新手跪求指导

heugaodie

r = 3.04042*10^(-6);
' R: w  }- T; y# A5 _0 X' S  ap[x_] := x^5 - (2 + r) x^4 + (1 + 2 r) x^3 - (1 - r) x^2 +
  2 (1 - r) x + r - 1
q[x_] := p[x] - 2 r*x^2;
/ N) d1 t* z, Qa0 = 0.5; b0 = 1.5; delta = 10^(-6); k0 = 100;
a = a0; b = b0;
& D1 m) L3 s. U$ C6 SDo[x = (a + b)/2;
) [) ]. t5 W7 r( b" s4 T If[p[x] == 0, Break[], If[N[p[x]*p[b]] < 0, a = x, b = x]];
If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
4 |! F/ P) y. X, H- y" X. Ox1 = x
- x0 L2 r! l2 qClear[x]
) s0 ~3 [9 K9 HDo[x = (a + b)/2;
* p; v, u5 z8 f# ?0 R If[q[x] == 0, Break[], If[N[q[x]*q[b]] < 0, a = x, b = x]];
If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
x2 = x
Clear[x]

" D9 |$ C" I. n" T' a& V3 [9 |我想让p q 两函数的解都求出来 每次都是两个一样的解（是第一个的）  明明用了clear的 怎么做
; d& C; F% f: P; ?) e; E

qudazi

你试一下将Clear[x]换成x=.看看

花如梦

别只用x,换个变量试试

小小灰

看不懂，看不懂