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发表于 2009-8-16 18:59
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修改一下循环的下标可以使得程序编译通过,但是不知道是不是和你的模型相符合,你仔细分析一下吧!
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, o9 b8 X. }4 b& g$ |! t- model:
$ M) K: a4 D0 U% v' [ D3 D% B1 { - !n个货车8收点运输问题;
/ V( S) d6 l2 ~& J3 ^ - sets:( G# G5 V# Z* t+ V% u
- place/place1..place10/:time1,time2,timexie;
# D6 p, i, Z* Q: O\" {( Y8 P% f - car/car1..car3/:time;9 n4 t: @8 A' t' z4 _
8 |/ t7 _, |8 W- jiu/1..9/;- q5 c3 w+ g8 \% b! m2 O\" M
- er/1..2/;$ a, ]) R- v7 _3 t. _& |# j
- # I\" j! }1 l/ I: z% B2 D. V8 @$ {
- lc(car,jiu):lucheng,ct;0 [' f. k% V* j+ l
- plan(place,place,car):a;
( d$ o( A6 m. D; h+ p) a8 j4 ` - distance(place,place):dd,dt,which;
, i% }6 B2 Q7 O* p: O0 ` - endsets
! q' D0 A3 |& c1 ~6 l
' l( X' Q8 @ K `
7 f) X: L+ r! ?$ w; G- !这里是数据;7 C\" m$ d7 _9 j0 f. F( h
- data:6 U8 Z5 W0 D- |. j l
- s=1;+ a( h- o, Q$ A& s9 N3 f
- time1=-10 1 4 1 4 3.5 2 5 1.5 1;
7 b4 ?0 d5 v: D+ H+ a - time2=7 4 6 2 7 5 5 8 4 10 ;9 w6 W2 N2 Q' Y8 Y) Z# s
- timexie=0 1 2 1 3 2 2.5 3 0.8 0;
4 T% e! [$ R& {# g5 u7 b; U - , |: h) w. r0 @( K5 K2 a- K- U
- 7 z: m7 X, v B: H5 b
- dd=\" t+ {* n& l# r/ B- n
- 0 40 60 75 90 90 100 135 80 07 C: R' P7 B8 D3 F3 v7 t
- 40 0 65 40 100 50 75 110 100 40
; ]6 j9 W: Z6 l2 i4 } - 60 65 0 75 100 100 75 75 75 60
# J+ T% d& P% u( d - 75 40 75 0 100 50 90 90 125 75
& V2 ~4 M L: }0 W8 X7 R1 ~ - 90 100 100 100 0 100 75 75 100 90. C- s1 y: p+ @3 v& ~( F
- 90 50 100 50 100 0 70 90 75 909 k3 |. Y& x) |$ ?0 m V
- 100 75 75 90 75 70 0 70 100 100
4 N3 g$ d# ?* z - 135 110 75 90 75 90 70 0 100 135
M5 _9 i& x& p' S5 P! K; ` - 80 100 75 125 100 75 100 100 0 80
0 C% i9 k0 Y( q7 j7 r& _5 L9 Y - 0 40 60 75 90 90 100 135 80 0 ;; x+ ^' \' ~& w6 r0 @
- dt= 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0, g$ c3 e% N6 V8 T
- 0.8000 0 1.3000 0.8000 2.0000 1.0000 1.5000 2.2000 2.0000 0.8000$ J\" w- y( H! J+ f. S
- 1.2000 1.3000 0 1.5000 2.0000 2.0000 1.5000 1.5000 1.5000 1.2000) R3 [( G\" p7 P; L8 w
- 1.5000 0.8000 1.5000 0 2.0000 1.0000 1.8000 1.8000 2.5000 1.5000. V1 A8 I2 ^1 ^# l$ A4 Q, ^
- 1.8000 2.0000 2.0000 2.0000 0 2.0000 1.5000 1.5000 2.0000 1.8000
: y0 p1 j$ Y u. w( X- Q8 B& F% t - 1.8000 1.0000 2.0000 1.0000 2.0000 0 1.4000 1.8000 1.5000 1.8000
; b9 U+ ~0 a9 `9 { - 2.0000 1.5000 1.5000 1.8000 1.5000 1.4000 0 1.4000 2.0000 2.0000
/ r' f4 ]9 H3 e8 f - 2.7000 2.2000 1.5000 1.8000 1.5000 1.8000 1.4000 0 2.0000 2.7000
/ Z! h9 t7 P1 E2 N - 1.6000 2.0000 1.5000 2.5000 2.0000 1.5000 2.0000 2.0000 0 1.6000
% i- h* o4 z& E; _\" p _ - 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0;
6 f) D: ~1 Z8 P& } - enddata( V* M+ {$ Q3 y: Z- ^: Z$ c
' ~% C* ], \; }# ~; S- ! a# H) d- A/ d\" M) D8 C
- !目标函数;2 n3 \* f5 b2 n# a4 H1 e; l. T
- min=@sum(lc(I,J): lucheng(I,J));
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, }, S( N+ W/ y* F: N/ ^- !整数约束;4 q) i2 E1 R0 [4 R9 U9 ^
- @for(plan:@bin(a));
W, c+ a6 S V d6 { - @for(car(I):@free(time(I)) ;# G# ~3 Y) W8 K. ^; ~\" r
- - ~' y7 K( V$ N5 J\" P- ^
- !从零点开始最终回来;
. y& x: W$ z9 d% N - @for(car(I):
' ~# ]0 M9 }0 N8 L - a(1,1,I)=1;a(10,10,I)=1);
: N8 [( ?* J8 m9 Y2 T* M
3 M5 u P* S9 t) v/ U; o5 R- !每个任务只能有一个;4 N+ W$ ?3 [( T! ]( v
- @sum(car(I):9 G8 h; I1 Y) T' X. D
- @sum(place(K):$ {; `2 E: i8 O! |& o x( A3 z! M
- @sum(place(J): a(J,K,I))))=1;
; ?& f$ N' Y\" T3 ]) o
N( u( }# ]4 L+ o- !每个车的任务最多有四个;
\" i% s+ W: V K. t - @for(car(I):
0 L2 f5 c+ m; s% w$ A - @sum(plan(J,K,I):a(J,k,I))<=6);
/ E( d4 l0 C+ Q N9 ]5 M - : C/ x* n0 a! V. n
- !前一辆车任务大于等于后一辆车;
% H/ \9 J' O8 M+ v+ ~9 \ - @for(car(I)|I#lt#1:
3 N* M7 _) S\" Y9 n# X4 [9 N1 v6 @ - @sum(plan:a(J,K,I))>=@sum(plan:a(J,K,I+1) );- s8 {3 f% U* ]) Y2 M
- & [2 j& P! j& L4 }/ v4 I3 Q' E
- !求which 例子 若a(1,:)=[1 0 0 1 0 1 0 0 0 1];* |# `7 \! o7 ~1 ^0 N
- ! 则 which(1,:)=[1 1 1 4 4 6 6 6 6 10] ;
2 f4 @+ K+ X% V! n5 N\" S - @for(car(I):
C3 _8 m0 F' v+ F4 ~; e9 U - @for(place(kk)|@sum(place(jj):a(kk,jj,I)) #eq#1:
; d% k* N K! t r - @for(place(jj)|a(kk,jj,I) #eq#1:, _# a) J2 s. c7 J\" r
- which(I,kk)=jj ););
4 _3 a- x2 ], _ F6 v( j - @for(place(kk)|@sum(place(kk):a(kk,jj,I)) #ne#1:
, N) i) P& R\" x8 B& L - which(I,kk)=which(I,kk-1));! Y# O3 ~9 S\" l
- ( P, `4 A$ \- ]; ?
- !时间限制;0 q: {& ]8 Z6 _' j8 C\" h5 G5 C
- @for(car(jjj):
; }1 U6 h/ |) o, `. L% P+ s( ?: h - time(jjj)>=-10;time(jjj)<=7);8 v$ J) u, `/ D) }* q
- 9 H$ `\" J: \5 V/ e! J3 Z) ^( N
- @for(jiu(jjj):
2 L( K- L! }# c7 D - ct(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dt(which(I,jjj),which(I,jjj+1))+timexie(which(I,jjj)),0));
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2 P, K. \4 ]0 c- @for(jiu(jjj):3 A1 ?$ X( Z8 V8 b( \4 W; L4 Q
- time(I)+ct(I,jjj)>=time1(jjj+1);time(I)+ct(I,jjj)<=time2(jjj+1));
& P9 \* J0 ^, h2 t0 b3 y# N4 M - * q0 v% J9 o w9 ?) |, C\" q
- !求每辆车行驶的距离;
( c+ S! o2 o$ n - @for(jiu(jjj):
/ C1 v6 D# x* W5 a+ L2 \ - lucheng(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dd(which(I,jjj),which(I,jjj+1)),0) );. O: |8 U( @5 f. t1 ~4 l
- );););
8 |# j+ _5 J$ d# \4 h) c - end1 b5 s; }5 L+ R3 b! r+ Y7 l; d0 U
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