Lingo建模语言与实例4

longde

目标与约束段
$ i6 {4 a1 X6 U8 i3 O! H集合段（SETS    ENDSETS）
数据段（DATA   ENDDATA）
! q% w3 \( ?. g" s) ~, f初始段（INIT  ENDINIT）
) N" ~# K3 D5 b3 _（计算段 (CALC ENDCALC)）
& e2 z' i5 W& v1 x+ lMODEL:
. Q. X: ]) i( ?$ ?7 A% T% JTitle Location Problem;
sets:
  B. z  K* V" \# }0 ]    demand/1..6/:a,b,d;
7 ?2 w8 }5 @$ Y: z2 k% j+ s( U    supply/1..2/:x,y,e;
5 r. t! ^4 ^! ?" q. o& R8 D6 ?. O    link(demand,supply):c;
endsets
data:
a=1.25,8.75,0.5,5.75,3,7.25;
b=1.25,0.75,4.75,5,6.5,7.75;
# Q3 N6 [" b5 X$ od=3,5,4,7,6,11; e=20,20;
enddata
init:
x,y=5,1,2,7;
0 v6 k* v9 E' k& S3 t% f; ?endinit
min=@sum(link(i,j):c(i,j)*((x(j)-a(i))^2+(y(j)-b(i))^2)^(1/2));
@for(demand(i)sum(supply(j):c(i,j))=d(i););
+ l6 N- x. [) N5 }; ]@for(supply(i)sum(demand(j):c(j,i))<=e(i););
END

longde

好
" y6 a* ?1 {* U+ F9 L" H, w