lingo建模语言与实例4

longde

目标与约束段
! k& Q3 h3 y8 e% Z) Y# T集合段（SETS    ENDSETS）
数据段（DATA   ENDDATA）
& E# `3 S6 i2 `1 ]! W6 d初始段（INIT  ENDINIT）
7 @! s5 ~2 ?. c/ H9 g; M$ m$ D（计算段 (CALC ENDCALC)）
$ U* c9 [" E6 r) V7 P& aMODEL:
Title Location Problem;
sets:
    demand/1..6/:a,b,d;
# N2 C# j6 Q' I5 H  n9 |" O! R7 i    supply/1..2/:x,y,e;
7 m4 C) ?: {  I: Y" B" Z    link(demand,supply):c;
endsets
% X$ S- o2 v, F! V: Ydata:
a=1.25,8.75,0.5,5.75,3,7.25;
" S2 T4 d* C4 G5 Q( R) vb=1.25,0.75,4.75,5,6.5,7.75;
% K) u8 A  Q5 q8 Id=3,5,4,7,6,11; e=20,20;
enddata
0 n  P" I+ h- `/ F9 L0 ]/ ginit:
' ~- m' y1 }9 D6 y- s' \x,y=5,1,2,7;
endinit
# `' w- y9 d, n: mmin=@sum(link(i,j):c(i,j)*((x(j)-a(i))^2+(y(j)-b(i))^2)^(1/2));
9 E4 A6 _5 Y, K0 ~2 ^@for(demand(i)sum(supply(j):c(i,j))=d(i););
@for(supply(i)sum(demand(j):c(j,i))<=e(i););
END
4 l7 _' N7 p% D1 z0 \' J! A
$ {" B( `! o. o4 x: m+ X2 T+ v