谁来帮忙看一下这个题错在哪里？

Winter_moon

Cryptoquote
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Time Limit: 1000 ms Memory Limit: 65536 kB
Solved: 79 Tried: 281

% K  w5 C6 s4 ?7 S) r4 ODescription
6 b* j0 z5 p& x% P; _( t6 vA cryptoquote is a ** encoded message where one letter is simply replaced by another throughout the message. For example:
) a' q4 T& M) c% t2 {8 _
Encoded: HPC PJVYMIY
Decoded: ACM CONTEST

In the example above, H=A, P=C, C=M, J=O, V=N, Y=T, M=E and I=S. For this problem, you will decode messages.
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  O+ ?; l7 j  N
+ @3 p2 G# `$ V. _' m4 Y% ^# gInput
The first line of input contains a single integer N,(1<=N<=1000) which is the number of data sets that follow. Each data set consists of two lines of input. The first line is the encoded message. The second line is a 26 character string of upper case letters giving the character mapping for each letter of the alphabet: the first character gives the mapping for A, the second for B and so on. Only upper case letters will be used. Spaces may appear in the encoded message, and should be preserved in the output string.



Output
4 E) l& S3 \' ]; w4 ^4 LFor each data set, you should generate one line of output with the following values: The data set number as a decimal integer (start counting at one), a space and the decoded message.


* d  a  g  J" a+ b; G+ C' MSample Input
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HPC PJVYMIY
; A* K2 r; p1 R* u0 @BLMRGJIASOPZEFDCKWYHUNXQTV
" G5 a. A3 u: W/ i/ c% uFDY GAI BG UKMY
; E* \- W7 @9 D' SKIMHOTSQYRLCUZPAGWJNBVDXEF
8 H6 j7 c. k3 y! t+ P8 N9 x
8 H/ S% H2 `2 \+ |

Sample Output
8 D1 s  w; S, T1 ACM CONTEST
2 THE SKY IS BLUE
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, ^3 f* v3 \+ _* [+ V" W3 X我的代码是：
) k- F: c: C4 M# y9 y#include<stdio.h>
#include<string.h>
! {! ~* N" W& D7 c5 O2 iint main()
7 L9 L6 |* @  H{
     int N,i,j,k;
     char c;
     char code[1000];
, C& h% f' E. w$ R6 \3 S     char map[27];
: t% v; k: w! l! r. N     char trans[1000];
     char wrong[3];
     scanf("%d",&N);
     gets(wrong);
1 O% S: B$ W: U# c' b) t5 s     int h=1;
     while(N--)
6 I1 `! R7 p. P( I, H/ k& l     {
         gets(code);
6 E% m- z3 U1 s* \7 V- [1 ^) D         gets(map);
8 ?% F. W) v' W; O         for(i=0;((c=code[i])!='\0');i++)
% J$ y: K9 `% O2 s# V: C- z. j         {
             if(c==' ')trans[i]=' ';
             else {j=code[i]-'A';
             trans[i]=map[j];}       }
         printf("%d ",h);
' l' D0 i, t$ p1 S         for(i=0;((k=trans[i]<=90)&&(k=trans[i]>=65)||(k=trans[i]==' '));i++)
         printf("%c",trans[i]);
& w! ~4 K3 m1 E) E0 }! c         h++;
% Q5 r. v$ x6 ]8 j+ a         printf("\n");
$ U; u3 o# ^* l     }
4 ^2 l% }# D0 z$ g     return 0;
6 W7 n0 [* O2 X9 z. S}


样例过了，但是提交答案的时候还是wrong answer。是哪里有陷阱？
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zjqylcy

把答案也附上来吗。。。
是不是k是int型？

葉_浅浅

.....................

linmatsas

C………………………………

_我还活着

没有看懂.....

huangliao6252

int h=1;这个定义应该在 scanf("%d",&N);前面。