数学建模社区-数学中国
标题:
极限测试之Matlab与Forcal真实演练
[打印本页]
作者:
forcal
时间:
2011-8-4 08:15
标题:
极限测试之Matlab与Forcal真实演练
首先要说明的是本测试系列,除了比较编译效率外,其余所有运行效率的比较都是将matlab的首次运行排出在外,因matlab程序首次运行效率较低。理论上,Forcal程序任意次运行效率都是一样的。不过话又说回来,任意程序包含的函数,有些是需要多次运行的,而有些仅运行一次,甚至一次都不运行,故matlab函数首次运行效率较低应该是一个缺点。但如果说,matlab函数首次运行会对函数进行优化,以后运行效率会显著提高,则matlab函数首次运行效率较低就成了一个优点。
6 p. n4 H0 }4 K: K1 S. z0 |1 d. C
5 n y: L& V( X% S( ]: n& s4 Q, @
=============
1 E. |" C( v7 x9 K* z
& L( ?/ S/ f b* A! g6 K/ g p
本次演练要用matlab和Forcal实现两个实用函数并进行测试。当然,对脚本来说,这些函数用C/C++或Fortran来实现应是脚本的最佳选择。
9 S) l% h# O( R' W3 e4 J$ \
+ [# P9 K0 W; v+ q- m4 W
=============
: T; U/ X4 Q5 G" v4 w
, O s$ W# E3 C9 V% l0 j. G
1、求解实系数方程组的全选主元高斯消去法:包含大量数组元素存取操作
% d1 y* J g: f* s; D( \
, ]1 [" V0 N, w
C/C++代码:
#include "stdafx.h"
2 z: |- _; l0 d
#include <stdio.h>
8 H+ u2 ^, {9 y
#include <stdlib.h>
+ y3 L, u) `. d2 g& @5 V
#include "time.h"
. k$ E2 W6 J' Q2 E. X
#include "math.h"
5 P7 l: v6 a& _; @% B1 y: ]
# O# [4 F9 u6 H! M5 m! c! x. [
int agaus(double *a,double *b,int n)
1 H- r* W6 L; J; T
{
1 _3 f. ], K5 ^* ~% h
int *js,l,k,i,j,is,p,q;
0 x1 N/ Y6 K) f1 B8 n& T0 f" [
double d,t;
# S; c) h/ ~2 M. n: \% k( y8 M
js=new int[n];
" {1 L1 q- j$ C- M: I4 a
l=1;
) b! B% j! d; u. N( {7 G7 m
for (k=0;k<=n-2;k++)
+ R. `& y! {% e% v
{
s) } |2 | l9 T v; w5 y2 M: H! o" O
d=0.0;
: U# M; r) M1 D5 n& C2 M( C0 x# U
for (i=k;i<=n-1;i++)
" i: v8 z+ I" Y- c( @) r
{
2 \, n! S5 B3 @2 T3 `% h
for (j=k;j<=n-1;j++)
3 q2 C' s! c" R! m9 w, o- i
{
' l0 }+ T$ M/ F
t=fabs(a[i*n+j]);
' p1 ]; L6 l2 i
if (t>d) { d=t; js[k]=j; is=i;}
# F! g7 o+ d7 U0 L6 e. A. L' c/ N R
}
# Y; D: g& `) s& Y3 ]4 y
}
2 V0 e) T# q. N1 b8 @ c# G @5 B
if (d+1.0==1.0)
, Y0 i' P) I8 a* p' G( v9 o4 A
{
3 m$ ~6 ]& k% [" _0 I
l=0;
3 }* ?( O Z; S2 ?1 x1 U$ O5 T
}
* n. q. y; K7 ?% Z, T1 L
else
% W; z3 q7 n- K% I0 ]( w/ }! m
{
7 X& \% T$ e5 d& _
if (js[k]!=k)
2 B+ r; ]& c0 v# ?" N
{
6 D9 w* c9 U& v
for (i=0;i<=n-1;i++)
$ F: b. ?. Z/ k
{
9 c7 J& U# }+ W8 b
p=i*n+k; q=i*n+js[k];
: v4 {% y" c6 A; U( q
t=a[p]; a[p]=a[q]; a[q]=t;
7 R+ @1 _! W/ k! c: {5 j& q
}
' J3 v4 f% L6 f
}
' q, M5 |4 \; A7 e! b$ X
if (is!=k)
( |: y9 }7 a9 H6 [) `
{
7 |1 S& f! V7 \: t
for (j=k;j<=n-1;j++)
/ Y- s9 R! w: R/ H
{
. c$ P7 n2 y3 {& `) S' _
p=k*n+j; q=is*n+j;
) \; d. N- k$ _& C6 ~
t=a[p]; a[p]=a[q]; a[q]=t;
7 E8 G( f' {- j% b
}
1 B v* y7 i8 p. j
t=b[k]; b[k]=b[is]; b[is]=t;
5 i: x1 w8 d) j* C. y
}
* u, O( M1 b: [ T, r9 _( @
}
* K/ d6 Z' d' B$ u8 A4 k# L
if (l==0)
1 J% I6 s% D) s4 o* F `
{
3 C, D, b, j% U+ C* Y
delete[] js; printf("fail\n");
) T; p' J! {& Z) |; G% _# l! R- @$ F* u1 q
return(0);
/ {# o8 n: ?# e
}
0 Z4 v& P/ n# j2 n/ L
d=a[k*n+k];
0 l; Q# e7 Y8 r& Z
for (j=k+1;j<=n-1;j++)
/ ?& s S3 q0 j5 B1 \& u
{
9 c; ?! `1 \7 k. K, s, `) F% s
p=k*n+j; a[p]=a[p]/d;
4 T: `; @! n. p/ E, R9 t0 w( j4 D
}
, G+ w, {$ g& l8 U
b[k]=b[k]/d;
5 ~, F: f A$ ]: i; j* e( e
for (i=k+1;i<=n-1;i++)
w4 Y: B$ @- l
{
1 v0 Z8 K _ [6 K
for (j=k+1;j<=n-1;j++)
9 e4 F# F9 a$ W$ U7 d8 f. m
{
5 u q4 [/ V3 F$ q- u
p=i*n+j;
: b6 v9 ^/ ?' {0 u0 P/ P
a[p]=a[p]-a[i*n+k]*a[k*n+j];
* g$ b, U( m3 P/ R
}
# H/ ?: x$ h+ N0 I6 T' n% _
b[i]=b[i]-a[i*n+k]*b[k];
- G% M4 ^8 c3 T8 f' b
}
$ ?3 b9 M( G5 K) k7 q
}
+ P' N3 F: ^- q, X
d=a[(n-1)*n+n-1];
' h U# Y/ |% D- E$ M* O
if (fabs(d)+1.0==1.0)
/ n: S8 ]# F2 f h" ]; g6 \# T
{
: c# ], e- Z* {3 K
delete[] js; printf("fail\n");
/ N2 ^8 C& R) E# u& T N5 k7 V/ \0 t
return(0);
$ ]5 i- C+ I A9 F; Z4 \9 a4 t0 K' v
}
' y+ p4 W/ O6 ]3 ?, n2 ^8 x/ u# @$ |
b[n-1]=b[n-1]/d;
3 `0 I! z9 @ S6 t+ z, o. y3 A6 o6 p' i5 R
for (i=n-2;i>=0;i--)
5 V0 G3 n8 w) H& l
{
, r- Q# e+ }, W" n4 R- T: A- v
t=0.0;
+ W. U9 z. D5 F1 N
for (j=i+1;j<=n-1;j++)
" d. I' ^& {3 C) o( \; b4 U* X
{
- }1 Y, F; W1 f- U5 W0 `: g/ B3 B
t=t+a[i*n+j]*b[j];
% S* ^) M/ a, \$ Q6 b, B) O' c
}
. u* j( s4 A5 q
b[i]=b[i]-t;
! o$ {2 k! k8 U
}
2 L) u6 _+ x, e+ p- q
js[n-1]=n-1;
2 U1 p- j5 `- x
for (k=n-1;k>=0;k--)
( |: k8 g7 Y7 Y5 w
{
+ m! S/ R; G/ [! K& w
if (js[k]!=k)
( V( e5 d! K0 X* \. L2 M+ R; \
{
9 ?6 B( @* T7 T( _! F i
t=b[k]; b[k]=b[js[k]]; b[js[k]]=t;
6 C, I! k! E" Q) u8 \! E
}
2 o- a a" p% `6 C: _
}
, ]) v2 R0 ?$ H
delete[] js;
0 I) A+ k6 i' u! B
return(1);
5 v# u5 } b. e7 l
}
x% @9 e, x, v( H- p( P- u9 E0 e
$ a! {( |- g0 [1 x. c/ P& v) g
) J! ?8 P4 p# r5 R' R
int main(int argc, char *argv[])
% i3 z3 C+ G& \4 `0 _/ z
{
! J5 |" w0 o/ e1 b% `8 U
int i,j,k;
! y" f9 T0 W. p6 g+ O
double a[4][4]=
' I; M# F$ y5 M
{ {0.2368,0.2471,0.2568,1.2671},
% ]. ]( j6 g( ~: v/ Z* M( R
{0.1968,0.2071,1.2168,0.2271},
8 P$ Y2 \8 N; q G
{0.1581,1.1675,0.1768,0.1871},
4 X0 ~2 @/ e- V5 `1 d
{1.1161,0.1254,0.1397,0.1490} };
4 u1 l$ R# z* v0 V- _ Y" H
double b[4]={1.8471,1.7471,1.6471,1.5471};
& M+ x2 f2 t. x$ a4 y. M
double aa[4][4],bb[4];
$ w0 l' k4 A# J ^ L
clock_t tm;
" [/ T( x0 {' ?3 y2 E
. x: A+ [. w3 P% Y+ D( g! c
tm=clock();
! K. J% A4 R) U2 n- }, M( l% j, w
for(i=0;i<10000;i++)
& n) o4 s5 x b& t) t6 W% t8 B
{
' |- P. h$ H" j) }
for(j=0;j<4;j++)
+ ~" q3 f; `8 I( S, Q* ~
{
% U( c g; ` D. Y; {
for(k=0;k<4;k++)
& \* N5 B, g9 ?8 p- b9 @
{
3 D" a+ k0 P* X0 f
aa[j][k]=a[j][k];
) x, L! p8 l, M5 V6 E
}
& W; ?8 y- F0 A' z9 h9 G0 U8 ?' n
}
% K$ a1 R* t9 w$ m7 b5 m
for(j=0;j<4;j++)
% m1 g; I9 W; ~* j& }
{
( Y7 \1 V$ v+ A9 v% v" r: P' ^
bb[j]=b[j];
7 B- ^; C- d) I
}
2 \- t& u0 x: K6 ?3 I
agaus((double *)aa,bb,4);
+ i+ S% E: Q( ]$ N5 L
}
1 q2 Y% Z9 k% t% p
printf("循环 %d 次, 耗时 %d 毫秒。\n", i,(clock()-tm));
% u; p: F( k! N2 \
3 z# f o5 K/ g3 E& {
for (i=0;i<=3;i++)
' y" R7 y1 Z; ?/ N' G3 ~# V
{
; d+ x. _9 z; |! D
printf("x(%d)=%e\n",i,bb[i]);
' B5 v+ R: f: V: R3 c
}
0 X" W3 Z* [& n6 s& M
}
复制代码
结果:
; n2 n: b- Y) E) s9 m
循环 10000 次, 耗时 31 毫秒。
. D" e- Y: Q3 F8 L
x(0)=1.040577e+000
3 s$ _, {0 n B; p6 b
x(1)=9.870508e-001
& ^ O$ l- u' y2 {/ G# N8 b
x(2)=9.350403e-001
2 q# {. O' X/ ?" W
x(3)=8.812823e-001
6 J8 D F8 D) p) ~ E1 j3 Z
6 G3 f; @& `+ u* T- i( f
---------
" G/ {* X l- e i) a8 b' h7 l& A
& k! u8 H0 }# U9 q7 ^; _
matlab 2009a代码:
%file agaus.m
; \( e7 U4 o8 r$ }( Y% I8 Z
function c=agaus(a,b,n)
0 `! i& ]: I" `( b, V
js=linspace(0,0,n);
. T' h& M! H1 N" O1 W/ N
l=1;
/ M" s! ]6 v h" ~0 b4 j
for k=1:n-1
" [2 @# e& {. T1 ~; ~. c
d=0.0;
- w% u: f ?- {4 _+ w) T
for i=k:n
- } f7 d) g, g$ i9 k8 C
for j=k:n
5 L- D4 t. q: ~" w4 j
t=abs(a(i,j));
2 j) u3 P0 u* k) o& r. B6 H2 ]
if (t>d)
5 V5 e! n( O0 p+ B4 H; J3 g, t) ~+ \: M
d=t; js(k)=j; is=i;
`2 z9 [- X- q9 l
end
3 E5 D, P) c6 E9 W
end
; M6 _( L8 V6 l0 w6 L# Z5 N
end
3 V4 ?+ F* w/ C( s$ F1 r. y
if d+1.0==1.0
7 ?$ P4 V3 i1 y0 ^/ R" \
l=0;
4 Y7 r5 G" T* |
else
' e8 r& X# e2 C/ ~! z: U6 i$ S
if js(k)~=k
( I2 x6 V% f0 b9 H5 _% j
for i=1:n
6 v+ o% @: I) R( i0 A% M
t=a(i,k); a(i,k)=a(i,js(k)); a(i,js(k))=t;
7 S, P" Y& T/ E4 r# x9 o
end
1 B0 H1 X. l1 P" V1 a' X' t
end
9 t' \2 a# `- v/ G5 u
if is~=k
, l$ ^% ]) W) _4 z& J' H; ]
for j=k:n
5 [9 Y. `$ I9 z k2 k
t=a(k,j); a(k,j)=a(is,j); a(is,j)=t;
0 I4 q1 b2 j9 ~2 y
end
4 y* y( m! j `" L
t=b(k); b(k)=b(is); b(is)=t;
9 s! M' d8 K) C! ]
end
: A4 ~9 x) U' Z# r% @0 ]5 y
end
0 c% R. K* q& `& L" {% d% U
if l==0
# k- F: D( D& s4 R* R1 |* s
printf('fail\n');
% l8 S* r* ?" v
c=[];
/ g3 t9 N- I6 l; k- ?, H
return;
3 x. Z2 ~: g/ {! ]" J
end
. A* P9 r6 ?' w( S, t# Q
d=a(k,k);
/ y$ @+ }- l' {6 W" [
for j=k+1:n
: @% w6 i2 ^1 M0 ] Y( B8 ?* H2 r
a(k,j)=a(k,j)/d;
& Y% l7 F, S) j8 {) q. u
end
; B; D+ \4 L1 {6 f. S
b(k)=b(k)/d;
* G [) f \4 x7 O c$ R
for i=k+1:n
# c+ A% s: l+ ?, S. N9 `) T7 x8 X3 `
for j=k+1:n
( a6 c, A6 u6 z7 o. V* a5 U0 @
a(i,j)=a(i,j)-a(i,k)*a(k,j);
' L l8 f' A! x2 p! p# @- A
end
9 J7 X7 n) M; W2 P& A6 `- ?
b(i)=b(i)-a(i,k)*b(k);
* E: B& O6 @' b: q: ]
end
6 k' _/ S, ~: C# B( }
end
) d. I% y' k( h/ P# n6 ^+ {) E
d=a(n,n);
# \7 O% n5 U/ X* ]
if abs(d)+1.0==1.0
% k$ j1 e) R; n( z+ e" [. _
printf('fail\n');
; n6 J& d- Y3 W; l
c=[];
4 Z u' f! R' V$ t1 p5 z+ ?- w0 X
return;
0 @1 P- r, q" J7 h5 H
end
9 i9 g1 f1 `* P* X) w _- C
b(n)=b(n)/d;
5 T4 ` t% N K) O
for i=n-1:-1:1
$ Y/ F. f i6 s; F* h
t=0.0;
* t% y* K s- O Z7 o7 \
for j=i+1:n
8 o& X- H) E% m7 d0 @0 D( Z
t=t+a(i,j)*b(j);
2 r* `0 q' u' Q3 O4 h1 P! G
end
4 @4 K$ l2 V! f6 h8 }0 D
b(i)=b(i)-t;
+ ~% L1 @- w! s, O, P
end
0 F3 T* Z/ ^; {; F( B$ B
js(n)=n;
$ M: B# M/ ~0 `
for k=n:-1:1
9 S) v& J9 h" K
if js(k)~=k
. Q7 U) ~; W$ v) ]) E: Y8 y
t=b(k); b(k)=b(js(k)); b(js(k))=t;
7 C; ~' h! [) k( H! H
end
0 C' s( x9 N7 a' o# v' S# i: F; G" ?4 L
end
r6 S' h5 q) F- j0 Z3 k! |, I
c=b;
6 ^ o$ B/ i( l% I' t0 ^
return;
) L3 j; Z7 s3 L0 G! t3 ^7 n* V3 i/ y
end
3 t8 L( C8 A2 Z/ n
M4 t; c, i; B+ ~* e
a=[0.2368,0.2471,0.2568,1.2671;
+ L5 l6 V* J+ u* {" ~
0.1968,0.2071,1.2168,0.2271;
6 X7 U7 C u. y# D/ `
0.1581,1.1675,0.1768,0.1871;
9 {- D$ {; D% _
1.1161,0.1254,0.1397,0.1490] ;
, B1 _& N0 R- z& {
b=[ 1.8471,1.7471,1.6471,1.5471];
( J- f$ W+ O6 c, p& y, p+ N
9 Y. T+ f/ f$ i/ N* `
tic
3 h! Z% e0 n% I2 F
for i=1:10000
% e% p8 v' Q @7 P3 l: e
c=agaus(a,b,4);
/ A, v0 s8 V5 e6 i
end
: D' d5 a0 z7 _
c
* J' l% n3 E: r( [& I
toc
. ]9 t+ |5 P- ]" V
' h! l% Q0 t+ G
c =
0 L$ k7 E# p8 [* H
9 ^( u; j7 m8 q
1.0406 0.9871 0.9350 0.8813
7 m8 b9 O9 {. E( H$ ^
+ v5 X+ a4 ^' f% \/ ~& l) Y
Elapsed time is 0.762713 seconds.
复制代码
----------
/ _: ]2 `0 C6 F* C8 `5 a: ?
* i+ W+ \+ h& |
Forcal代码:
!using["math","sys"];
& }+ [, s" {' x
agaus(a,b,n : js,l,k,i,j,is, d,t)=
) M5 B+ q' h2 G4 R4 q# d
{
) X' N& b, s( ~+ ~
oo{ js=array(n)},
, N; G# Q2 o7 n; \, ~
l=1, k=0,
$ r0 W# w; |# w0 q2 U
while{ k<n-1,
$ u: z4 r* c7 x. ~% W. D
d=0.0, i=k,
/ }6 q" @2 h) q5 n: W G
while{ i<n,
7 @. j$ y5 G2 p7 G$ O/ ~- Y( b
j=k, while{j<n,
e7 v; M8 j0 |4 j9 N" O
t=abs(a[i,j]),
9 l9 j. D9 b+ N' p) C% t
if{t>d, d=t, js[k]=j, is=i},
" O4 i! u% o# ^2 X8 Q! o
j++
4 C5 W. E* t, P, V" ]
},
% `1 w3 O9 Y1 C! }0 Y8 l; l5 w6 t8 M( ~
i++
# }* y' x- G" B& W- B1 k
},
9 D) G7 Z' I. g! z
which{ d+1.0==1.0, l=0,
4 |; |- L, P8 y; e2 p0 r
{ if{ (js[k]!=k),
: B# C+ |. y9 C
i=0, while{i<n,
( @) i) T7 o) A
t=a[i,k], a[i,k]=a[i,js[k]], a[i,js[k]]=t,
& E1 m1 L: @( O% k: Y2 x9 b
i++
R( o5 E% t2 Y E1 I: v; K% N
}
% c+ \5 O% a) H
},
' \1 j: \! ?8 s8 d( ?* E: v- o
if{ (is!=k),
8 t9 M5 d! d. B& ^$ j
j=k, while{j<n,
4 V5 D0 D, |4 J, f% r; K/ J
t=a[k,j], a[k,j]=a[is,j], a[is,j]=t,
% H* R2 \, G) i4 U9 k2 q8 ]+ M
j++
8 `6 ]3 @) I8 L6 U' x9 r! h
},
5 H! j' v; u$ |; ~' t
t=b[k], b[k]=b[is], b[is]=t
: o" q$ N2 M8 P) e: ^' V2 @) s @5 j
}
/ Q0 t2 W1 z" G
}
: B; i2 T. ^/ q- Q3 J
},
$ r$ ^# y' s. m, j
if{ (l==0),
) |7 j9 p: l% |- U
printff("fail\r\n"),
3 f) }$ {2 P" D: F
return(0)
+ z4 `7 \7 E8 g$ j9 i! K
},
+ e/ G7 j# ~3 B. u
d=a[k,k],
+ T; v$ u, \7 G- G/ r N. T" l, w# f
j=k+1, while {j<n, a[k,j]=a[k,j]/d, j++},
+ X% J4 ]1 ^ J% E! y) Z
b[k]=b[k]/d,
7 _4 ]6 o U" v! h6 F
i=k+1, while {i<n,
8 W' F* n: ]" N" z5 B6 v4 P; I Y
j=k+1, while{j<n,
# o+ }3 F/ J! H4 r+ {8 b* C: q4 }
a[i,j]=a[i,j]-a[i,k]*a[k,j],
0 z% |# ^/ V( x' w. A0 |& l
j++
8 g( E& x" b! n; X) Y( v
},
* I9 S5 \6 V4 E: K; ^
b[i]=b[i]-a[i,k]*b[k],
' b1 q- Y5 j( q" p, P
i++
. Y+ i& r) F" \/ u
},
: O! Z$ m- t) _9 P* Y. `5 X& r
k++
- j0 c7 A8 f, L( \4 W# I& \6 j
},
9 V% g! ~, _+ m2 ]+ b9 q ?
d=a[(n-1),n-1],
+ n) B" X4 c5 u$ z/ E
if{ abs(d)+1.0==1.0,
, P; j' L: t$ B9 j
printff("fail\r\n"),
) H0 J& C, D9 A1 _1 V' F
return(0)
' e7 h) S w$ c4 I
},
# v) p. w$ n, I. z) S
b[n-1]=b[n-1]/d,
$ X+ w1 |% b- ], P
i=n-2, while{i>=0,
' G( V+ d4 l1 K5 e% L
t=0.0,
9 n9 _- x. a+ F- o
j=i+1, while{j<n, t=t+a[i,j]*b[j], j++},
, A& E! M# i. W. p4 p8 o
b[i]=b[i]-t,
2 H( y0 X3 |0 _& x' D% b# z6 I; i
i--
, C3 j1 N. g0 `% p @
},
/ L4 p7 Q) Q: k; C; g3 { H5 F1 F
js[n-1]=n-1,
1 `7 x$ q3 N$ }) T5 L* i5 a
k=n-1, while{k>=0,
; F4 o1 a9 T7 J1 X% |7 p0 \
if{(js[k]!=k), t=b[k], b[k]=b[js[k]], b[js[k]]=t},
/ Q3 q9 b/ b$ ]) F" v+ I
k--
7 ?) K; l7 s! B, S2 e
},
' b4 c/ a* z+ G- }6 K
return(1)
" B' r) P( s- u
};
. L {6 s- P1 ~# i5 q3 k
* t3 @8 B1 C' T# s7 p: k# l3 E
main(:i,a,b,aa,bb,t0)=
2 a7 z+ b- M: C$ H8 y" H* ^" J
{
6 q+ g( Q& g# Q( }1 N
oo{a=arrayinit{2,4,4 :
# P8 m2 ?4 L* p# ~$ Y
0.2368,0.2471,0.2568,1.2671,
9 u: [, J7 C' G: d" ]& {; i
0.1968,0.2071,1.2168,0.2271,
& T% y" X7 X; E# O6 y/ G# e
0.1581,1.1675,0.1768,0.1871,
# N+ \. c1 |! \; z( W3 X
1.1161,0.1254,0.1397,0.1490},
$ Y5 M7 a- H' T% N
b=arrayinit{1,4 : 1.8471,1.7471,1.6471,1.5471},
" Z/ o. T8 J/ Y7 N8 S( {. T
aa=array[4,4], bb=array[4]
4 S- Y- I0 G0 ? O3 H2 l. C6 I# O, \8 N
},
0 h3 A" I/ z( j" \% r8 w
t0=clock(),
0 @% I e1 ^1 x/ t+ U8 F$ e
i=0, while{i<10000, aa.=a, bb.=b, agaus(aa,bb,4), i++},
) d6 y! |7 U! w( x
outm[bb],
?5 o: z5 v2 C
[clock()-t0]/1000
/ v& m8 h) K( r+ p
};
复制代码
结果:
b/ ?# z8 r% a( T& }/ F9 d6 |
1.04058 0.987051 0.93504 0.881282
4 O% {3 \ z9 U7 `7 E! T! l6 M
$ m$ W, E* @( V# O" s
2.125
7 R! v3 a! J( l3 G; O2 k) Z. l3 w
# X9 b& S9 R" x4 q+ m; I) c
Forcal用函数sys::A()对数组元素进行存取:
!using["math","sys"];
! d1 X4 | A) j
agaus(a,b,n : js,l,k,i,j,is, d,t)=
- c7 w/ b9 ~2 _, h) C
{
% M$ S$ e4 K8 H/ H; i) |
oo{ js=array(n)},
+ o6 p/ @( D, c4 b8 v0 q$ a
l=1, k=0,
+ U$ \& H% l. V) c. \3 G
while{ k<n-1,
0 B ?$ c/ Y( c' ]
d=0.0, i=k,
( u7 _, A8 e' n0 ^$ W
while{ i<n,
: i7 i2 T, r' ~& m6 T
j=k, while{j<n,
+ M$ M! p/ y" N) A& s& `' \
t=abs(A[a,i,j]),
3 d1 k( m4 D. U# X
if{t>d, d=t, A[js,k]=j, is=i},
% M6 r3 J1 L" \/ o
j++
6 M/ D, C" @7 N7 G! |( Z! p' [
},
2 Q, P/ e6 p( ^
i++
# \; G) R* D9 P+ l( U6 W- T( D
},
, c. y4 v% l. G/ N( i0 `3 t
which{ d+1.0==1.0, l=0,
6 b# M# D* e6 \/ I+ Z9 O+ p6 u
{ if{ (A[js,k]!=k),
* v7 i$ G0 G4 E9 t" q
i=0, while{i<n,
2 } w0 e3 P1 B- C
t=A[a,i,k], A[a,i,k]=A[a,i,A[js,k]], A[a,i,A[js,k]]=t,
+ q% `( I, i! H7 @
i++
4 r/ B7 }, j) t) X( E& s' z: s, z! e, R
}
% O, G" ~9 T% I
},
1 y$ w" p6 j) n7 o& R
if{ (is!=k),
- z( u8 U5 ~% g( z4 x3 v6 I
j=k, while{j<n,
9 p' b9 {3 y$ V% v; O
t=A[a,k,j], A[a,k,j]=A[a,is,j], A[a,is,j]=t,
, w! p- v# [. M) r
j++
0 x! }; W" y- d/ D& N! D9 b) C5 ?
},
8 J& J! I# c4 l) G/ q2 J
t=A[b,k], A[b,k]=A[b,is], A[b,is]=t
# a! t* S! I8 a- Q8 i
}
& u& j3 F5 E" ?& |) n# f4 a& U% F+ |
}
8 @5 Y! x W$ j' Z" x6 A! T
},
4 x7 u$ K5 M* J# t$ _7 q
if{ (l==0),
+ J8 `" f6 t+ i6 ]
printff("fail\r\n"),
. P/ n" E8 x5 }, u
return(0)
9 r- z0 R, L% r* Z
},
0 u* @" R& A0 n: q- {/ g& W& h
d=A[a,k,k],
e. ~4 x+ M' c
j=k+1, while {j<n, A[a,k,j]=A[a,k,j]/d, j++},
5 w2 _: V' J8 t4 c
A[b,k]=A[b,k]/d,
8 N% M+ D8 `- s
i=k+1, while {i<n,
+ ~& C0 O4 C! w9 \# A! n2 s
j=k+1, while{j<n,
G% @2 X4 q r3 [2 e# v' Z3 R
A[a,i,j]=A[a,i,j]-A[a,i,k]*A[a,k,j],
2 q3 L- }0 D1 E, d/ b' h7 z
j++
: g" K. Q: H: V: O) H* G5 B& X; m
},
' A6 ~4 F/ l( r; Y9 a
A[b,i]=A[b,i]-A[a,i,k]*A[b,k],
9 `0 X/ m5 ~/ w/ j
i++
3 ]- N+ `% R! q9 B8 ]( Y
},
x& t9 ]" V/ K( D o
k++
. I1 G3 N" b3 b$ K r4 f6 |, ]; O" B
},
1 o- B: y' L3 A- h5 v/ {" u* D
d=A[a,(n-1),n-1],
9 c( {) `+ {- @8 [7 a
if{ abs(d)+1.0==1.0,
6 Q1 \6 _( p6 s
printff("fail\r\n"),
, Z2 {! K" I: N6 u7 h
return(0)
8 R0 z# ]0 v3 X2 Y8 q/ P* |' h
},
8 x2 M. I! R2 @
A[b,n-1]=A[b,n-1]/d,
9 J4 l) W1 y( j$ ~& w m
i=n-2, while{i>=0,
; _2 ^" U/ d! s! Q N6 _
t=0.0,
! c& d1 ]4 n& `, S
j=i+1, while{j<n, t=t+A[a,i,j]*A[b,j], j++},
' v' Z! S1 R2 i: j" ~, o
A[b,i]=A[b,i]-t,
l2 V# i0 {0 Z I8 X) y
i--
0 P- K9 b% V: v& `9 J. x
},
2 ?7 i, H( s" ]5 k1 D. F
A[js,n-1]=n-1,
2 J: @9 c& [1 a: R4 z, l
k=n-1, while{k>=0,
9 [; L$ M2 r0 R( M
if{(A[js,k]!=k), t=A[b,k], A[b,k]=A[b,A[js,k]], A[b,A[js,k]]=t},
! a% h2 D9 N, j* [7 n# E: D
k--
: g. B p* R3 X5 U( o
},
1 C% f0 I% Y* x H/ u+ b; Z
return(1)
& U1 j( F; }" B& g: t. Y, W t
};
" U- Z$ ]& d2 W l
8 P% \2 ` z5 U' h2 t( X6 O8 f
main(:i,a,b,aa,bb,t0)=
! ]& f# X% i7 d0 D M
{
. Z6 }$ K- O3 @2 N6 o8 X
oo{a=arrayinit{2,4,4 :
# J$ v# r; o, W! ^ ^) Y, O @* k- z
0.2368,0.2471,0.2568,1.2671,
/ o6 Q7 A' O6 e% i: Q
0.1968,0.2071,1.2168,0.2271,
" |6 Y4 S5 K/ @: ]% T+ A
0.1581,1.1675,0.1768,0.1871,
6 ?: ~7 ?$ R; b, Z1 U
1.1161,0.1254,0.1397,0.1490},
' X6 [! q& V' k0 x+ s
b=arrayinit{1,4 : 1.8471,1.7471,1.6471,1.5471},
3 F7 _6 V4 M9 y4 N" J
aa=array[4,4], bb=array[4]
. l, L" U2 {& {% [( m- f
},
, T" x/ `+ n6 `$ b
t0=clock(),
" E6 j+ a! U( m1 b$ g
i=0, while{i<10000, aa.=a, bb.=b, agaus(aa,bb,4), i++},
4 v/ G. E" B' F4 [
outm[bb],
( ~: H' f+ s+ ~ {9 Y# ?8 P1 b$ Y' a
[clock()-t0]/1000
9 E/ c# {6 \! F& I
};
复制代码
结果:
$ \' w1 |. g! T1 o# n; F
1.04058 0.987051 0.93504 0.881282
- ]) {5 l* c+ l* h
4 ]$ ]( L; \1 P% u- s
1.454
5 D, m! J1 V" t) s9 ~- |) H
5 b. u) [8 r. N9 b6 U
----------
9 r- i ]& ^3 H4 f# v
8 v4 B* f) a3 B/ S% l
可以看出C/C++、matlab、Forcal耗时之比为 1 :25:68 (Forcal不使用函数sys::A())。
& T; k& Y' u, Q+ H$ N% l( e0 D
可以看出C/C++、matlab、Forcal耗时之比为 1 :25:47 (Forcal使用函数sys::A())。
/ S$ ^8 ?8 ^7 X& M0 o0 e
. ~7 j) H5 f8 m0 H# \& b
本例Forcal耗时较长的原因在于本例程序含有大量的数组元素存取操作。
作者:
forcal
时间:
2011-8-4 08:44
2、变步长辛卜生二重求积法:没有数组元素操作
& ^6 S% ]0 v G h6 l/ R3 `6 K
4 ^0 k8 n/ E% h: |1 ~. X. |
C/C++代码:
#include "stdafx.h"
B- z9 v1 P) v" e7 U
#include <stdio.h>
$ n- a; q* N9 e, |+ P9 t! o2 q
#include <stdlib.h>
6 ?9 ~# r$ Z$ H5 L2 Y
#include "time.h"
% h* j, [/ @0 t9 }! d
#include "math.h"
4 a/ P) E+ D. s8 C7 } T" l
4 o9 j. p8 `5 o8 N0 g8 F9 V% @
double simp1(double x,double eps);
" W9 u/ S% B( S& Q4 V4 \5 P
void fsim2s(double x,double y[]);
! e5 ]4 J! g9 Y; G3 ]$ J# ?
double fsim2f(double x,double y);
; ~! {+ X! h; z, s
9 A4 O: Y, w$ Y; H0 [
double fsim2(double a,double b,double eps)
s/ z. Q: v5 q8 X) @
{
N8 _# [3 S" N
int n,j;
& ~- K6 G* H* e7 u" Q) k
double h,d,s1,s2,t1,x,t2,g,s,s0,ep;
* p* X6 p: Y7 Z$ \3 C1 B! t
; _0 b: @- ?; w/ q6 E. G/ o
n=1; h=0.5*(b-a);
* X& W: n' f5 t! N2 g0 ]
d=fabs((b-a)*1.0e-06);
; o+ K6 z# u$ V1 ~) Z. b
s1=simp1(a,eps); s2=simp1(b,eps);
9 _' o, |: f1 p# e. Y( ^
t1=h*(s1+s2);
6 ^6 U% p' K2 ~' _- y
s0=1.0e+35; ep=1.0+eps;
8 ?3 C( @* d7 C2 s
while (((ep>=eps)&&(fabs(h)>d))||(n<16))
! |8 _( K7 ?2 }3 ^; ^
{
" Q3 p5 P- M" F" w5 h
x=a-h; t2=0.5*t1;
( a" C* z G- Q) m5 M% y7 D
for (j=1;j<=n;j++)
( w4 \ R0 r. n- a$ K& Y* i! v
{
' j" C: w; W, E; x3 P
x=x+2.0*h;
0 n+ K, Y9 p5 z0 a7 F/ R8 E5 v6 W
g=simp1(x,eps);
2 ^. ?' Q$ N7 f
t2=t2+h*g;
, L+ H8 _, p, B& }! @0 C
}
0 }' q$ E( t5 O& d e2 b* u
s=(4.0*t2-t1)/3.0;
7 m/ t1 l6 [- d5 B5 \
ep=fabs(s-s0)/(1.0+fabs(s));
! l! P1 x3 Y' U; T& A9 m% h7 G
n=n+n; s0=s; t1=t2; h=h*0.5;
( A& K7 q# F. w. k
}
/ k4 |, }7 p- w, }3 X% A! X1 A7 W
return(s);
% J p+ @' E c3 _3 H
}
, `. l/ j9 n* K- B' J! [
# Y, Y8 V5 x7 L7 g) R& c' {& Y
double simp1(double x,double eps)
' K' o. z; E! \& g
{
G; G. ?6 j" p X$ ~7 X
int n,i;
$ G9 X Z. o- j! ?, N& z
double y[2],h,d,t1,yy,t2,g,ep,g0;
. K6 G0 Q o, R+ D" w: ^% {
, f- }) F1 o8 e* e0 x
n=1;
* @9 b1 Z- z+ r+ L
fsim2s(x,y);
' U2 F% H3 `- q9 D1 D
h=0.5*(y[1]-y[0]);
* M/ H% y+ \) D0 [! N1 H
d=fabs(h*2.0e-06);
, x: N* t6 ]+ j( R3 j P
t1=h*(fsim2f(x,y[0])+fsim2f(x,y[1]));
9 m/ K/ ]- t1 g# H
ep=1.0+eps; g0=1.0e+35;
C" Q$ m# G8 e3 K" w7 j. g; d
while (((ep>=eps)&&(fabs(h)>d))||(n<16))
* D2 L( v* V; W$ V; d, C' x
{
) @" _5 V6 _% a; [3 U1 ?& r& s1 O6 J
yy=y[0]-h;
1 _7 k8 ~& e# V/ b6 f: ~
t2=0.5*t1;
4 N% m- e! `0 A$ b" g$ S% }( O
for (i=1;i<=n;i++)
- P/ p- q( L, ]" X7 q8 i; A
{
7 ~/ O4 C! v% w) S. h% ~) c6 G
yy=yy+2.0*h;
- e( w2 u1 l; y0 ^ \1 Q% u
t2=t2+h*fsim2f(x,yy);
- U8 U1 f4 _0 L8 [4 u6 m& \8 M
}
4 @/ A& n0 q- V5 T/ g" [
g=(4.0*t2-t1)/3.0;
; e5 G* S N' b. L: O* ?
ep=fabs(g-g0)/(1.0+fabs(g));
- k# B9 Y: z6 x Y
n=n+n; g0=g; t1=t2; h=0.5*h;
7 J) S6 D# D- q+ S9 {$ T
}
/ n5 P# h3 ~( ~
return(g);
0 m" B2 E) g( l) Q
}
b4 a0 o- X' w" T1 A/ z: i
* M( h' Y$ u. B9 E
void fsim2s(double x,double y[])
. K2 K" E8 X* h8 A7 d
{
, B8 [# ]5 A: Z1 A
y[0]=-sqrt(1.0-x*x);
- l: B' }! R: u1 k! y, d6 {
y[1]=-y[0];
$ K9 S- c" E" l4 [
}
: y. k ^; p7 W4 D7 L, ^- e
9 @" E5 J- W. I" r; J
double fsim2f(double x,double y)
7 b* V, [1 R, U6 n0 t
{
+ P8 }4 g9 S5 Y1 Z$ U5 Z$ D2 V
return exp(x*x+y*y);
, o9 r- [9 z c4 ]; Z
}
' R, o1 ]( q1 Z8 W
6 x z1 D/ Y, V, H v7 u
int main(int argc, char *argv[])
( i; O$ X0 x0 N q+ I
{
4 [7 G# |0 p3 e- i) f
int i;
8 C5 C6 Y/ \8 _: `
double a,b,eps,s;
# n( b! g( L; X3 T6 P
clock_t tm;
2 p# M0 `4 g) \) Z# h$ p5 m) i
9 A3 N( M- }4 ^
a=0.0; b=1.0; eps=0.0001;
" V9 |1 i8 K) D$ @& O
tm=clock();
; \, i! |$ ?# t' n. j
for(i=0;i<100;i++)
2 ~! \ ?; S* ?/ B0 k5 {( |' v {
{
$ x8 V( ?% g5 v* e1 Z
s=fsim2(a,b,eps);
. b: h `0 ?. L. h; o3 K0 p5 Q
}
) f* E4 V% s( Y; }0 D: w+ d+ i
printf("s=%e , 耗时 %d 毫秒。\n", s, (clock()-tm));
, @6 s( S" L0 K, m+ P
}
复制代码
结果:
4 K8 `- l* n. Y, ? n
s=2.698925e+000 , 耗时 78 毫秒。
8 C6 b% t6 _( H# I6 \7 {5 m
1 X" L3 c& Q, w3 v. J
-------
P E4 p" s1 |7 X& B% V
1 ^- s) H$ F3 a7 ?' J" O) g J% {1 C
matlab代码:
%file fsim2.m
7 \/ X1 T& l8 m+ Q" L# M0 q
function s=fsim2(a,b,eps)
1 a* T( I$ d$ a
n=1; h=0.5*(b-a);
1 n: D& x, `! ~' r9 d; t
d=abs((b-a)*1.0e-06);
! n& V# D; ]9 ~. ]7 m
s1=simp1(a,eps); s2=simp1(b,eps);
& {; N* @* J8 t1 B# h! e. J; h
t1=h*(s1+s2);
6 F: n. I9 S5 ?: A- d- F
s0=1.0e+35; ep=1.0+eps;
% d+ Y7 n: @* O+ Y8 U8 k
while ((ep>=eps)&&(abs(h)>d))||(n<16),
$ H5 T k% J/ I: [
x=a-h; t2=0.5*t1;
/ U+ x7 L- j% M/ _+ B0 K R
for j=1:n
0 p# x/ }0 C/ H; y
x=x+2.0*h;
- Q5 x4 c. w9 Q0 E, [8 M2 Q, F
g=simp1(x,eps);
9 w+ y! q" i: }% K& x/ Y3 w
t2=t2+h*g;
; T9 a: K t) N2 u( z
end
2 f! o/ p T3 @3 V5 N2 y. X
s=(4.0*t2-t1)/3.0;
3 Q; A a# x3 o. Q. n
ep=abs(s-s0)/(1.0+abs(s));
" `: q/ G. ], b1 q, I
n=n+n; s0=s; t1=t2; h=h*0.5;
! m. t5 F, P/ j! y$ A
end
8 O2 @/ g2 d O) |2 U
end
* d( }+ R" ~; W( P; d$ I/ e2 V
* J" K& y" C0 Y' b! C
function g=simp1(x,eps)
; e8 S1 u, s! y( F6 d, W
n=1;
9 ]9 t( E* [6 R2 V5 G0 C/ P
[y0,y1]=f2s(x);
* A9 |; g! I! J# s
h=0.5*(y1-y0);
- K9 \! B* R* ~, ?% x6 O; |
d=abs(h*2.0e-06);
% o4 Y* A' j! d" X% q
t1=h*(f2f(x,y0)+f2f(x,y1));
/ P# M3 o! c4 V+ j; _6 M
ep=1.0+eps; g0=1.0e+35;
# p/ f4 m& |( R" |1 t2 a* N. [0 }
while (((ep>=eps)&&(abs(h)>d))||(n<16))
5 c: z! Z% P3 z: b
yy=y0-h;
) q2 z2 M7 ^, `, l3 K
t2=0.5*t1;
5 |( R7 d1 F% D- l/ \% S- F
for i=1:n
# L/ ?. C0 y! a5 L. ~' P
yy=yy+2.0*h;
6 |/ g% W6 x! w9 z5 T
t2=t2+h*f2f(x,yy);
. x. G% I. ?; k
end
& r+ |* _& z/ S0 n3 Y4 c1 h. s
g=(4.0*t2-t1)/3.0;
0 L: \ g7 A6 j2 L/ j7 {1 U' ^7 I
ep=abs(g-g0)/(1.0+abs(g));
# p* z& [. Y1 t- q( E! E
n=n+n; g0=g; t1=t2; h=0.5*h;
# L3 N) ~3 w. B3 J
end
+ r9 \$ x: q! q- Q$ c
end
, Q# @* E! A6 ~' m* z# y0 I
, I& e* U, r& ^6 ^! t
%file f2s.m
1 `8 J7 h M* Q. X/ M
function [y0,y1]=f2s(x)
# {: |: x. z* U& n* G. t, [5 V
y0=-sqrt(1.0-x*x);
" H% [* K t- |1 s% N! D
y1=-y0;
8 h' t) m1 i8 K s1 i+ |
end
3 A7 R; ?, \. n% U) w) S
9 y( P" W0 S) N- m6 s% h6 L
%file f2f.m
- N# \- a" b* |9 H
function c=f2f(x,y)
# u2 X& v& e6 F$ x7 A! a. D
c=exp(x*x+y*y);
3 y9 b* }6 T' q6 t
end
) I( R6 |9 h$ c6 [& a$ {4 X
5 Z% u; E/ D( N# c- M3 l
%%%%%%%%%%%%%
- E x, ^+ b1 Q0 P; w
& t' y& A8 N3 }- w3 ^6 o
>> tic
* A a3 w' ?0 `) ~+ P
for i=1:100
* z, l; `2 R3 L# a! T# B
a=fsim2(0,1,0.0001);
8 ]; \, M9 }( `& [, j: P
end
% m _& h2 \- j8 S ~
a
9 K$ T/ d/ x2 n, A: Q6 x$ Y# N
toc
) R8 t0 {8 q$ M4 d b! q
6 J h, Y" p; [- D! X7 X( y! g
a =
+ R5 j+ a7 y# g( r+ o
' A: Z R! D* t z' P# T
2.6989
, x, Y* }9 k( N/ l% |
% V0 ]% I. J' Z5 h. T" F5 r
Elapsed time is 0.995575 seconds.
复制代码
-------
6 s. U% L' ^, I$ j* V3 l
8 @4 T! X1 r) j4 u8 m: C) h1 w
Forcal代码:
fsim2s(x,y0,y1)=
, o6 X3 X2 s% A) `( O1 Q* f
{
! q, x4 K- f6 ~0 o
y0=-sqrt(1.0-x*x),
& ~0 g$ c* g8 o+ G0 ]
y1=-y0
|; w5 A9 b- O7 ?- W d. u
};
. j# v2 w R6 c
fsim2f(x,y)=exp(x*x+y*y);
. Y6 S1 B4 h8 A
//////////////////
7 \3 U1 S) A. |) W5 S1 ~3 q; K
simp1(x,eps : n,i,y0,y1,h,d,t1,yy,t2,g,ep,g0)=
( e$ U, |9 S2 r8 R% z
{
. Z5 l' r- Q _. K! r( u
n=1,
f; L& E( C% r. E# F
fsim2s(x,&y0,&y1),
* V/ a# ?) G4 c
h=0.5*(y1-y0),
* D, t w: y8 H0 s6 r2 A
d=abs(h*2.0e-06),
1 Z7 ^0 Y" v9 M9 t
t1=h*(fsim2f(x,y0)+fsim2f(x,y1)),
( t+ e$ R1 p% ~1 i, g" v
ep=1.0+eps, g0=1.0e+35,
4 M5 k; n% _& l( H
while {((ep>=eps)&(abs(h)>d))|(n<16),
1 v" T- q/ G( J% t1 U2 ^$ h3 P9 \# d
yy=y0-h,
& _$ b! c) p) ?( l2 b: T# l- g
t2=0.5*t1,
1 ^# A% o4 Q$ Y- G/ S/ I& b2 ^
i=1, while{i<=n,
" W: {4 ?5 i+ y1 N$ s
yy=yy+2.0*h,
! z6 M/ i' h6 H! [ W
t2=t2+h*fsim2f(x,yy),
: `' q& j6 [7 [. D% H8 j# e$ C
i++
3 Z' l% J0 t" B
},
& q* z f1 h; B0 F' b* m
g=(4.0*t2-t1)/3.0,
0 g, L5 M c. R6 @) l( z
ep=abs(g-g0)/(1.0+abs(g)),
1 b! O. b% r! j* f7 v& z) C
n=n+n, g0=g, t1=t2, h=0.5*h
6 C, F! H% Y* J$ ^" x. u1 g3 {
},
& q2 x+ w' I$ l! P& f ]' }
g
1 a6 P a1 m+ l3 s7 }9 B
};
' ]2 Y. y2 a5 Q' e2 @) G7 ^' u
: N s* Q( I+ x' j) W# J
fsim2(a,b,eps : n,j,h,d,s1,s2,t1,x,t2,g,s,s0,ep)=
- d6 k% n3 c! n) V. g& @0 M
{
$ ]1 ?: y! W1 N
n=1, h=0.5*(b-a),
3 m3 H2 g& d1 R3 Z$ }3 F
d=abs((b-a)*1.0e-06),
" l+ g! K" K: O8 W' q T
s1=simp1(a,eps), s2=simp1(b,eps),
/ N: d' ^- L1 T, |0 q6 }9 d
t1=h*(s1+s2),
* \' |+ n0 B4 Y' v& a
s0=1.0e+35, ep=1.0+eps,
, j) H' x/ }7 j" R* E9 t
while {((ep>=eps)&(abs(h)>d))|(n<16),
0 E4 E! o9 K7 v* ]) _/ g" Q0 O
x=a-h, t2=0.5*t1,
: H5 |" n/ N( O% K& {8 c
j=1, while{j<=n,
4 ]. i4 Z9 R5 E+ U. q0 |: {/ ~
x=x+2.0*h,
2 q% v4 y0 D% G/ \0 A. z
g=simp1(x,eps),
" B2 M. ]/ K+ j, ^- e3 o/ c j
t2=t2+h*g,
( [/ @( L7 s; A+ @
j++
. h" W( H0 X" n/ c; l- T
},
/ X1 X& y, u3 @4 ~4 t) m/ c4 N
s=(4.0*t2-t1)/3.0,
% ] f. u1 H/ ~1 f4 x! A8 E% k
ep=abs(s-s0)/(1.0+abs(s)),
# s3 w8 j% U! o' w; n
n=n+n, s0=s, t1=t2, h=h*0.5
7 x/ L9 U d7 I6 N l, X$ R- Q
},
& c3 [; W$ e# {4 X* I8 P5 a
s
0 P O1 M5 S$ U/ W/ A
};
0 r; {/ w; n- g
7 T0 @# h% Q. r- y. P
//////////////////
! q1 d, [9 }8 Z: e
/ x2 ?& H$ L! y e
mvar:
) t |+ v) A. a& V
t0=sys::clock(),
3 h+ \! |7 M* b5 m. ]4 [
i=0, while{i<100, a=fsim2(0,1,0.0001), i++}, a;
; ]/ u% L2 D, v3 u& e
[sys::clock()-t0]/1000;
复制代码
结果:
' x4 ^; H& {# q# _! }( ^
2.698925000624303
4 Y% H$ k: z( u+ K: |3 a
0.328
1 @' a( K a h
- Z e L% A* {3 O' a! t) r2 A
---------
1 t6 O2 K' u# j1 s7 ]; l' K( U
5 Z) z: W$ o- J! D4 K0 E: o/ p {6 B
本例C/C++、matlab、Forcal运行耗时之比为 1:12.7:4.2 。
0 J: [1 {3 ?2 B+ j% ^
4 m* u8 m, n" r$ u2 b- K
本例matlab慢的原因应该在于有大量的函数调用。另外,matlab要求每一个函数必须存为磁盘文件真的很麻烦。
: O+ {4 ?. {- I3 g- H0 q
7 k3 o" ]. X$ q6 n7 {; t
本例还说明,对C/C++和Forcal脚本来说,C/C++的一条指令,Forcal平均大约用4.2条指令进行解释。
作者:
forcal
时间:
2011-8-4 09:00
3、变步长辛卜生二重求积法,写成通用的函数:没有数组元素操作
* g$ D4 f) i" U1 B6 Q
, W+ ~6 X$ B% l& r
注意函数fsim2中增加了两个参数,函数句柄fsim2s用于计算二重积分时内层的上下限,函数句柄fsim2f用于计算积分函数的值。
5 x' C- C1 ^* i' b
) s& p4 [* Q1 K
不再给出C/C++代码,因其效率不会发生变化。
! e2 |, v' Z6 v
2 o$ F( `5 V7 ~1 ?2 ?! z
Matlab代码:
%file fsim2.m
8 T$ l; s3 M2 l: V
function s=fsim2(a,b,eps,fsim2s,fsim2f)
. [; n! K% {) h; a: R6 t+ P7 ^! t
n=1; h=0.5*(b-a);
1 i( f; z- [: c0 K6 n' v5 _& Q5 a
d=abs((b-a)*1.0e-06);
5 j- o" l& u+ I& F
s1=simp1(a,eps,fsim2s,fsim2f); s2=simp1(b,eps,fsim2s,fsim2f);
2 J8 z/ U! @8 \ z0 l
t1=h*(s1+s2);
: Z6 Z% y6 s0 E( X: }8 Z
s0=1.0e+35; ep=1.0+eps;
* l% G3 E2 [- a) s# [' ?/ P
while ((ep>=eps)&&(abs(h)>d))||(n<16),
7 q, u( e- f$ g+ E7 w
x=a-h; t2=0.5*t1;
- I' e7 f4 U, U- L
for j=1:n
% ?$ V% \1 |. ?7 I; m' @( X
x=x+2.0*h;
" a: h/ n# ~+ ^! y+ E e" s% |
g=simp1(x,eps,fsim2s,fsim2f);
# \* v4 n, V* Z2 R/ b
t2=t2+h*g;
: d( T4 _ f' g3 ^7 c! i
end
2 m2 K7 n9 G; a: D: C9 Q" O$ Q2 \5 g
s=(4.0*t2-t1)/3.0;
# C6 J, B8 ~# q! f
ep=abs(s-s0)/(1.0+abs(s));
' K* B( q# Y3 {
n=n+n; s0=s; t1=t2; h=h*0.5;
; S0 v6 L! Y, ]) b
end
2 ~- g) f: m2 K9 b- ~9 S4 h
end
5 ^7 n% s h; \! I
1 D# ^9 b0 ^# [# b
function g=simp1(x,eps,fsim2s,fsim2f)
0 H9 z8 m9 c2 W2 }
n=1;
% y( L- I. a4 _/ s6 ~
[y0,y1]=fsim2s(x);
0 v7 G j5 ~, e* _' a
h=0.5*(y1-y0);
) C) _0 I7 S- t2 D4 G
d=abs(h*2.0e-06);
M, c$ x/ F' D" |& P7 m- j9 H& s5 t
t1=h*(fsim2f(x,y0)+fsim2f(x,y1));
8 E1 |; B& V( h. N; H# F; J) { r
ep=1.0+eps; g0=1.0e+35;
2 W0 B L9 T! p' c
while (((ep>=eps)&&(abs(h)>d))||(n<16))
( s8 a# R7 k! {; e
yy=y0-h;
# L! f/ M0 v4 @ ^! y. ~
t2=0.5*t1;
4 j3 O2 ~8 _: o+ x6 ]! s0 e
for i=1:n
3 l' A0 W0 p& p# z
yy=yy+2.0*h;
1 M1 p5 s# d% v# n/ Q9 e
t2=t2+h*fsim2f(x,yy);
) R0 x% b4 c) r1 y* l) x. s
end
/ @& F% j3 X% a6 H! H
g=(4.0*t2-t1)/3.0;
; M1 {) e% g7 Y0 {4 a! o
ep=abs(g-g0)/(1.0+abs(g));
y5 q8 W4 H) z9 W* G: n. f/ p
n=n+n; g0=g; t1=t2; h=0.5*h;
2 o. V4 Q7 H' f! U8 T; y N" k4 G
end
- }: y; X7 L0 m: C6 x
end
5 l$ H& _, A, ~8 `4 Q
9 W9 h* p& ?# o0 w3 Y0 x
%file f2s.m
1 \5 F, U/ q0 G5 Q) n& H+ P
function [y0,y1]=f2s(x)
5 @$ _5 V, R" w* _% I6 t. W
y0=-sqrt(1.0-x*x);
2 z3 e T! Q4 |4 x
y1=-y0;
& j7 j1 z1 ?, r
end
# P; A) {/ E# _
" H: ^8 l$ U/ y3 c
%file f2f.m
5 Y! w- _$ x* T. {, S. A
function c=f2f(x,y)
5 _8 u4 B Q8 b0 m8 `9 T3 F
c=exp(x*x+y*y);
, r. c$ n# t R* R3 ]: z$ Z6 y
end
+ J2 k2 C/ K$ R" A7 h/ c7 w
( B( {: D" L7 K; { i2 }- p- f
%%%%%%%%%%%%%%%%
" i. y: X6 W! P c) D
+ s9 L- U; z; i' \/ X
>> tic
) X8 B. R5 j$ J# ?* s5 [+ H" b" d3 q
for i=1:100
1 G3 v& t8 L' l* R) u" K7 U4 L
a=fsim2(0,1,0.0001,@f2s,@f2f);
. f3 r) T) G$ ^2 J5 B& Y6 y
end
5 Q/ K+ W; h1 [5 D2 }9 M
a
- j& V* Q, o+ \& D* \) N3 X# n
toc
$ V8 c2 ~, P# V4 j W7 l/ t
9 _8 ~. U5 a8 s5 v7 C. Q, M4 h
a =
; b: \( M2 h* u+ ]
0 L0 \# D! j/ Q& A b; B% W
2.6989
4 W0 n# i, a( |' k* B1 f# ]2 B
7 N3 p/ R5 W- q& |$ m9 o4 i" ?
Elapsed time is 1.267014 seconds.
复制代码
--------
5 \- ^, g$ Z3 P% N& t& t8 x
" e. ]* i$ V+ {! M2 \
Forcal代码:
simp1(x,eps,fsim2s,fsim2f : n,i,y0,y1,h,d,t1,yy,t2,g,ep,g0)=
W7 \1 G; U7 W2 b! S" }) H7 R( g) @
{
; R3 _& I' ]8 R; R+ M! b0 F
n=1,
( r- k3 Q R; V( x7 U4 {
fsim2s(x,&y0,&y1),
" S, T4 b( ^& f- O& N2 Q
h=0.5*(y1-y0),
/ {. i9 L" U8 W$ w- U
d=abs(h*2.0e-06),
: V! a/ j R" H$ U/ u: p; B
t1=h*(fsim2f(x,y0)+fsim2f(x,y1)),
% S. c# C$ u+ `# W( A) F/ L8 M6 J) T
ep=1.0+eps, g0=1.0e+35,
8 }: Y) R/ F* D$ Z1 s
while {((ep>=eps)&(abs(h)>d))|(n<16),
. A9 @0 R, ^& T7 |
yy=y0-h,
) N( ?% _. ^# I, I+ z
t2=0.5*t1,
- t& L8 I; o+ {" m5 M; K7 e
i=1, while{i<=n,
4 d ^( S T* ?7 g* m
yy=yy+2.0*h,
6 B0 p; t2 P6 T
t2=t2+h*fsim2f(x,yy),
3 |( ]1 z8 }* c5 X
i++
6 _8 l; Z, R$ _7 Y
},
/ x- ]- w3 o. M" B z+ Q; ], ]
g=(4.0*t2-t1)/3.0,
8 C' J4 P$ G* `5 x7 z
ep=abs(g-g0)/(1.0+abs(g)),
* n S* U4 I/ r9 J5 m# I# K) m
n=n+n, g0=g, t1=t2, h=0.5*h
" P! I! [+ W) c9 p2 l
},
* F ?, ^4 {# ]8 ]
g
& L& W" M. W; h3 \% p* s: y
};
; d0 m& W( W+ t2 ?6 e F; F3 T
5 Y' ^4 [8 }/ j3 N5 T7 ?
fsim2(a,b,eps,fsim2s,fsim2f : n,j,h,d,s1,s2,t1,x,t2,g,s,s0,ep)=
, ^! r8 m- v& d2 r# [2 F, ~- ~! U# H
{
; h2 F# S W9 ^. q! Q0 b( q
n=1, h=0.5*(b-a),
( a$ r: {8 H P% \& Q
d=abs((b-a)*1.0e-06),
; f% @3 o3 ~$ s" k0 N3 z
s1=simp1(a,eps,fsim2s,fsim2f), s2=simp1(b,eps,fsim2s,fsim2f),
9 h8 @# \8 T7 P, r4 c
t1=h*(s1+s2),
% {" f: \) H" m+ D) @) {% U
s0=1.0e+35, ep=1.0+eps,
( b3 f# k% b9 t
while {((ep>=eps)&(abs(h)>d))|(n<16),
5 R- g/ J$ R: V) F1 i
x=a-h, t2=0.5*t1,
% q' n. D% W$ W0 s# r
j=1, while{j<=n,
! q+ G6 B B, o. \0 v# m" }
x=x+2.0*h,
- O* r0 X; t8 C+ b4 R* D) O8 K! b' J
g=simp1(x,eps,fsim2s,fsim2f),
- R! y$ [* s6 E' S# d1 k7 v
t2=t2+h*g,
, O ?( T. c# v) @
j++
+ ]6 O5 N. z G/ ~- ^& v& j* @
},
$ T- h9 {2 e8 |* u/ r3 s5 b7 N
s=(4.0*t2-t1)/3.0,
# g4 u$ w6 L% u) u7 Y
ep=abs(s-s0)/(1.0+abs(s)),
# `3 a* C2 Y p% u8 D$ t3 s
n=n+n, s0=s, t1=t2, h=h*0.5
1 K |/ I8 S; r, B0 c/ ~
},
$ P5 h5 m$ F4 i" ^1 L) q
s
* m- R. ~0 \( G1 o; E4 [
};
6 e+ a8 V8 q7 B8 m; j
; g- f7 C8 b: h: _' f
//////////////////
6 f2 t4 Y2 S8 A/ F7 m
/ a' ?2 ?) F% p9 B
f2s(x,y0,y1)=
( d2 d1 u) C, S6 Z9 L3 J
{
5 b0 P, K# C4 d I8 W' f! x# e
y0=-sqrt(1.0-x*x),
% a% A8 r' I6 y9 J/ o0 ]" ?
y1=-y0
+ z* i4 g- @8 b+ g- t
};
( _! X1 V* i. y0 \: e7 B' A
f2f(x,y)=exp(x*x+y*y);
- n3 V/ z6 l9 y' h3 m
6 F2 F; n' \" ]* @5 R
mvar:
+ u6 U0 V- O ?7 m
t0=sys::clock(),
8 D R1 e4 Q5 [$ x, T9 Z
i=0, while{i<100, a=fsim2(0,1,0.0001,HFor("f2s"),HFor("f2f")), i++}, a;
' c5 G8 Y. N$ f# ]3 W: h7 c
[sys::clock()-t0]/1000;
复制代码
结果:
" L% }6 q# d/ H4 `
2.698925000624303
6 O& U+ a3 D) C V$ e
0.844
: a N6 Q/ H U
3 K- e+ c3 k4 S4 u
--------
) o9 k' F6 p* j) H0 [8 J
: t7 v/ Q0 Y4 ]' T9 z
本例matlab与Forcal耗时之比为1.267014 :0.844。Forcal仍有优势。
! _8 k) |7 n+ R( L& }6 {; f# Z q$ i
5 Q0 Y8 v2 _* c% I) M
本例Forcal耗时增加的原因:在函数fsim2及simp1中要动态查找函数句柄fsim2s,fsim2f,并验证其是否有效,故效率下降了。
作者:
sxjm567
时间:
2012-7-30 01:48
百年不遇的好帖子,不得不顶
作者:
1055486706
时间:
2012-9-2 16:31
确实很不错
作者:
1055486706
时间:
2012-9-5 09:29
好深奥哦,肿么办?
欢迎光临 数学建模社区-数学中国 (http://www.madio.net/)
Powered by Discuz! X2.5