Lingo建模语言与实例4

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目标与约束段
$ Q  }$ ~( q2 n# x集合段（SETS    ENDSETS）
1 m# r! O- f9 L9 ]& ^数据段（DATA   ENDDATA）
初始段（INIT  ENDINIT）
; u+ h" N* s/ ~' O' l4 K: ^7 G（计算段 (CALC ENDCALC)）
" {6 w2 t- d* ?MODEL:
& _/ J- f$ P6 P! L, mTitle Location Problem;
sets:
- }- {8 c7 v7 v8 M    demand/1..6/:a,b,d;
/ L0 K8 {( I' A( u    supply/1..2/:x,y,e;
    link(demand,supply):c;
# @- f3 N- r! J9 M4 ]9 `endsets
# U# C2 t0 w; h( s" rdata:
a=1.25,8.75,0.5,5.75,3,7.25;
7 d3 B% L& e8 {6 D: U# C* pb=1.25,0.75,4.75,5,6.5,7.75;
2 U, R( c& ^9 C: t8 ?# A5 Z# |  Ud=3,5,4,7,6,11; e=20,20;
2 B9 D7 q; G9 S+ u6 Oenddata
$ R' Y1 M9 h; J. K8 dinit:
x,y=5,1,2,7;
6 ~0 @% F% ]2 n+ Mendinit
min=@sum(link(i,j):c(i,j)*((x(j)-a(i))^2+(y(j)-b(i))^2)^(1/2));
@for(demand(i)sum(supply(j):c(i,j))=d(i););
@for(supply(i)sum(demand(j):c(j,i))<=e(i););
# g3 [- |2 @  K  A. d* vEND
" F1 Y! A" ?0 g  Y1 W1 A

longde

好
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