</FONT><p><P 0cm 0pt?><FONT face="Times New Roman">continuity </FONT>连续性<FONT face="Times New Roman"> assume </FONT>假定<FONT face="Times New Roman">,</FONT>取<FONT face="Times New Roman"> </FONT></P><P 0cm 0pt?><FONT face="Times New Roman">continuous </FONT>连续的<FONT face="Times New Roman"> specify </FONT>指定<FONT face="Times New Roman">, </FONT>详细说明</P><P 0cm 0pt?><FONT face="Times New Roman">continuous function </FONT>连续函数<FONT face="Times New Roman"> statement </FONT>陈述<FONT face="Times New Roman">,</FONT>语句</P><P 0cm 0pt?><FONT face="Times New Roman">intuitive </FONT>直观的<FONT face="Times New Roman"> right-hand limit </FONT>右极限</P><P 0cm 0pt?><FONT face="Times New Roman">corresponding </FONT>对应的<FONT face="Times New Roman"> left-hand limit </FONT>左极限</P><P 0cm 0pt?><FONT face="Times New Roman">correspondence </FONT>对应<FONT face="Times New Roman"> restrict </FONT>限制于</P><P 0cm 0pt?><FONT face="Times New Roman">graph </FONT>图形<FONT face="Times New Roman"> assertion </FONT>断定</P><P 0cm 0pt?><FONT face="Times New Roman">approach </FONT>趋近<FONT face="Times New Roman">,</FONT>探索<FONT face="Times New Roman">,</FONT>入门<FONT face="Times New Roman"> consequently </FONT>因而<FONT face="Times New Roman">,</FONT>所以</P><P 0cm 0pt?><FONT face="Times New Roman">tend to </FONT>趋向<FONT face="Times New Roman"> prove </FONT>证明</P><P 0cm 0pt?><FONT face="Times New Roman">regardless </FONT>不管<FONT face="Times New Roman">,</FONT>不顾<FONT face="Times New Roman"> proof </FONT>证明</P><P 0cm 0pt?><FONT face="Times New Roman">discontinuous </FONT>不连续的<FONT face="Times New Roman"> bound </FONT>限界</P><P 0cm 0pt?><FONT face="Times New Roman">jump discontinuity </FONT>限跳跃不连续<FONT face="Times New Roman"> least upper bound </FONT>上确界</P><P 0cm 0pt?><FONT face="Times New Roman">mathematician </FONT>科学家<FONT face="Times New Roman"> greatest lower bound </FONT>下确界</P><P 0cm 0pt?><FONT face="Times New Roman">formulate </FONT>用公式表示<FONT face="Times New Roman">,</FONT>阐述<FONT face="Times New Roman"> boundedness </FONT>有界性</P><P 0cm 0pt?><FONT face="Times New Roman">limit </FONT>极限<FONT face="Times New Roman"> maximum </FONT>最大值</P><P 0cm 0pt?><FONT face="Times New Roman">Interval </FONT>区间<FONT face="Times New Roman"> minimum </FONT>最小值</P><P 0cm 0pt?><FONT face="Times New Roman">open interval </FONT>开区间<FONT face="Times New Roman"> extreme value </FONT>极值</P><P 0cm 0pt?><FONT face="Times New Roman">equation </FONT>方程<FONT face="Times New Roman"> extremum </FONT>极值</P><P 0cm 0pt?><FONT face="Times New Roman">neighborhood </FONT>邻域<FONT face="Times New Roman"> increasing function </FONT>增函数</P><P 0cm 0pt?><FONT face="Times New Roman">midpoint </FONT>中点<FONT face="Times New Roman"> decreasing function </FONT>减函数</P><P 0cm 0pt?><FONT face="Times New Roman">symmetric </FONT>对称的<FONT face="Times New Roman"> strict </FONT>严格的</P><P 0cm 0pt; tab-stops: 216.0pt?><FONT face="Times New Roman">radius </FONT>半径<FONT face="Times New Roman">(</FONT>单数<FONT face="Times New Roman">) uniformly continuous </FONT>一致连续</P><P 0cm 0pt?><FONT face="Times New Roman">radii </FONT>半径<FONT face="Times New Roman">(</FONT>复数<FONT face="Times New Roman">) monotonic </FONT>单调的</P><P 0cm 0pt?><FONT face="Times New Roman">inequality </FONT>不等式<FONT face="Times New Roman"> monotonic function </FONT>单调函数</P><P 0cm 0pt?><FONT face="Times New Roman">equivalent </FONT>等价的</P><P 0cm 0pt?><FONT face="Times New Roman"><I> </I> </FONT></P> <P align=center 0cm 0pt; TEXT-ALIGN: center?><FONT face="Times New Roman"><B>Notes</B>
</FONT><p><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list 18.0pt; 18pt; -18pt; l61 lfo9?><FONT face="Times New Roman">1. It wad not until late in the 18th century that discontinuous functions began appearing in connection with various kinds of physical problems.</FONT></P><P 0cm 0pt 18pt?>意思是<FONT face="Times New Roman">:</FONT>直到十八世纪末<FONT face="Times New Roman">,</FONT>不连续函数才开始出现于与物理学有关的各类问题中<FONT face="Times New Roman">.</FONT></P><P 0cm 0pt 18pt?>这里<FONT face="Times New Roman">It was not until …that</FONT>译为“直到<FONT face="Times New Roman">……</FONT>才”</P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list 18.0pt; 18pt; -18pt; l61 lfo9?><FONT face="Times New Roman">2. </FONT><FONT face="Times New Roman">The symbol </FONT><v:shapetype><v:stroke joinstyle="miter"></v:stroke><v:formulas><v:f eqn="if lineDrawn pixelLineWidth 0"></v:f><v:f eqn="sum @0 1 0"></v:f><v:f eqn="sum 0 0 @1"></v:f><v:f eqn="prod @2 1 2"></v:f><v:f eqn="prod @3 21600 pixelWidth"></v:f><v:f eqn="prod @3 21600 pixelHeight"></v:f><v:f eqn="sum @0 0 1"></v:f><v:f eqn="prod @6 1 2"></v:f><v:f eqn="prod @7 21600 pixelWidth"></v:f><v:f eqn="sum @8 21600 0"></v:f><v:f eqn="prod @7 21600 pixelHeight"></v:f><v:f eqn="sum @10 21600 0"></v:f></v:formulas><v:path extrusionok="f" connecttype="rect" gradientshapeok="t"></v:path><LOCK aspectratio="t" v:ext="edit"></LOCK></v:shapetype><v:shape><v:imagedata><FONT face="Times New Roman"></FONT></v:imagedata></v:shape><FONT face="Times New Roman"><I>f ( x ) = A</I> means that for every </FONT>ε<FONT face="Times New Roman">> 0 ,there is a </FONT>δ<FONT face="Times New Roman">> 0, such that</FONT></P><P 0cm 0pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: 31.5pt; 3.0;><FONT face="Times New Roman">|<I>f( x ) - A|<</I></FONT><I>ε</I><FONT face="Times New Roman"> whenever <I>0 <</I>|<I> x – p </I>|<I><</I></FONT><I>δ</I></P><P 0cm 0pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: 31.5pt; 3.0;>注意此种句型<FONT face="Times New Roman">.</FONT>凡涉及极限的其它定义<FONT face="Times New Roman">,</FONT>如本课中定义函数在点<FONT face="Times New Roman">P</FONT>连续及往后出现的关于收敛的定义等<FONT face="Times New Roman">,</FONT>都有完全类似的句型<FONT face="Times New Roman">,</FONT>参看附录<FONT face="Times New Roman">IV.</FONT></P><P 0cm 0pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: 31.5pt; 3.0;>有时句中<FONT face="Times New Roman">there is</FONT>可换为<FONT face="Times New Roman">there exists; such that</FONT>可换为<FONT face="Times New Roman">satisfying; whenever</FONT>换成<FONT face="Times New Roman">if</FONT>或<FONT face="Times New Roman">for.</FONT></P><P 0cm 0pt?><FONT face="Times New Roman">3. Let…and assume (suppose)…Then…</FONT></P><P 0cm 0pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: 31.5pt; 3.0;>这一句型是定理叙述的一种最常见的形式<FONT face="Times New Roman">;</FONT>参看附录<FONT face="Times New Roman">IV.</FONT>一般而语文课<FONT face="Times New Roman"> Let</FONT>假设条件的大前提<FONT face="Times New Roman">,assume (suppose)</FONT>是小前提<FONT face="Times New Roman">(</FONT>即进一步的假设条件<FONT face="Times New Roman">),</FONT>而<FONT face="Times New Roman">if</FONT>是对具体而关键的条件的使用语<FONT face="Times New Roman">.</FONT></P><P 0cm 0pt?><FONT face="Times New Roman">4. Approach</FONT>在这里是“趋于”<FONT face="Times New Roman">,</FONT>“趋近”的意思<FONT face="Times New Roman">,</FONT>是及物动词<FONT face="Times New Roman">.</FONT>如<FONT face="Times New Roman">:</FONT></P><P 0cm 0pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: 31.5pt; 3.0;><FONT face="Times New Roman"><I>f ( x ) </I>approaches <I>A </I>as <I>x</I> approaches <I>p</I>. Approach</FONT>有时可代以<FONT face="Times New Roman">tend to. </FONT>如<FONT face="Times New Roman"><I>f ( x )</I> tends to <I>A</I> as <I>x</I> tends to <I>p</I>.</FONT>值得留意的是<FONT face="Times New Roman">approach</FONT>后不加<FONT face="Times New Roman">to</FONT>而<FONT face="Times New Roman">tend</FONT>之后应加<FONT face="Times New Roman">to.</FONT></P><P 0cm 0pt?><FONT face="Times New Roman">5. as close to <I>A</I> as we please = arbitrarily close to <I>A..</I></FONT></P> <P align=center 0cm 0pt; TEXT-ALIGN: center?><FONT face="Times New Roman"><B>Exercise</B>
</FONT><p><P 0cm 0pt?><FONT face="Times New Roman">I. Fill in each blank with a suitable word to be chosen from the words given below:</FONT></P><P 0cm 0pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: 48pt; 4.57;><FONT face="Times New Roman">independent domain correspondence</FONT></P><P 0cm 0pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: 48pt; 4.57;><FONT face="Times New Roman">associates variable range</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -18pt; 28.5pt; l14 lfo11?><FONT face="Times New Roman">(a) Let <I>y = f ( x )</I> be a function defined on [<I>a, b</I>]. Then</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: list -36pt; level2 l14 lfo11? 67.5pt;><FONT face="Times New Roman">(i) <I>x</I> is called the ____________variable.</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: list -36pt; level2 l14 lfo11? 67.5pt;><FONT face="Times New Roman">(ii) <I>y</I> is called the dependent ___________.</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: list -36pt; level2 l14 lfo11? 67.5pt;><FONT face="Times New Roman">(iii) The interval is called the ___________ of the function.</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -18pt; 28.5pt; l14 lfo11?><FONT face="Times New Roman">(b) In set terminology, the definition of a function may be given as follows:</FONT></P><P 0cm 0pt 28.5pt?><FONT face="Times New Roman">Given two sets <I>X</I> and <I>Y</I>, a function <I>f : X </I></FONT><I>→<FONT face="Times New Roman"> Y</FONT></I><FONT face="Times New Roman"> is a __________which ___________with each element of <I>X</I> one and only one element of <I>Y.</I> </FONT></P><P 0cm 0pt?><FONT face="Times New Roman">II. a) Which function, the exponential function or the logarithmic function, has the property that it satisfies the functional equation</FONT></P><P 0cm 0pt; TEXT-INDENT: 78.75pt?><I><FONT face="Times New Roman">f ( xy ) = f ( x ) + f ( v ) <p></FONT></I><p><P 0cm 0pt 21pt?><FONT face="Times New Roman"> b) Give the functional equation which will be satisfied by the function which you do not choose in (a).</FONT></P><P 0cm 0pt 21pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: -21pt; -2.0;><FONT face="Times New Roman">III. Let <I>f</I> be a real-valued function defined on a set <I>S</I> of real numbers. Then we have the following two definitions:</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -36pt; 52.5pt; l2 lfo12?><FONT face="Times New Roman">i) <I>f</I> is said to be increasing on the set <I>S </I>if<I> f ( x ) < f ( y )</I> for every pair of points <I>x </I>and <I>y </I>with <I>x < y.</I></FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -36pt; 52.5pt; l2 lfo12?><FONT face="Times New Roman">ii) <I>f </I>is said to have and absolute maximum on the set <I>S</I> if there is a point <I>c</I> in <I>S </I>such that <I>f ( x ) < f ( c )</I> for all <I>x</I></FONT><I>∈<FONT face="Times New Roman"> S.</FONT></I></P><P 0cm 0pt 16.5pt?><FONT face="Times New Roman"><p></FONT><p><P 0cm 0pt?><FONT face="Times New Roman">Now define</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: list level2 -18pt; l2 lfo12? 55.5pt;><FONT face="Times New Roman">a) a strictly increasing function;</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: list level2 -18pt; l2 lfo12? 55.5pt;><FONT face="Times New Roman">b) a monotonic function;</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: list level2 -18pt; l2 lfo12? 55.5pt;><FONT face="Times New Roman">c) the relative (or local ) minimum of <I>f </I>.</FONT></P><P 0cm 0pt 37.5pt?><FONT face="Times New Roman"><p></FONT><p><P 0cm 0pt 37.5pt?><FONT face="Times New Roman"><p></FONT><p><P 0cm 0pt?><FONT face="Times New Roman">IV. Translate theorems 1-3 into Chinese.</FONT></P><P 0cm 0pt?><FONT face="Times New Roman">V. Translate the following definition into English:</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> </FONT>定义<FONT face="Times New Roman">:</FONT>设<FONT face="Times New Roman">E </FONT>是定义在实数集<FONT face="Times New Roman"> <I>E</I> </FONT>上的函数<FONT face="Times New Roman">,</FONT>那么<FONT face="Times New Roman">, </FONT>当且仅当对应于每一ε<FONT face="Times New Roman">>0(</FONT>ε不依赖于<I><FONT face="Times New Roman">E</FONT></I>上的点<FONT face="Times New Roman">)</FONT>存在一个正数δ使得当<FONT face="Times New Roman"><I> p</I> </FONT>和<FONT face="Times New Roman"> <I>q</I> </FONT>属于<FONT face="Times New Roman">E</FONT>且<FONT face="Times New Roman">|<I>p –q</I>| <</FONT>δ时有<FONT face="Times New Roman">|<I>f ( p ) – f ( q )</I>|<</FONT>ε<FONT face="Times New Roman">,</FONT>则称<I><FONT face="Times New Roman">f</FONT></I>在<I><FONT face="Times New Roman">E</FONT></I>上一致连续<FONT face="Times New Roman">.</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"><p></FONT><p><P 0cm 0pt?><FONT face="Times New Roman"><p></FONT><p><P 0cm 0pt?><FONT face="Times New Roman"><p></FONT><p><P 0cm 0pt?><FONT face="Times New Roman"><p></FONT><p>
数学专业英语[4]-Differential Calculus
<P><B><FONT face="Times New Roman">Historical Introduction</FONT></B></P><P><FONT face="Times New Roman" size=3>Newton and Leibniz,quite independently of one another,were largely responsible for developing the ideas of integral calculus to the point where hitherto insurmountable problems could be solved by more or less routine methods.The successful accomplishments of these men were primarily due to the fact that they were able to fuse together the integral calculus with the second main branch of calculus,differential calculus.</FONT></P>
<P><FONT face="Times New Roman" size=3>The central idea of differential calculus is the notion of derivative.Like the integral,the derivative originated from a problem in geometry—the problem of finding the tangent line at a point of a curve.Unlile the integral,however,the derivative evolved very late in the history of mathematics.The concept was not formulated until early in the 17<SUP>th</SUP> century when the French mathematician Pierre de Fermat,attempted to determine the maxima and minima of certain special functions.</FONT></P>
<P><FONT face="Times New Roman" size=3>Fermat’s idea,basically very simple,can be understood if we refer to a curve and assume that at each of its points this curve has a definite direction that can be described by a tangent line.Fermat noticed that at certain points where the curve has a maximum or minimum,the tangent line must be horizontal.Thus the problem of locating such extreme values is seen to depend on the solution of another problem,that of locating the horizontal tangents.</FONT></P>
<P><FONT face="Times New Roman" size=3>This raises the more general question of determining the direction of the tangent line at an arbitrary point of the curve.It was the attempt to solve this general problem that led Fermat to discover some of the rudimentary ideas underlying the notion of derivative.</FONT></P>
<P><FONT face="Times New Roman" size=3>At first sight there seems to be no connection whatever between the problem of finding the area of a region lying under a curve and the problem of finding the tangent line at a point of a curve.The first person to realize that these two seemingly remote ideas are,in fact, rather intimately related appears to have been Newton’s teacher,Isaac Barrow(1630-1677).However,Newton and Leibniz were the first to understand the real importance of this relation and they exploited it to the fullest,thus inaugurating an unprecedented era in the development of mathematics.</FONT></P>
<P><FONT face="Times New Roman" size=3>Although the derivative was originally formulated to study the problem of tangents,it was soon found that it also provides a way to calculate velocity and,more generally,the rate of change of a function.In the next section we shall consider a special problem involving the calculation of a velocity.The solution of this problem contains all the essential fcatures of the derivative concept and may help to motivate the general definition of derivative which is given below.</FONT></P>
<P><B><FONT face="Times New Roman">A Problem Involving Velocity</FONT></B></P>
<P><FONT face="Times New Roman" size=3>Suppose a projectile is fired straight up from the ground with initial velocity of 144 feet persecond.Neglect friction,and assume the projectile is influenced only by gravity so that it moves up and back along a straight line.Let f(t) denote the height in feet that the projectile attains t seconds after firing.If the force of gravity were not acting on it,the projectile would continue to move upward with a constant velocity,traveling a distance of 144 feet every second,and at time t we woule have f(t)=144 t.In actual practice,gravity causes the projectile to slow down until its velocity decreases to zero and then it drops back to earth.Physical experiments suggest that as the projectile is aloft,its height f(t) is given by the formula</FONT></P>
<P><FONT face="Times New Roman"><FONT size=3>(1)</FONT> <FONT size=3>f(t)=144t –16 t<SUP>2</SUP></FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>The term –16t<SUP>2</SUP> is due to the influence of gravity.Note that f(t)=0 when t=0 and when t=9.This means that the projectile returns to earth after 9 seconds and it is to be understood that formula (1) is valid only for 0<t<9.</FONT></P>
<P><FONT face="Times New Roman" size=3>The problem we wish to consider is this:To determine the velocity of the projectile at each instant of its motion.Before we can understand this problem,we must decide on what is meant by the velocity at each instant.To do this,we introduce first the notion of average velocity during a time interval,say from time t to time t+h.This is defined to be the quotient.</FONT></P>
<P><FONT face="Times New Roman" size=3>Change in distance during time interval =f(t+h)-f(t)/h</FONT></P>
<TABLE cellSpacing=0 cellPadding=0 border=1>
<TR>
<TD vAlign=top width=276>
<P><FONT face="Times New Roman">Length of time interval</FONT></P></TD></TR></TABLE>
<P><FONT face="Times New Roman" size=3>This quotient,called a difference quotient,is a number which may be calculated whenever both t and t+h are in the interval.The number h may be positive or negative,but not zero.We shall keep t fixed and see what happens to the difference quotient as we take values of h with smaller and smaller absolute value.</FONT></P>
<P><FONT face="Times New Roman" size=3>The limit process by which v(t) is obtained from the difference quotient is written symbolically as follows:</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">V(t)=lim<SUB>(h</SUB></FONT><SUB>→<FONT face="Times New Roman">0)</FONT></SUB><FONT face="Times New Roman"> /h</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>The equation is used to define velocity not only for this particular example but,more generally,for any particle moving along a straight line,provided the position function f is such that the differerce quotient tends to a definite limit as h approaches zero.</FONT></P>
<P><FONT face="Times New Roman" size=3>The example describe in the foregoing section points the way to the introduction of the concept of derivative.We begin with a function f defined at least on some open interval(a,b) on the x axis.Then we choose a fixed point in this interval and introduce the difference quotient</FONT></P>
<P><FONT face="Times New Roman" size=3>/h</FONT></P>
<P><FONT face="Times New Roman" size=3>where the number h,which may be positive or negative(but not zero),is such that x+h also lies in(a,b).The numerator of this quotient measures the change in the function when x changes from x to x+h.The quotient itself is referred to as the average rate of change of f in the interval joining x to x+h.</FONT></P>
<P><FONT face="Times New Roman" size=3>Now we let h approach zero and see what happens to this quotient.If the quotient.If the quotient approaches some definite values as a limit(which implies that the limit is the same whether h approaches zero through positive values or through negative values),then this limit is called the derivative of f at x and is denoted by the symbol f’(x) (read as “f prime of x”).Thus the formal definition of f’(x) may be stated as follows:</FONT></P>
<P><FONT face="Times New Roman" size=3>Definition of derivative.The derivative f’(x)is defined by the equation</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">f’(x)=lim<SUB>(h</SUB></FONT><SUB>→<FONT face="Times New Roman">o)</FONT></SUB><FONT face="Times New Roman">/h</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>provided the limit exists.The number f’(x) is also called the rate of change of f at x.</FONT></P>
<P><FONT face="Times New Roman" size=3>In general,the limit process which produces f’(x) from f(x) gives a way of obtaining a new function f’ from a given function f.This process is called differentiation,and f’ is called the first derivative of f.If f’,in turn,is defined on an interval,we can try to compute its first derivative,denoted by f’’,and is called the second derivative of f.Similarly,the nth derivative of f denoted by f^(n),is defined to be the first derivative of f^(n-1).We make the convention that f^(0)=f,that is,the zeroth derivative is the function itself.</FONT></P> <P align=center 0cm 0pt; TEXT-ALIGN: center?><A><B><FONT face="Times New Roman">Vocabulary</FONT></B></A></P><P 0cm 0pt?><FONT face="Times New Roman">differential calculus</FONT>微积分<FONT face="Times New Roman"> differentiable</FONT>可微的</P><P 0cm 0pt?><FONT face="Times New Roman">intergral calculus </FONT>积分学<FONT face="Times New Roman"> differentiate </FONT>求微分</P><P 0cm 0pt?><FONT face="Times New Roman">hither to </FONT>迄今<FONT face="Times New Roman"> integration </FONT>积分法</P><P 0cm 0pt?><FONT face="Times New Roman">insurmountable </FONT>不能超越<FONT face="Times New Roman"> integral </FONT>积分</P><P 0cm 0pt?><FONT face="Times New Roman">routine </FONT>惯常的<FONT face="Times New Roman"> integrable </FONT>可积的</P><P 0cm 0pt?><FONT face="Times New Roman">fuse </FONT>融合<FONT face="Times New Roman"> integrate </FONT>求积分</P><P 0cm 0pt?><FONT face="Times New Roman">originate </FONT>起源于<FONT face="Times New Roman"> sign-preserving</FONT>保号</P><P 0cm 0pt?><FONT face="Times New Roman">evolve </FONT>发展,引出<FONT face="Times New Roman"> axis </FONT>轴(单数)</P><P 0cm 0pt?><FONT face="Times New Roman">tangent line </FONT>切线<FONT face="Times New Roman"> axes </FONT>轴(复数)</P><P 0cm 0pt?><FONT face="Times New Roman">direction </FONT>方向<FONT face="Times New Roman"> contradict </FONT>矛盾</P><P 0cm 0pt?><FONT face="Times New Roman">horizontal </FONT>水平的<FONT face="Times New Roman"> contradiction </FONT>矛盾</P><P 0cm 0pt?><FONT face="Times New Roman">vertical </FONT>垂直的<FONT face="Times New Roman"> contrary </FONT>相反的</P><P 0cm 0pt?><FONT face="Times New Roman">rudimentary </FONT>初步的,未成熟的<FONT face="Times New Roman"> composite function </FONT>合成函数,复合函数</P><P 0cm 0pt?><FONT face="Times New Roman">area </FONT>面积<FONT face="Times New Roman"> composition </FONT>复合函数</P><P 0cm 0pt?><FONT face="Times New Roman">intimately </FONT>紧密地<FONT face="Times New Roman"> interior </FONT>内部</P><P 0cm 0pt?><FONT face="Times New Roman">exploit </FONT>开拓,开发<FONT face="Times New Roman"> interior point </FONT>内点</P><P 0cm 0pt?><FONT face="Times New Roman">inaugurate </FONT>开始<FONT face="Times New Roman"> imply </FONT>推出,蕴含</P><P 0cm 0pt?><FONT face="Times New Roman">projectile </FONT>弹丸<FONT face="Times New Roman"> aloft </FONT>高入云霄</P><P 0cm 0pt?><FONT face="Times New Roman">friction</FONT>摩擦<FONT face="Times New Roman"> initial </FONT>初始的</P><P 0cm 0pt?><FONT face="Times New Roman">gravity </FONT>引力<FONT face="Times New Roman"> instant </FONT>瞬时</P><P 0cm 0pt?><FONT face="Times New Roman">rate of change </FONT>变化率<FONT face="Times New Roman"> integration by parts</FONT>分部积分</P><P 0cm 0pt?><FONT face="Times New Roman">attain </FONT>达到<FONT face="Times New Roman"> definite integral </FONT>定积分</P><P 0cm 0pt?><FONT face="Times New Roman">defferential </FONT>微分<FONT face="Times New Roman"> indefinite integral </FONT>不定积分</P><P 0cm 0pt?><FONT face="Times New Roman">differentiation </FONT>微分法<FONT face="Times New Roman"> average </FONT>平均</P><P 0cm 0pt?><FONT face="Times New Roman"> </FONT></P> <P align=center 0cm 0pt; TEXT-ALIGN: center?><FONT face="Times New Roman"><B>Notes</B>
</FONT><p><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list 18.0pt; 18pt; -18pt; l69 lfo14?><FONT face="Times New Roman">1. Newton and Leibniz,quite independently of one another,were largely responsible for developing…by more or less routine methods.</FONT></P><P 0cm 0pt 18pt?>意思是:在很大程度上是牛顿和莱伯尼,他们相互独立地把积分学的思想发展到这样一种程度,使得迄今一些难于超越的问题可以或多或少地用通常的方法加以解决。</P><P 0cm 0pt 18pt?>这里<FONT face="Times New Roman">responsible for</FONT>的基本意义是:“对<FONT face="Times New Roman">…</FONT>负责”,但也可作“应归功于”解,这里应理解为“归功于”。</P><P 0cm 0pt 21pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: -21pt; -2.0;><FONT face="Times New Roman">2</FONT>.<FONT face="Times New Roman">The example described in the foregoing section points the way to the introduction of the concept of derivative.</FONT></P><P 0cm 0pt 21pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: -21pt; -2.0;><FONT face="Times New Roman"> </FONT>意思是:前面一节所描述的例子指出了引进导数概念的方法。</P><P 0cm 0pt 21pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: -21pt; -2.0;><FONT face="Times New Roman"> </FONT>这里<FONT face="Times New Roman">described</FONT>是过去分词,<FONT face="Times New Roman">foregoing</FONT>是现在分词,两者都用作定语,切不可误认<FONT face="Times New Roman">described</FONT>为过去式谓语。类似句子如:</P><P 0cm 0pt 21pt; TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: -21pt; -2.0;><FONT face="Times New Roman"> We begin with a function f defined on some interval(a,b);</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list 18.0pt; 18pt; -18pt; l58 lfo15?><FONT face="Times New Roman">3. The quotient itself is referred to as the average of change of f in the interval joining x to x+h.</FONT></P><P 0cm 0pt 18pt?>意思是:商本身是指区间<FONT face="Times New Roman">x</FONT>到<FONT face="Times New Roman">x+h</FONT>上<FONT face="Times New Roman">f</FONT>的平均变化率。这里<FONT face="Times New Roman">be referred to as</FONT>意思是:“把<FONT face="Times New Roman">…</FONT></P><P 0cm 0pt; TEXT-INDENT: 21.75pt?>认为是“</P><P 0cm 0pt?><FONT face="Times New Roman">4</FONT>.<FONT face="Times New Roman">We make the convention that f<SUP>0</SUP>=f</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> </FONT>意思是:我们约定(按惯例)<FONT face="Times New Roman">f<SUP>0</SUP>=f</FONT></P> <P align=center 0cm 0pt; TEXT-ALIGN: center?><FONT face="Times New Roman"><B>Exercise</B>
</FONT><p><P 0cm 0pt?><FONT face="Times New Roman">I.1.Fill in the missing words in column B such that the word in column B corresponds to the word in column A in the same sense as “integration”corresponds to “differentiation”</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> A B</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> Differentiation integration</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> Differential</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> Differentiate</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> Differentiable</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list 18.0pt; 18pt; -18pt; l69 lfo14?><FONT face="Times New Roman">1. Then choose the correct word from either column A or column B and insert it in each of the blanks.</FONT></P><P 0cm 0pt?><FONT face="Times New Roman">(i)The process of finding the derivative of a function is called( )</FONT></P><P 0cm 0pt?><FONT face="Times New Roman">(ii) If f(x) has a derivative at the point x<SUB>0 </SUB>then f(x) is said to be ( )at x<SUB>0. <p></SUB></FONT><p><P 0cm 0pt?><FONT face="Times New Roman">(iii) </FONT>∫<FONT face="Times New Roman">f(x)dx is called the indefinite( ) of f(x).</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"><p></FONT><p><P 0cm 0pt?><FONT face="Times New Roman">II Translate the following two examples into Chinese(pay attention to the phrases used):</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> Example 1 Find the derivative of </FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> f(x)=(3x+1)<SUP>4</SUP>/(x<SUP>2</SUP>+2)<SUP>3</SUP></FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> solution:Taking the logarithms of both sides,we have</FONT></P><P 0cm 0pt; TEXT-INDENT: 27pt?><FONT face="Times New Roman">ln f(x)=4ln(3x+1)-3ln(x<SUP>2</SUP>+2)</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> Differentiating both sides of the above equation,we obtain</FONT></P><P 0cm 0pt; TEXT-INDENT: 26.25pt?><FONT face="Times New Roman">f’(x)/f(x)=12/(3x+1)-6/(x<SUP>2</SUP>+2)</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -18pt; 44.25pt; l25 lfo16?><FONT face="Times New Roman">(1) and (2)together yield </FONT></P><P 0cm 0pt 26.25pt?><FONT face="Times New Roman">f’(x)=[(3x+1)<SUP>4</SUP>/(x2+2)<SUP>3</SUP>]</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> Example 2 Integrate </FONT>∫<FONT face="Times New Roman"> x<SUP>2</SUP> cosxdx</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> Solution:Let u=x<SUP>2</SUP>,v=sin x;</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> Then du=2xdx,dv=cos x dx</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> So we have I=</FONT>∫<FONT face="Times New Roman">x<SUP>2</SUP> cos x dx =</FONT>∫<FONT face="Times New Roman">u dv</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> By applying integration by parts,we have</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> I=</FONT>∫<FONT face="Times New Roman">udv=uv-</FONT>∫<FONT face="Times New Roman">vdu=x<SUP>2</SUP> sinx-2</FONT>∫<FONT face="Times New Roman">x sinx dx (1)</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> Applying integration by parts once again to the indefinite integral</FONT>∫<FONT face="Times New Roman">xsinxdx,we get</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> </FONT>∫<FONT face="Times New Roman">x sinx dx = -x cos x +sin x +c (2)</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> Substituting (2)into (1)yields</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> </FONT>∫<FONT face="Times New Roman"> x<SUP>2</SUP> cos x dx=x<SUP>2</SUP> sin x+2x cos x-2 sin x +c </FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> where c is an arbitrary constant.</FONT></P><P 0cm 0pt?><FONT face="Times New Roman">III. Translate the following example into English:</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> </FONT>求<FONT face="Times New Roman">y=ln(2x<SUP>2</SUP>-4)</FONT>的导数</P><P 0cm 0pt?><FONT face="Times New Roman"> </FONT>【解】令<FONT face="Times New Roman">y=ln u,u=(2x2-4),</FONT>则<FONT face="Times New Roman">dy/du=1/u. du/dx=4x (1)</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> </FONT>据复合函数求导数的公式,我们有</P><P 0cm 0pt?><FONT face="Times New Roman"> dy/du=dy/du-du/dx (2)</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> </FONT>把(<FONT face="Times New Roman">1</FONT>)代入(<FONT face="Times New Roman">2</FONT>)式得<FONT face="Times New Roman">dy/dx=(1/u)4x</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> </FONT>把<FONT face="Times New Roman">u</FONT>换为<FONT face="Times New Roman">2x<SUP>2</SUP>-4,</FONT>最后得<FONT face="Times New Roman">dy/dx=4x/(2x<SUP>2</SUP>-4) </FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -36pt; 36pt; 36.0pt; lfo17? l0><FONT face="Times New Roman">IV. Theorem Let f be defined on an open interval I,and assume that f has a relative maximum or a relative minimum at an interior point c of I.If the derivative f’(c )exists,then f’(c )=0</FONT></P><P 0cm 0pt 36pt?><FONT face="Times New Roman">The proof of this theorem is given in Chinese as follows.Turn it into English:</FONT></P><P 0cm 0pt 36pt?>证明:</P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -36pt; 63pt; 63.0pt; l49 lfo18?>(1) 在<FONT face="Times New Roman">I</FONT>上定义函数<FONT face="Times New Roman">Q</FONT>(<FONT face="Times New Roman">x</FONT>)</P><P 0cm 0pt 63pt?><FONT face="Times New Roman">Q(x)=/(x-c) x</FONT>≠<FONT face="Times New Roman">c</FONT></P><P 0cm 0pt TEXT-INDENT: 26.25pt? 63pt;><FONT face="Times New Roman">f’(c ) x=c</FONT></P><P 0cm 0pt TEXT-INDENT: 10.5pt? mso-char-indent-count: mso-char-indent-size: 63pt; -63pt; -6.0;><FONT face="Times New Roman"> (2) </FONT>因为<FONT face="Times New Roman">f’(c)</FONT>存在,故当<FONT face="Times New Roman">x</FONT>趋向<FONT face="Times New Roman">c</FONT>时,<FONT face="Times New Roman">Q</FONT>(<FONT face="Times New Roman">x</FONT>)趋向<FONT face="Times New Roman">Q</FONT>(<FONT face="Times New Roman">c</FONT>),也即<FONT face="Times New Roman">Q</FONT>(<FONT face="Times New Roman">x</FONT>)在点<FONT face="Times New Roman">x</FONT>=<FONT face="Times New Roman">c</FONT>连续<FONT face="Times New Roman"> </FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -36pt; 63pt; 63.0pt; l49 lfo18?>(2) 我们将证明:若<FONT face="Times New Roman">f’</FONT>(<FONT face="Times New Roman">c</FONT>)=<FONT face="Times New Roman">Q</FONT>(<FONT face="Times New Roman">c</FONT>)≠<FONT face="Times New Roman">0</FONT>,则导致矛盾;</P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -36pt; 63pt; 63.0pt; l49 lfo18?>(3) 设<FONT face="Times New Roman">Q</FONT>(<FONT face="Times New Roman">c</FONT>)<FONT face="Times New Roman">>0</FONT>,根据连续函数的保号性质,存在<FONT face="Times New Roman">c</FONT>点的一个领域,在此领域里,<FONT face="Times New Roman">Q</FONT>(<FONT face="Times New Roman">x</FONT>)是正的;</P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -36pt; 63pt; 63.0pt; l49 lfo18?>(4) 因此在此领域内,对所有<FONT face="Times New Roman">x</FONT>≠<FONT face="Times New Roman">c</FONT>,<FONT face="Times New Roman">Q</FONT>(<FONT face="Times New Roman">x</FONT>)的分子和分母同号;</P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -36pt; 63pt; 63.0pt; l49 lfo18?>(5) 即是说,当<FONT face="Times New Roman">x>c</FONT>时,<FONT face="Times New Roman">f</FONT>(<FONT face="Times New Roman">x</FONT>)<FONT face="Times New Roman">>f(c ),</FONT>而当<FONT face="Times New Roman">x<c</FONT>时,<FONT face="Times New Roman">f</FONT>(<FONT face="Times New Roman">x</FONT>)<FONT face="Times New Roman"><f</FONT>(<FONT face="Times New Roman">c</FONT>)这与<FONT face="Times New Roman">f</FONT>在<FONT face="Times New Roman">x</FONT>=<FONT face="Times New Roman">c</FONT>处有一极值相矛盾;</P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list -36pt; 63pt; 63.0pt; l49 lfo18?>(6) 因此<FONT face="Times New Roman">Q</FONT>(<FONT face="Times New Roman">c</FONT>)<FONT face="Times New Roman">>0</FONT>不可能,同理可证<FONT face="Times New Roman">Q</FONT>(<FONT face="Times New Roman">c</FONT>)<FONT face="Times New Roman"><0</FONT>也不真。</P><P 0cm 0pt?><FONT face="Times New Roman"><p></FONT><p><P 0cm 0pt?><FONT face="Times New Roman"><p></FONT><p><P 0cm 0pt?><FONT face="Times New Roman"><p></FONT><p>
数学专业英语[5]-First Order Differential Equations
<P><FONT face="Times New Roman" size=3>A differential equation is an equation between specified derivatives of a function, its</FONT></P><P><FONT face="Times New Roman" size=3>valves,and known quantities.Many laws of physics are most simply and naturally formu-</FONT></P>
<P><FONT face="Times New Roman" size=3>lated as differential equations (or DE’s, as we shall write for short).For this reason,DE’s </FONT></P>
<P><FONT face="Times New Roman" size=3>have been studies by the greatest mathematicians and mathematical physicists since the </FONT></P>
<P><FONT face="Times New Roman" size=3>time of Newton..</FONT></P>
<P><FONT face="Times New Roman" size=3>Ordinary differential equations are DE’s whose unknowns are functions of a single va-</FONT></P>
<P><FONT face="Times New Roman" size=3>riable;they arise most commonly in the study of dynamic systems and electric networks.</FONT></P>
<P><FONT face="Times New Roman" size=3>They are much easier to treat than partial differential equations,whose unknown functions</FONT></P>
<P><FONT face="Times New Roman" size=3>depend on two or more independent variables.</FONT></P>
<P><FONT face="Times New Roman" size=3>Ordinary DE’s are classified according to their order. The order of a DE is defined as </FONT></P>
<P><FONT face="Times New Roman" size=3>the largest positive integer, n, for which an n-th derivative occurs in the equation. This</FONT></P>
<P><FONT face="Times New Roman" size=3>chapter will be restricted to real first order DE’s of the form</FONT></P>
<P><FONT size=3><FONT face="Times New Roman"> </FONT>Φ<FONT face="Times New Roman">(x, y, y</FONT>′<FONT face="Times New Roman">)=0 (1)</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">Given the function </FONT>Φ<FONT face="Times New Roman">of three real variables, the problem is to determine all real functions y=f(x) which satisfy the DE, that is ,all solutions of(1)in the following sense.</FONT></FONT></P>
<P><FONT face="Times New Roman"><FONT size=3><B>DEFINITION </B> A solution of (1)is a differentiable function f(x) such that </FONT></FONT></P>
<P><FONT size=3>Φ<FONT face="Times New Roman">(x. f(x),f</FONT>′<FONT face="Times New Roman">(x))=0 for all x in the interval where f(x) is defined.</FONT></FONT></P>
<P><FONT face="Times New Roman"><FONT size=3><B>EXAMPLE 1.</B> In the first-other DE</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman"> x+yy</FONT>′<FONT face="Times New Roman">=0 (2)</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">the function </FONT>Φ<FONT face="Times New Roman"> is a polynomial function </FONT>Φ<FONT face="Times New Roman">(x, y, z)=x+ yz of three variables in-</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>volved. The solutions of (2) can be found by considering the identity</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">d(x</FONT>²<FONT face="Times New Roman">+y</FONT>²<FONT face="Times New Roman">)/d x=2(x+yy</FONT>ˊ<FONT face="Times New Roman">).From this identity,one sees that x</FONT>²<FONT face="Times New Roman">+y</FONT>²<FONT face="Times New Roman"> is a con-</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>stant if y=f(x) is any solution of (2).</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">The equation x</FONT>²<FONT face="Times New Roman">+y</FONT>²<FONT face="Times New Roman">=c defines y implicitly as a two-valued function of x,</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>for any positive constant c.Solving for y,we get two solutions,the(single-valued)</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">functions y=</FONT>±<FONT face="Times New Roman">(c-x</FONT>²<FONT face="Times New Roman">)<SUP>0.5</SUP> ,for each positive constant c.The graphs of these so-</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>lutions,the so-called solution curves,form two families of scmicircles,which fill the upper half-plane y>0 and the lower half-plane y>0,respectively.</FONT></P>
<P><FONT face="Times New Roman" size=3>On the x-axis,where y=0,the DE(2) implies that x=0.Hence the DE has no solutions</FONT></P>
<P><FONT face="Times New Roman" size=3>which cross the x-axis,except possibly at the origin.This fact is easily overlooked,</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">because the solution curves appear to cross the x-axis;hence y</FONT>ˊ<FONT face="Times New Roman">does not exist,and the DE (2) is not satisfied there.</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">The preceding difficulty also arises if one tries to solve the DE(2)for y</FONT>ˊ<FONT face="Times New Roman">. Dividing through by y,one gets y</FONT>ˊ<FONT face="Times New Roman">=-x/y,an equation which cannot be satisfied if y=0.The preceding difficulty is thus avoided if one restricts attention to regions where the DE(1) is normal,in the following sense.</FONT></FONT></P>
<P><FONT face="Times New Roman"><FONT size=3><B> DEFINITION. </B>A normal first-order DE is one of the form</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman"> y</FONT>ˊ<FONT face="Times New Roman">=F(x,y) (3)</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">In the normal form y</FONT>ˊ<FONT face="Times New Roman">=-x/y of the DE (2),the function F(x,y) is continuous in the upper half-plane y>0 and in the lower half-plane where y<0;it is undefined on the x-axis.</FONT></FONT></P>
<P><FONT face="Times New Roman"><FONT size=3>
</FONT></FONT>
<p>
<P><B><FONT face="Times New Roman"><FONT size=3>Fundamental Theorem of the Calculus.
<p></FONT></FONT></B>
<p>
<P><FONT face="Times New Roman"><FONT size=3>
<p></FONT></FONT>
<p>
<P><FONT face="Times New Roman"><FONT size=3>The most familiar class of differential equations consists of the first-order DE’s of the form </FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman"> y</FONT>ˊ<FONT face="Times New Roman">=g(x) (4)</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>Such DE’s are normal and their solutions are descried by the fundamental thorem of the calculus,which reads as follows.</FONT></P>
<P><FONT face="Times New Roman"><FONT size=3><B>FUNDAMENTAL THEOREM OF THE CALCULUS</B>. Let the function g(x)in DE(4) be continuous in the interval a<x<b.Given a number c,there is one and only one solution f(x) of the DE(4) in the interval such that f(a)=c. This solution is given by the definite integral</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">f(x)=c+</FONT>∫<FONT face="Times New Roman"><SUB>a</SUB><SUP>x</SUP>g(t)dt , c=f(a) (5)</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>This basic result serves as a model of rigorous formulation in several respects. First,it specifies the region under consideration,as a vertical strip a<x<b in the xy-plane.Second,it describes in precise terms the class of functions g(x) considered.And third, it asserts the existence and uniqueness of a solution,given the “initial condition”f(a)=c.</FONT></P>
<P><FONT face="Times New Roman" size=3>We recall that the definite integral </FONT></P>
<P><FONT size=3>∫<FONT face="Times New Roman"><SUB>a</SUB><SUP>x</SUP>g(t)dt=lim(max</FONT>Δ<FONT face="Times New Roman">t<SUB>k</SUB>->0)</FONT>Σ<FONT face="Times New Roman">g(t<SUB>k</SUB>)</FONT>Δ<FONT face="Times New Roman">t<SUB>k </SUB>, </FONT>Δ<FONT face="Times New Roman">t<SUB>k</SUB>=t<SUB>k</SUB>-t<SUB>k-1 </SUB> (5</FONT>ˊ<FONT face="Times New Roman">)</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">is defined for each fixed x as a limit of Ricmann sums; it is not necessary to find a formal expression for the indefinite integral </FONT>∫<FONT face="Times New Roman"> g(x) dx to give meaning to the definite integral </FONT>∫<FONT face="Times New Roman"><SUB>a</SUB><SUP>x</SUP>g(t)dt,provided only that g(t) is continuous.Such functions as the error function crf x =(2/(</FONT>π<FONT face="Times New Roman">)<SUP>0.5</SUP>)</FONT>∫<FONT face="Times New Roman"><SUB>0</SUB><SUP>x</SUP>e<SUP>-t</SUP></FONT><SUP>²<FONT face="Times New Roman"> </FONT></SUP><FONT face="Times New Roman">dt and the sine integral function SI(x)=</FONT>∫<SUB><FONT face="Times New Roman">x</FONT></SUB><SUP>∞</SUP><FONT face="Times New Roman">[(sin t )/t]dt are indeed commonly defined as definite integrals.</FONT></FONT></P>
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<P align=center><B><FONT face="Times New Roman">Solutions and Integrals
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<P><FONT size=3><FONT face="Times New Roman">According to the definition given above a solution of a DE is always a function. For example, the solutions of the DE x+yy</FONT>ˊ<FONT face="Times New Roman">=0 in Example I are the functions y=</FONT>±<FONT face="Times New Roman"> (c-x</FONT>²<FONT face="Times New Roman">)<SUP>0.5</SUP>,whose graphs are semicircles of arbitrary diameter,centered at the origin.The graph of the solution curves are ,however,more easily described by the equation x</FONT>²<FONT face="Times New Roman">+y</FONT>²<FONT face="Times New Roman">=c,describing a family of circles centered at the origin.In what sense can such a family of curves be considered as a solution of the DE ?To answer this question,we require a new notion.</FONT></FONT></P>
<P><FONT face="Times New Roman"><FONT size=3><B>DEFINITION.</B> An integral of DE(1)is a function of two variables,u(x,y),which assumes a constant value whenever the variable y is replaced by a solution y=f(x) of the DE.</FONT></FONT></P>
<P><FONT size=3><FONT face="Times New Roman">In the above example, the function u(x,y)=x</FONT>²<FONT face="Times New Roman">+y</FONT>²<FONT face="Times New Roman"> is an integral of the DE x+yy</FONT>ˊ<FONT face="Times New Roman"> =0,because,upon replacing the variable y by any function </FONT>±<FONT face="Times New Roman">( c-x</FONT>²<FONT face="Times New Roman">)<SUP>0.5</SUP>,we obtain u(x,y)=c.</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>The second-order DE</FONT></P>
<P><FONT size=3><FONT face="Times New Roman"> d</FONT>²<FONT face="Times New Roman">x/dt</FONT>²<FONT face="Times New Roman">=-x (2</FONT>ˊ<FONT face="Times New Roman">)</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>becomes a first-order DE equivalent to (2) after setting dx/dx=y:</FONT></P>
<P><FONT face="Times New Roman" size=3>y ( dy/dx )=-x (2)</FONT></P>
<P><FONT size=3><FONT face="Times New Roman">As we have seen, the curves u(x,y)=x</FONT>²<FONT face="Times New Roman">+y</FONT>²<FONT face="Times New Roman">=c are integrals of this DE.When the DE (2</FONT>ˊ<FONT face="Times New Roman">)</FONT></FONT></P>
<P><FONT face="Times New Roman" size=3>is interpreted as equation of motion under Newton’s second law,the integrals </FONT></P>
<P><FONT size=3><FONT face="Times New Roman">c=x</FONT>²<FONT face="Times New Roman">+y</FONT>²<FONT face="Times New Roman"> represent curves of constant energy c.This illustrates an important principle:an integral of a DE representing some kind of motion is a quantity that remains unchanged through the motion.</FONT></FONT></P>
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<p> <P align=center 0cm 0pt; TEXT-ALIGN: center?><B><FONT face="Times New Roman">Vocabulary
</FONT></B><p><P 0cm 0pt?><FONT face="Times New Roman"><p></FONT><p><P 0cm 0pt?><FONT face="Times New Roman">differential equation </FONT>微分方程<FONT face="Times New Roman"> error function </FONT>误差函数<FONT face="Times New Roman"> </FONT></P><P 0cm 0pt?><FONT face="Times New Roman">ordinary differential equation </FONT>常微分方程<FONT face="Times New Roman"> sine integral function </FONT>正弦积分函数</P><P 0cm 0pt?><FONT face="Times New Roman">order </FONT>阶<FONT face="Times New Roman">,</FONT>序<FONT face="Times New Roman"> diameter </FONT>直径</P><P 0cm 0pt?><FONT face="Times New Roman">derivative </FONT>导数<FONT face="Times New Roman"> curve </FONT>曲线</P><P 0cm 0pt?><FONT face="Times New Roman">known quantities </FONT>已知量<FONT face="Times New Roman"> replace </FONT>替代</P><P 0cm 0pt?><FONT face="Times New Roman">unknown </FONT>未知量<FONT face="Times New Roman"> substitute </FONT>代入</P><P 0cm 0pt?><FONT face="Times New Roman">single variable </FONT>单变量<FONT face="Times New Roman"> strip </FONT>带形</P><P 0cm 0pt?><FONT face="Times New Roman">dynamic system </FONT>动力系统<FONT face="Times New Roman"> exact differential </FONT>恰当微分</P><P 0cm 0pt?><FONT face="Times New Roman">electric network </FONT>电子网络<FONT face="Times New Roman"> line integral </FONT>线积分</P><P 0cm 0pt?><FONT face="Times New Roman">partial differential equation </FONT>偏微分方程<FONT face="Times New Roman"> path of integral </FONT>积分路径</P><P 0cm 0pt?><FONT face="Times New Roman">classify </FONT>分类<FONT face="Times New Roman"> endpoints </FONT>端点</P><P 0cm 0pt?><FONT face="Times New Roman">polynomial </FONT>多项式<FONT face="Times New Roman"> general solution </FONT>通解</P><P 0cm 0pt?><FONT face="Times New Roman">several variables </FONT>多变量<FONT face="Times New Roman"> parameter </FONT>参数</P><P 0cm 0pt?><FONT face="Times New Roman">family </FONT>族<FONT face="Times New Roman"> rigorous </FONT>严格的</P><P 0cm 0pt?><FONT face="Times New Roman">semicircle </FONT>半圆<FONT face="Times New Roman"> existence </FONT>存在性</P><P 0cm 0pt?><FONT face="Times New Roman">half-plane </FONT>半平面<FONT face="Times New Roman"> initial condition </FONT>初始条件</P><P 0cm 0pt?><FONT face="Times New Roman">region </FONT>区域<FONT face="Times New Roman"> uniqueness </FONT>唯一性</P><P 0cm 0pt?><FONT face="Times New Roman">normal </FONT>正规<FONT face="Times New Roman">,</FONT>正常<FONT face="Times New Roman"> Riemann sum </FONT>犁曼加</P><P 0cm 0pt?><FONT face="Times New Roman">identity </FONT>恒等<FONT face="Times New Roman">(</FONT>式<FONT face="Times New Roman">)</FONT></P> <P align=center 0cm 0pt; TEXT-ALIGN: center?><FONT face="Times New Roman"><B>Notes</B><B>
</B></FONT><p><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list 18.0pt; 18pt; -18pt; l29 lfo19?><FONT face="Times New Roman">1. The order of a DE is defined as the largest positive integral n,for which an nth derivative occurs in the question.</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> </FONT>这是另一种定义句型<FONT face="Times New Roman">,</FONT>请参看附录<FONT face="Times New Roman">IV.</FONT>此外要注意<FONT face="Times New Roman">nth derivative </FONT>之前用<FONT face="Times New Roman">an </FONT>不用<FONT face="Times New Roman">a .</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list 18.0pt; 18pt; -18pt; l29 lfo19?><FONT face="Times New Roman">2. This chapter will be restricted to real first order differential equations of the form </FONT></P><P 0cm 0pt; TEXT-INDENT: 32.25pt?>Φ<FONT face="Times New Roman">(x,y,y</FONT>ˊ<FONT face="Times New Roman">)=0</FONT></P><P 0cm 0pt; TEXT-INDENT: 32.25pt?>意思是<FONT face="Times New Roman">;</FONT>文章限于讨论形如<FONT face="Times New Roman"> </FONT>Φ<FONT face="Times New Roman">(x,y,y</FONT>ˊ<FONT face="Times New Roman">)=0</FONT>的实一阶微分方程<FONT face="Times New Roman">.</FONT></P><P 0cm 0pt; TEXT-INDENT: 32.25pt?>有时可以用<FONT face="Times New Roman">of the type</FONT>代替<FONT face="Times New Roman"> of the form </FONT>的用法<FONT face="Times New Roman">.</FONT></P><P 0cm 0pt; TEXT-INDENT: 32.25pt?><FONT face="Times New Roman"> The equation can be rewritten in the form y</FONT>ˊ<FONT face="Times New Roman">=F(x,y).</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list 18.0pt; 18pt; -18pt; l29 lfo19?><FONT face="Times New Roman">3. Dividing through by y,one gets y</FONT>ˊ<FONT face="Times New Roman">=-x/y,</FONT>…</P><P 0cm 0pt?><FONT face="Times New Roman"> </FONT>划线短语意思是<FONT face="Times New Roman">:</FONT>全式除以<FONT face="Times New Roman">y</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list 18.0pt; 18pt; -18pt; l29 lfo19?><FONT face="Times New Roman">4. As we have seen, the curves u(x,y)=x</FONT>²<FONT face="Times New Roman">+y</FONT>²<FONT face="Times New Roman">=c are integrals of this DE</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> </FONT>这里<FONT face="Times New Roman">x</FONT>²<FONT face="Times New Roman">+y</FONT>²<FONT face="Times New Roman">=c </FONT>因<FONT face="Times New Roman">c</FONT>是参数<FONT face="Times New Roman">,</FONT>故此方程代表一族曲线<FONT face="Times New Roman">,</FONT>由此<FONT face="Times New Roman">”</FONT>曲线<FONT face="Times New Roman">”</FONT>这一词要用复数<FONT face="Times New Roman">curves.</FONT></P><P 0cm 0pt tab-stops: TEXT-INDENT: mso-list: level1 list 18.0pt; 18pt; -18pt; l29 lfo19?><FONT face="Times New Roman">5. Their solutions are described by the fundamental theorem of the calculus,which reads as follows.</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> </FONT>意思是<FONT face="Times New Roman">:</FONT>它们的解由微积分基本定理所描述<FONT face="Times New Roman">,(</FONT>基本定理<FONT face="Times New Roman">)</FONT>可写出如下<FONT face="Times New Roman">.</FONT></P><P 0cm 0pt?><FONT face="Times New Roman"> </FONT>句中<FONT face="Times New Roman">reads as follows </FONT>就是<FONT face="Times New Roman">”</FONT>写成<FONT face="Times New Roman">(</FONT>读成<FONT face="Times New Roman">)</FONT>下面的样子<FONT face="Times New Roman">”</FONT>的意思<FONT face="Times New Roman">.</FONT>注意<FONT face="Times New Roman">follows</FONT>一词中的<FONT face="Times New Roman">”s”</FONT>不能省略<FONT face="Times New Roman">.</FONT></P>