新手跪求指导

heugaodie

r = 3.04042*10^(-6);
p[x_] := x^5 - (2 + r) x^4 + (1 + 2 r) x^3 - (1 - r) x^2 +
7 j% v& u3 u, o  d  2 (1 - r) x + r - 1
: _/ Q6 O8 X2 Jq[x_] := p[x] - 2 r*x^2;
a0 = 0.5; b0 = 1.5; delta = 10^(-6); k0 = 100;
/ U% ^3 K3 G# F4 \& v# @a = a0; b = b0;
Do[x = (a + b)/2;
& d/ S' z& B. W If[p[x] == 0, Break[], If[N[p[x]*p[b]] < 0, a = x, b = x]];
. b* V2 q. u: B! M2 P If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
4 v$ [! G( H8 Q0 lx1 = x
Clear[x]
0 M3 {" E+ k: T$ P) YDo[x = (a + b)/2;
If[q[x] == 0, Break[], If[N[q[x]*q[b]] < 0, a = x, b = x]];
If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
x2 = x
Clear[x]
% q8 j# b. E8 _. u& {7 T
# t6 X4 _& ^7 y' N  Z8 y我想让p q 两函数的解都求出来 每次都是两个一样的解（是第一个的）  明明用了clear的 怎么做

qudazi

你试一下将Clear[x]换成x=.看看

花如梦

别只用x,换个变量试试

小小灰

看不懂，看不懂