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标题: 函数大全(a开头) [打印本页]

作者: 韩冰    时间: 2004-10-4 03:03
标题: 函数大全(a开头)
< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(a开头)</FONT></B></FONT></P>
& [) r0 J! C$ i" A* d# T<><FONT color=#ff0000>函数名: abort </FONT>  D. O1 G& ]7 L' B  G; z2 g
功 能: 异常终止一个进程
& d( W. W+ b8 e* C$ D用 法: void abort(void);
3 e/ P" L- C" `1 ?程序例:
7 a2 c) R& g, J6 W! g1 r' \<FONT color=#0000ff>#include <STDIO.H>6 Y3 d* _0 t5 X) T; E
#include <STDLIB.H></FONT></P>0 p' N# E) n) W! [* @+ ~0 }$ Z* u
<><FONT color=#0000ff>int main(void)
3 S4 C: Q0 x$ n  B% S+ d9 T$ M{ ; G0 _5 X/ g- j; p, S0 F
printf("Calling abort()\n"); % [( m7 q: y( ?. j( P+ ^
abort();
! R. u5 J2 |  D  A* ~5 h" W  u. zreturn 0; /* This is never reached */
0 z6 W! s0 ^9 b. \1 f2 A1 J} 5 O; N: N: C6 z7 w
</FONT>
0 B6 Q" W: a2 Y" H</P>1 J; [" a$ l- h  k  k! o; @
<><FONT color=#ff0000>函数名: abs </FONT>
# }4 |# R; P6 D; O$ l  {; x功 能: 求整数的绝对值
( c) n" r' ]/ P* l. X5 c& h用 法: int abs(int i);
( U+ C7 U& Z3 Z' b; Y6 T程序例:
! i) ?8 a- V, I: N- t3 [<FONT color=#0000ff>#include <STDIO.H>
* b/ L8 k9 R  ]$ g+ q! Z& j#include <MATH.H></FONT></P>
# u) [  Y' L9 e6 D+ q9 Z$ Q<><FONT color=#0000ff>int main(void) 5 C/ i9 g5 P! h5 I# e' Y) e- P7 z! Y
{
  h8 S  ~% t  d4 i; S9 c  Wint number = -1234; </FONT></P>+ `- K8 Z3 u2 ^, S" w
<><FONT color=#0000ff>printf("number: %d absolute value: %d\n", number, abs(number)); 5 D% J% B: M+ Q" n* z( u
return 0; ' g3 S. O3 C  r3 I6 Z. E1 e$ d" {
}
- c+ W) `! s) r7 z" x% S" ]5 z% S/ S) \</FONT>
2 W1 F7 |& u: Z</P>
$ C) u& ]! ^$ i7 u<><FONT color=#ff0000>函数名: absread, abswirte </FONT>% C: D8 `, X; u
功 能: 绝对磁盘扇区读、写数据 6 V1 k5 a% j# @8 f8 A4 u
用 法: int absread(int drive, int nsects, int sectno, void *buffer); 8 c5 j" C2 J  Q- @
int abswrite(int drive, int nsects, in tsectno, void *buffer);
/ u+ x+ h0 W% t: |( h$ B程序例:
3 E0 h5 V% t# n3 }% W/ e<FONT color=#0000ff>/* absread example */ </FONT></P># c" h4 C0 ?) \8 V. k  }; f( N
<><FONT color=#0000ff>#include <STDIO.H>
3 A- A8 k' z) }; Y: M# d$ z#include <CONIO.H>
  L2 r* D' q3 r1 z, {' x7 y#include <ROCESS.H>
5 B9 T; G- @0 |! |5 W8 L#include <DOS.H></FONT></P># d2 p4 h' ~" ]: S- B) r
<><FONT color=#0000ff>int main(void) * S- y4 R2 \, E2 |' ~  I6 S3 K
{
& \* ~6 P$ ]7 b0 o8 o. uint i, strt, ch_out, sector; / P/ C/ V. u6 P0 ?% H
char buf[512]; </FONT></P>3 O8 H! `7 u* O7 P* i
<><FONT color=#0000ff>printf("Insert a diskette into drive A and press any key\n"); + @+ {9 \) b, n/ C7 U/ [+ M+ `
getch(); % p$ i8 T) K0 H& i, v
sector = 0; 7 u2 R& D6 x" `
if (absread(0, 1, sector, &amp;buf) != 0)
: i. X" U9 C1 `% V! R% ]8 L{
  i9 V$ T' I% \! mperror("Disk problem"); 8 G) g- S% s$ W* j. }
exit(1);
( I2 |5 r' ]/ r( b3 E} 6 m/ C' Z3 C; ?: q+ c
printf("Read OK\n");
) o& x) G: {8 E2 }4 C/ Ostrt = 3;
& P' V" e8 M" {( |. w% ]% Lfor (i=0; i&lt;80; i++)
+ W, [9 ^# H2 l- z  M/ f! z; {{ ( |5 ~2 K( [  w3 t* Z+ k6 ~" G
ch_out = buf[strt+i]; 4 A( J$ K# l. N+ N
putchar(ch_out); 9 j% J+ W& _$ T& V* N8 p5 f) b+ t
}
* d# H8 i* s7 Qprintf("\n"); 5 |, p7 q9 h, T+ S# k# |
return(0); ) [& f: I! W  F% N' w$ h- V7 Y
}
& m6 H- y/ t5 j; H. x& `% F  X4 a. w: h7 A</FONT>$ D* j% _: M+ J( k3 `

/ Y8 \2 m! I9 D; R, [</P>4 C9 I3 y! R/ v3 @$ n; I
<><FONT color=#ff0000>函数名: access </FONT>
1 p: ~6 i9 K3 x" B. m功 能: 确定文件的访问权限 3 t. o5 G. K: c' U
用 法: int access(const char *filename, int amode);
; q4 C. D  a7 v0 y9 X* G- \- A/ E" Z) P, r程序例: : x) O2 u$ r4 p# o
<FONT color=#0000ff>#include <STDIO.H># U. `- x: G) `, E7 e' |
#include <IO.H></FONT></P>
) q2 Z! Y4 h) }  T" H7 Z+ ~<><FONT color=#0000ff>int file_exists(char *filename); </FONT></P>, v8 t) {+ `, m" f3 z5 ~9 ?
<><FONT color=#0000ff>int main(void) 8 W6 S* v  t" ^- |& \) R. y, k
{
$ I- J" o* D0 v+ ]( m) R; dprintf("Does NOTEXIST.FIL exist: %s\n",
! w: _  Z1 M  D" ?' Gfile_exists("NOTEXISTS.FIL") ? "YES" : "NO"); - }; ~4 o: L$ o- o  a. F* R
return 0; # r$ i' j  B5 K. e
} </FONT></P>
' F( N( l* k: ~2 x# B<><FONT color=#0000ff>int file_exists(char *filename)
1 r: }! u$ N5 m) C. h{ : j% m4 W/ J. S; X$ o
return (access(filename, 0) == 0); & Q1 ]: A* M& b! i8 {( ?
} - B+ O* \2 C' e3 [4 `9 J
</FONT></P>; K2 w- y$ r4 ^* u3 \9 [) F  g1 H
<><FONT color=#ff0000>函数名: acos </FONT>
1 P/ S2 U. c3 @; J功 能: 反余弦函数
  P8 q: b5 _* [9 o3 @1 k5 w用 法: double acos(double x); ; }0 e  t) `* j; k3 N% l
程序例: : l' f4 P$ S- Z9 Y# p- ~& C
<FONT color=#0000ff>#include <STDIO.H>' G& `& t4 ^8 w$ n6 r" P0 I
#include <MATH.H></FONT></P>
6 F' l/ M- ~: N% t. C<><FONT color=#0000ff>int main(void) 1 e$ M9 K0 F; W$ x4 R: E
{ & S4 Y, t4 t* `% r
double result; , P& _: K0 @3 U- }
double x = 0.5; </FONT></P>
# d( ^* x2 n) U* H8 B1 h<><FONT color=#0000ff>result = acos(x);
6 e3 b- c6 _  l8 |4 A  Eprintf("The arc cosine of %lf is %lf\n", x, result); $ h! i7 B* x  e: z, `2 e
return 0; 1 \( ~; d+ O8 K# b+ y% l
} </FONT>
/ s, |) u% N: }' y) [# w2 B$ g8 l" ^( n1 p: e; o
</P>
% h* g- v& y6 K% A) D7 L<><FONT color=#ff0000>函数名: allocmem </FONT>
  f3 c- ^) @( {. x. x2 R: o功 能: 分配DOS存储段 # l9 N2 _) h$ y& l9 Z/ }0 G
用 法: int allocmem(unsigned size, unsigned *seg);
1 u2 W" O4 F6 Y- X. H/ i9 A程序例:
# j9 w6 K* z+ Z# ?+ `7 M<FONT color=#0000ff>#include <DOS.H>; p6 o( W$ ?  d/ G4 N- D- ?
#include <ALLOC.H>
& i7 I  T9 \; T- a7 e8 y! u#include <STDIO.H></FONT></P>! a8 f% }& q" f2 y+ l' W) A
<><FONT color=#0000ff>int main(void)
4 o4 r' Y, T$ A: Q{ + ~* L7 G3 x" ^9 X5 K+ a
unsigned int size, segp;
% [0 a; |$ v' \8 z9 x9 D' g7 sint stat; </FONT></P>( l- b/ v6 }+ g
<><FONT color=#0000ff>size = 64; /* (64 x 16) = 1024 bytes */
9 c6 i6 v* p1 b* K2 b& G/ ]* x' [# Rstat = allocmem(size, &amp;segp);
* s$ a! Y) C  J; {if (stat == -1) 5 w4 a- D0 ?3 x* I( v- |# u. ]
printf("Allocated memory at segment: %x\n", segp);
5 |1 h3 M0 ]& k; Oelse 4 x8 o& x  h: H1 d( Z+ `2 Y, A
printf("Failed: maximum number of paragraphs available is %u\n",
$ w( |8 n1 h; R6 ]stat); </FONT></P>
6 A- q/ w8 k# k% t' F6 _<><FONT color=#0000ff>return 0; 0 |3 J% a! I  u4 ]5 _/ N3 i
} </FONT>& l% T  H5 d- g
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</P>& T6 z' @9 @0 X8 ?
<><FONT color=#ff0000>函数名: arc</FONT>
; G( s3 ~3 i+ e7 N8 Q! P- `  t2 N功 能: 画一弧线 ' A) K5 z: B2 A0 b
用 法: void far arc(int x, int y, int stangle, int endangle, int radius); & \8 z2 R+ X- f, d. ?
程序例:
) ?  p3 j4 E! s! F8 r. _& J6 d<FONT color=#0000ff>#include <GRAPHICS.H>
' @( }! L8 E+ h5 z; Q5 f#include <STDLIB.H>! |: [9 @' b. t9 }0 g
#include <STDIO.H>
7 @: A  C6 b( I' I" s) O#include <CONIO.H></FONT></P>5 Y8 r% B% Q4 [* @
<><FONT color=#0000ff>int main(void) 2 z0 A$ ?' }' B9 d. q7 g0 P6 ?
{
/ [* ~8 V" O! t  v$ |8 ]/* request auto detection */ 7 i4 M3 {! k6 X( Y+ l! }# O0 Z8 [
int gdriver = DETECT, gmode, errorcode;
3 T9 O1 F8 K7 u! P  k. Iint midx, midy;
5 N, O8 d! E3 k' H& ?- s6 D- t1 P$ Tint stangle = 45, endangle = 135; 7 B0 h4 H: l3 g) c- J7 |
int radius = 100; </FONT></P>2 ^' V" g3 S0 m1 ^  J2 v
<><FONT color=#0000ff>/* initialize graphics and local variables */
# [, \  n, i4 l" h1 B( u1 xinitgraph(&amp;gdriver, &amp;gmode, ""); </FONT></P>. ]8 |* m; u$ h( I; ^' t4 J
<><FONT color=#0000ff>/* read result of initialization */
' p, e/ n# K- m% Verrorcode = graphresult(); /* an error occurred */ 9 J- O0 D6 K& n& q" R4 h$ `
if (errorcode != grOk)
, x' U2 E2 O/ y7 p# T1 Z{ 8 Y) G2 c* R. F" \3 M( }
printf("Graphics error: %s\n", grapherrormsg(errorcode));
/ e) E6 a5 r- q1 m0 B# [printf("ress any key to halt:");
1 y: i% \' R6 c6 ~getch(); </FONT></P>
) r/ c( H! z( {<><FONT color=#0000ff>exit(1); /* terminate with an error code */
8 w+ ^0 m0 |$ e% J" @( q} </FONT></P># X. A1 G# Y: e0 Z. W) U- g7 t7 j
<><FONT color=#0000ff>midx = getmaxx() / 2;
" W+ `, c9 b; D$ umidy = getmaxy() / 2;
4 p; F$ ~" T" v0 |0 c5 S! h( \setcolor(getmaxcolor()); </FONT></P>
& p1 ~0 _, _+ v<><FONT color=#0000ff>/* draw arc */
& C8 m7 Y6 e' Rarc(midx, midy, stangle, endangle, radius); </FONT></P>
1 V9 z* H5 D6 X1 E5 _0 k<P><FONT color=#0000ff>/* clean up */ , U( X, \& B2 Y. g: \: f- G% @) f
getch(); " f6 f# {$ P  t$ w1 _
closegraph();
2 U/ E! r; P/ U0 `% R6 d% breturn 0; * S2 {0 ?* m/ e8 ~
}
* `$ b. [# W7 z. l! g. ]6 `. V% v</FONT>
! ^% T4 {7 m6 E( S$ q5 w</P>
7 S. E7 t' E3 G' \1 {<P><FONT color=#ff0000>函数名: asctime </FONT>: y9 Z0 w: c' E7 l9 d* k# m
功 能: 转换日期和时间为ASCII码
- k% w" `0 D& i用 法: char *asctime(const struct tm *tblock); ' R5 Q* v/ I; u- A# j! P# i
程序例:
) m+ d! c9 s/ |' G1 M! n<FONT color=#0000ff>#include <STDIO.H>& ~. T, B+ b: {( M9 F8 v/ {8 G
#include <STRING.H>
, w8 y! k- c% z6 e* a; Q9 F3 j  c#include <TIME.H></FONT></P>
# L, z& F3 U- S' E7 Q5 q7 b2 v3 K3 ~) \<P><FONT color=#0000ff>int main(void)
0 y) @! [" Y3 K5 V" A/ `: \{
4 B: ^, D" v  k! [1 hstruct tm t;
) g8 F: ~7 }- f& K) m8 Schar str[80]; </FONT></P>
; L1 }0 ?/ S; e9 L  D<P><FONT color=#0000ff>/* sample loading of tm structure */ </FONT></P>
& x3 V% b  W6 Y<P><FONT color=#0000ff>t.tm_sec = 1; /* Seconds */   Q6 g8 e0 \: [& x% S$ f
t.tm_min = 30; /* Minutes */
$ T) ?7 ~+ \+ \- Et.tm_hour = 9; /* Hour */
. E+ S( ^1 R7 D; n( \5 vt.tm_mday = 22; /* Day of the Month */
) Z( N: F- c: F' e# P& gt.tm_mon = 11; /* Month */
/ w0 f0 P$ R5 R$ I- qt.tm_year = 56; /* Year - does not include century */
/ |- x) A( G# @" o, q: u- |9 O& Lt.tm_wday = 4; /* Day of the week */
. y* ]/ ]+ B$ i  T' B1 ]# B* V6 U$ yt.tm_yday = 0; /* Does not show in asctime */
: }  g  C7 g- B3 Z% Kt.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */ </FONT></P>2 z6 V! L' l% |2 u4 K' O2 C
<P><FONT color=#0000ff>/* converts structure to null terminated
- \9 Q+ P2 h, t4 y, v: m& vstring */ </FONT></P>/ o! j) p/ p7 k0 F+ L: t( i
<P><FONT color=#0000ff>strcpy(str, asctime(&amp;t)); + i, S0 j7 P" d
printf("%s\n", str); </FONT></P>
' |  `/ D, ?* k<P><FONT color=#0000ff>return 0;
* i; b& ^2 y. J5 p. U9 S) o} 2 M0 s% K+ N% v& P- |4 v  ^

' }% j. x# f- E8 ]2 e5 P</FONT>
) J$ l, L1 @2 D3 n. ]' C</P>$ D* q  `, D" r; `6 a# z
<P><FONT color=#ff0000>函数名: asin </FONT>
% U) s' k: A' V* u" R3 u+ K" q2 K功 能: 反正弦函数
. b6 H9 a+ @2 D/ u* _! X+ f用 法: double asin(double x);
6 N. x1 O0 l3 v. v9 }5 K程序例:
1 u3 ^, ]5 j7 d5 f<FONT color=#0000ff>#include <STDIO.H>8 J' z7 H3 _, p# `
#include <MATH.H></FONT></P>/ a* A/ c* y# S( q
<P><FONT color=#0000ff>int main(void)
/ Q# q1 d5 C9 ?- ], F{
4 k, w  q9 K" r3 P5 ]0 }double result;
) a- n$ K. q" mdouble x = 0.5; </FONT></P>( ^; }" K* n) }. G2 i
<P><FONT color=#0000ff>result = asin(x); 3 H3 f  t, h0 A- J9 U
printf("The arc sin of %lf is %lf\n", x, result); 8 Q$ i0 T1 g+ M  ]0 l, u# J% |
return(0);
! y$ s/ O1 [# R! [}
- I' k: Z" E8 @7 x. e2 D$ ?. @</FONT>
; p# ?! A6 J% W& o4 b% y' b* ?, [5 h  s9 a" W
</P>( q, g. L! ?4 P8 v
<P><FONT color=#ff0000>函数名: assert </FONT>& k+ ^3 g" [5 M) Y! u) h! Q$ z, k7 M
功 能: 测试一个条件并可能使程序终止
; k! W0 u. t; O, q; U, }1 f/ J: s用 法: void assert(int test);
2 M8 [$ V, Q8 j7 T5 `- E, [  U程序例:
1 A+ H3 a+ _0 H# d<FONT color=#0000ff>#include <ASSERT.H>5 O1 ?' ^5 o* Q! R9 s
#include <STDIO.H>8 S# v/ V# P5 f/ G3 R9 S
#include <STDLIB.H></FONT></P>
2 t+ W  C$ x; v& R# Y) m! @/ \<P><FONT color=#0000ff>struct ITEM { " K# j0 p% v; y6 O, v4 c, ?
int key;
% _' J, A5 p: l* D# P0 a$ u. xint value; : B7 o1 V) _3 n2 `4 U% R4 P
}; </FONT></P>
2 {2 q/ N/ T: c2 W; Q" F! L: A& V<P><FONT color=#0000ff>/* add item to list, make sure list is not null */
3 j3 `/ x" @1 K/ H7 b' L. M, pvoid additem(struct ITEM *itemptr) { ) I: M. Z& |5 u8 Y* K/ _, }
assert(itemptr != NULL);
' _2 V% ~( O$ f& w$ y/* add item to list */ , G6 i: c0 M0 W3 A- O' ?; U% b
} </FONT></P>9 O, F" f! P) m, e
<P><FONT color=#0000ff>int main(void)
4 M  [4 I0 f* I* {7 o* @$ a" I{
: \7 E4 I) N* y% B2 zadditem(NULL); 2 T. L3 F& K% p- M
return 0;
3 u+ e' N. B& l  H}
9 j! B7 U% U, r4 M  Q</FONT>
2 q' X3 p1 F3 q/ g$ n$ P! B5 U" ~
8 x0 U$ J) k/ Z' a" F& p</P>: v# E! V# U  [$ q
<P><FONT color=#ff0000>函数名: atan </FONT>1 b3 u$ u) _! f7 A  B
功 能: 反正切函数
& r+ b1 ?" P) N6 |6 k9 Z# r用 法: double atan(double x); % E0 S, E! k; ?) s6 D
程序例:
/ a# @7 P  S) m3 d- B4 g& y5 `7 T0 i<FONT color=#0000ff>#include <STDIO.H>
, x. m7 O" i* a6 ]#include <MATH.H></FONT></P>4 d0 Z% @+ |* @* T) F  {
<P><FONT color=#0000ff>int main(void) . ?8 c7 l0 {( k4 ^7 ^0 u" h2 p
{ ( t- x5 g- B% `; B% q
double result; ) @, A! p' X" \; d  X6 H
double x = 0.5; </FONT></P>: }+ J2 p( C9 K( @# l0 r9 x4 h
<P><FONT color=#0000ff>result = atan(x);
  m5 S2 i- N0 z/ [7 Bprintf("The arc tangent of %lf is %lf\n", x, result);
+ ^) ?; B' p4 x$ B1 Preturn(0); 7 u8 K) w) }/ K
}
3 K* _8 _1 S8 D  F) E' j; d6 q8 v</FONT>
& T  X: k5 r3 X0 M- e' J</P>: V- U/ U5 B$ K+ \6 P0 s4 l
<P><FONT color=#ff0000>函数名: atan2 </FONT>
$ S( x6 r, G) ~  l功 能: 计算Y/X的反正切值
% d7 _  q$ d3 a0 Q8 w用 法: double atan2(double y, double x);
: B! D0 t3 C( M, p. K+ X3 t程序例: . w* ?- U4 p/ Q; l
<FONT color=#0000ff>#include <STDIO.H>
/ n, y" s$ ?% B$ Z9 M#include <MATH.H></FONT></P>
5 o4 r8 _+ Q# K6 F<P><FONT color=#0000ff>int main(void)
  a0 ~* f; m/ O+ ?3 k$ W. M) @" h{
' w: P2 p& {+ C7 `  D; W$ ~double result;
9 S+ J9 V6 n5 Fdouble x = 90.0, y = 45.0; </FONT></P>7 `4 {  [+ s# B" _0 m( r9 N
<P><FONT color=#0000ff>result = atan2(y, x); : g; d; C$ D  ]. B8 z
printf("The arc tangent ratio of %lf is %lf\n", (y / x), result);
8 P2 C: B0 ?& P1 P1 Kreturn 0; " o5 y) O) W5 I: T
}   S; S0 P1 J) X: E
</FONT>8 L/ _' Y. k4 J! z3 ~+ K9 n
</P>9 Y1 o/ S9 N( J5 A; T
<P><FONT color=#ff0000>函数名: atexit </FONT>: ?" l+ Q3 H5 k! V5 K  g( P
功 能: 注册终止函数
4 H) Y, F% z- ^用 法: int atexit(atexit_t func);
* b8 P4 @+ ~/ e2 x8 i- F9 }程序例: + q+ ]( y; F) a; w
<FONT color=#0000ff>#include <STDIO.H>6 k5 ^) S" T" L* }1 ]; I' M6 k9 y  B2 Q
#include <STDLIB.H></FONT></P>3 k4 q. \6 }1 X! X
<P><FONT color=#0000ff>void exit_fn1(void)
7 b  [' q6 E4 p5 [{ 4 O$ v% V9 |. w5 i5 r
printf("Exit function #1 called\n");
' w& D; I9 T: Z} </FONT></P>; }5 m' h! r; F8 R) C  q3 o9 k8 ]
<P><FONT color=#0000ff>void exit_fn2(void)
# d; t0 l! h8 j. L2 H  [{ . s0 F1 ~  A9 E
printf("Exit function #2 called\n"); & N4 s5 R1 G, b9 M
} </FONT></P>/ I! m1 a4 P5 w$ \" @
<P><FONT color=#0000ff>int main(void)
4 x, {. a9 M& @; A1 L1 O% i. |{ ; }( O; p5 ]1 @$ d3 H' a
/* post exit function #1 */ 4 u* q+ Q4 v9 l/ x
atexit(exit_fn1); & }8 s: L: ^" A7 a2 m6 o
/* post exit function #2 */ 0 G* t" o  b- e- y* e
atexit(exit_fn2);
2 F) p6 u# o+ ureturn 0;
2 ^+ |6 v" L* }) Q  h7 S9 s2 L! B" f. l} 1 X  F, h& x2 X6 T" _2 j3 f0 y
</FONT>
1 w# @5 C* r5 e6 k9 ]- X& A, I" h9 ?: ^( R  Y+ N1 Z8 Q
</P>
2 V2 T) u' X! R' l8 c8 \<P><FONT color=#ff0000>函数名: atof </FONT>6 C" p6 D9 o! n. p1 R
功 能: 把字符串转换成浮点数 + B/ \9 z$ ?/ s8 F+ y$ w
用 法: double atof(const char *nptr); ) Y  q  h* _1 V1 Z8 R) ~
程序例: 2 Y' B& G6 ^& I2 S0 {
<FONT color=#0000ff>#include <STDLIB.H>
" g5 z( r1 K4 \5 h( ]7 G#include <STDIO.H></FONT></P>
5 D! T$ h# Y: [+ L  {5 Z( H4 C- ~0 f8 R<P><FONT color=#0000ff>int main(void) 2 v7 F2 j4 L" X% P
{
, ]" L. t3 t; R: Q. cfloat f; . x' B% w# |6 b
char *str = "12345.67"; </FONT></P>
# L1 W+ u( Q: j" j<P><FONT color=#0000ff>f = atof(str);
- y7 I+ L! \1 B- G. J2 iprintf("string = %s float = %f\n", str, f);
8 k8 @" {! q$ \, oreturn 0;
7 W% u  P+ K( s4 o} ' q- u$ _# u' d/ ?8 K1 C6 C* y
</FONT>; l  ]0 L# q' M2 F) i" m( }
</P>! \4 W$ G6 X9 x$ A8 m/ \( b7 ?
<P><FONT color=#ff0000>函数名: atoi </FONT>
5 t7 k% p# Y* U功 能: 把字符串转换成长整型数
7 Q4 {. H; _, v4 O用 法: int atoi(const char *nptr); $ C# V/ U* y# C+ w  u, \% e+ T4 I
程序例:
' K) |  z, b5 p<FONT color=#0000ff>#include <STDLIB.H>+ b9 ]" K5 P% ~# X
#include <STDIO.H></FONT></P>6 b- V1 Z6 L" l8 y6 ?. K2 V
<P><FONT color=#0000ff>int main(void) & S  T" R4 [% {5 R. B* I3 X1 j. B7 _
{
$ I, e+ r5 r9 s# s4 _7 c- n1 Oint n;
: a$ L/ m# f% K1 ?& j* g& [2 D1 jchar *str = "12345.67"; </FONT></P>
& Q0 k# ]/ ]" y" s' p<P><FONT color=#0000ff>n = atoi(str);   f" h7 n& u" z5 k
printf("string = %s integer = %d\n", str, n);   j- F0 a8 g3 X
return 0; 7 L% j" W3 u9 @9 m) y
}
' v6 \: W5 d, B! V: q</FONT>
+ I& Y7 g* i9 i; U" ]0 Q: \</P>. ~2 B9 }! u) @& {- n
<P><FONT color=#ff0000>函数名: atol </FONT>
7 v+ r# h- n6 ?功 能: 把字符串转换成长整型数
) C' J8 M- c" [$ N" b- O8 p9 T用 法: long atol(const char *nptr);
$ ~- G' m  D! f  d5 y程序例: </P>
( ^4 I' s" M6 y2 K$ t( }<P><FONT color=#0000ff>#include <STDLIB.H>
. j8 F  ]1 N2 [6 k' P8 Z#include <STDIO.H></FONT></P>, F% L& h) q- E2 G0 H/ j
<P><FONT color=#0000ff>int main(void) ( O# j. e( H* ]) T# W9 x
{ 7 @2 T+ L) z8 Y& d9 S
long l;
7 j/ ?9 }) Z8 g' t* }  Qchar *str = "98765432"; </FONT></P># r% v6 }5 o8 F  E
<P><FONT color=#0000ff>l = atol(lstr); : o5 \# k$ d0 V
printf("string = %s integer = %ld\n", str, l);
0 o5 P* s* }$ Yreturn(0);
# G) N0 P* e7 Z# R1 L! z5 w8 {}</FONT></P>




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