求帮助，关于S1的积分，为什么我的结果带int啊，这是怎么回事。正确的应该怎么办！！

dyd

syms g v aA bA cA zA u  t1 t2;
int(g);
int(v);
8 w* S" F; [; V; X  Fh=0.856;
aA=(1+tan(g)*tan(g));
% y7 K4 U% V9 i' Q1 |bA=-(2*1.625+2*tan(g)*(h+30*tan(g))-30*tan(g));
cA=(h+30*tan(g)-15)*(h+30*tan(g)-15);
* E7 P% v# v3 i& ?; nzA=(-bA-sqrt(bA*bA-4*aA*cA))/(2*aA);
# ~1 o5 ^4 L( a2 `8 hya=h+30*tan(g)-tan(g)*zA;
8 a' t$ R& {, a5 }s1=(1.625*1.625-(z-1.625)*(z-1.625))*cos(v)*sqrt(tan(v)*tan(v)+1)*(sin(2*((asin(((h+30*tan(g)-z*tan(g))-15)/(sqrt(1.625*1.625-(z-1.625)*(z-1.625))*sqrt(tan(v)*tan(v)+1))))))/2-sin(2*((asin(-1/(cos(v)*sqrt(tan(v)*tan(v)+1))))))/2+((asin(((h+30*tan(g)-z*tan(g))-15)/(sqrt(1.625*1.625-(z-1.625)*(z-1.625))*sqrt(tan(v)*tan(v)+1)))))+((asin(-1/(cos(v)*sqrt(tan(v)*tan(v)+1))))));
0 I6 l& d6 H# |" y9 W9 `! wp=1.625-sqrt(1.625^2-((15-ya)/sqrt(tan(v)*tan(v)+1)));
" Y  U; F0 y, D$ w1 IH=int(s1,z,p,10);

厚积薄发

放个截图看看

①不小xin--!

啊啊啊啊啊啊是的的的的飞飞飞

dyd

厚积薄发 发表于 2012-5-9 16:25
; _7 ?* N8 V& ?+ ^" [1 Z: W8 {8 V4 k放个截图看看

! B! C: y  z4 R3 c4 z' I9 r
# z5 Y6 Q. t% n3 E好了···我想得到的是带g v h 但是对s1积分却积分不出来，即使积出来也带int 谢谢了
6 ]0 d* w7 Z4 [+ _- m9 _7 _! C

ealx0yJu

呵呵,打酱油的.