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发表于 2009-8-16 18:59
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修改一下循环的下标可以使得程序编译通过,但是不知道是不是和你的模型相符合,你仔细分析一下吧! \, r2 M& r) w6 a/ h
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- model:8 G7 v1 z8 p2 L9 b5 }! c, x
- !n个货车8收点运输问题;% N( l6 `) ]( a! E! x# g
- sets:7 |0 F- k5 ^3 Y
- place/place1..place10/:time1,time2,timexie;. x4 P3 \, s9 G* c
- car/car1..car3/:time;0 J6 L& q* p9 U v
& Z: @! a; Y W\" `, f- _- jiu/1..9/;' l: O O' A% |$ @+ l
- er/1..2/;- _- t. W* @! ^- j
) e8 R- n2 ~/ l z- lc(car,jiu):lucheng,ct;8 i2 t7 p, G, V' f% I
- plan(place,place,car):a;
. a\" d7 D* ^6 E E - distance(place,place):dd,dt,which;
) N3 F4 a; S$ l1 i\" t! A& J5 R - endsets5 A& u* y# j ~( \
- n4 d7 r4 a6 }, F\" |& s- ( P6 h; e5 f. |# W\" ?7 c
- !这里是数据;2 O1 C\" A# m( k! J6 s. ?4 L$ R I
- data:
. h5 t: f; r- @$ j+ Z$ o( j - s=1;
% r% C' _6 F5 ~( S - time1=-10 1 4 1 4 3.5 2 5 1.5 1;
0 A2 I8 V0 ]7 O9 U( t - time2=7 4 6 2 7 5 5 8 4 10 ;
1 t$ v8 h\" }& n- | - timexie=0 1 2 1 3 2 2.5 3 0.8 0;
# K7 x$ T' \. \0 b) ^0 s
9 U' R2 ]: b0 D1 c. m* ]
& t' z- V4 f0 h/ N, `5 V( p- dd=4 M7 Q- R7 P; v: S* m+ b3 R
- 0 40 60 75 90 90 100 135 80 04 A6 o9 ~4 q2 I2 u: H) @5 A$ p
- 40 0 65 40 100 50 75 110 100 40
, n5 @- d6 @# G0 Q' Y, D! |- Y - 60 65 0 75 100 100 75 75 75 60
( u$ Y\" B5 _+ F Q - 75 40 75 0 100 50 90 90 125 755 \6 r c7 q\" c6 o1 K) J
- 90 100 100 100 0 100 75 75 100 90
; B: t+ ?' G) ]3 m. d. z9 Z/ k - 90 50 100 50 100 0 70 90 75 90
9 K( F- N6 B- u - 100 75 75 90 75 70 0 70 100 100
; P; E0 _' l5 Z* i- e$ g - 135 110 75 90 75 90 70 0 100 135! M. K! ~' K7 s
- 80 100 75 125 100 75 100 100 0 80) m! ~. ~4 ?1 T4 n6 |7 k1 f$ ~
- 0 40 60 75 90 90 100 135 80 0 ; S, y$ ^( F% @
- dt= 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0: w0 F' T( Y k2 \7 Q, w3 v7 Y
- 0.8000 0 1.3000 0.8000 2.0000 1.0000 1.5000 2.2000 2.0000 0.8000 y P: `/ u& H
- 1.2000 1.3000 0 1.5000 2.0000 2.0000 1.5000 1.5000 1.5000 1.20006 S8 H! T- {, ]8 u2 Y! {* `; f
- 1.5000 0.8000 1.5000 0 2.0000 1.0000 1.8000 1.8000 2.5000 1.5000 B5 i& V8 X4 L: o, _# _ ?( j4 H
- 1.8000 2.0000 2.0000 2.0000 0 2.0000 1.5000 1.5000 2.0000 1.80000 u* [2 Z- Y7 ~, x' L) l
- 1.8000 1.0000 2.0000 1.0000 2.0000 0 1.4000 1.8000 1.5000 1.8000; v1 B0 }# u0 b. G( ~1 t- d% f3 J
- 2.0000 1.5000 1.5000 1.8000 1.5000 1.4000 0 1.4000 2.0000 2.0000! O! H+ ]; |& d# y! S# p
- 2.7000 2.2000 1.5000 1.8000 1.5000 1.8000 1.4000 0 2.0000 2.70007 d+ J& z: d$ W$ _7 A
- 1.6000 2.0000 1.5000 2.5000 2.0000 1.5000 2.0000 2.0000 0 1.6000
# S$ m. k\" a- r6 Y5 @+ f: E1 W2 G9 H! \ - 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0;
6 K2 o9 m) x4 d8 p4 P7 F4 ^ - enddata
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- : D- ?: _\" D9 }* E# E/ a$ K
- !目标函数;
& @\" m\" k, q\" u! A3 Z) M - min=@sum(lc(I,J): lucheng(I,J));4 y' K g# n) r
- \" F- i B2 x) r& o
- !整数约束;( I2 t8 m1 w4 V
- @for(plan:@bin(a));
3 f/ P/ y1 ]. ]5 ? c. }\" S - @for(car(I):@free(time(I)) ;: b7 b: `, ]+ K/ |
1 t% O( y. }/ t% n$ v$ @9 p- !从零点开始最终回来;
/ K( s* R# G; n\" k - @for(car(I):
_& k4 b4 b% U3 H3 Y8 ? - a(1,1,I)=1;a(10,10,I)=1);+ _ Z6 G* F3 Y4 {$ x- _
) l* Q% t2 I9 A! V! c- !每个任务只能有一个;& t2 [8 z8 H/ }. a2 r7 u& h
- @sum(car(I):: u1 c: p* K4 } B( S
- @sum(place(K):
$ w9 t9 r! S6 v4 A- O0 O - @sum(place(J): a(J,K,I))))=1;/ G, o4 n' Y( F5 m% L
( n8 u2 u* f) Y8 A3 e* `+ r9 m- !每个车的任务最多有四个;
x6 ]: h0 ? ^6 @4 D$ x# ? - @for(car(I):
( q) J: M\" n7 e; C( @% D3 F7 ^ - @sum(plan(J,K,I):a(J,k,I))<=6);
# S5 t$ U! I# H+ F2 \+ m
/ m' X* t7 S1 |8 k: M6 b- !前一辆车任务大于等于后一辆车;+ D; ^( f5 j, ]
- @for(car(I)|I#lt#1:' r: H7 b5 ?\" A. i! A$ j
- @sum(plan:a(J,K,I))>=@sum(plan:a(J,K,I+1) );( c4 Z C0 t; k- D- w! \
- ; O' G! ?' y& t T2 u- C# y+ x5 T7 h8 l
- !求which 例子 若a(1,:)=[1 0 0 1 0 1 0 0 0 1];
& ^% u* w; [' _5 d; w0 N - ! 则 which(1,:)=[1 1 1 4 4 6 6 6 6 10] ;
& H+ n! j8 f+ K9 ^- { - @for(car(I):/ [! g0 }+ k; m; u
- @for(place(kk)|@sum(place(jj):a(kk,jj,I)) #eq#1:. f, u' ^3 }! Q9 V( n ?, }9 r
- @for(place(jj)|a(kk,jj,I) #eq#1:
' c0 J# ~\" g9 l - which(I,kk)=jj ););
! y. e( K9 h% s; n! f- U/ T& W4 @. C - @for(place(kk)|@sum(place(kk):a(kk,jj,I)) #ne#1:! \\" a7 F& x( B! u) U7 h
- which(I,kk)=which(I,kk-1));
* p9 i- D. K9 P5 G# h# D4 X3 q s! ^ - $ P2 G' @' i7 k% \
- !时间限制;2 B' P3 L3 k2 `
- @for(car(jjj):+ o% |\" o/ _, a& f- |6 F7 O* e3 P4 a
- time(jjj)>=-10;time(jjj)<=7);
% B0 T6 K, x! ?( r. X' G3 {5 f: r
: X7 e: k3 n0 A7 b9 |- @for(jiu(jjj):
+ e9 u. i1 k( n7 E% R9 [; f0 D - ct(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dt(which(I,jjj),which(I,jjj+1))+timexie(which(I,jjj)),0));% T% P! f t9 ^3 D# N3 Z* n
8 z$ q, i! p/ x8 C& J- @for(jiu(jjj):
. s( c; A: e3 M8 s+ b9 P - time(I)+ct(I,jjj)>=time1(jjj+1);time(I)+ct(I,jjj)<=time2(jjj+1));\" m2 u+ Z& v% }6 T
$ Q& m! e7 |5 o. z& N1 l- !求每辆车行驶的距离;
1 o+ K. L3 s& G& {% Z/ w+ y - @for(jiu(jjj):3 A/ {. o F2 x5 c- ] Q! Z
- lucheng(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dd(which(I,jjj),which(I,jjj+1)),0) );
: D; S9 a# B& m: y$ c - );););
- e\" L$ h* I0 B) d! z - end
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