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发表于 2009-8-16 18:59
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修改一下循环的下标可以使得程序编译通过,但是不知道是不是和你的模型相符合,你仔细分析一下吧!
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- model:
1 R) m2 O4 r5 [! b9 c9 C9 ~ - !n个货车8收点运输问题;
7 B5 y0 S# ~2 W3 H7 {9 |* x3 t4 _4 x - sets:7 S9 i3 L9 P3 j. I
- place/place1..place10/:time1,time2,timexie;1 J7 I5 Q& A( ]4 G: _
- car/car1..car3/:time;2 s- u8 ~; r* F; W* t
- 2 Q0 G# v5 b% P
- jiu/1..9/;
4 P, z c+ L0 ~0 ~ - er/1..2/;5 T( s- t4 M1 \, Z
- W- v7 K9 H0 b1 U9 q4 H- Q; N
- lc(car,jiu):lucheng,ct;9 ?. {7 s2 O B' r* O
- plan(place,place,car):a;
- ^$ m+ D7 A8 t6 m9 u - distance(place,place):dd,dt,which;5 s# r* t% `4 T& ^4 }. l
- endsets/ \\" M0 C% q\" @4 ]9 r
- 2 Q5 Q+ \! p3 {! P+ z, A/ U
- # O9 T ]. n5 ], R
- !这里是数据;
% V n# c/ N& @7 \8 p; Q - data: ^4 q! x: C1 T; O6 z0 S
- s=1;
' @- }\" i$ b) w - time1=-10 1 4 1 4 3.5 2 5 1.5 1;
7 I2 g. N, ~3 P3 e - time2=7 4 6 2 7 5 5 8 4 10 ;
4 }6 U. ]* j; G - timexie=0 1 2 1 3 2 2.5 3 0.8 0;
9 s: i/ V s- Q, e J - \" r/ a) ^# ^& C\" X# b% J/ l% x
\" F/ L\" ?. x% R! a+ ` W( X5 L- dd=
2 h& n& j8 s3 z+ B+ p\" N. T' O - 0 40 60 75 90 90 100 135 80 01 w0 S) Y, T, A1 v6 ?/ r, G& `
- 40 0 65 40 100 50 75 110 100 409 T- v9 Y1 w5 S5 v5 H
- 60 65 0 75 100 100 75 75 75 60
2 X3 Z% Z( I\" Q9 t- N+ w1 m, ]* y - 75 40 75 0 100 50 90 90 125 75
; i( B. Q* ?4 d2 V Z. W - 90 100 100 100 0 100 75 75 100 90( s: h) h- y( n$ \6 L# D
- 90 50 100 50 100 0 70 90 75 90$ Z3 h9 R\" T- i1 H2 ^8 V
- 100 75 75 90 75 70 0 70 100 100
+ x) ?( l7 y7 Y1 l- R0 h\" Y - 135 110 75 90 75 90 70 0 100 135
7 C$ [1 a/ y; D' s- i7 A - 80 100 75 125 100 75 100 100 0 80! p4 ]\" s9 h1 U7 k3 b4 a3 V+ a
- 0 40 60 75 90 90 100 135 80 0 ;
0 T1 V) ^) m5 @( J5 V) E1 V - dt= 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0; Q0 s1 Y6 m& }; s4 ^3 M
- 0.8000 0 1.3000 0.8000 2.0000 1.0000 1.5000 2.2000 2.0000 0.8000
- ]! \% g0 [7 i; n d - 1.2000 1.3000 0 1.5000 2.0000 2.0000 1.5000 1.5000 1.5000 1.2000
' Z/ b. g$ T9 v) z - 1.5000 0.8000 1.5000 0 2.0000 1.0000 1.8000 1.8000 2.5000 1.5000
X# ] @, m) r, R% I: G0 Q, p - 1.8000 2.0000 2.0000 2.0000 0 2.0000 1.5000 1.5000 2.0000 1.8000
& t8 |# D t- ]$ W - 1.8000 1.0000 2.0000 1.0000 2.0000 0 1.4000 1.8000 1.5000 1.8000, ^! j; W/ `* c! `0 Z# a5 T5 P: j
- 2.0000 1.5000 1.5000 1.8000 1.5000 1.4000 0 1.4000 2.0000 2.0000* [, X\" t4 C6 L
- 2.7000 2.2000 1.5000 1.8000 1.5000 1.8000 1.4000 0 2.0000 2.70005 w1 i0 p8 H: D! p1 j# z
- 1.6000 2.0000 1.5000 2.5000 2.0000 1.5000 2.0000 2.0000 0 1.6000
) Y# Q# W h; {: l/ B9 d( u - 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0;
/ P3 P8 X4 W: Y# a; M - enddata2 G, j1 V, U# \. K/ X
- + N\" l$ F) U\" }+ Y
- # m) N: ^$ L2 Q1 ^4 {
- !目标函数;
6 |$ L2 H. S5 L\" M - min=@sum(lc(I,J): lucheng(I,J));( O7 T: D9 s. k% |6 k: C0 z( T
\" l9 k, T% ?& O3 g) c$ E- !整数约束;
! p3 T# |; P! J& e - @for(plan:@bin(a));9 P% L' Z4 {4 V' K, n/ }; @
- @for(car(I):@free(time(I)) ;
7 P. ?4 h S [0 V4 s1 v
! ~; {2 J6 a- j# o- !从零点开始最终回来;* C2 X$ G0 _4 M
- @for(car(I):
+ @% E8 p0 y9 l$ p1 u - a(1,1,I)=1;a(10,10,I)=1);
' i5 H! z+ ~: s% j - 1 d: [# l1 c p0 E6 j# M0 p; ?
- !每个任务只能有一个;8 n w1 @' X' B, [. Q% z5 w
- @sum(car(I):5 R4 S3 R. I& `: Z! ^* Q; ?
- @sum(place(K):
; E9 k. d3 N& @ - @sum(place(J): a(J,K,I))))=1;
9 g6 v6 n c\" T
5 Q' Z* m, _- X\" ^2 h6 y2 B- !每个车的任务最多有四个;6 g1 }5 [' J M4 A$ x
- @for(car(I):
: {\" U1 ~: Q2 q6 t% c1 R* V! V - @sum(plan(J,K,I):a(J,k,I))<=6);1 v& h9 A) P\" w0 X, h
- ( m; ~- k: T\" H9 @9 _; u0 ?! D
- !前一辆车任务大于等于后一辆车;
: B |/ Y6 h) s\" b8 P\" a+ h+ E - @for(car(I)|I#lt#1:7 K5 Y9 a& A, X
- @sum(plan:a(J,K,I))>=@sum(plan:a(J,K,I+1) );
+ n. O. b, q; ?# g# x\" ~5 q - {1 N' Y\" F e R+ l1 K\" \3 [3 Y) S
- !求which 例子 若a(1,:)=[1 0 0 1 0 1 0 0 0 1];
) u# J9 j% ]' K$ z - ! 则 which(1,:)=[1 1 1 4 4 6 6 6 6 10] ;0 s4 r; r$ {% i; Q5 h
- @for(car(I):
) Y; i1 M* h0 J/ Z - @for(place(kk)|@sum(place(jj):a(kk,jj,I)) #eq#1:
0 M: K' o; O$ m - @for(place(jj)|a(kk,jj,I) #eq#1:
' u' [% Z+ E8 W. \# u: H) a' h2 A - which(I,kk)=jj ););
* n\" N# m% a\" M( ?$ D1 o, P, T - @for(place(kk)|@sum(place(kk):a(kk,jj,I)) #ne#1:6 I3 H# i/ e% d5 j
- which(I,kk)=which(I,kk-1));
0 Q. I+ ?8 j& J - & g- Q; W\" W$ F k- m- r
- !时间限制;; v' x' o* x# ?! y- D4 z. ~- B
- @for(car(jjj):6 |: [& ~0 b% A. U# o, Q
- time(jjj)>=-10;time(jjj)<=7);
, Q( A# X& U9 D( j
+ D/ @: ^\" Y8 W- @for(jiu(jjj):( @9 X6 D- h* K0 B9 j& K
- ct(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dt(which(I,jjj),which(I,jjj+1))+timexie(which(I,jjj)),0));2 ?! H# ~! s\" z0 w
4 d! \6 r\" [1 B3 R% z- @for(jiu(jjj):+ B% C0 ?) ~0 n8 j* W+ e
- time(I)+ct(I,jjj)>=time1(jjj+1);time(I)+ct(I,jjj)<=time2(jjj+1));4 d N( y9 E2 s- [6 w; X: Y
- - m! q, ~$ p/ J+ X
- !求每辆车行驶的距离;4 ]( _; {1 j0 h- G2 C% D8 R0 r
- @for(jiu(jjj):
! R+ b* {7 a. M8 F, C9 e - lucheng(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dd(which(I,jjj),which(I,jjj+1)),0) );6 p+ F% J/ k1 F# f7 Q; v
- );););
M! R' [4 \; M# J' D2 b - end
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