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发表于 2009-8-16 18:59
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修改一下循环的下标可以使得程序编译通过,但是不知道是不是和你的模型相符合,你仔细分析一下吧!3 t# A7 M$ ?+ h8 L4 y, Q
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- model:\" ?* K8 M7 K4 O2 s% C
- !n个货车8收点运输问题;
- S1 ]3 \2 k6 ]3 a0 [8 P; R - sets:- K& G7 x& C0 `) l8 N+ n6 y/ V0 C
- place/place1..place10/:time1,time2,timexie;
. H) T0 J: E5 n$ [; h' n; y - car/car1..car3/:time;: m\" o' j2 P1 V8 K4 h
$ c8 h- ?, {6 y- jiu/1..9/;0 U+ Y\" e% p& T- o4 `
- er/1..2/;8 g1 F% w' Q4 k8 g
p) U4 Z3 Z\" o6 g* @- lc(car,jiu):lucheng,ct;6 I- Y7 B' u$ i0 T
- plan(place,place,car):a;
7 \% {- q, A% c - distance(place,place):dd,dt,which;- Z' F\" f* I9 U\" [* b5 c
- endsets
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$ o O9 _0 v# w ~7 [0 }8 s, i# X* e- !这里是数据;' o+ ^# g4 {+ ? n+ l
- data:
: o/ U1 Y1 N4 w3 `8 X6 J - s=1;$ k. f8 r: l% L3 C, T7 Z/ w1 ~
- time1=-10 1 4 1 4 3.5 2 5 1.5 1;
. ]- K3 f9 w5 }+ m+ \+ Q - time2=7 4 6 2 7 5 5 8 4 10 ;& o. `# E! w8 t5 Y% l
- timexie=0 1 2 1 3 2 2.5 3 0.8 0;
% ?. S4 q }% C4 L) N8 p
\" K& g; P, O% Z) r; G' c# S: Y9 Q6 e3 y- ' S M% J, X( f6 K; M' N
- dd=
0 M8 R3 ^# H, [$ { - 0 40 60 75 90 90 100 135 80 02 `6 o% s( x. Q! V, L; v
- 40 0 65 40 100 50 75 110 100 40- [/ `8 t+ [8 t1 p, J6 H
- 60 65 0 75 100 100 75 75 75 60
N3 k; h# w: p( f9 [3 ~5 W( T- ` - 75 40 75 0 100 50 90 90 125 750 \* n& \) U/ \
- 90 100 100 100 0 100 75 75 100 90
0 w- y$ R0 F1 N6 ^) i( }% J - 90 50 100 50 100 0 70 90 75 90
' g% u. Q\" M, i& T! D7 p @ - 100 75 75 90 75 70 0 70 100 100
# B# j6 Y7 l/ l! b5 o- q - 135 110 75 90 75 90 70 0 100 135& c8 j6 y E8 g
- 80 100 75 125 100 75 100 100 0 80+ V3 B' _* `6 E2 S
- 0 40 60 75 90 90 100 135 80 0 ;1 F2 G0 B\" A1 E
- dt= 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0: a' N9 c0 \; G- \
- 0.8000 0 1.3000 0.8000 2.0000 1.0000 1.5000 2.2000 2.0000 0.8000
& }) h6 ~; j1 S5 l - 1.2000 1.3000 0 1.5000 2.0000 2.0000 1.5000 1.5000 1.5000 1.20009 T; i+ @\" h) u3 Y4 ?; F
- 1.5000 0.8000 1.5000 0 2.0000 1.0000 1.8000 1.8000 2.5000 1.50008 N) g1 |& Q! ^# e' U+ h* d
- 1.8000 2.0000 2.0000 2.0000 0 2.0000 1.5000 1.5000 2.0000 1.8000% E% \6 o, @6 b$ W
- 1.8000 1.0000 2.0000 1.0000 2.0000 0 1.4000 1.8000 1.5000 1.8000
& m+ m- F- j9 z4 R6 d/ X7 P; a - 2.0000 1.5000 1.5000 1.8000 1.5000 1.4000 0 1.4000 2.0000 2.00006 `1 {. S) Y' l
- 2.7000 2.2000 1.5000 1.8000 1.5000 1.8000 1.4000 0 2.0000 2.7000( s! ?/ ^! V7 {* A6 z0 W
- 1.6000 2.0000 1.5000 2.5000 2.0000 1.5000 2.0000 2.0000 0 1.6000
1 s* h4 Q# M) q - 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0;% v; I\" P! Y$ o\" A$ |4 i3 ?
- enddata
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- 8 L! e: a1 j9 h! j) L
- !目标函数; l) R) H8 `, H5 `# _; w& ^0 V3 N
- min=@sum(lc(I,J): lucheng(I,J));' U% D* O8 u0 @
8 {# m8 }3 K6 @& ]/ C& `- !整数约束;
/ j2 z# w% |3 _5 q3 W# q3 h& } - @for(plan:@bin(a));8 O% T B$ m6 n/ @ U
- @for(car(I):@free(time(I)) ;
~4 K1 x% W! r - + b( Z u- F3 s
- !从零点开始最终回来;
, T6 x2 ^; C u$ V! P/ i: Y7 A. r - @for(car(I):
; I8 S/ ?6 r; J7 {- _' V# [ - a(1,1,I)=1;a(10,10,I)=1);7 [4 ?4 P1 ?% ^* y2 Z% i
5 ~1 [% T8 G) M* m2 Q- !每个任务只能有一个;
8 W4 D/ Y& u; s ` - @sum(car(I):# i. H1 p# F6 R9 S% R
- @sum(place(K):
5 X c- F. D+ Z) Y' _% W5 z - @sum(place(J): a(J,K,I))))=1;
0 X6 t Q7 m% y/ L9 i - ' @0 }( g& c# @8 U* X* N
- !每个车的任务最多有四个;
- ]/ q. M6 H; u2 }: z - @for(car(I):5 M8 e, M4 f8 u! z# c- f+ Z0 v
- @sum(plan(J,K,I):a(J,k,I))<=6);% U- u! I; P. ^% X, @7 e
- \" Z4 @4 F5 s2 _
- !前一辆车任务大于等于后一辆车;
7 C( a. }6 _\" \( D* e6 a# ]9 F - @for(car(I)|I#lt#1:
2 R0 H9 L( ~2 V7 O3 ~0 P - @sum(plan:a(J,K,I))>=@sum(plan:a(J,K,I+1) );! w3 b! L3 k* J9 q
, a8 ?6 J! a( s9 q' L: a- !求which 例子 若a(1,:)=[1 0 0 1 0 1 0 0 0 1];
$ s4 @+ z: `* t$ m) I' U - ! 则 which(1,:)=[1 1 1 4 4 6 6 6 6 10] ;- y* y1 b# l/ l
- @for(car(I):
8 L+ ^6 ?) [\" f# c7 O - @for(place(kk)|@sum(place(jj):a(kk,jj,I)) #eq#1:
9 ~: A! @( C% O: j4 l3 r2 @ - @for(place(jj)|a(kk,jj,I) #eq#1:9 P( a r7 k% o+ J2 f% Z2 A
- which(I,kk)=jj ););
; l7 n+ [1 U! M* f. ] - @for(place(kk)|@sum(place(kk):a(kk,jj,I)) #ne#1:% f& \ K\" `5 N4 k2 C
- which(I,kk)=which(I,kk-1));
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# l9 C0 ^6 H# X% h9 I7 G2 h3 w: S- !时间限制;
8 J( x3 @7 H, P0 N2 V - @for(car(jjj):$ D2 R6 h4 I8 P0 Y\" p
- time(jjj)>=-10;time(jjj)<=7);
- ~5 z$ A7 i4 D
& C* z Y# s: [- E\" @* a- @for(jiu(jjj):% b9 }, O4 t$ h+ y6 I1 ?0 Y; ?1 y
- ct(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dt(which(I,jjj),which(I,jjj+1))+timexie(which(I,jjj)),0));8 |4 u% W# M$ y S% H
`8 O3 l9 `7 W; u$ w% }- @for(jiu(jjj):
9 X5 w9 j/ t+ {! f0 |% } - time(I)+ct(I,jjj)>=time1(jjj+1);time(I)+ct(I,jjj)<=time2(jjj+1));! c) L6 x/ n4 U) H R
- # {* m0 \1 K% Y6 |
- !求每辆车行驶的距离;2 r9 V; g$ e8 u3 {' c& H4 O
- @for(jiu(jjj):
/ q! {* C0 K9 P0 f - lucheng(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dd(which(I,jjj),which(I,jjj+1)),0) );4 I% @% D. O% l5 c% n
- );););\" N3 N* H- }4 t: ]4 U/ X* E
- end7 i9 u: ] o, g& R. q) \4 V
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