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发表于 2009-8-16 18:59
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修改一下循环的下标可以使得程序编译通过,但是不知道是不是和你的模型相符合,你仔细分析一下吧!' f7 F& P' t) W% x% N
0 y- a3 _+ ^: T. C$ J! W/ P+ v
- model:
c\" V' U# W1 Z2 N# y\" @ - !n个货车8收点运输问题;
( _. R1 N5 g( O7 b\" P6 ~ - sets:
% U! p9 i+ v3 e - place/place1..place10/:time1,time2,timexie;8 q: |+ E P, L0 H1 a8 Q7 n1 d; r
- car/car1..car3/:time;
; m5 n1 O2 X$ I) d9 T7 Y
9 v6 \2 I/ b0 D7 D1 d1 u- jiu/1..9/;( Q! i% D' X\" @+ w& y+ o3 f8 B' |) x
- er/1..2/;9 f, |2 s% J8 \1 ^
- ( m2 k# _4 q3 t* ]. h Z2 U! T4 m
- lc(car,jiu):lucheng,ct;
8 G! Z7 u5 J7 L! b8 v: I5 {+ N/ [ - plan(place,place,car):a;2 _( X8 d% A- z
- distance(place,place):dd,dt,which;
6 V$ H! q/ {4 M) ]( ` - endsets\" e7 y2 Q% K9 A4 o
- ' x\" f+ e# [, F. t5 N
. z& v; K5 ~' s. Y6 K# D# ^- !这里是数据;
9 p o( B7 P( i; H8 l - data:
3 @9 v. s7 `% O) M% Y\" q& e - s=1;
: B- O& _; }! T6 v/ H - time1=-10 1 4 1 4 3.5 2 5 1.5 1; ; s( Y- o2 K\" U\" X4 L8 f$ l% z- {
- time2=7 4 6 2 7 5 5 8 4 10 ;# p( n# `$ j4 E
- timexie=0 1 2 1 3 2 2.5 3 0.8 0;\" R5 J: p8 h- _' R& a\" |- O
4 A# {0 h1 w% s\" }3 `: f6 f5 ^
& j6 V; R# q a5 x- dd=1 N\" M1 L# D b! T\" F7 t
- 0 40 60 75 90 90 100 135 80 0
, [$ b& p# m\" U\" v - 40 0 65 40 100 50 75 110 100 40
' B# [/ m: _. d8 B - 60 65 0 75 100 100 75 75 75 60. k4 g* J7 C# m& v
- 75 40 75 0 100 50 90 90 125 75. h, m/ X8 F% @ P
- 90 100 100 100 0 100 75 75 100 90
+ a# q- C5 w! [0 X Q) x' L# w - 90 50 100 50 100 0 70 90 75 909 N' t5 h$ \0 ^/ t6 K V: e# y& a# L
- 100 75 75 90 75 70 0 70 100 100
+ @* @: k: _: ?. B7 V/ P - 135 110 75 90 75 90 70 0 100 1355 {! E$ ^. s5 P' u3 ]* o
- 80 100 75 125 100 75 100 100 0 80
; O! h. d' x) Y: v! U3 a; p6 q7 G - 0 40 60 75 90 90 100 135 80 0 ;
7 e; c0 J& w/ h) a9 @ - dt= 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0
8 Y0 s; ]8 J! A7 P/ K7 b - 0.8000 0 1.3000 0.8000 2.0000 1.0000 1.5000 2.2000 2.0000 0.8000( @+ E4 D# p+ S S& w
- 1.2000 1.3000 0 1.5000 2.0000 2.0000 1.5000 1.5000 1.5000 1.20008 r+ `. M, H+ f
- 1.5000 0.8000 1.5000 0 2.0000 1.0000 1.8000 1.8000 2.5000 1.5000
, y6 a, ~\" E! e9 D$ e - 1.8000 2.0000 2.0000 2.0000 0 2.0000 1.5000 1.5000 2.0000 1.8000
b J l8 F* ^* ~8 N T - 1.8000 1.0000 2.0000 1.0000 2.0000 0 1.4000 1.8000 1.5000 1.8000: E\" p; f, `- X1 n; T' J( K9 i
- 2.0000 1.5000 1.5000 1.8000 1.5000 1.4000 0 1.4000 2.0000 2.00004 s* D, v o6 F' X! ~\" B7 D/ S
- 2.7000 2.2000 1.5000 1.8000 1.5000 1.8000 1.4000 0 2.0000 2.70005 F4 k* |1 ?# U! O+ R$ \+ w
- 1.6000 2.0000 1.5000 2.5000 2.0000 1.5000 2.0000 2.0000 0 1.6000
9 z- Y\" P4 N, s - 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0;
( v- T* T+ z* i, r - enddata: v% T5 B- |: M1 _; n$ m% _! t
- ) n5 N# h\" D& G0 O
+ O( q6 i7 w9 H# `- !目标函数;\" q/ H: N ^* _+ |9 O4 ~
- min=@sum(lc(I,J): lucheng(I,J));
: @9 _- H! }' n( i* v i k% t
4 [! V5 z$ S; R0 ?- !整数约束;
$ X( M2 @, `/ q$ M6 H3 m; k - @for(plan:@bin(a));
, n; A# K7 q% f) M7 s5 P/ B7 J, E - @for(car(I):@free(time(I)) ;
U) T; a6 _5 I( e8 l7 r - . M$ I8 K3 M. L, M) x5 c& Z% f9 y# T
- !从零点开始最终回来;% a0 d) [* }, F- a9 N
- @for(car(I): t5 W: y1 t$ _/ T
- a(1,1,I)=1;a(10,10,I)=1);* O0 z% h& V8 b$ X0 _
- # l R. i9 ], L\" S4 e6 C) D, B
- !每个任务只能有一个;
: v! e; V& p\" ~1 O$ X, @ - @sum(car(I):\" @0 ~3 m8 ~1 c0 s1 i6 |% ~
- @sum(place(K):
7 w' u: l\" Q. x) O; J - @sum(place(J): a(J,K,I))))=1;
7 y- J ^+ ?3 G2 G s - 3 G- J2 X\" I4 s\" J- e8 O- O1 l
- !每个车的任务最多有四个;( l1 `\" W\" C; z6 [* i$ O
- @for(car(I):& D7 ~) E% Y* k y; ?% y
- @sum(plan(J,K,I):a(J,k,I))<=6);
7 }% U- x* r$ |& a) n% H+ k - 4 h- U. \; i% `\" g( L
- !前一辆车任务大于等于后一辆车;
3 w! A; W8 Z/ ] - @for(car(I)|I#lt#1:
8 z* S& }; M9 q/ ?6 R, o - @sum(plan:a(J,K,I))>=@sum(plan:a(J,K,I+1) );8 O: R2 R\" t& F4 J) m
# t, M2 b1 [% g/ a$ r% x1 E- !求which 例子 若a(1,:)=[1 0 0 1 0 1 0 0 0 1];; k% t# g$ O1 i9 k
- ! 则 which(1,:)=[1 1 1 4 4 6 6 6 6 10] ;
( ^1 d6 N. u/ T - @for(car(I):
2 u; h. c- R# X- U; G% \. D - @for(place(kk)|@sum(place(jj):a(kk,jj,I)) #eq#1:+ B1 @' _; a5 ?# R
- @for(place(jj)|a(kk,jj,I) #eq#1:
9 i2 J9 A: b0 x - which(I,kk)=jj ););$ b z0 \! N D2 a
- @for(place(kk)|@sum(place(kk):a(kk,jj,I)) #ne#1:
2 u1 A0 j. T+ w1 }5 \- \8 a; E - which(I,kk)=which(I,kk-1));
1 u9 h3 K8 ]5 ~4 [2 t! z* z+ M; M - 9 a5 s* M7 Z: e- @* |1 i5 ~+ l5 Q
- !时间限制;
a6 b\" G; A0 K5 C% k - @for(car(jjj):
# @ n# X5 w7 l; b. m- u: B - time(jjj)>=-10;time(jjj)<=7);
* i0 \* l3 ^: v6 y - 5 ?8 ~8 g9 |1 M& Y( {
- @for(jiu(jjj):
5 U2 C$ m E\" ] - ct(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dt(which(I,jjj),which(I,jjj+1))+timexie(which(I,jjj)),0));
9 X) H' n\" `. u: \
# H% f. p5 O8 h) f$ y- M. y) F- @for(jiu(jjj):
0 B, C( }% ?; q. i( Q - time(I)+ct(I,jjj)>=time1(jjj+1);time(I)+ct(I,jjj)<=time2(jjj+1));
/ v3 Z$ @( T- _
& E l. H4 ]% x- !求每辆车行驶的距离;
& A+ n4 J/ |! t& G6 D - @for(jiu(jjj):
9 \+ o7 d% C8 W - lucheng(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dd(which(I,jjj),which(I,jjj+1)),0) );
( \# I( F0 e9 q\" P' T - );););\" S1 c: u/ }4 @0 X3 ^
- end ]3 j! t7 O W% |
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