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发表于 2009-8-16 18:59
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修改一下循环的下标可以使得程序编译通过,但是不知道是不是和你的模型相符合,你仔细分析一下吧!
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7 ~ F% ~4 J5 w0 K1 ]- model:
/ v0 k+ F' c4 J) {8 e6 X( ? | - !n个货车8收点运输问题;
1 k: G& V: j4 ~9 J0 d) T2 h - sets:
0 @8 d& g$ q9 b7 z2 M+ P2 b - place/place1..place10/:time1,time2,timexie;
& u. n# G\" }1 p3 I6 g } - car/car1..car3/:time;
3 u7 o+ c1 U7 c( @, W7 K0 q8 w) c
8 k2 ^9 C5 ^! j3 B7 n$ A0 X- jiu/1..9/;
, g; B- w3 f5 q W! Y/ v: T, X - er/1..2/;+ A5 D4 u0 q$ _. }\" N
- $ c* w& }) E1 }9 K+ T; g
- lc(car,jiu):lucheng,ct;
9 z: A& D: s+ W+ } - plan(place,place,car):a;6 m4 S0 Z- r3 _3 L; ~
- distance(place,place):dd,dt,which;
' t5 ?0 m+ h6 A6 Q, ~. C& O+ T9 D - endsets
9 L$ [) a6 J7 S( c\" F - 0 P, |* L; U7 C9 b6 g2 |/ A$ |
+ b7 E7 Y% g* i. B- !这里是数据;, S3 c7 J# B4 | n9 y$ |+ Y8 f
- data:, }# o4 Z3 I+ E k# W: O2 O
- s=1;
+ C. d: h& n\" o- B; k, `% ~) f* Y - time1=-10 1 4 1 4 3.5 2 5 1.5 1;
' L, B( ~6 `% G7 _8 V2 a - time2=7 4 6 2 7 5 5 8 4 10 ;8 d/ q! ?. w7 q4 D
- timexie=0 1 2 1 3 2 2.5 3 0.8 0;
2 f8 q P, z5 B3 P9 _) i - $ t, s$ {- X; ?4 L% r- N% ^
5 F& ~& h2 \0 p+ m0 V5 ?' b- dd= m F. o6 o( V! l7 I; U& i
- 0 40 60 75 90 90 100 135 80 0
6 n. W+ k8 q7 l1 c; Q9 \ - 40 0 65 40 100 50 75 110 100 405 r5 E6 j! W9 X* [. a2 o
- 60 65 0 75 100 100 75 75 75 60/ k, Y) p\" Y$ `\" U- H
- 75 40 75 0 100 50 90 90 125 75/ `( J9 R* [) i( ^0 p, V
- 90 100 100 100 0 100 75 75 100 90
( j. k* m) H* B& c - 90 50 100 50 100 0 70 90 75 90
! U4 C8 T! _6 Z, c, h! v - 100 75 75 90 75 70 0 70 100 100 H* J6 Z: X+ ~8 g
- 135 110 75 90 75 90 70 0 100 1355 P# j% |4 E) p5 X# ^& X
- 80 100 75 125 100 75 100 100 0 80
: W7 G, j1 u' _. n3 W, Y# \3 J - 0 40 60 75 90 90 100 135 80 0 ;
8 K( ^1 F# ?0 l - dt= 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0
5 B\" O* {1 {( ]$ g6 C* S( q# _ - 0.8000 0 1.3000 0.8000 2.0000 1.0000 1.5000 2.2000 2.0000 0.8000
' N6 x' P2 k& Q& V5 _! [, F - 1.2000 1.3000 0 1.5000 2.0000 2.0000 1.5000 1.5000 1.5000 1.2000: w i. v) C& X- L4 {: G1 p' w- y
- 1.5000 0.8000 1.5000 0 2.0000 1.0000 1.8000 1.8000 2.5000 1.5000
7 X* h\" _% S; d; `8 h, }# A - 1.8000 2.0000 2.0000 2.0000 0 2.0000 1.5000 1.5000 2.0000 1.8000' n. _, P1 A, m) E* M4 l4 v
- 1.8000 1.0000 2.0000 1.0000 2.0000 0 1.4000 1.8000 1.5000 1.8000
# \, r$ g& k' G; h4 u) Y) w& u\" A - 2.0000 1.5000 1.5000 1.8000 1.5000 1.4000 0 1.4000 2.0000 2.0000* p2 g8 d$ q' J! F+ P) |* {& ~
- 2.7000 2.2000 1.5000 1.8000 1.5000 1.8000 1.4000 0 2.0000 2.7000\" {3 Z' w+ C0 P: o
- 1.6000 2.0000 1.5000 2.5000 2.0000 1.5000 2.0000 2.0000 0 1.6000( N c4 a\" F$ Z0 A$ t
- 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0;2 D' J0 x+ c7 W2 W' ~8 N& C
- enddata7 v% E8 b5 _0 ]& h1 k
4 q8 n K$ [# b1 X/ e; E- % d\" m% V; v% r g* H6 ^
- !目标函数;
7 L2 e; u# c% s2 Z1 g# B - min=@sum(lc(I,J): lucheng(I,J));# V5 C6 U4 U2 n
, f+ _& X5 {3 u; g. E5 E: l- !整数约束;
1 {- ~* i4 H' ?) a' m, o d - @for(plan:@bin(a));
* F0 R% r, N% v% j - @for(car(I):@free(time(I)) ;) y7 b# |\" x/ q+ v9 d\" `
- p3 _ A, x2 g8 p4 K( `( l- !从零点开始最终回来;1 F\" g) n( J) {5 L4 ]/ w3 H: F
- @for(car(I):. X( a0 i0 X: I4 _. B! [# J8 `
- a(1,1,I)=1;a(10,10,I)=1);
% X v$ \! U, Y8 v. U8 G0 T4 K5 y
; }7 F( e\" Y. r$ O- !每个任务只能有一个;\" q* a7 @- s5 s6 g
- @sum(car(I):
8 z0 L1 M( _4 q7 B7 v+ d% A - @sum(place(K):0 v. v6 q$ {& \$ [4 z5 N\" Z L
- @sum(place(J): a(J,K,I))))=1;2 D+ E) `5 y% v3 {
- 2 d/ _! d. ^: A8 W8 X
- !每个车的任务最多有四个;
% v/ a$ k+ u' e7 A7 R% j' d. K - @for(car(I):
* V# C0 H3 J& U - @sum(plan(J,K,I):a(J,k,I))<=6);
* p1 ]/ F( Z+ N4 g- L7 d$ A& ^ - $ }1 C5 a% g\" j' Y' j4 z
- !前一辆车任务大于等于后一辆车;0 E# R7 c\" |% H; n, e( d, B7 d
- @for(car(I)|I#lt#1:
) d+ _8 W+ {) t6 f3 T8 L - @sum(plan:a(J,K,I))>=@sum(plan:a(J,K,I+1) );
8 S+ E ~* ]) i7 d3 p% I
$ t( l, o! Q( ?/ O6 W6 r- !求which 例子 若a(1,:)=[1 0 0 1 0 1 0 0 0 1];
* X7 `/ g; s3 ]- p) K9 `' d3 u - ! 则 which(1,:)=[1 1 1 4 4 6 6 6 6 10] ;7 r; S! K- P5 P4 D: a# t$ t
- @for(car(I):. z\" n# g$ f0 o' x\" J. t\" c
- @for(place(kk)|@sum(place(jj):a(kk,jj,I)) #eq#1:& e, ^# y$ j5 x9 n9 S! S3 B
- @for(place(jj)|a(kk,jj,I) #eq#1:
8 v/ {. b/ o0 A) u% y& X& [1 } - which(I,kk)=jj ););+ ~ O5 O1 { v\" d5 O2 X0 R
- @for(place(kk)|@sum(place(kk):a(kk,jj,I)) #ne#1:! _7 D1 n, Y2 ?% t$ _# Z; S
- which(I,kk)=which(I,kk-1));9 j8 @2 P( o U: s- n( A
4 \0 @, Y8 U! S, L6 g\" y- !时间限制;
Z. E$ b9 q. h* Z6 t5 B - @for(car(jjj):
3 O+ M* Z4 i! X+ N0 @5 Z- h - time(jjj)>=-10;time(jjj)<=7);2 [7 T7 V; G! s* o) O
( I, @* K$ l9 T- @for(jiu(jjj):\" X2 G5 d. t9 _7 K, y9 [
- ct(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dt(which(I,jjj),which(I,jjj+1))+timexie(which(I,jjj)),0));7 L' G\" l: ]1 i' E7 y- ~\" v
- - W9 e. u% V% Q9 q, I9 k* v
- @for(jiu(jjj):. G' a! c/ J\" X, \: ^. B
- time(I)+ct(I,jjj)>=time1(jjj+1);time(I)+ct(I,jjj)<=time2(jjj+1));8 d+ k0 ^) T X
- , A5 D\" @' L: k; c1 C0 G; Q9 O: s
- !求每辆车行驶的距离;
/ a\" J8 V9 y) I7 S, v& a* | - @for(jiu(jjj):% Z* t9 P* B1 }( U- t* }( e
- lucheng(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dd(which(I,jjj),which(I,jjj+1)),0) );
' r: Z% J! q$ P% k5 ?+ Y4 U; @2 M - );););! e( T6 Q Z1 ]% [0 ]7 p2 s5 {
- end
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