新手跪求指导

heugaodie

r = 3.04042*10^(-6);
p[x_] := x^5 - (2 + r) x^4 + (1 + 2 r) x^3 - (1 - r) x^2 +
  2 (1 - r) x + r - 1
- u* Q  F% O' L8 h3 Xq[x_] := p[x] - 2 r*x^2;
+ p' A- @; |, C! ]) Oa0 = 0.5; b0 = 1.5; delta = 10^(-6); k0 = 100;
a = a0; b = b0;
9 N! `; ?% E+ o! }' z7 mDo[x = (a + b)/2;
4 U3 ?- A9 S- }6 b% N& d% @ If[p[x] == 0, Break[], If[N[p[x]*p[b]] < 0, a = x, b = x]];
If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
x1 = x
" Z  Y# w0 B4 RClear[x]
. T5 s* G( d) @4 P8 oDo[x = (a + b)/2;
If[q[x] == 0, Break[], If[N[q[x]*q[b]] < 0, a = x, b = x]];
If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
1 `! x' R8 W" m; e& q1 T/ H% @- d* Ax2 = x
  S) G1 ^2 d2 dClear[x]
" t3 v+ ]5 g$ d8 H2 {. \. |9 M
我想让p q 两函数的解都求出来 每次都是两个一样的解（是第一个的）  明明用了clear的 怎么做

qudazi

你试一下将Clear[x]换成x=.看看

花如梦

别只用x,换个变量试试

小小灰

看不懂，看不懂