新手跪求指导

heugaodie

r = 3.04042*10^(-6);
p[x_] := x^5 - (2 + r) x^4 + (1 + 2 r) x^3 - (1 - r) x^2 +
  2 (1 - r) x + r - 1
q[x_] := p[x] - 2 r*x^2;
$ I- n, _2 O% ?4 |a0 = 0.5; b0 = 1.5; delta = 10^(-6); k0 = 100;
a = a0; b = b0;
% j0 Z8 w! L* V7 S7 q% uDo[x = (a + b)/2;
0 _! }$ o: a2 E% D If[p[x] == 0, Break[], If[N[p[x]*p[b]] < 0, a = x, b = x]];
+ Z$ r1 {$ ^: z6 Y If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
x1 = x
# z7 Y( L' P3 s- P* \' U7 _Clear[x]
Do[x = (a + b)/2;
( E3 W2 [5 Z. [( [$ r: a% w If[q[x] == 0, Break[], If[N[q[x]*q[b]] < 0, a = x, b = x]];
# u0 C) e. c' T' Q* i+ w! r0 ?( y1 t If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
x2 = x
Clear[x]
" ?# t. K* `4 V+ @2 G( ~
我想让p q 两函数的解都求出来 每次都是两个一样的解（是第一个的）  明明用了clear的 怎么做

qudazi

你试一下将Clear[x]换成x=.看看

花如梦

别只用x,换个变量试试

小小灰

看不懂，看不懂