# w0 o6 H, g cout <<"Yes " <<a<<endl;% j1 p+ J5 o R
cout <<"NO " <<b<<endl;# z' v& M% G6 ^* v& Q+ g5 ^
//============================================================== + X$ y$ ~1 h- H& w% d
*/
: S# h8 G. A* ?: i( W1 c% h7 A& n
' Q/ K, E( V: n9 i6 k1 g/*+ W/ d+ H; O* k M9 c% |/ {/ w
//==========产生测试用数据===================' F2 J9 f! Y* s% ^3 w1 g* }4 P
ofstream OutFile("input.txt");
5 I& Q& [* _2 X# R( b, q n=10000;
# i0 i: {" H: ^6 P" [# ~ OutFile<< n<<endl;
( }! F" R) d* q for( i= 0 ;i<n;i++) OutFile<< i<<" ";
: R$ W' d7 W8 ]4 y OutFile<<endl; d1 V1 @1 a \
for( i= 0 ;i<n;i++) OutFile<< i<<" ";0 ?* @2 i( i* [/ m1 n) R+ r5 ^, g
OutFile<<endl;9 d% b* ~: P1 U- Z7 d8 j
//=========================================9 V- ^! i$ |, w2 T) `
*/' X7 Q3 M# l3 f9 h B$ `2 j" x
# H: c6 Z2 _) Z/ @7 t& f* w}
- e. h, Y# `% A% F
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