【连载】科普之---随机数的应用（猜数字游戏的实现） - 数学建模社区-数学中国

#include<stdio.h>: v* Y: s5 P4 ]! V6 y
#include<stdlib.h>0 k( z- ^" L6 ^, H3 w
#include<time.h>
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int judge(int *a,int *b)
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int i,j;
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int count_A,count_B;# A7 H! U* U& n( i5 ?
count_A = count_B = 0;
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for(i = 0;i<4 ;i++ )6 x" {# ~/ _6 a% X* z
{
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if(a[i] == b[i]) count_A++;: F, f" E; l& e8 C: ?
}
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if(count_A == 4) {printf("%dA%dB\n",count_A,count_B);return 1;}
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for(i = 0; i < 4;i ++)4 C9 \& k, n# G
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for(j = 0;j < 4;j ++)
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if(a[j] == b[i]) {count_B++;j = 4;}
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}
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printf("%dA%dB\n",count_A,count_B);
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return 0;
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}
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void main()//c语言版猜数字游戏
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int r_num[4];. r N0 N2 J6 e* z7 G/ p4 y. @0 U; s
int input_num[4];
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srand(time(0));1 j) O0 g, o/ S; O. `8 V$ l
int j,i = 0,temp1,temp2 = 0;& \4 p4 ^! [8 z1 d
/*********************生成四个随机数***********************/
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while(i<4), l& M w8 s* _; i9 U7 p0 O
{
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if(i == 0) {r_num[i] = rand()%10;i++;}
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else
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{
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temp1 = rand()%10;
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for(j=0;j<i;j++)
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{
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if(temp1 == r_num[j]) temp2++;
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}
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if(temp2 == 0); J. Q; j8 M' }# k8 s$ ]& ]
{
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r_num[i] = temp1;8 z5 \/ }( n* y) t2 x
temp2 = 0;# ~8 G4 e/ R' q; ?) a) h
i ++;8 g# O2 t: r; [+ ?; \7 O# `: C
}
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else8 T; r7 S/ m- V4 H
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temp2 = 0;' g5 Q! \+ _9 }* I* B5 i2 g
continue;8 D, |( v/ [% a
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}
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}
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for(i = 0;i<4;i++)1 n1 d# l3 L: K, o! n8 ` f/ [
printf("%d\n",r_num[i]);
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/************************猜数字游戏核心部分*********************/: Z1 C# L7 M7 A5 o/ J* C5 w( w
for(;;)) K9 q* n' _ `! F/ `& J
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scanf("%d",&j);
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input_num[0] = j/1000;
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input_num[3] = j%10;4 @" w9 V" _% x9 h
input_num[1] = (j - input_num[0]*1000)/100;
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input_num[2] = (j - input_num[0]*1000 - input_num[1]*100)/10;
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/********这个地方缺一个函数判断输入的四个数是否一样,由大家自己实现********/- p, t* V2 H; k* x3 c$ B6 X
if(judge(input_num,r_num)==1) break;+ T% f# b) @8 M, }7 R+ P
else9 v# C4 s5 R" j1 ^1 k/ f/ Z4 {9 H
continue;4 \" X/ S7 k5 P
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}

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