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发表于 2009-8-16 18:59
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修改一下循环的下标可以使得程序编译通过,但是不知道是不是和你的模型相符合,你仔细分析一下吧!
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3 ]+ P' _! c% b! t- model:
5 i0 X5 Y9 h5 z! e) J+ O$ i2 M - !n个货车8收点运输问题;4 t- c- l% P: l
- sets:
4 e* F; D6 [4 E% z! W* d3 j\" S - place/place1..place10/:time1,time2,timexie;- a% J x% m0 { ?, p0 D8 A* a, U
- car/car1..car3/:time;) [* }, @- ]0 I
- , c# k6 I* D% P* \, n$ g/ R; v
- jiu/1..9/;2 t5 O8 _+ z9 A( ~: T0 _2 b; M/ B
- er/1..2/;4 I% y* Z' u6 x
, Q. @7 l3 Y! e( w0 j! f! x- lc(car,jiu):lucheng,ct;
8 Z, n\" t8 R# J8 {# ` - plan(place,place,car):a; U4 g! g* {5 Q
- distance(place,place):dd,dt,which;5 _7 n$ \; N7 W4 b- ]% f) E/ X
- endsets
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- 6 U1 w8 R: I# a' P; C
- !这里是数据;3 [1 p {+ A I
- data:
\" q! x2 e: Y( I) i) \; t - s=1;! s5 F3 y1 ?) v5 Y& A) L! ]
- time1=-10 1 4 1 4 3.5 2 5 1.5 1; & \0 l* F: }( H0 U: w) Y2 B: C
- time2=7 4 6 2 7 5 5 8 4 10 ;
, T1 Y9 W, S1 e - timexie=0 1 2 1 3 2 2.5 3 0.8 0;: U) W6 q6 h- u4 I
- $ _- I. H2 H8 V$ e
- ' R6 n+ z0 V$ D; b! ?9 I. {+ d
- dd=
* \3 _2 N* ~5 I6 S7 S - 0 40 60 75 90 90 100 135 80 0\" L% ?\" H0 h/ ?/ o( y
- 40 0 65 40 100 50 75 110 100 40
2 f, Y\" |5 S. `$ ^\" I u\" @6 y - 60 65 0 75 100 100 75 75 75 60/ M! ]9 `4 J\" G E
- 75 40 75 0 100 50 90 90 125 75: n8 w4 {\" \( F2 [
- 90 100 100 100 0 100 75 75 100 901 T/ |6 L4 k U2 Z/ v* x
- 90 50 100 50 100 0 70 90 75 90
( A4 b- M\" o5 n3 `# ?, M - 100 75 75 90 75 70 0 70 100 100% u# l0 x8 t0 X' f& i2 r
- 135 110 75 90 75 90 70 0 100 1356 `\" n4 R( M. b7 B( M* x
- 80 100 75 125 100 75 100 100 0 803 `7 A0 T6 W0 n5 x+ T
- 0 40 60 75 90 90 100 135 80 0 ;. y& r* A7 y( Y( o* R# Z5 [. r
- dt= 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0
0 c& R+ [% C4 J! b* p* ?- L% O - 0.8000 0 1.3000 0.8000 2.0000 1.0000 1.5000 2.2000 2.0000 0.8000
1 l! c$ D! L1 G6 `$ @ - 1.2000 1.3000 0 1.5000 2.0000 2.0000 1.5000 1.5000 1.5000 1.2000
$ U% A6 e; I# k3 M0 A3 q - 1.5000 0.8000 1.5000 0 2.0000 1.0000 1.8000 1.8000 2.5000 1.5000) ] L1 F1 F* i; {
- 1.8000 2.0000 2.0000 2.0000 0 2.0000 1.5000 1.5000 2.0000 1.8000
8 y5 B/ }6 P7 s4 u) A& i - 1.8000 1.0000 2.0000 1.0000 2.0000 0 1.4000 1.8000 1.5000 1.8000) t4 L: G& d+ t, J( T
- 2.0000 1.5000 1.5000 1.8000 1.5000 1.4000 0 1.4000 2.0000 2.0000# l# O B, T+ A6 T- |
- 2.7000 2.2000 1.5000 1.8000 1.5000 1.8000 1.4000 0 2.0000 2.7000
) `/ p0 B2 k) @# j\" H5 {# R9 l - 1.6000 2.0000 1.5000 2.5000 2.0000 1.5000 2.0000 2.0000 0 1.6000
4 i! U5 b: L0 P - 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0;, o' X, A0 A\" s f3 M, ~
- enddata
. x; c6 m+ d+ {% V+ ^, R - * }& c( {7 [4 j% \
+ a, f m. `3 I4 P0 ?- !目标函数;
- }: Y/ ~' X0 Z/ _' z( ^ - min=@sum(lc(I,J): lucheng(I,J));+ v9 X7 o! D7 i/ Z5 L2 R2 H! Y
- $ E) |* S/ ^1 ~# i* a# N
- !整数约束;
4 I! O3 S# f4 `$ F - @for(plan:@bin(a));
# k! w% X2 G2 n% B9 L, N! ] - @for(car(I):@free(time(I)) ; X# o. T\" j* V# d' d- I
- / O, u2 {( T) S5 A
- !从零点开始最终回来;
2 q. l' J; _; R' b- E$ } - @for(car(I):1 m; S: H; M$ {' h# r) @
- a(1,1,I)=1;a(10,10,I)=1);
3 L+ g* ^' ~9 x' c- A - 3 k/ H3 T4 O: D8 Z# A* Q' ]2 O
- !每个任务只能有一个;9 x0 I% i$ G1 {0 N# _: Y
- @sum(car(I):4 |% P8 J/ }# o- i1 X) y- m8 h
- @sum(place(K):' C+ |3 S3 H+ v( {0 z0 r' k
- @sum(place(J): a(J,K,I))))=1;* }! W+ z# R* X\" v$ q- h
- 9 ?) q, z- O4 t7 P0 Z# L1 n6 A
- !每个车的任务最多有四个;
. y, G8 w* m1 [- ~4 s9 e4 e - @for(car(I):
& P! i3 X4 C\" m5 [/ e' ? - @sum(plan(J,K,I):a(J,k,I))<=6);3 K: k+ D& }/ V; T
# F# a( P4 u& T: X5 [' j* |- !前一辆车任务大于等于后一辆车;
/ K1 n' J9 Q0 K- c8 S/ } - @for(car(I)|I#lt#1:
( [\" ]- `: ^7 R' r - @sum(plan:a(J,K,I))>=@sum(plan:a(J,K,I+1) );3 E, E( a, m5 a$ E
- . ^6 k( m$ v\" ~7 h
- !求which 例子 若a(1,:)=[1 0 0 1 0 1 0 0 0 1];
3 q n& a3 r3 L4 B3 q# x6 Q\" ~ - ! 则 which(1,:)=[1 1 1 4 4 6 6 6 6 10] ;; ], ^\" O4 ?- J8 b$ f
- @for(car(I):, n+ ?1 r0 s\" g/ A\" ~: R
- @for(place(kk)|@sum(place(jj):a(kk,jj,I)) #eq#1:
+ i/ U: a d\" x7 L! {4 G - @for(place(jj)|a(kk,jj,I) #eq#1:
* W8 H# c% B8 t* H& ]1 E - which(I,kk)=jj ););, f1 P3 o) M$ E+ g- L
- @for(place(kk)|@sum(place(kk):a(kk,jj,I)) #ne#1:
! ~8 x1 o* p9 n& \6 ?* Q\" R - which(I,kk)=which(I,kk-1));
4 V4 \7 y+ Q* L9 N6 h# K - 2 [4 p, e+ q+ I8 H {! o
- !时间限制;
5 I! q6 B. F6 s1 ]( N - @for(car(jjj):
5 l4 S c1 V1 K6 a! o5 m+ g# j' J: v - time(jjj)>=-10;time(jjj)<=7);, g _: O9 A# g7 Z% V
- . T! H y( w% k- n
- @for(jiu(jjj):& K7 e# F: b/ m) Y+ _9 V
- ct(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dt(which(I,jjj),which(I,jjj+1))+timexie(which(I,jjj)),0));( Y0 |2 F/ c3 N+ M, M
\" j$ M! ~: X) ^7 P9 @- @for(jiu(jjj):! k5 H& g% I. h; \
- time(I)+ct(I,jjj)>=time1(jjj+1);time(I)+ct(I,jjj)<=time2(jjj+1));
. Y% n\" T9 C2 A - 5 G; X0 P# O0 P5 p# [6 q
- !求每辆车行驶的距离;
+ p; ]6 `( I! a# J5 ]1 x' e - @for(jiu(jjj):7 N( L! F, y1 ^1 C
- lucheng(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dd(which(I,jjj),which(I,jjj+1)),0) );
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- end
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