Lingo建模语言与实例4

longde

目标与约束段
集合段（SETS    ENDSETS）
" Y7 z# }5 t# V$ ]% |" }; h数据段（DATA   ENDDATA）
初始段（INIT  ENDINIT）
# S9 _: x' |. R$ k5 {（计算段 (CALC ENDCALC)）
MODEL:
Title Location Problem;
sets:
5 C& ?& m7 W( l. `3 R    demand/1..6/:a,b,d;
. y% {! g4 F* `0 A    supply/1..2/:x,y,e;
    link(demand,supply):c;
* @7 n+ X, a# q4 sendsets
data:
. Y% M( H3 Z1 z# wa=1.25,8.75,0.5,5.75,3,7.25;
0 I( ~- H: K9 ]+ {8 {b=1.25,0.75,4.75,5,6.5,7.75;
- }% E% L* e& F* Sd=3,5,4,7,6,11; e=20,20;
enddata
init:
$ l( o2 D" r6 P" a- T8 Q7 i! sx,y=5,1,2,7;
- W2 z' I; H6 v( R1 Uendinit
min=@sum(link(i,j):c(i,j)*((x(j)-a(i))^2+(y(j)-b(i))^2)^(1/2));
@for(demand(i)sum(supply(j):c(i,j))=d(i););
@for(supply(i)sum(demand(j):c(j,i))<=e(i););
END
. Y/ l" \6 p  ]4 h. e8 V4 Q8 Z

longde

好
& y. y0 I" Z# y& ?