求助 一个简单的多元一次求和方程怎么编写LINGO
已知a1+a2+a3+a4+a5+a6=57442053.49
b1+b2+b3+b4+b5+b6=644527482.3
a1/b1约等于0.05
a2/b2约等于0.1
a3/b3约等于0.2
a4/b4约等于0.5
a5/b5约等于0.8
a6/b6约等于1
怎么分别求出a1、a2、a3、a4、a5、a6、b1、b2、b3、b4、b5、b6的值
有人能帮忙回复下吗
a1+a2+a3+a4+a5+a6=57442053.49;
b1+b2+b3+b4+b5+b6=644527482.3;
a1/b1>0.049;
a1/b1<0.051;
a2/b2>0.099;
a2/b2<0.101;
a3/b3>0.19;
a3/b3<0.201;
a4/b4>0.49;
a4/b4<0.501;
a5/b5>0.79;
a5/b5<0.801;
a6/b6>0.99;
a6/b6<1.004;
我这样建系统反馈错误
有人能帮忙回复下吗
a1+a2+a3+a4+a5+a6=57442053.49;
b1+b2+b3+b4+b5+b6=644527482.3;
a1/b1>0.049;
a1/b1<0.051;
a2/b2>0.099;
a2/b2<0.101;
a3/b3>0.19;
a3/b3<0.201;
a4/b4>0.49;
a4/b4<0.501;
a5/b5>0.79;
a5/b5<0.801;
a6/b6>0.99;
a6/b6<1.004;
我这样建系统反馈错误
构造最小二乘解法；SETS:
VAR/ 1..6/: A, B, C;
ENDSETS
MIN = Z;
Z = @SUM( VAR( I): ( A( I)/ B( I) - C( I))^2);
@SUM( VAR( I): A( I)) = 57442053.49;
@SUM( VAR( I): B( I)) = 644527482.3;
DATA:
C = 0.05, 0.1, 0.2, 0.5, 0.8, 1;
ENDDATA
CALC:
@SET( 'GLOBAL', 1);
ENDCALC求解结果： Global optimal solution found.
Objective value: 0.6000000E-09
Objective bound: 0.6000000E-09
Infeasibilities: 0.4348427E-07
Extended solver steps: 2
Total solver iterations: 634
Variable Value Reduced Cost
Z 0.000000 1.000000
A( 1) 0.3056445E+08 0.000000
A( 2) 0.9674469E-05 0.000000
A( 3) 0.5568388E-05 0.000000
A( 4) 0.2797364E-05 0.000000
A( 5) 0.2687761E+08 0.000000
A( 6) 0.3339973E-04 0.000000
B( 1) 0.6109298E+09 0.000000
B( 2) 0.9673430E-04 0.000000
B( 3) 0.2784192E-04 0.000000
B( 4) 0.5594727E-05 0.000000
B( 5) 0.3359770E+08 0.000000
B( 6) 0.3339973E-04 0.000000
C( 1) 0.5000000E-01 0.000000
C( 2) 0.1000000 0.000000
C( 3) 0.2000000 0.000000
C( 4) 0.5000000 0.000000
C( 5) 0.8000000 0.000000
C( 6) 1.000000 0.000000
Row Slack or Surplus Dual Price
1 0.000000 -1.000000
2 -0.1247501E-08 0.000000
3 -0.1219200E-08 0.000000
4 -0.4348427E-07 0.000000
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