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发表于 2009-8-16 18:59
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修改一下循环的下标可以使得程序编译通过,但是不知道是不是和你的模型相符合,你仔细分析一下吧!" S5 f+ n1 {) r% M. G2 Q l
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- model:
& R\" r$ |4 P$ B; e - !n个货车8收点运输问题;
. C7 p3 J3 f2 z\" g% s - sets:
d, o7 p E E- z/ O* Q - place/place1..place10/:time1,time2,timexie;
) T/ \% J9 D/ \; I, A* j, Z/ u - car/car1..car3/:time;
) n1 F8 _9 ^6 n, G# O) D - * v' g4 q- V( ?% @; M) q' J
- jiu/1..9/;# d\" |1 X7 k0 e' r$ H6 i& I
- er/1..2/;4 M* [, ^/ v3 n6 ], C+ s6 q
- ) F/ l\" ^. A0 z5 T$ v7 T
- lc(car,jiu):lucheng,ct;
* _5 Z, C5 P8 t$ f+ q - plan(place,place,car):a;4 I* ]2 X& U `; g
- distance(place,place):dd,dt,which;
$ x/ m) c: _8 [) m5 Q T, Z: i - endsets
2 N( O5 p1 ]+ Z. R9 D - 7 N% n8 j9 O D& M, Q2 U
- / u, j( u4 y. F5 z
- !这里是数据;
, N5 E5 T1 o6 _% e2 q9 X0 y - data:
- }& G1 U5 r: e% K - s=1;1 a! j! ~' n& T$ A c& a
- time1=-10 1 4 1 4 3.5 2 5 1.5 1;
6 E) X9 I* A\" F- I- n% _ - time2=7 4 6 2 7 5 5 8 4 10 ;6 [, N$ @# N& l6 y+ |\" t& h
- timexie=0 1 2 1 3 2 2.5 3 0.8 0;
. V# C) Y8 r3 F6 p _; y8 h\" u3 K
9 y8 H; u! c\" T1 B& L8 p- 1 h) s; Z8 d0 e7 H' A% e5 T1 \# W
- dd=: L7 z; n5 V& H7 E
- 0 40 60 75 90 90 100 135 80 0# d7 U$ x* k4 p
- 40 0 65 40 100 50 75 110 100 40. c6 X, c& s6 c1 g! H& ]1 h
- 60 65 0 75 100 100 75 75 75 60 w* p# [3 x0 G/ b3 ^0 `
- 75 40 75 0 100 50 90 90 125 75. [3 }0 o- i; {$ w\" Y
- 90 100 100 100 0 100 75 75 100 90
7 q) S B$ N `8 P0 h. n - 90 50 100 50 100 0 70 90 75 906 T! {7 W4 o/ X9 U
- 100 75 75 90 75 70 0 70 100 100
\" f- m3 x; g9 E! k - 135 110 75 90 75 90 70 0 100 1352 s$ H6 Z: v7 i- t( R7 C3 b8 N
- 80 100 75 125 100 75 100 100 0 80# \, y5 \. k D% V\" i) L/ J0 J
- 0 40 60 75 90 90 100 135 80 0 ;/ n- ?1 A ?6 P
- dt= 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 03 n$ f# V+ q- S. j) z8 S
- 0.8000 0 1.3000 0.8000 2.0000 1.0000 1.5000 2.2000 2.0000 0.8000* s- ^2 p3 A. W' N2 A\" g
- 1.2000 1.3000 0 1.5000 2.0000 2.0000 1.5000 1.5000 1.5000 1.2000* D' b: E6 y3 N7 Z* r1 g
- 1.5000 0.8000 1.5000 0 2.0000 1.0000 1.8000 1.8000 2.5000 1.5000& r. O\" ?6 B) _% _7 ]9 S9 W; C
- 1.8000 2.0000 2.0000 2.0000 0 2.0000 1.5000 1.5000 2.0000 1.8000
) _8 l4 ?/ F9 A - 1.8000 1.0000 2.0000 1.0000 2.0000 0 1.4000 1.8000 1.5000 1.8000
7 ?- w% C, H2 O C9 y8 ~# w - 2.0000 1.5000 1.5000 1.8000 1.5000 1.4000 0 1.4000 2.0000 2.0000
& q- l/ l; H; b0 l* D. r - 2.7000 2.2000 1.5000 1.8000 1.5000 1.8000 1.4000 0 2.0000 2.7000: w( f& e6 w1 o4 s( }5 s2 R
- 1.6000 2.0000 1.5000 2.5000 2.0000 1.5000 2.0000 2.0000 0 1.60003 A3 q- J' X# V, h i8 ~
- 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0;' H# v U' u q, M8 v3 u
- enddata! e% j7 L/ }- n
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- 2 P1 E, U6 e( N) C: w; h. a
- !目标函数;
. z$ V. W5 v8 |9 t) c2 ^2 b - min=@sum(lc(I,J): lucheng(I,J));9 a7 ~. y' N3 W! h+ j7 K
: T4 t2 N0 {! b f9 _. w+ I9 X- !整数约束;3 P6 u; q8 Q, K+ Q9 k. m S! j
- @for(plan:@bin(a));
7 p, q- e' x7 L# \4 n7 n - @for(car(I):@free(time(I)) ;3 |- u6 _! g1 C\" u4 P
& n4 ~ w, x4 I- Y) Q b- !从零点开始最终回来;* P' V+ q) t+ V/ e
- @for(car(I):
- N; I5 d5 d/ \. J+ z' ?+ W6 L - a(1,1,I)=1;a(10,10,I)=1);
$ Z5 b n\" _, e% q+ D
( J$ }& B9 g3 f: j/ S. `- !每个任务只能有一个;, g' b: O* L7 H# F% z7 }3 i
- @sum(car(I):
! D4 g! E& E m0 ~. @8 C4 X4 l - @sum(place(K):
K; }+ H; R) ]7 l - @sum(place(J): a(J,K,I))))=1;
% w/ X' S$ R9 b1 }6 d
0 T, U& v3 x* Y4 g. H& j1 u% v/ d- !每个车的任务最多有四个;0 r5 y; K) y+ X8 d& x8 Z
- @for(car(I):
4 W% D$ @: z5 y1 r% y - @sum(plan(J,K,I):a(J,k,I))<=6);
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; b3 U7 P3 v3 ]5 j7 X+ S- !前一辆车任务大于等于后一辆车;, M\" b5 x0 H/ o
- @for(car(I)|I#lt#1:3 f8 U. q, U0 `% N
- @sum(plan:a(J,K,I))>=@sum(plan:a(J,K,I+1) );7 g\" L$ l0 K: z# x
, ~; Z. s1 U5 ~. u/ b& ]- !求which 例子 若a(1,:)=[1 0 0 1 0 1 0 0 0 1]; N& @( D, X1 \) [/ }
- ! 则 which(1,:)=[1 1 1 4 4 6 6 6 6 10] ;! B! ^6 \# x+ O( ]8 i
- @for(car(I):
0 e& d( ?& C7 A8 I. k - @for(place(kk)|@sum(place(jj):a(kk,jj,I)) #eq#1:
& d* H- f' }$ z' a3 ^! D. F/ W% l5 K - @for(place(jj)|a(kk,jj,I) #eq#1:2 p2 X6 T9 {4 s+ l# U5 P9 r
- which(I,kk)=jj ););8 x8 N; {' e\" l) L4 C\" P. y9 v
- @for(place(kk)|@sum(place(kk):a(kk,jj,I)) #ne#1:
* i+ p0 p% d' x/ {6 a0 l. V/ ^ - which(I,kk)=which(I,kk-1));
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- !时间限制;
: w$ F' g' o& Q+ M' { - @for(car(jjj):
8 |: x5 a H4 M% w$ ~. v - time(jjj)>=-10;time(jjj)<=7);
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6 q: b) `9 `' `8 Z\" A# J! X/ B l$ ]- @for(jiu(jjj):
6 ~\" ^/ S' q1 ?$ ~' S6 Y2 Q - ct(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dt(which(I,jjj),which(I,jjj+1))+timexie(which(I,jjj)),0));
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7 T$ i9 |) n+ Q8 q. d! k+ C- @for(jiu(jjj):
, m% @! t+ }/ } - time(I)+ct(I,jjj)>=time1(jjj+1);time(I)+ct(I,jjj)<=time2(jjj+1));
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- !求每辆车行驶的距离;7 @+ c0 e v8 s/ n
- @for(jiu(jjj):
4 J! g x+ P! A. L2 C/ Q7 m - lucheng(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dd(which(I,jjj),which(I,jjj+1)),0) );
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- end _4 M5 } w% }9 h8 N
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