新手跪求指导

heugaodie

r = 3.04042*10^(-6);
p[x_] := x^5 - (2 + r) x^4 + (1 + 2 r) x^3 - (1 - r) x^2 +
9 v6 O$ J4 [* {, _1 `  R  2 (1 - r) x + r - 1
q[x_] := p[x] - 2 r*x^2;
a0 = 0.5; b0 = 1.5; delta = 10^(-6); k0 = 100;
a = a0; b = b0;
Do[x = (a + b)/2;
$ [. g! p- L: F1 k+ Q If[p[x] == 0, Break[], If[N[p[x]*p[b]] < 0, a = x, b = x]];
If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
x1 = x
7 L9 I6 l( K# a3 }' J. m4 |4 IClear[x]
Do[x = (a + b)/2;
$ T" x: ]/ a: S( H If[q[x] == 0, Break[], If[N[q[x]*q[b]] < 0, a = x, b = x]];
If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
: m0 X, x" t; y# |* S5 xx2 = x
Clear[x]
* j+ Q. q' J6 V- o2 |3 d' L2 s, O
我想让p q 两函数的解都求出来 每次都是两个一样的解（是第一个的）  明明用了clear的 怎么做

qudazi

你试一下将Clear[x]换成x=.看看

花如梦

别只用x,换个变量试试

小小灰

看不懂，看不懂