新手跪求指导

heugaodie

r = 3.04042*10^(-6);
p[x_] := x^5 - (2 + r) x^4 + (1 + 2 r) x^3 - (1 - r) x^2 +
2 o" o0 W0 N/ D+ ^6 n* E3 w  2 (1 - r) x + r - 1
: s- [* i. M0 ~+ f, y8 ^q[x_] := p[x] - 2 r*x^2;
2 _' X+ G- s0 t& k1 Ta0 = 0.5; b0 = 1.5; delta = 10^(-6); k0 = 100;
- z; B$ g# S( Ja = a0; b = b0;
Do[x = (a + b)/2;
9 \+ a) h/ b/ w' |4 G$ o& h/ V If[p[x] == 0, Break[], If[N[p[x]*p[b]] < 0, a = x, b = x]];
If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
x1 = x
Clear[x]
Do[x = (a + b)/2;
1 P5 A, u8 m0 i! \ If[q[x] == 0, Break[], If[N[q[x]*q[b]] < 0, a = x, b = x]];
8 L7 g' K. U5 b4 f2 B; _ If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
x2 = x
4 ^' W& {4 P* [2 f: J5 oClear[x]

我想让p q 两函数的解都求出来 每次都是两个一样的解（是第一个的）  明明用了clear的 怎么做

qudazi

你试一下将Clear[x]换成x=.看看

花如梦

别只用x,换个变量试试

小小灰

看不懂，看不懂