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发表于 2009-8-16 18:59
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修改一下循环的下标可以使得程序编译通过,但是不知道是不是和你的模型相符合,你仔细分析一下吧!2 N5 u0 Z, r, k& W
6 I% o) w9 U8 A6 t4 W2 ?, K- model:- x! `3 M, P9 R, x2 q! i1 N: a
- !n个货车8收点运输问题;
6 [8 Z2 Q. P8 Q2 H - sets:. d+ ^! w3 g8 c2 u) ?4 X8 X
- place/place1..place10/:time1,time2,timexie;9 Z9 K/ D: f& {
- car/car1..car3/:time;
$ N0 }2 h9 y: U* j8 {
# b0 c1 }5 H) T3 h- jiu/1..9/;' g5 _2 R2 ~# c4 w: {( b
- er/1..2/;
3 f( C, O. x2 E! K. h; D+ R& K0 J - # q$ u& C' B2 W) ]
- lc(car,jiu):lucheng,ct;
& U, L ]4 b- Y( [+ _# v3 @: { - plan(place,place,car):a;
% m, d, |$ e. S/ D7 d& x - distance(place,place):dd,dt,which;
9 L* S; s% k& _\" h7 Z - endsets# @9 y0 A# W/ c& k9 i
- , [; k4 y6 z4 ~: m3 U; y- S
- * f7 x3 ? x3 S1 i
- !这里是数据;3 ~' x9 S- M; x' o7 h7 i7 C
- data:
3 a& K: Y4 a; Q' d# K4 O) u - s=1;, ^5 _\" j\" @! Y$ i$ k% h
- time1=-10 1 4 1 4 3.5 2 5 1.5 1;
: b5 R9 U6 Y7 ^, u# N - time2=7 4 6 2 7 5 5 8 4 10 ;
/ I @4 x+ e% T# I4 ]5 C - timexie=0 1 2 1 3 2 2.5 3 0.8 0;
: p- s' j. z. ]) `9 H+ s5 A
( W- m/ Y$ U$ _
/ U a3 f+ i- h! ^$ o+ R4 s4 {- dd=
7 D) `: M' ]& U5 ^( \' i' H8 l - 0 40 60 75 90 90 100 135 80 0, Q\" j9 J7 z( k0 _4 f' h; {
- 40 0 65 40 100 50 75 110 100 40; E0 V8 V; I$ o2 c
- 60 65 0 75 100 100 75 75 75 60
: }' g3 G5 }+ s5 D# B. i - 75 40 75 0 100 50 90 90 125 75& u1 I+ B5 N! ^8 l\" X- Q/ h' Q
- 90 100 100 100 0 100 75 75 100 90
$ P, t& C3 e z. n% Z - 90 50 100 50 100 0 70 90 75 90' {1 i\" Y8 b$ e9 L7 ~* k$ {$ L
- 100 75 75 90 75 70 0 70 100 1004 T( I& h& `, K8 C9 H5 |
- 135 110 75 90 75 90 70 0 100 1359 C# x5 Q; d& j9 j* V& z, K
- 80 100 75 125 100 75 100 100 0 80+ k' w$ `0 B N/ k6 f' h+ P
- 0 40 60 75 90 90 100 135 80 0 ;6 j j# @* I9 ^: b7 k$ _
- dt= 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 08 `4 @: P, v\" M
- 0.8000 0 1.3000 0.8000 2.0000 1.0000 1.5000 2.2000 2.0000 0.8000
& f, c0 r: U( T4 g5 M @* `/ Y5 R, M - 1.2000 1.3000 0 1.5000 2.0000 2.0000 1.5000 1.5000 1.5000 1.20003 ?; W\" E$ u1 x+ v& H
- 1.5000 0.8000 1.5000 0 2.0000 1.0000 1.8000 1.8000 2.5000 1.50003 I) v6 B( q$ A6 N% u
- 1.8000 2.0000 2.0000 2.0000 0 2.0000 1.5000 1.5000 2.0000 1.8000/ O! J4 s4 U: K8 R, |% ^. ^
- 1.8000 1.0000 2.0000 1.0000 2.0000 0 1.4000 1.8000 1.5000 1.80002 v( l* S D- v1 u O0 |
- 2.0000 1.5000 1.5000 1.8000 1.5000 1.4000 0 1.4000 2.0000 2.0000: n y4 P; j4 y: B) W
- 2.7000 2.2000 1.5000 1.8000 1.5000 1.8000 1.4000 0 2.0000 2.7000
: n6 O2 H: m( t - 1.6000 2.0000 1.5000 2.5000 2.0000 1.5000 2.0000 2.0000 0 1.6000
& H) j& c; M6 q1 q* G( z' K8 } - 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0;5 }2 y3 O\" K7 |; G5 U\" L \
- enddata3 o+ I5 X. l1 \3 d
- ! o\" b, x! W4 p. e8 A) A\" U
- 2 @) G' W+ P+ y$ G
- !目标函数;\" f' |1 J7 U7 i& k ?- X* i: ^0 ?
- min=@sum(lc(I,J): lucheng(I,J));. O& b, ?' J2 s9 q2 }! S
* R5 b0 A4 }0 y9 b' N* Q5 n- !整数约束;
0 T- R+ w$ c- O6 f\" _3 X: s6 g' T9 O - @for(plan:@bin(a));, g* ~5 q9 B% A& }% P3 W! U3 N
- @for(car(I):@free(time(I)) ;
9 A ^% l# I4 D' c! r* O9 p# o - . H4 u3 e& |& ^* h4 L: l5 u
- !从零点开始最终回来;
4 D5 B/ S+ [. k - @for(car(I):
7 u9 F2 A- k3 b - a(1,1,I)=1;a(10,10,I)=1);
) L2 C7 c8 q7 b4 l3 f- \2 P - 1 o# m3 X# X4 t
- !每个任务只能有一个;) C! F3 z- L1 K9 d# F5 ~
- @sum(car(I):* I; _% S! w4 f7 G9 \7 ~. K- }
- @sum(place(K):
+ f( m' M0 N9 O4 U - @sum(place(J): a(J,K,I))))=1;
! a\" _! ~6 R1 P - 1 X; l- w& n% T9 }
- !每个车的任务最多有四个;/ ^2 B5 t+ H6 l# b+ `; l1 H
- @for(car(I):& B8 U- Q$ U# |
- @sum(plan(J,K,I):a(J,k,I))<=6);
' O: C0 S0 X1 J9 n* M' N5 U; X, x
( a/ {9 h$ [: g& I; a3 a( W( ?7 }, l- !前一辆车任务大于等于后一辆车;
* Y5 `* s' `% R7 Q, ?5 l - @for(car(I)|I#lt#1:
' V4 D/ I/ ]& O' n8 e* Y/ H: a - @sum(plan:a(J,K,I))>=@sum(plan:a(J,K,I+1) );
7 K1 t- t4 A. ~: M - - B G$ ]4 J5 S1 q
- !求which 例子 若a(1,:)=[1 0 0 1 0 1 0 0 0 1];
% O* N! f# z( \5 y8 h' Q8 B - ! 则 which(1,:)=[1 1 1 4 4 6 6 6 6 10] ;
D& [$ d0 c; b, O+ X - @for(car(I):' Y/ u0 I; m% N }: U7 C
- @for(place(kk)|@sum(place(jj):a(kk,jj,I)) #eq#1:
( e; p( a; k% o/ D/ s8 k) I - @for(place(jj)|a(kk,jj,I) #eq#1:
. U. ^# H$ k0 o' j, r5 _) G7 L& L - which(I,kk)=jj ););
, r3 x4 H4 D% b e7 F; Y - @for(place(kk)|@sum(place(kk):a(kk,jj,I)) #ne#1:
8 z; ~; `6 H' N: O - which(I,kk)=which(I,kk-1));4 V7 u I& s( D4 p* W/ o& F
- 7 M, \3 f' g7 o5 i5 m
- !时间限制;4 X: Q8 K: z& c! i1 E
- @for(car(jjj):
+ ?# \4 \/ x! C, T* d - time(jjj)>=-10;time(jjj)<=7);
$ m4 o( J9 R\" |/ g - % w+ J$ X0 g\" J/ ]/ d
- @for(jiu(jjj):
2 w2 T' G9 c4 z _6 v1 b9 L1 z- Y: ^ - ct(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dt(which(I,jjj),which(I,jjj+1))+timexie(which(I,jjj)),0));
: m' E' b$ O- @\" o. V$ a+ n - ! o9 o. M! v: z* U2 k
- @for(jiu(jjj):5 P, n* P, d. O+ Y& {! R
- time(I)+ct(I,jjj)>=time1(jjj+1);time(I)+ct(I,jjj)<=time2(jjj+1));4 U0 ~& l$ _& u& r1 V
- # K4 w4 T- q: M% D0 W
- !求每辆车行驶的距离;
) [- S# k( K! V+ \% v6 r, e9 m: R - @for(jiu(jjj): {; Y& y' J! |9 X$ b* v* Q
- lucheng(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dd(which(I,jjj),which(I,jjj+1)),0) );
' x$ Z @; G5 Q9 [. g$ ^. E9 K9 H - );););\" }- B* ]5 b/ S4 t$ Y/ N( G
- end
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