hehe123 发表于 2004-11-27 12:37

数学专业英语[5]-First Order Differential Equations

<P><FONT face="Times New Roman" size=3>A differential equation is an equation between specified derivatives of a function, its</FONT></P>
<P><FONT face="Times New Roman" size=3>valves,and known quantities.Many laws of physics are most simply and naturally formu-</FONT></P>
<P><FONT face="Times New Roman" size=3>lated as differential equations (or DE’s, as we shall write for short).For this reason,DE’s </FONT></P>
<P><FONT face="Times New Roman" size=3>have been studies by the greatest mathematicians and mathematical physicists since the </FONT></P>
<P><FONT face="Times New Roman" size=3>time of Newton..</FONT></P>
<P><FONT face="Times New Roman" size=3>Ordinary differential equations are DE’s whose unknowns are functions of a single va-</FONT></P>
<P><FONT face="Times New Roman" size=3>riable;they arise most commonly in the study of dynamic systems and electric networks.</FONT></P>
<P><FONT face="Times New Roman" size=3>They are much easier to treat than partial differential equations,whose unknown functions</FONT></P>
<P><FONT face="Times New Roman" size=3>depend on two or more independent variables.</FONT></P>
<P><FONT face="Times New Roman" size=3>Ordinary DE’s are classified according to their order. The order of a DE is defined as </FONT></P>
<P><FONT face="Times New Roman" size=3>the largest positive integer, n, for which an n-th derivative occurs in the equation. This</FONT></P>
<P><FONT face="Times New Roman" size=3>chapter will be restricted to real first order DE’s of the form</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">               </FONT>Φ<FONT face="Times New Roman">(x, y, y</FONT>′<FONT face="Times New Roman">)=0                                         (1)</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">Given the function </FONT>Φ<FONT face="Times New Roman">of three real variables, the problem is to determine all real functions y=f(x) which satisfy the DE, that is ,all solutions of(1)in the following sense.</FONT></FONT></P>
<P><FONT face="Times New Roman"><FONT size=3><B>DEFINITION  </B> A solution of (1)is a differentiable function f(x) such that  </FONT></FONT></P>
<P><FONT size=3>Φ<FONT face="Times New Roman">(x. f(x),f</FONT>′<FONT face="Times New Roman">(x))=0 for all x in the interval where f(x) is defined.</FONT></FONT></P>
<P><FONT face="Times New Roman"><FONT size=3><B>EXAMPLE 1.</B>  In the first-other DE</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">              x+yy</FONT>′<FONT face="Times New Roman">=0                                            (2)</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">the function </FONT>Φ<FONT face="Times New Roman"> is a polynomial function </FONT>Φ<FONT face="Times New Roman">(x, y, z)=x+ yz of three variables in-</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>volved. The solutions of (2) can be found by considering the identity</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">d(x</FONT>&sup2;<FONT face="Times New Roman">+y</FONT>&sup2;<FONT face="Times New Roman">)/d x=2(x+yy</FONT>ˊ<FONT face="Times New Roman">).From this identity,one sees that x</FONT>&sup2;<FONT face="Times New Roman">+y</FONT>&sup2;<FONT face="Times New Roman"> is a con-</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>stant if y=f(x) is any solution of (2).</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">The equation x</FONT>&sup2;<FONT face="Times New Roman">+y</FONT>&sup2;<FONT face="Times New Roman">=c defines y implicitly as a two-valued function of x,</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>for any positive constant c.Solving for y,we get two solutions,the(single-valued)</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">functions y=</FONT>±<FONT face="Times New Roman">(c-x</FONT>&sup2;<FONT face="Times New Roman">)<SUP>0.5</SUP> ,for each positive constant c.The graphs of these so-</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>lutions,the so-called solution curves,form two families of scmicircles,which fill the upper half-plane y&gt;0 and the lower half-plane y&gt;0,respectively.</FONT></P>
<P><FONT face="Times New Roman" size=3>On the x-axis,where y=0,the DE(2) implies that x=0.Hence the DE has no solutions</FONT></P>
<P><FONT face="Times New Roman" size=3>which cross the x-axis,except possibly at the origin.This fact is easily overlooked,</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">because the solution curves appear to cross the x-axis;hence y</FONT>ˊ<FONT face="Times New Roman">does not exist,and the DE (2) is not satisfied there.</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">The preceding difficulty also arises if one tries to solve the DE(2)for y</FONT>ˊ<FONT face="Times New Roman">. Dividing through by y,one gets y</FONT>ˊ<FONT face="Times New Roman">=-x/y,an equation which cannot be satisfied if y=0.The preceding difficulty is thus avoided if one restricts attention to regions where the DE(1) is normal,in the following sense.</FONT></FONT></P>
<P><FONT face="Times New Roman"><FONT size=3><B>   DEFINITION. </B>A normal first-order DE is one of the form</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">       y</FONT>ˊ<FONT face="Times New Roman">=F(x,y)                                                  (3)</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">In the normal form y</FONT>ˊ<FONT face="Times New Roman">=-x/y of the DE (2),the function F(x,y) is continuous in the upper half-plane y&gt;0 and in the lower half-plane where y&lt;0;it is undefined on the x-axis.</FONT></FONT></P>
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<P><B><FONT face="Times New Roman"><FONT size=3>Fundamental Theorem of the Calculus.
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<P><FONT face="Times New Roman"><FONT size=3>The most familiar class of differential equations consists of the first-order DE’s of the form  </FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">                   y</FONT>ˊ<FONT face="Times New Roman">=g(x)                                            (4)</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>Such DE’s are normal and their solutions are descried by the fundamental thorem of the calculus,which reads as follows.</FONT></P>
<P><FONT face="Times New Roman"><FONT size=3><B>FUNDAMENTAL THEOREM OF THE CALCULUS</B>. Let the function g(x)in DE(4) be continuous in the interval a&lt;x&lt;b.Given a number c,there is one and only one solution f(x) of the DE(4) in the interval such that f(a)=c. This solution is given by the definite integral</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">f(x)=c+</FONT>∫<FONT face="Times New Roman"><SUB>a</SUB><SUP>x</SUP>g(t)dt ,       c=f(a)                                    (5)</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>This basic result serves as a model of rigorous formulation in several respects. First,it specifies the region under consideration,as a vertical strip a&lt;x&lt;b in the xy-plane.Second,it describes in precise terms the class of functions g(x) considered.And third, it asserts the existence and uniqueness of a solution,given the “initial condition”f(a)=c.</FONT></P>
<P><FONT face="Times New Roman" size=3>We recall that the definite integral </FONT></P>
<P><FONT size=3>∫<FONT face="Times New Roman"><SUB>a</SUB><SUP>x</SUP>g(t)dt=lim(max</FONT>Δ<FONT face="Times New Roman">t<SUB>k</SUB>-&gt;0)</FONT>Σ<FONT face="Times New Roman">g(t<SUB>k</SUB>)</FONT>Δ<FONT face="Times New Roman">t<SUB>k </SUB>,     </FONT>Δ<FONT face="Times New Roman">t<SUB>k</SUB>=t<SUB>k</SUB>-t<SUB>k-1 </SUB>                 (5</FONT>ˊ<FONT face="Times New Roman">)</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">is defined for each fixed x as a limit of Ricmann sums; it is not necessary to find a formal expression for the indefinite integral </FONT>∫<FONT face="Times New Roman"> g(x) dx to give meaning to the definite integral </FONT>∫<FONT face="Times New Roman"><SUB>a</SUB><SUP>x</SUP>g(t)dt,provided only that g(t) is continuous.Such functions as the error function crf x =(2/(</FONT>π<FONT face="Times New Roman">)<SUP>0.5</SUP>)</FONT>∫<FONT face="Times New Roman"><SUB>0</SUB><SUP>x</SUP>e<SUP>-t</SUP></FONT><SUP>&sup2;<FONT face="Times New Roman">  </FONT></SUP><FONT face="Times New Roman">dt and the sine integral function       SI(x)=</FONT>∫<SUB><FONT face="Times New Roman">x</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">[(sin t )/t]dt are indeed commonly defined as definite integrals.</FONT></FONT></P>
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<P align=center><B><FONT face="Times New Roman">Solutions and Integrals
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<P><FONT size=3><FONT face="Times New Roman">According to the definition given above a solution of a DE is always a function. For example, the solutions of the DE x+yy</FONT>ˊ<FONT face="Times New Roman">=0 in Example I are the functions y=</FONT>±<FONT face="Times New Roman"> (c-x</FONT>&sup2;<FONT face="Times New Roman">)<SUP>0.5</SUP>,whose graphs are semicircles of arbitrary diameter,centered at the origin.The graph of the solution curves are ,however,more easily described by the equation x</FONT>&sup2;<FONT face="Times New Roman">+y</FONT>&sup2;<FONT face="Times New Roman">=c,describing a family of circles centered at the origin.In what sense can such a family of curves be considered as a solution of the DE ?To answer this question,we require a new notion.</FONT></FONT></P>
<P><FONT face="Times New Roman"><FONT size=3><B>DEFINITION.</B>    An integral of DE(1)is a function of two variables,u(x,y),which assumes a constant value whenever the variable y is replaced by a solution y=f(x) of the DE.</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">In the above example, the function u(x,y)=x</FONT>&sup2;<FONT face="Times New Roman">+y</FONT>&sup2;<FONT face="Times New Roman"> is an integral of the DE     x+yy</FONT>ˊ<FONT face="Times New Roman"> =0,because,upon replacing the variable y by any function </FONT>±<FONT face="Times New Roman">( c-x</FONT>&sup2;<FONT face="Times New Roman">)<SUP>0.5</SUP>,we obtain u(x,y)=c.</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>The second-order DE</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">           d</FONT>&sup2;<FONT face="Times New Roman">x/dt</FONT>&sup2;<FONT face="Times New Roman">=-x                                          (2</FONT>ˊ<FONT face="Times New Roman">)</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>becomes a first-order DE equivalent to (2) after setting dx/dx=y:</FONT></P>
<P><FONT face="Times New Roman" size=3>y ( dy/dx )=-x                                          (2)</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">As we have seen, the curves u(x,y)=x</FONT>&sup2;<FONT face="Times New Roman">+y</FONT>&sup2;<FONT face="Times New Roman">=c are integrals of this DE.When the DE (2</FONT>ˊ<FONT face="Times New Roman">)</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>is interpreted as equation of motion under Newton’s second law,the integrals </FONT></P>
<P><FONT size=3><FONT face="Times New Roman">c=x</FONT>&sup2;<FONT face="Times New Roman">+y</FONT>&sup2;<FONT face="Times New Roman"> represent curves of constant energy c.This illustrates an important principle:an integral of a DE representing some kind of motion is a quantity that remains unchanged through the motion.</FONT></FONT></P>
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hehe123 发表于 2004-11-27 12:37

<P align=center 0cm 0pt; TEXT-ALIGN: center?><B><FONT face="Times New Roman">Vocabulary
</FONT></B><p><P 0cm 0pt?><FONT face="Times New Roman"><p></FONT><p><P 0cm 0pt?><FONT face="Times New Roman">differential equation       </FONT>微分方程<FONT face="Times New Roman">        error function   </FONT>误差函数<FONT face="Times New Roman">              </FONT></P><P 0cm 0pt?><FONT face="Times New Roman">ordinary differential equation  </FONT>常微分方程<FONT face="Times New Roman">  sine integral function  </FONT>正弦积分函数</P><P 0cm 0pt?><FONT face="Times New Roman">order    </FONT>阶<FONT face="Times New Roman">,</FONT>序<FONT face="Times New Roman">                              diameter    </FONT>直径</P><P 0cm 0pt?><FONT face="Times New Roman">derivative    </FONT>导数<FONT face="Times New Roman">                          curve      </FONT>曲线</P><P 0cm 0pt?><FONT face="Times New Roman">known quantities </FONT>已知量<FONT face="Times New Roman">                     replace    </FONT>替代</P><P 0cm 0pt?><FONT face="Times New Roman">unknown   </FONT>未知量<FONT face="Times New Roman">                           substitute    </FONT>代入</P><P 0cm 0pt?><FONT face="Times New Roman">single variable   </FONT>单变量<FONT face="Times New Roman">                       strip        </FONT>带形</P><P 0cm 0pt?><FONT face="Times New Roman">dynamic system     </FONT>动力系统<FONT face="Times New Roman">                  exact differential   </FONT>恰当微分</P><P 0cm 0pt?><FONT face="Times New Roman">electric network    </FONT>电子网络<FONT face="Times New Roman">                   line integral      </FONT>线积分</P><P 0cm 0pt?><FONT face="Times New Roman">partial differential equation     </FONT>偏微分方程<FONT face="Times New Roman">       path of integral     </FONT>积分路径</P><P 0cm 0pt?><FONT face="Times New Roman">classify    </FONT>分类<FONT face="Times New Roman">                              endpoints        </FONT>端点</P><P 0cm 0pt?><FONT face="Times New Roman">polynomial     </FONT>多项式<FONT face="Times New Roman">                        general solution   </FONT>通解</P><P 0cm 0pt?><FONT face="Times New Roman">several variables        </FONT>多变量<FONT face="Times New Roman">                 parameter      </FONT>参数</P><P 0cm 0pt?><FONT face="Times New Roman">family      </FONT>族<FONT face="Times New Roman">                               rigorous       </FONT>严格的</P><P 0cm 0pt?><FONT face="Times New Roman">semicircle    </FONT>半圆<FONT face="Times New Roman">                            existence       </FONT>存在性</P><P 0cm 0pt?><FONT face="Times New Roman">half-plane    </FONT>半平面<FONT face="Times New Roman">                          initial condition   </FONT>初始条件</P><P 0cm 0pt?><FONT face="Times New Roman">region    </FONT>区域<FONT face="Times New Roman">                               uniqueness      </FONT>唯一性</P><P 0cm 0pt?><FONT face="Times New Roman">normal   </FONT>正规<FONT face="Times New Roman">,</FONT>正常<FONT face="Times New Roman">                           Riemann sum  </FONT>犁曼加</P><P 0cm 0pt?><FONT face="Times New Roman">identity    </FONT>恒等<FONT face="Times New Roman">(</FONT>式<FONT face="Times New Roman">)</FONT></P>

hehe123 发表于 2004-11-27 12:38

<P align=center 0cm 0pt; TEXT-ALIGN: center?><FONT face="Times New Roman"><B>Notes</B><B>
</B></FONT><p><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list 18.0pt; 18pt; -18pt; l29 lfo19?><FONT face="Times New Roman">1.       The order of a DE is defined as the largest positive integral n,for which an nth derivative occurs in the question.</FONT></P><P 0cm 0pt?><FONT face="Times New Roman">       </FONT>这是另一种定义句型<FONT face="Times New Roman">,</FONT>请参看附录<FONT face="Times New Roman">IV.</FONT>此外要注意<FONT face="Times New Roman">nth derivative </FONT>之前用<FONT face="Times New Roman">an </FONT>不用<FONT face="Times New Roman">a .</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list 18.0pt; 18pt; -18pt; l29 lfo19?><FONT face="Times New Roman">2.       This chapter will be restricted to real first order differential equations of the form </FONT></P><P 0cm 0pt; TEXT-INDENT: 32.25pt?>Φ<FONT face="Times New Roman">(x,y,y</FONT>ˊ<FONT face="Times New Roman">)=0</FONT></P><P 0cm 0pt; TEXT-INDENT: 32.25pt?>意思是<FONT face="Times New Roman">;</FONT>文章限于讨论形如<FONT face="Times New Roman">  </FONT>Φ<FONT face="Times New Roman">(x,y,y</FONT>ˊ<FONT face="Times New Roman">)=0</FONT>的实一阶微分方程<FONT face="Times New Roman">.</FONT></P><P 0cm 0pt; TEXT-INDENT: 32.25pt?>有时可以用<FONT face="Times New Roman">of the type</FONT>代替<FONT face="Times New Roman"> of the form </FONT>的用法<FONT face="Times New Roman">.</FONT></P><P 0cm 0pt; TEXT-INDENT: 32.25pt?><FONT face="Times New Roman">        The equation can be rewritten in the form  y</FONT>ˊ<FONT face="Times New Roman">=F(x,y).</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list 18.0pt; 18pt; -18pt; l29 lfo19?><FONT face="Times New Roman">3.       Dividing through by y,one gets y</FONT>ˊ<FONT face="Times New Roman">=-x/y,</FONT>…</P><P 0cm 0pt?><FONT face="Times New Roman">      </FONT>划线短语意思是<FONT face="Times New Roman">:</FONT>全式除以<FONT face="Times New Roman">y</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list 18.0pt; 18pt; -18pt; l29 lfo19?><FONT face="Times New Roman">4.       As we have seen, the curves u(x,y)=x</FONT>&sup2;<FONT face="Times New Roman">+y</FONT>&sup2;<FONT face="Times New Roman">=c are integrals of this DE</FONT></P><P 0cm 0pt?><FONT face="Times New Roman">     </FONT>这里<FONT face="Times New Roman">x</FONT>&sup2;<FONT face="Times New Roman">+y</FONT>&sup2;<FONT face="Times New Roman">=c </FONT>因<FONT face="Times New Roman">c</FONT>是参数<FONT face="Times New Roman">,</FONT>故此方程代表一族曲线<FONT face="Times New Roman">,</FONT>由此<FONT face="Times New Roman">”</FONT>曲线<FONT face="Times New Roman">”</FONT>这一词要用复数<FONT face="Times New Roman">curves.</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list 18.0pt; 18pt; -18pt; l29 lfo19?><FONT face="Times New Roman">5.       Their solutions are described by the fundamental theorem of the calculus,which reads as follows.</FONT></P><P 0cm 0pt?><FONT face="Times New Roman">        </FONT>意思是<FONT face="Times New Roman">:</FONT>它们的解由微积分基本定理所描述<FONT face="Times New Roman">,(</FONT>基本定理<FONT face="Times New Roman">)</FONT>可写出如下<FONT face="Times New Roman">.</FONT></P><P 0cm 0pt?><FONT face="Times New Roman">        </FONT>句中<FONT face="Times New Roman">reads as follows </FONT>就是<FONT face="Times New Roman">”</FONT>写成<FONT face="Times New Roman">(</FONT>读成<FONT face="Times New Roman">)</FONT>下面的样子<FONT face="Times New Roman">”</FONT>的意思<FONT face="Times New Roman">.</FONT>注意<FONT face="Times New Roman">follows</FONT>一词中的<FONT face="Times New Roman">”s”</FONT>不能省略<FONT face="Times New Roman">.</FONT></P>

hehe123 发表于 2004-11-27 12:38

<P align=center 0cm 0pt; TEXT-ALIGN: center?><FONT face="Times New Roman"><B>Exercise</B><B>
</B></FONT><p><P 0cm 0pt?>Ⅰ<FONT face="Times New Roman">.Translate the following passages into Chinese:</FONT></P><P 0cm 0pt?><FONT face="Times New Roman">  1.A differential M(x,y) dx +N(x,y) dy ,where M, N are real functions of two variables x and y, is called exact in a domain D when the line integral </FONT>∫<FONT face="Times New Roman"><SUB>c </SUB>M(x,y) dx +N(x,y) dy is the same for all paths of integration c in D, which have the same endpoints.</FONT></P><P 0cm 0pt; TEXT-INDENT: 37.5pt?><FONT face="Times New Roman">Mdx+Ndy is exact if and only if there exists a continuously differentiable function u(x,y) such that M= u/ x, N=u/ y.</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -18.75pt; 18.75pt; l38 lfo20?><FONT face="Times New Roman">2.       For any normal first order DE y</FONT>ˊ<FONT face="Times New Roman">=F(x,y)  and any initial x<SUB>0  </SUB>, the initial valve problem consists of finding the solution or solutions of the DE ,for x&gt;x<SUB>0  </SUB>which assumes a given initial valve f(x<SUB>0</SUB>)=c.</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -18.75pt; 18.75pt; l38 lfo20?><FONT face="Times New Roman">3.       To show that the initial valve problem is well-set requires proving theorems of existence (there is a solution), uniqueness (there is only one solution) and continuity (the solution depends continuously on the initial value).</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"><p></FONT><p><P 0cm 0pt?>Ⅱ<FONT face="Times New Roman">. Translate the following sentences into English:</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: list level2 l38 lfo20? -24.75pt; 45.75pt;><FONT face="Times New Roman">1)           </FONT>因为<FONT face="Times New Roman">y=</FONT>ч<FONT face="Times New Roman">(x) </FONT>是微分方程<FONT face="Times New Roman">dy/ dx=f(x,y)</FONT>的解<FONT face="Times New Roman">,</FONT>故有</P><P 0cm 0pt 45.75pt?><FONT face="Times New Roman">d</FONT>ч<FONT face="Times New Roman">(x)/dx=f (x,</FONT>ч<FONT face="Times New Roman">(x))</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: list level2 l38 lfo20? -24.75pt; 45.75pt;><FONT face="Times New Roman">2)           </FONT>两边从<FONT face="Times New Roman">x<SUB>0</SUB></FONT>到<FONT face="Times New Roman">x</FONT>取定积分得</P><P 0cm 0pt 45.75pt?>ч<FONT face="Times New Roman">(x)-</FONT>ч<FONT face="Times New Roman">(x<SUB>0</SUB>)=</FONT>∫<FONT face="Times New Roman"><SUB>x0</SUB><SUP>x </SUP>f(x,</FONT>ч<FONT face="Times New Roman">(x)) dx   x<SUB>0</SUB>&lt;x&lt;x<SUB>0</SUB>+h</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: list level2 l38 lfo20? -24.75pt; 45.75pt;><FONT face="Times New Roman">3)           </FONT>把<FONT face="Times New Roman">y<SUB>0</SUB>=</FONT>ч<FONT face="Times New Roman">(x<SUB>0</SUB>)</FONT>代入上式<FONT face="Times New Roman">, </FONT>即有</P><P 0cm 0pt 45.75pt?>ч<FONT face="Times New Roman">(x)=y<SUB>0</SUB>+</FONT>∫<FONT face="Times New Roman"><SUB>x0</SUB><SUP>x  </SUP>f(x,</FONT>ч<FONT face="Times New Roman">(x)) dx           x<SUB>0</SUB>&lt;x&lt;x<SUB>0</SUB>+h</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: list level2 l38 lfo20? -24.75pt; 45.75pt;><FONT face="Times New Roman">4)           </FONT>因此<FONT face="Times New Roman"> y=</FONT>ч<FONT face="Times New Roman">(x) </FONT>是积分方程</P><P 0cm 0pt?><FONT face="Times New Roman">                        y=y<SUB>0</SUB>+</FONT>∫<FONT face="Times New Roman"><SUB>x0</SUB><SUP>x</SUP> f (x,y) dx</FONT></P><P 0cm 0pt?><FONT face="Times New Roman">         </FONT>定义于<FONT face="Times New Roman">x<SUB>0</SUB>&lt;x&lt;x<SUB>0</SUB>+h </FONT>的连续解<FONT face="Times New Roman">.</FONT></P><P 0cm 0pt?><FONT face="Times New Roman">    </FONT></P><P 0cm 0pt?><FONT face="Times New Roman">   </FONT>Ⅲ<FONT face="Times New Roman">.    Translate the following sentences into English:</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -24.75pt; 46.5pt; l31 lfo21?><FONT face="Times New Roman">1)           </FONT>现在讨论型如<FONT face="Times New Roman">  y=f (x,y</FONT>ˊ<FONT face="Times New Roman">) </FONT>的微分方程的解<FONT face="Times New Roman">,</FONT>这里假设函数<FONT face="Times New Roman"> f (x, dy/dx)  </FONT>有连续的偏导数<FONT face="Times New Roman">.</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -24.75pt; 46.5pt; l31 lfo21?><FONT face="Times New Roman">2)           </FONT>引入参数<FONT face="Times New Roman">dy/dx=p, </FONT>则已给方程变为<FONT face="Times New Roman"> y=f (x,p).</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -24.75pt; 46.5pt; l31 lfo21?><FONT face="Times New Roman">3)           </FONT>在<FONT face="Times New Roman"> y=f (x,p)   x  p=dy/dx       p= f/ x+f/ p  dp/dx</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -24.75pt; 46.5pt; l31 lfo21?><FONT face="Times New Roman">4)           </FONT>这是一个关于<FONT face="Times New Roman">x</FONT>和<FONT face="Times New Roman">p</FONT>的一阶微分方程<FONT face="Times New Roman">,</FONT>它的解法我们已经知道<FONT face="Times New Roman">.</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -24.75pt; 46.5pt; l31 lfo21?><FONT face="Times New Roman">5)           </FONT>若<FONT face="Times New Roman">(A)</FONT>的通解的形式为<FONT face="Times New Roman">p=</FONT>ч<FONT face="Times New Roman">(x,c) ,</FONT>则原方程的通解为</P><P 0cm 0pt; TEXT-INDENT: 116.25pt?><FONT face="Times New Roman">y=f (x,</FONT>ч<FONT face="Times New Roman">(x,c)).</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -24.75pt; 46.5pt; l31 lfo21?><FONT face="Times New Roman">6)           </FONT>若<FONT face="Times New Roman">(A) </FONT>有型如<FONT face="Times New Roman">x=</FONT>ψ<FONT face="Times New Roman">(x,c)</FONT>的通解<FONT face="Times New Roman">,</FONT>则原方程有参数形式的通解</P><P 0cm 0pt 21.75pt?><FONT face="Times New Roman">                  x=</FONT>ψ<FONT face="Times New Roman">(p,c)</FONT></P><P 0cm 0pt 21.75pt?><FONT face="Times New Roman">                  y=f(</FONT>ψ<FONT face="Times New Roman">(p,c)p)</FONT></P><P 0cm 0pt 21.75pt?><FONT face="Times New Roman">      </FONT>其中<FONT face="Times New Roman">p</FONT>是参数<FONT face="Times New Roman">,c</FONT>是任意常数<FONT face="Times New Roman">.</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"><p></FONT><p><P 0cm 0pt?><FONT face="Times New Roman"><p></FONT><p><P 0cm 0pt?><FONT face="Times New Roman"><p></FONT><p>

hehe123 发表于 2004-11-27 12:45

数学专业英语[6]-Sequences and Series

<P><FONT face="Times New Roman" size=3>Series are a natural continuation of our study of functions. In the previous chapter we found how </FONT></P>
<P><FONT face="Times New Roman" size=3>to approximate our elementary functions by polynomials, with a certain error term. Conversely, one can define arbitrary functions by giving a series for them. We shall see how in the sections below.</FONT></P>
<P><FONT face="Times New Roman"><FONT size=3>   In practice, very few tests are used to determine convergence of series. Essentially, the comparision test is the most frequent. Furthermore, the most important series are those which converge absolutely. Thus we shall put greater emphasis on these.</FONT></FONT></P>
<P><FONT face="Times New Roman"><FONT size=3>

</FONT></FONT>
<p>
<P><FONT face="Times New Roman" size=3>Convergent Series</FONT></P>
<P><FONT face="Times New Roman"><FONT size=3>
<p></FONT></FONT>
<p>
<P><FONT face="Times New Roman" size=3>Suppose that we are given a sequcnce of numbers</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">a<SUB>1</SUB>,a<SUB>2</SUB>,a<SUB>3</SUB></FONT>…<FONT face="Times New Roman"> </FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">i.e. we are given a number a<SUB>n</SUB>, for each integer </FONT>n><FONT face="Times New Roman">1.We form the sums</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">                         S<SUB>n</SUB>=a<SUB>1</SUB>+a<SUB>2</SUB>+</FONT>…<FONT face="Times New Roman">+a<SUB>n
<p></SUB></FONT></FONT>
<p>
<P><FONT face="Times New Roman" size=3>It would be meaningless to form an infinite sum</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">a<SUB>1</SUB>+a<SUB>2</SUB>+a<SUB>3</SUB>+</FONT>…</FONT></P>
<P><FONT face="Times New Roman" size=3>because we do not know how to add infinitely many numbers. However, if our sums S<SUB>n</SUB> approach a limit as n becomes large, then we say that the sum of our sequence converges, and we now define its sum to be that limit.</FONT></P>
<P><FONT face="Times New Roman"><FONT size=3>   The symbols </FONT></FONT></P>
<P><FONT size=3>∑<SUB><FONT face="Times New Roman">a=1 </FONT></SUB><SUP>∞<FONT face="Times New Roman"> </FONT></SUP><FONT face="Times New Roman">a<SUB>n</SUB><SUP>                 
<p></SUP></FONT></FONT>
<p>
<P><FONT face="Times New Roman"><FONT size=3><SUP></SUP>will be called a series. We shall say that the series converges if the sums approach a limit as n becomes large. Otherwise, we say that it does not converge, or diverges. If the seriers converges, we say that the value of the series is </FONT></FONT></P>
<P><FONT size=3>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">=lim<SUB>a</SUB></FONT><SUB>→∞</SUB><FONT face="Times New Roman">S<SUB>n</SUB>=lim<SUB>a</SUB></FONT><SUB>→∞</SUB><FONT face="Times New Roman">(a<SUB>1</SUB>+a<SUB>2</SUB>+</FONT>…<FONT face="Times New Roman">+a<SUB>n</SUB>)</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>In view of the fact that the limit of a sum is the sum of the limits, and other standard properties of limits, we get:</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">THEOREM 1. Let{ a<SUB>n</SUB> }and { b<SUB>n</SUB> }(n=1,2,</FONT>…<FONT face="Times New Roman">)</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>be two sequences and assume that the series </FONT></P>
<P><FONT size=3>∑<FONT face="Times New Roman"><SUB>a=1</SUB><SUP> </SUP></FONT><SUP>∞<FONT face="Times New Roman"> </FONT></SUP><FONT face="Times New Roman">a<SUB>n</SUB></FONT>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞<FONT face="Times New Roman"> </FONT></SUP><FONT face="Times New Roman">b<SUB>n</SUB><SUP>
<p></SUP></FONT></FONT>
<p>
<P><FONT size=3><FONT face="Times New Roman">converge. Then </FONT>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">(a<SUB>n </SUB>+ b<SUB>n </SUB>) also converges, and is equal to the sum of the two series. If c is a number, then </FONT></FONT></P>
<P><FONT size=3>∑<FONT face="Times New Roman"> <SUB>a=1</SUB></FONT><SUP>∞</SUP><FONT face="Times New Roman">c a<SUB>n</SUB> =c</FONT>∑<FONT face="Times New Roman"><SUB>a=1</SUB> </FONT><SUP>∞</SUP><FONT face="Times New Roman">a<SUB>n
<p></SUB></FONT></FONT>
<p>
<P><FONT size=3><FONT face="Times New Roman">Finally, if s<SUB>n</SUB>=a<SUB>1</SUB>+a<SUB>2</SUB>+</FONT>…<FONT face="Times New Roman">+a<SUB>n</SUB> and t<SUB>n</SUB>=b<SUB>1</SUB>+b<SUB>2</SUB>+</FONT>…<FONT face="Times New Roman">+b<SUB>n</SUB> then</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">                           </FONT>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">a<SUB>n </SUB></FONT>∑<SUB><FONT face="Times New Roman"> a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">b<SUB>n</SUB>=lim<SUB>a</SUB></FONT><SUB>→∞<FONT face="Times New Roman"> </FONT></SUB><FONT face="Times New Roman">s<SUB>n </SUB>t<SUB>n </SUB></FONT></FONT></P>
<P><FONT face="Times New Roman"><FONT size=3>   In particular, series can be added term by term. Of course , they cannot be multiplied term by term.</FONT></FONT></P>
<P><FONT face="Times New Roman"><FONT size=3>   We also observe that a similar theorem holds for the difference of two series.</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">   If a series </FONT>∑<FONT face="Times New Roman">a<SUB>n</SUB> converges, then the numbers a<SUB>n</SUB> must approach 0 as n becomes large. However, there are examples of sequences {an} for which the series does not converge, and yet lim<SUB>a</SUB></FONT><SUB>→∞</SUB><FONT face="Times New Roman">a<SUB>n</SUB>=0</FONT></FONT></P>
<P><FONT face="Times New Roman"><FONT size=3>
<p></FONT></FONT>
<p>
<P><FONT face="Times New Roman" size=3>Series with Positive Terms</FONT></P>
<P><FONT face="Times New Roman"><FONT size=3>
<p></FONT></FONT>
<p>
<P><FONT size=3><FONT face="Times New Roman">Throughout this section, we shall assume that our numbers a<SUB>n</SUB> are </FONT>><FONT face="Times New Roman"> 0. Then the partial sums</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">                           S<SUB>n</SUB>=a<SUB>1</SUB>+a<SUB>2</SUB>+</FONT>…<FONT face="Times New Roman">+a<SUB>n</SUB></FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>are increasing, i.e.</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">s<SUB>1</SUB></FONT><<FONT face="Times New Roman">s<SUB>2 </SUB></FONT><<FONT face="Times New Roman">s<SUB>3</SUB></FONT><…<<FONT face="Times New Roman">s<SUB>n</SUB></FONT><<FONT face="Times New Roman">s<SUB>n+1</SUB></FONT><…</FONT></P>
<P><FONT face="Times New Roman" size=3>If they are approach a limit at all, they cannot become arbitrarily large. Thus in that case there is a  number B such that </FONT></P>
<P><FONT face="Times New Roman"><FONT size=3>                         S<SUB>n</SUB>&lt; B</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>for all n. The collection of numbers {s<SUB>n</SUB>} has therefore a least upper bound ,i.e. there is a smallest number S such that </FONT></P>
<P><FONT face="Times New Roman"><FONT size=3>                          s<SUB>n</SUB>&lt;S</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">for all n. In that case , the partial sums s<SUB>n</SUB> approach S as a limit. In other words, given any positive number </FONT>ε<FONT face="Times New Roman">&gt;0, we have </FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">S –</FONT>ε<FONT face="Times New Roman">&lt; s<SUB>n </SUB>&lt; S</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>for all n .sufficiently large. This simply expresses the fact that S is the least of all upper bounds for our collection of numbers s<SUB>n</SUB>. We express this as a theorem.</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">THEOREM 2. Let{a<SUB>n</SUB>}(n=1,2,</FONT>…<FONT face="Times New Roman">)be a sequence of numbers&gt;0 and let </FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">                 S<SUB>n</SUB>=a<SUB>1</SUB>+a<SUB>2</SUB>+</FONT>…<FONT face="Times New Roman">+a<SUB>n</SUB></FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>If the sequence of numbers {s<SUB>n</SUB>} is bounded, then it approaches a limit S , which is its least upper bound.</FONT></P>
<P><FONT face="Times New Roman" size=3>Theorem 3 gives us a very useful criterion to determine when a series with positive terms converges:</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">THEOREM 3. Let</FONT>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">a<SUB>n</SUB> and</FONT>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman"> b<SUB>n</SUB> be two series , with a<SUB>n</SUB>&gt;0 for all n and b<SUB>n</SUB>&gt;0 for all n. Assume that there is a number c such that </FONT></FONT></P>
<P><FONT face="Times New Roman"><FONT size=3>                 a<SUB>n</SUB>&lt; c b<SUB>n</SUB></FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">for all n, and that</FONT>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">b<SUB>n</SUB> converges. Then </FONT>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman"> a<SUB>n</SUB> converges, and </FONT></FONT></P>
<P><FONT size=3>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">a<SUB>n </SUB>≤ c</FONT>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">b<SUB>n</SUB></FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>PROOF. We have </FONT></P>
<P><FONT size=3><FONT face="Times New Roman">              a<SUB>1</SUB>+</FONT>…<FONT face="Times New Roman">+a<SUB>n</SUB></FONT>≤<FONT face="Times New Roman">cb<SUB>1</SUB>+</FONT>…<FONT face="Times New Roman">+cb<SUB>n</SUB></FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">              =c(b<SUB>1</SUB>+</FONT>…<FONT face="Times New Roman">+b<SUB>n</SUB>)</FONT>≤<FONT face="Times New Roman"> c</FONT>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">b<SUB>n</SUB> </FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">This means that c</FONT>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">b<SUB>n</SUB> is a bound for the partial sums a<SUB>1</SUB>+</FONT>…<FONT face="Times New Roman">+a<SUB>n</SUB>.The least upper bound of these sums is therefore </FONT>≤<FONT face="Times New Roman"> c</FONT>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">b<SUB>n</SUB>, thereby proving our theorem.</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>Differentiation and Intergration of Power Series.</FONT></P>
<P><FONT face="Times New Roman" size=3>If we have a polynomial</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">                           a<SUB>0</SUB>+a<SUB>1</SUB>x+</FONT>…<FONT face="Times New Roman">+a<SUB>n</SUB>x<SUP>n</SUP></FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">with numbers a<SUB>0</SUB>,a<SUB>1</SUB>,</FONT>…<FONT face="Times New Roman">,a<SUB>n</SUB> as coefficients, then we know how to find its derivative. It is a<SUB>1</SUB>+2a<SUB>2</SUB>x+</FONT>…<FONT face="Times New Roman">+na<SUB>n</SUB>x<SUP>n</SUP></FONT><SUP>–<FONT face="Times New Roman">1</FONT></SUP><FONT face="Times New Roman">. We would like to say that the derivative of a series can be taken in the same way, and that the derivative converges whenever the series does.</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">   THEOREM 4. Let r be a number &gt;0 and let </FONT>∑<FONT face="Times New Roman">a<SUB>n</SUB>x<SUP>n</SUP> be a series which converges absolutely for </FONT>∣<FONT face="Times New Roman">x</FONT>∣<FONT face="Times New Roman">&lt;r. Then the series </FONT>∑<FONT face="Times New Roman">na<SUB>n</SUB>x<SUP>n-1</SUP> also converges absolutely for</FONT>∣<FONT face="Times New Roman">x</FONT>∣<FONT face="Times New Roman">&lt;r.</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">A similar result holds for integration, but trivially. Indeed, if we have a series </FONT>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">a<SUB>n</SUB>x<SUP>n </SUP>which converges absolutely for </FONT>∣<FONT face="Times New Roman">x</FONT>∣<FONT face="Times New Roman">&lt;r, then the series </FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">                  </FONT>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">a<SUB>n</SUB>/n+1 x<SUP>n+1</SUP>=x</FONT>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">a<SUB>n</SUB>x<SUP>n</SUP><SUB> </SUB></FONT>∕<FONT face="Times New Roman">n+1 </FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>has terms whose absolute value is smaller than in the original series.</FONT></P>
<P><FONT face="Times New Roman"><FONT size=3>   The preceding result can be expressed by saying that an absolutely convergent series can be integrated and differentiated term by term and and still yields an absolutely convergent power series.</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>It is natural to expect that if </FONT></P>
<P><FONT size=3><FONT face="Times New Roman">                              f (x)=</FONT>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">a<SUB>n</SUB>x<SUP>n</SUP>,</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>then f is differentiable and its derivative is given by differentiating the series term by term. The next theorem proves this.</FONT></P>
<P><FONT face="Times New Roman"><FONT size=3>   THEOREM 5. Let </FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">                                 f (x)=</FONT>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman"> a<SUB>n</SUB>x<SUP>n</SUP></FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">be a power series, which converges absolutely for</FONT>∣<FONT face="Times New Roman">x</FONT>∣<FONT face="Times New Roman">&lt;r. Then f is differentiable for </FONT>∣<FONT face="Times New Roman">x</FONT>∣<FONT face="Times New Roman">&lt;r, and </FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">                                 f</FONT>′<FONT face="Times New Roman">(x)=</FONT>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">na<SUB>n</SUB>x<SUP>n-1</SUP>.</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">   THEOREM 6. Let f (x)=</FONT>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">a<SUB>n</SUB>x<SUP>n</SUP> be a power series, which converges absolutely for </FONT>∣<FONT face="Times New Roman">x</FONT>∣<FONT face="Times New Roman">&lt;r. Then the relation </FONT></FONT></P>
<P><FONT size=3>∫<FONT face="Times New Roman">f (x)d x=</FONT>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">a<SUB>n</SUB>x<SUP>n+1</SUP></FONT>∕<FONT face="Times New Roman">n+1</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">is valid in the interval </FONT>∣<FONT face="Times New Roman">x</FONT>∣<FONT face="Times New Roman">&lt;r.</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>We omit the proofs of theorems 4,5 and 6.</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">
<p></FONT></FONT>
<p>

hehe123 发表于 2004-11-27 12:46

<P align=center 0cm 0pt; TEXT-ALIGN: center?><B><FONT face="Times New Roman">Vocabulary
</FONT></B><p><P 0cm 0pt; TEXT-INDENT: 21.75pt?><FONT face="Times New Roman"><p></FONT><p><P 0cm 0pt; TEXT-INDENT: 21.75pt?><FONT face="Times New Roman">sequence   </FONT>序列<FONT face="Times New Roman">                           positive term  </FONT>正项</P><P 0cm 0pt; TEXT-INDENT: 21.75pt?><FONT face="Times New Roman">series  </FONT>级数<FONT face="Times New Roman">                               alternate term  </FONT>交错项</P><P 0cm 0pt; TEXT-INDENT: 21.75pt?><FONT face="Times New Roman">approximate </FONT>逼近<FONT face="Times New Roman">,</FONT>近似<FONT face="Times New Roman">                      partial sum  </FONT>部分和</P><P 0cm 0pt; TEXT-INDENT: 21.75pt?><FONT face="Times New Roman">elementary functions </FONT>初等函数<FONT face="Times New Roman">                criterion  </FONT>判别准则<FONT face="Times New Roman">(</FONT>单数<FONT face="Times New Roman">)</FONT></P><P 0cm 0pt; TEXT-INDENT: 21.75pt?><FONT face="Times New Roman">section  </FONT>章节<FONT face="Times New Roman">                              criteria   </FONT>判别准则<FONT face="Times New Roman">(</FONT>多数<FONT face="Times New Roman">)</FONT></P><P 0cm 0pt; TEXT-INDENT: 21.75pt?><FONT face="Times New Roman">convergence  </FONT>收敛<FONT face="Times New Roman">(</FONT>名词<FONT face="Times New Roman">)                    power series </FONT>幂级数</P><P 0cm 0pt; TEXT-INDENT: 21.75pt?><FONT face="Times New Roman">convergent   </FONT>收敛<FONT face="Times New Roman">(</FONT>形容词<FONT face="Times New Roman">)                   coefficient </FONT>系数</P><P 0cm 0pt; TEXT-INDENT: 21.75pt?><FONT face="Times New Roman">absolute convergence </FONT>绝对收敛<FONT face="Times New Roman">                Cauchy sequence </FONT>哥西序列</P><P 0cm 0pt; TEXT-INDENT: 21.75pt?><FONT face="Times New Roman">diverge  </FONT>发散<FONT face="Times New Roman">                               radius of convergence </FONT>收敛半径</P><P 0cm 0pt; TEXT-INDENT: 21.75pt?><FONT face="Times New Roman">term by term  </FONT>逐项<FONT face="Times New Roman">                           M-test  M—</FONT>判别法</P><P 0cm 0pt; TEXT-INDENT: 21.75pt?><FONT face="Times New Roman"><p></FONT><p>

hehe123 发表于 2004-11-27 12:46

<P align=center 0cm 0pt; TEXT-ALIGN: center?><B><FONT face="Times New Roman">Notes
</FONT></B><p><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -18pt; 29.25pt; l7 lfo22?><FONT face="Times New Roman">1.       series</FONT>一词的单数和复数形式都是同一个字<FONT face="Times New Roman">.</FONT>例如<FONT face="Times New Roman">:</FONT></P><P 0cm 0pt TEXT-INDENT: 32.25pt? 11.25pt;><FONT face="Times New Roman">One can define arbitrary functions by giving a series for them(</FONT>单数<FONT face="Times New Roman">)</FONT></P><P 0cm 0pt TEXT-INDENT: 32.25pt? 11.25pt;><FONT face="Times New Roman">The most important series are those which converge absolutely(</FONT>复数<FONT face="Times New Roman">)</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -18pt; 29.25pt; l7 lfo22?><FONT face="Times New Roman">2.       In view of the fact that the limit of a sum of the limits, and other standard properties of limits, we get:</FONT></P><P 0cm 0pt TEXT-INDENT: 37.5pt? 11.25pt;><FONT face="Times New Roman">Theorem 1…</FONT></P><P 0cm 0pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: 1.57; 16.5pt;>这是叙述定理的一种方式<FONT face="Times New Roman">: </FONT>即先将事实说明在前面<FONT face="Times New Roman">,</FONT>再引出定理<FONT face="Times New Roman">. </FONT>此句用<FONT face="Times New Roman">in view of the fact that </FONT>说明事实<FONT face="Times New Roman">,</FONT>再用<FONT face="Times New Roman">we get </FONT>引出定理<FONT face="Times New Roman">.</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -18pt; 29.25pt; l7 lfo22?><FONT face="Times New Roman">3.       We express this as a theorem.</FONT></P><P 0cm 0pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: -21pt; -2.0;><FONT face="Times New Roman">         </FONT>这是当需要证明的事实已再前面作了说明或加以证明后<FONT face="Times New Roman">,</FONT>欲吧已证明的事实总结成定理时<FONT face="Times New Roman">,</FONT>常用倒的一个句子<FONT face="Times New Roman">,</FONT>类似的句子还有<FONT face="Times New Roman">(</FONT>参看附录Ⅲ<FONT face="Times New Roman">):</FONT></P><P 0cm 0pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: -21pt; -2.0;><FONT face="Times New Roman">         We summarize this as the following theorem; Thus we come to the following theorem</FONT>等等<FONT face="Times New Roman">.</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -18pt; 29.25pt; l7 lfo22?><FONT face="Times New Roman">4.       The least upper bound of these sums is therefore </FONT>≤<FONT face="Times New Roman">c</FONT>∑<SUB><FONT face="Times New Roman">a=1</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">b<SUB>n</SUB>, thereby proving our theorem.</FONT></P><P 0cm 0pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: -21pt; -2.0;><FONT face="Times New Roman">        </FONT>最一般的定理证明格式是<FONT face="Times New Roman">”</FONT>给出定理<FONT face="Times New Roman">…</FONT>定理证明<FONT face="Times New Roman">…</FONT>定理证毕<FONT face="Times New Roman">”,</FONT>即<FONT face="Times New Roman">thereby proving our theorem;</FONT>或<FONT face="Times New Roman">we have thus proves the theorem</FONT>或<FONT face="Times New Roman">This completes the proof</FONT>等等作结尾<FONT face="Times New Roman">(</FONT>参看附录Ⅲ<FONT face="Times New Roman">).</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -18pt; 29.25pt; l7 lfo22?><FONT face="Times New Roman">5.       </FONT>本课文使用较多插入语<FONT face="Times New Roman">.</FONT>数学上常见的插入语有<FONT face="Times New Roman">:conversely; in practice; essentially; in particular; indeed; in other words; in short; generally speaking </FONT>等等<FONT face="Times New Roman">.</FONT>插入语通常与句中其它成份没有语法上的关系<FONT face="Times New Roman">,</FONT>一般用逗号与句子隔开<FONT face="Times New Roman">,</FONT>用来表示说话者对句子所表达的意思的态度<FONT face="Times New Roman">.</FONT>插入语可以是一个词<FONT face="Times New Roman">,</FONT>一个短语或者一个句子<FONT face="Times New Roman">.</FONT></P><P 0cm 0pt 11.25pt?><FONT face="Times New Roman"><p></FONT><p>

hehe123 发表于 2004-11-27 12:46

<b><FONT face="Times New Roman">Exercise </FONT></b>
<P><b><FONT face="Times New Roman"></FONT></b></P><P 0cm 0pt?>Ⅰ<FONT face="Times New Roman">. Translate the following exercises into Chinese:</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -18pt; 34.5pt; l22 lfo23?><FONT face="Times New Roman">1.       In exercise 1 through 4,a sequence f (n) is defined by the formula given. In each case, (</FONT>ⅰ<FONT face="Times New Roman">)</FONT></P><P 0cm 0pt?><FONT face="Times New Roman">Determine whether the sequence (the formulae are omitted).</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -18pt; 34.5pt; l22 lfo23?><FONT face="Times New Roman">2.       Assume f  is a non</FONT>–<FONT face="Times New Roman">negative function defined for all x&gt;1. Use the method</FONT></P><P 0cm 0pt; 21pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: 2.0; mso-char-indent-size:><FONT face="Times New Roman">suggested by the proof of the integral test to show that </FONT></P><P 0cm 0pt; 21pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: 2.0; mso-char-indent-size:><FONT face="Times New Roman">               </FONT>∑<FONT face="Times New Roman"><SUB>k=1</SUB><SUP>n-1</SUP>f(k)</FONT>≤∫<FONT face="Times New Roman"><SUB>1</SUB><SUP>n</SUP>f(x)d x </FONT>≤∑<FONT face="Times New Roman"><SUB>k=2</SUB><SUP>n</SUP>f(k)</FONT></P><P 0cm 0pt; 21pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: 2.0; mso-char-indent-size:><FONT face="Times New Roman">Take f(x)=log x and deduce the inequalities</FONT></P><P 0cm 0pt; 21pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: 2.0; mso-char-indent-size:><FONT face="Times New Roman">                c</FONT>•<FONT face="Times New Roman">n<SUP>n</SUP></FONT>•<FONT face="Times New Roman">c<SUP>-n</SUP>&lt; n</FONT>!<FONT face="Times New Roman">&lt;c</FONT>•<FONT face="Times New Roman">n<SUP>n+1</SUP></FONT>•<FONT face="Times New Roman">c<SUP>-n</SUP></FONT></P><P 0cm 0pt 21pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: -21pt; -2.0;>Ⅱ<FONT face="Times New Roman">. The proof of theorem 4 is given in English as follows(Read the proof through and try to learn how a theorem is proved, then translate this proof into Chinese ):</FONT></P><P 0cm 0pt 21pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: -21pt; -2.0;><FONT face="Times New Roman">        Proof of theorem 4 Since we are interested in the absolute convergence. We may assume that a<SUB>n</SUB>&gt;0 for all n. Let 0&lt;x&lt;r, and let c be a number such that x&lt;c&lt;r. Recall that lim<SUB>a</SUB></FONT><SUB>→∞</SUB><FONT face="Times New Roman">n<SUP>1/n</SUP>=1.</FONT></P><P 0cm 0pt 21pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: -21pt; -2.0;><FONT face="Times New Roman">        We may write n a<SUB>n </SUB>x<SUP>n </SUP>=a<SUB>n</SUB>(n<SUP>1/n</SUP>x)<SUP>n</SUP>. Then for all n sufficiently large, we conclude that n<SUP>1/n</SUP>x&lt;c. This is because n1/n comes arbitrarily close to x and x&lt;c. Hence for all n sufficiently large, we have na<SUB>n</SUB>x<SUP>n</SUP>&lt;a<SUB>n</SUB>c<SUP>n</SUP>. We can then compare the series </FONT>∑<FONT face="Times New Roman">na<SUB>n</SUB>x<SUP>n </SUP>with</FONT>∑<FONT face="Times New Roman">a<SUB>n</SUB>c<SUP>n</SUP> to conclude that</FONT>∑<FONT face="Times New Roman">na<SUB>n</SUB>x<SUP>n</SUP> converges. Since</FONT>∑<FONT face="Times New Roman">na<SUB>n</SUB>x<SUP>n-1</SUP>=1/x</FONT>∑<FONT face="Times New Roman">na<SUB>n</SUB>x<SUP>n</SUP>, we have proved theorem 4.</FONT></P><P 0cm 0pt 21pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: -21pt; -2.0;>Ⅲ<FONT face="Times New Roman">. Recall from what you have learned in Calculus about (</FONT>ⅰ<FONT face="Times New Roman">) Cauchy sequence and (</FONT>ⅱ<FONT face="Times New Roman">) the radius of convergence of a power series.</FONT></P><P 0cm 0pt 21pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: -21pt; -2.0;><FONT face="Times New Roman">      Now give the definitions of these two terms respectively.</FONT></P><P 0cm 0pt 21pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: -21pt; -2.0;>Ⅳ<FONT face="Times New Roman">.  Translate the following sentences into Chinese:</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -18pt; 45pt; 45.0pt; l15 lfo24?><FONT face="Times New Roman">1.       </FONT>一旦我们能证明<FONT face="Times New Roman">,</FONT>幂级数∑<FONT face="Times New Roman">a<SUB>n</SUB>z<SUP>n</SUP> </FONT>在点<FONT face="Times New Roman">z=z<SUB>1</SUB></FONT>收敛<FONT face="Times New Roman">,</FONT>则容易证明<FONT face="Times New Roman">,</FONT>对每一<FONT face="Times New Roman">z<SUB>1</SUB></FONT>∣<FONT face="Times New Roman">z</FONT>∣<FONT face="Times New Roman">&lt;</FONT>∣<FONT face="Times New Roman">z<SUB>1</SUB></FONT>∣<FONT face="Times New Roman"> ,</FONT>级数绝对收敛<FONT face="Times New Roman">;</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -18pt; 45pt; 45.0pt; l15 lfo24?><FONT face="Times New Roman">2.       </FONT>因为∑<FONT face="Times New Roman">a<SUB>n</SUB>z<SUP>n</SUP></FONT>在<FONT face="Times New Roman">z=z<SUB>1</SUB></FONT>收敛<FONT face="Times New Roman">,</FONT>于是<FONT face="Times New Roman">,</FONT>由<FONT face="Times New Roman">weierstrass</FONT>的<FONT face="Times New Roman">M—</FONT>判别法可立即得到∑<FONT face="Times New Roman">a<SUB>n</SUB>z<SUP>n</SUP></FONT>在点<FONT face="Times New Roman">z,</FONT>∣<FONT face="Times New Roman">z</FONT>∣<FONT face="Times New Roman">&lt;z<SUB>1</SUB></FONT>的绝对收敛性<FONT face="Times New Roman">;</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -18pt; 45pt; 45.0pt; l15 lfo24?><FONT face="Times New Roman">3.       </FONT>我们知道有限项和中各项可以重新安排而不影响和的值<FONT face="Times New Roman">,</FONT>但对于无穷级数<FONT face="Times New Roman">,</FONT>上述结论却不总是真的</P>

hehe123 发表于 2004-11-27 12:47

数学专业英语[7]-Linear Algebra

<P><FONT face="Times New Roman"><FONT size=3>For the definition that follows we assume that we are given a particular field K. The scalars to be used are to be elements of K.</FONT></FONT></P>
<P><FONT face="Times New Roman"><FONT size=3>   DEFINITION.    A vector space is a set  V  of elements called vectors satisfying the following axioms.</FONT></FONT></P>
<P><FONT face="Times New Roman"><FONT size=3>   (A)    To every pair,   x  and  y ,of vectors in  V  corresponds a vector x+y,called the sum of  x  and  y, in such a way that.</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>(1)  addition is commutative, x + y = y + x.</FONT></P>
<P><FONT face="Times New Roman" size=3>(2)  addition is associative, x + ( y + z ) = ( x + y ) + z.</FONT></P>
<P><FONT face="Times New Roman" size=3>(3)  there exists in  V  a unique vector 0 (called the origin ) such that x + 0 = x for every vector x , and</FONT></P>
<P><FONT face="Times New Roman" size=3>(4)  to every vector x in  V  there corresponds a unique vector - x such that x + ( - x ) = 0.</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">(B)   To every pair,</FONT>α<FONT face="Times New Roman">and x , where </FONT>α<FONT face="Times New Roman"> is a scalar and x is a vector in  V  ,there corresponds a vector </FONT>α<FONT face="Times New Roman">x in  V  , called the product of </FONT>α<FONT face="Times New Roman"> and x , in such a way that </FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">(1)  multiplication by scalars is associative,</FONT>α<FONT face="Times New Roman">(</FONT>β<FONT face="Times New Roman">x ) = (</FONT>αβ<FONT face="Times New Roman">) x</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>(2)  1 x = x for every vector x.</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">(C)  (1) multiplication by scalars is distributive with respect to vector addition,</FONT>α<FONT face="Times New Roman">( x + y ) = </FONT>α<FONT face="Times New Roman">x+</FONT>β<FONT face="Times New Roman">y , and</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">(2)multiplication by vectors is distributive with respect to scalar addition,(</FONT>α<FONT face="Times New Roman">+</FONT>β<FONT face="Times New Roman">) x = </FONT>α<FONT face="Times New Roman">x + </FONT>β<FONT face="Times New Roman">x .</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">The relation between a vector space  V  and the underlying field  K  is usually described by saying that  V  is a vector space over  K . The associated field of scalars is usually either the real numbers  R or the complex numbers  C . If  V is linear space and  M</FONT>真包含于<FONT face="Times New Roman">V , and if </FONT>α<FONT face="Times New Roman"> u -v belong to  M  for every  u  and  v  in  M     and every </FONT>α∈<FONT face="Times New Roman">  K  , then   M  is linear subspace of  V . If U = { u 1,u 2,</FONT>…<FONT face="Times New Roman">} is a collection of points in a linear space  V , then the (linear) span of the set  U  is the set of all points o the form </FONT>∑<FONT face="Times New Roman"> c <SUB>i</SUB> u <SUB>i</SUB> , where c <SUB>i</SUB></FONT>∈<FONT face="Times New Roman">  K ,and all but a finite number of the scalars c<SUB>i</SUB> are 0.The span of U is always a linear subspace of  V.</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">    A key concept in linear algebra is independence. A finite set { u <SUB>1</SUB>,u <SUB>2</SUB>,</FONT>…<FONT face="Times New Roman">, u <SUB>k </SUB>} is said to be linearly independent in  V if the only way to write 0 = </FONT>∑<FONT face="Times New Roman"> c <SUB>i</SUB> u <SUB>i </SUB>  is by choosing all the c <SUB>i</SUB> = 0 . An infinite set is linearly independent if every finite set is independent . If a set is not independent, it is linearly dependent, and in this case, some point in the set can be written as a linear combination of other points in the set. A basis for a linear space  M  is an independent set that spans  M .  A space  M  is finite-dimensional if it can be spanned by a finite set; it can then be shown that every spanning set contains a basis, and every basis for  M  has the same number of points in it. This common number is called the dimension of  M  .</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">Another key concept is that of linear transformation. If  V  and  W  are linear spaces with the same scalar field  K , a mapping  L  from  V  into  W  is called linear if  L (u + v ) =  L( u ) + L ( v ) and  L ( </FONT>α<FONT face="Times New Roman">u ) = </FONT>α<FONT face="Times New Roman"> L ( u )  for every  u  and  v  in  V  and </FONT>α<FONT face="Times New Roman"> in  K . With any  I , are associated two special linear spaces:</FONT></FONT></P>
<P><FONT face="Times New Roman"><FONT size=3>               ker (  L  ) = null space of  L  =  L<SUP>-1  </SUP>(0)</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">                    = { all x </FONT>∈<FONT face="Times New Roman"> V  such that  L ( X ) = 0 }</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">      Im ( L ) = image of  L  =  L( V )  = { all L( x ) for x</FONT>∈<FONT face="Times New Roman"> V }.</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>Then  r = dimension of Im ( L ) is called the rank of  L. If  W also has dimension  n, then the following useful criterion results: L is 1-to-1 if and only if L is onto.In particular, if  L is a linear map of  V into itself, and the only solution of  L( x ) = 0 is 0, then L IS onto and is therefore an isomorphism of V onto  V , and has an inverse  L <SUP>-1</SUP> . Such a transformation  V  is also said to be nonsingular.</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">Suppose now that  L  is a linear transformation from  V  into  W  where dim ( V ) = n and  dim  ( W ) =   m . Choose a basis {</FONT>υ<FONT face="Times New Roman"><SUB>1 </SUB>,</FONT>υ<SUB><FONT face="Times New Roman">2 ,</FONT></SUB>…<FONT face="Times New Roman">,</FONT>υ<FONT face="Times New Roman"><SUB>n</SUB>} for  V and a basis {w <SUB>1 </SUB>,w<SUB>2 </SUB>,</FONT>…<FONT face="Times New Roman">,w <SUB>m</SUB>} for  W . Then these define isomorphisms of  V onto  K<SUP>n  </SUP>and  W onto  K<SUP>m</SUP> , respectively, and these in turn induce a linear transformation  A  between these.  Any linear transformation ( such as  A  ) between  K<SUP>n  </SUP>and  K<SUP>m </SUP>is described by means of a matrix ( a<SUB>ij </SUB>), according to the formula  A ( x )  = y , where  x = { x<SUB>1</SUB> , x <SUB>2</SUB>,</FONT>…<FONT face="Times New Roman">, x<SUB>n</SUB> }    y = { y<SUB>1</SUB> , y <SUB>2</SUB>,</FONT>…<FONT face="Times New Roman">, y <SUB>m</SUB>} and    </FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>     </FONT></P>
<P><FONT size=3><FONT face="Times New Roman">                 Y <SUB>j</SUB>  =</FONT>Σ<FONT face="Times New Roman"><SUP>n</SUP><SUB>j=i</SUB>  a<SUB>ij</SUB> x<SUB>i         </SUB>  I=1,2,</FONT>…<FONT face="Times New Roman">,m.</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>The matrix A is said to represent the transformation  L and to be the representation induced by the particular basis chosen for         V and  W .</FONT></P>
<P><FONT face="Times New Roman" size=3>If S and T are linear transformations of  V into itself, so is the compositic transformation  ST . If we choose a basis in  V , and use this to obtain matrix representations for these, with  A  representing  S and  B representing  T , then ST must have a matrix representation  C  . This is defined to be the product  AB of the matrixes  A  and  B , and leads to the standard formula for matrix multiplication.</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">The least satisfactory aspect of linear algebra is still the theory of determinants even though this is the most ancient portion of the theory, dating back to Leibniz if not to early China. One standard approach to determinants is to regard an n -by- n matrix as an ordered array of vectors( u <SUB>1 </SUB>, u <SUB>2</SUB> ,</FONT>…<FONT face="Times New Roman">, u <SUB>n</SUB> ) and then its determinant det ( A ) as a function F( u <SUB>1 </SUB>, u <SUB>2 </SUB>,</FONT>…<FONT face="Times New Roman">, u <SUB>n</SUB> ) of these n vectors which obeys certain rules.</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">The determinant of such an array  A turns out to be a convenient criterion  for characterizing the nonsingularity of the associated linear transformation, since det ( A ) = F ( u <SUB>1</SUB> , u <SUB>2</SUB> ,</FONT>…<FONT face="Times New Roman">, u <SUB>n</SUB> ) = 0 if and only if the set of vectors  u<SUB>i </SUB>are linearly dependent. There are many other useful and elegant properties  of determinants, most of which will be found in any classic book on linear algebra. Thus, det ( AB ) = det ( A ) det ( B ), and det ( A ) = det ( A') ,where  A' is the transpose of  A , obtained by the formula  A' =( a <SUB>ji </SUB>), thereby rotating the array about the main diagonal. If a square matrix is triangular, meaning that all its entries above the main diagonal are 0,then det ( A ) turns out to be exactly the product of the diagonal entries.</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">Another useful concept is that of eigenvalue. A scalar is said to be an eigenvalue for a transformation  T if there is a nonzero vector  </FONT>υ<FONT face="Times New Roman"> with  T (</FONT>υ<FONT face="Times New Roman">)  </FONT>λυ<FONT face="Times New Roman"> . It is then clear that the eigenvalues will be those numbers </FONT>λ∈<FONT face="Times New Roman">  K such that  T -</FONT>λ<FONT face="Times New Roman"> I is a singular transformation. Any vector in the null space of  T -</FONT>λ<FONT face="Times New Roman"> I is called an eigenvector of  T associated with eigenvalue </FONT>λ<FONT face="Times New Roman">, and their span the eigenspace,  E </FONT><SUB>λ<FONT face="Times New Roman">.</FONT></SUB><FONT face="Times New Roman">  It is invariant under the action of  T , meaning that  T carries  E</FONT><SUB>λ</SUB><FONT face="Times New Roman"> into itself. The eigenvalues of  T  are then  exactly the set of roots of the polynomial  p(</FONT>λ<FONT face="Times New Roman">) =det ( T  -</FONT>λ<FONT face="Times New Roman"> I ).If  A is a matrix representing  T ,then one has  p (</FONT>λ<FONT face="Times New Roman">) det ( A -</FONT>λ<FONT face="Times New Roman">I ), which permits one to find the eigenvalues of  T easily if the dimension of  V is not too large, or if the matrix  A is simple enough. The eigenvalues and eigenspaces of   T provide a means by which the nature and structure of the linear transformation  T can be examined in detail.</FONT></FONT></P>

hehe123 发表于 2004-11-27 12:48

<P align=center 0cm 0pt; TEXT-ALIGN: center?><B><FONT face="Times New Roman">Vocabulary</FONT></B></P><P mso-layout-grid-align: none? 0cm 0pt;><FONT face="Times New Roman">
</FONT><p><P mso-layout-grid-align: none? 0cm 0pt; 21pt; TEXT-INDENT:><FONT face="Times New Roman">linear algebra     </FONT>线性代数<FONT face="Times New Roman">               non-singular    </FONT>非奇异</P><P mso-layout-grid-align: none? 0cm 0pt; 21pt; TEXT-INDENT:><FONT face="Times New Roman">field    </FONT>域<FONT face="Times New Roman">                               isomorphism     </FONT>同构</P><P mso-layout-grid-align: none? 0cm 0pt; 21pt; TEXT-INDENT:><FONT face="Times New Roman">vector   </FONT>向量<FONT face="Times New Roman">                             isomorphic    </FONT>同构</P><P mso-layout-grid-align: none? 0cm 0pt; 21pt; TEXT-INDENT:><FONT face="Times New Roman">scalar   </FONT>纯量<FONT face="Times New Roman">,</FONT>无向量<FONT face="Times New Roman">                      matrix    </FONT>矩阵<FONT face="Times New Roman">(</FONT>单数<FONT face="Times New Roman">)</FONT></P><P mso-layout-grid-align: none? 0cm 0pt; 21pt; TEXT-INDENT:><FONT face="Times New Roman">vector space   </FONT>向量空间<FONT face="Times New Roman">                   matrices    </FONT>矩阵<FONT face="Times New Roman">(</FONT>多数<FONT face="Times New Roman">)</FONT></P><P mso-layout-grid-align: none? 0cm 0pt; 21pt; TEXT-INDENT:><FONT face="Times New Roman">span    </FONT>生成<FONT face="Times New Roman">,</FONT>长成<FONT face="Times New Roman">                         determinant      </FONT>行列式</P><P mso-layout-grid-align: none? 0cm 0pt; 21pt; TEXT-INDENT:><FONT face="Times New Roman">independence   </FONT>无关<FONT face="Times New Roman">(</FONT>性<FONT face="Times New Roman">),</FONT>独立<FONT face="Times New Roman">(</FONT>性<FONT face="Times New Roman">)          array    </FONT>阵列</P><P mso-layout-grid-align: none? 0cm 0pt; 21pt; TEXT-INDENT:><FONT face="Times New Roman">dependence    </FONT>有关<FONT face="Times New Roman">(</FONT>性<FONT face="Times New Roman">)                    diagonal    </FONT>对角线</P><P mso-layout-grid-align: none? 0cm 0pt; 21pt; TEXT-INDENT:><FONT face="Times New Roman">linear combination    </FONT>线性组合<FONT face="Times New Roman">            triangular    </FONT>三角形的</P><P mso-layout-grid-align: none? 0cm 0pt; 21pt; TEXT-INDENT:><FONT face="Times New Roman">basis    </FONT>基<FONT face="Times New Roman">(</FONT>单数<FONT face="Times New Roman">)                         entry       </FONT>表值<FONT face="Times New Roman">,</FONT>元素</P><P mso-layout-grid-align: none? 0cm 0pt; 21pt; TEXT-INDENT:><FONT face="Times New Roman">basis    </FONT>基<FONT face="Times New Roman">(</FONT>多数<FONT face="Times New Roman">)                         eigenvalue   </FONT>特征值<FONT face="Times New Roman">,</FONT>本征值</P><P mso-layout-grid-align: none? 0cm 0pt; 21pt; TEXT-INDENT:><FONT face="Times New Roman">dimension  </FONT>维<FONT face="Times New Roman">                             eigenvector    </FONT>特征向量</P><P mso-layout-grid-align: none? 0cm 0pt; 21pt; TEXT-INDENT:><FONT face="Times New Roman">linear transformation   </FONT>线性变换<FONT face="Times New Roman">          invariant     </FONT>不变<FONT face="Times New Roman">,</FONT>不变量</P><P mso-layout-grid-align: none? 0cm 0pt; 21pt; TEXT-INDENT:><FONT face="Times New Roman">null space    </FONT>零空间<FONT face="Times New Roman">                      row    </FONT>行</P><P mso-layout-grid-align: none? 0cm 0pt; 21pt; TEXT-INDENT:><FONT face="Times New Roman">rank    </FONT>秩<FONT face="Times New Roman">                                column  </FONT>列</P><P mso-layout-grid-align: none? 0cm 0pt; 21pt; TEXT-INDENT:><FONT face="Times New Roman">singular    </FONT>奇异<FONT face="Times New Roman">                          system of equations   </FONT>方程组</P><P mso-layout-grid-align: none? 0cm 0pt; 21pt; TEXT-INDENT:><FONT face="Times New Roman">                                          homogeneous      </FONT>齐次</P>
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