QQ登录

只需要一步,快速开始

 注册地址  找回密码
查看: 2220|回复: 9
打印 上一主题 下一主题

虚二次域例两(-5/50)

[复制链接]
字体大小: 正常 放大
lilianjie        

43

主题

4

听众

204

积分

升级  52%

  • TA的每日心情
    开心
    2012-1-13 11:05
  • 签到天数: 15 天

    [LV.4]偶尔看看III

    跳转到指定楼层
    1#
    发表于 2012-1-4 17:41 |只看该作者 |倒序浏览
    |招呼Ta 关注Ta
    本帖最后由 lilianjie 于 2012-1-4 17:54 编辑
    5 G$ F6 W# M, e* F8 N* e4 e& I6 B: v7 q  I/ o2 z
    Q5:=QuadraticField(-5) ;
    . `- Q& L, x% }2 aQ5;
    ! f% o! M! f+ D; ^- J8 d' ]9 p
    0 k4 {) f* W% N* g' BQ<w> :=PolynomialRing(Q5);Q;
    : s. S& Q/ z! r' t" A0 ]EquationOrder(Q5);0 r. |2 \& q7 f* R3 B
    M:=MaximalOrder(Q5) ;
    ( I  g; }" H- v6 _( SM;% b6 i. F5 e; }- F2 c  C  x1 E
    NumberField(M);
    6 A. H+ ]; m4 D! F4 O, u6 sS1:=sub< M | 1 >;S2:=sub< M | 2 >;S3:=sub< M | 3 >;S4:=sub< M | 4 >;S5:=sub< M | 5 >;S25:=sub< M | 25 >;S625888888:=sub< M | 625888888 >;S625888888;
    + |+ {* t$ B# MIsQuadratic(Q5);0 R; `) C3 _2 i/ t* o7 g
    IsQuadratic(S1);
    3 {/ [. q- V! D. z, i. vIsQuadratic(S4);: g) G  h2 j) L- c0 n
    IsQuadratic(S25);! |6 m1 x, l' x: L9 n, a' j: B' a7 a) M
    IsQuadratic(S625888888);
    : c- b4 b2 }2 [5 T" Y. ^- Q, RFactorization(w^2+5);  
    3 |) `, ~1 m  DDiscriminant(Q5) ;- g$ U) N. w: c2 Y3 S
    FundamentalUnit(Q5) ;
    : g  ^; d: Z  K) Z& aFundamentalUnit(M);
    * R' ~6 P5 g, S6 u  S9 d# j+ aConductor(Q5) ;
    8 p  z8 v7 \2 v; ~0 h8 q, Y8 _. Z4 B: ?3 k1 s& J4 c) g3 Z  D
    Name(M, -5);
    1 g6 Y8 r) `3 i. g" V, I9 EConductor(M);( a, i! o& T2 {2 B4 U. L( G! m
    ClassGroup(Q5) ; ; C3 @' M% D3 l- H- ?) u
    ClassGroup(M);
    . k. i) _$ }+ N# FClassNumber(Q5) ;. p' V2 [* B" [, I2 H
    ClassNumber(M) ;/ k! i" `5 P! F! P
    PicardGroup(M) ;
    ( s. Y6 c, ], W) gPicardNumber(M) ;, Z) B9 ?0 S% t" ]# J5 E, m, b& R( V

    ! `: Y+ D/ \' K- R# i; c! N- g" iQuadraticClassGroupTwoPart(Q5);
    . z) ?' D, D" I" n" p: jQuadraticClassGroupTwoPart(M);
    ' u0 w4 z. Z, W( @# FNormEquation(Q5, -5) ;4 s+ p9 u0 d5 Q2 m: _
    NormEquation(M, -5) ;
    1 q  b' h6 O: E$ h7 {Quadratic Field with defining polynomial $.1^2 + 5 over the Rational Field+ q7 P0 H$ Z( p4 Y8 r& X
    Univariate Polynomial Ring in w over Q5
    ; m, e$ o) H; R: }: q3 S( v& IEquation Order of conductor 1 in Q5; m# Q1 S0 Z8 [! N
    Maximal Equation Order of Q5) v% `; U- A& b
    Quadratic Field with defining polynomial $.1^2 + 5 over the Rational Field7 L  x, J2 i! L$ E
    Order of conductor 625888888 in Q5
    $ T/ B0 Z2 J' X2 M2 Ktrue Quadratic Field with defining polynomial $.1^2 + 5 over the Rational Field3 M' ]( F* `9 J4 g5 m! Z8 r( |6 Z
    true Maximal Equation Order of Q55 I( {( o. [3 c$ x1 u- [8 _$ n
    true Order of conductor 1 in Q50 y. ?# f  t- D! f' n
    true Order of conductor 1 in Q5
    , `7 w0 d0 k/ n5 p9 vtrue Order of conductor 1 in Q5
    ) q' W) v( p) G% Z[: Y8 E9 {0 }. h; F0 y7 @3 f
        <w - Q5.1, 1>,  |, `* M) u) N, ]' O8 _, ]
        <w + Q5.1, 1>! k+ l/ i0 I. ~
    ]
    " M; G5 E. P- T-20
    $ J' M  l  L5 A
    0 H6 o' n; P7 @' [8 ?5 d' [>> FundamentalUnit(Q5) ;
    ( ^: I$ V* R: r. m/ P/ o) H                  ^
    : V+ j  z0 z. d3 [1 QRuntime error in 'FundamentalUnit': Field must have positive discriminant
    3 ?2 K; z' G7 q8 n
      K. \8 A3 {; x  s: K2 O9 @/ i! G+ G0 H3 ~  e; y; s+ J" `0 g
    >> FundamentalUnit(M);6 p$ B3 T& b2 u5 a
                      ^
    ! Y: Y1 P7 W$ hRuntime error in 'FundamentalUnit': Field must have positive discriminant
    $ ?3 N: J. E- x; y  D! _# {* V2 s5 u) d9 u- F( i7 r8 Z( L
    20* r  G( c' w2 o% P* F1 J( H; s

    7 [/ `3 f& m  z5 P>> Name(M, -5);) I% Q& D; Z! E/ D/ [+ Y
           ^
    , s) Z3 ~- m  [/ b$ T1 U& ERuntime error in 'Name': Argument 2 (-5) should be in the range [1 .. 1]' H1 Z8 J& Q7 f+ i* x
    4 g2 r% N1 y  Y; f
    18 J* \2 K  o1 m3 o
    Abelian Group isomorphic to Z/2; ^; w2 c% @. y& d
    Defined on 1 generator
    0 x8 H4 l- I+ W) m- QRelations:
    ) p; S% J. j, F* B; ?9 `" M- {    2*$.1 = 09 c+ [1 Y/ u# |7 P
    Mapping from: Abelian Group isomorphic to Z/28 \, k" i' y% ]# L; N* X6 b
    Defined on 1 generator
    ( S5 ^4 [5 g6 W4 O8 v. Q( WRelations:$ {) U* Q1 y0 f# d" N
        2*$.1 = 0 to Set of ideals of M
    % [0 H  z1 s: g- |) y  EAbelian Group isomorphic to Z/26 @$ c+ S- g/ t" U- q) q
    Defined on 1 generator% Z/ c6 S9 Z" B, u* P. b& r7 U
    Relations:
    + R( s; B9 k. H& |    2*$.1 = 0
    * A: F2 C% b& O& @3 U) b0 ], q- KMapping from: Abelian Group isomorphic to Z/2! [: f* L# v2 I  t; S
    Defined on 1 generator
    2 Y& j8 \3 M# e$ @: Z# c! hRelations:9 U: G' g- }5 y' d
        2*$.1 = 0 to Set of ideals of M# m' d- c5 ~& t% ^( A% s
    24 w+ ~& X# f$ a& b$ U
    2( ^1 h- G- E0 o7 G
    Abelian Group isomorphic to Z/2. J2 t* M7 n' ?$ S
    Defined on 1 generator
    6 ]6 P+ y* G9 K3 }Relations:. s9 H1 k! B. i+ ?
        2*$.1 = 09 e5 {0 v0 k  p; j2 |% p3 g
    Mapping from: Abelian Group isomorphic to Z/2# k: C+ H7 T' k% N- M) T
    Defined on 1 generator- @. S( i* C9 O" S6 u* Y
    Relations:
    * k6 T6 W+ o+ t    2*$.1 = 0 to Set of ideals of M given by a rule [no inverse]% S* C, ^& i8 }& @
    21 D# l+ t. P  ^: o4 F( k: w! m, K+ S
    Abelian Group isomorphic to Z/2  c8 @1 j0 h6 A2 B
    Defined on 1 generator
    9 c$ k8 ?+ k; U; b1 nRelations:  ^9 s& C4 P" T( D
        2*$.1 = 00 n; j8 o) ^5 K0 }
    Mapping from: Abelian Group isomorphic to Z/26 |  h) z4 e$ w8 R! W# ^2 G
    Defined on 1 generator
    & E  e. Z% W' C4 a/ f. V: GRelations:& r0 G9 Z$ [5 p4 @1 U2 t; t
        2*$.1 = 0 to Binary quadratic forms of discriminant -20 given by a rule [no 5 f! T/ C) G4 v6 v# @- s
    inverse]
    2 g, X, C* y  C6 Z7 OAbelian Group isomorphic to Z/2
    6 K- E1 h7 y+ L$ ODefined on 1 generator
    7 D4 ~: M, t* B5 I/ R& oRelations:$ r5 Z& b4 G, O7 g5 W
        2*$.1 = 0- d5 z, {) n3 W) q
    Mapping from: Abelian Group isomorphic to Z/2/ i+ R- U, r5 I/ j% B, {
    Defined on 1 generator( f2 [' r. y8 X
    Relations:
    , \  s1 R) Q2 D: J    2*$.1 = 0 to Binary quadratic forms of discriminant -20 given by a rule [no
    6 h* n1 ~; v( Winverse]
    " h# S) p# a4 A; B8 ?% cfalse
    6 m* O* p' @' B) u" f" N# ifalse7 f- Q9 Q) e2 @# |
    ==============
    3 `, D5 v& _. f7 q  V
    ; y) ?7 Q- ~! _2 B% h! E! W. }7 O: d) q" U4 ?$ G
    Q5:=QuadraticField(-50) ;
    ( _) g# v: v5 I7 _2 ?Q5;& `) X2 i$ b+ t- a
    : F" B, Y, j! D3 V
    Q<w> :=PolynomialRing(Q5);Q;9 T* \2 M/ M% M- p0 t3 `
    EquationOrder(Q5);
    % G" x: @; F! _1 f8 \; xM:=MaximalOrder(Q5) ;* q8 D3 `  Q( a
    M;5 z9 P4 ]# V/ {) y) p! j
    NumberField(M);
    . w0 L/ `7 d9 L3 e4 Y; \S1:=sub< M | 1 >;S2:=sub< M | 2 >;S3:=sub< M | 3 >;S4:=sub< M | 4 >;S5:=sub< M | 5 >;S25:=sub< M | 25 >;S625888888:=sub< M | 625888888 >;S625888888;2 U, p* V( \8 Y1 i7 G2 V/ q  ]
    IsQuadratic(Q5);
    / K! {! w+ D0 f) e* B2 Q1 l" q( YIsQuadratic(S1);
    " [& I5 x; a& j$ }- dIsQuadratic(S4);
    , U3 \2 I* D( |: t: A/ @1 ^IsQuadratic(S25);! F7 Q. k' E) \3 l% G* c* \: x
    IsQuadratic(S625888888);
    3 O- L* F7 ^' R5 I$ KFactorization(w^2+50);  . \; p, M1 H" Z& }* Z5 l
    Discriminant(Q5) ;  Q) s0 Z9 v0 n3 B
    FundamentalUnit(Q5) ;7 E. G* r0 N) E  N/ U6 }& l
    FundamentalUnit(M);
    9 o- L8 X( O8 k( ~' z- n3 k2 r' ~$ e3 LConductor(Q5) ;8 l0 P0 W' g: G4 S8 f: E, f* ~% h2 |

    3 T' s* o  ~) O5 |( j- MName(M, -50);1 Q- r) F9 J- J# k
    Conductor(M);* {: m5 r: z8 t; |
    ClassGroup(Q5) ; & x5 }/ p9 d& a9 b$ L
    ClassGroup(M);: B9 K2 Q+ l5 ^3 ~
    ClassNumber(Q5) ;7 a( ]7 i5 K0 |
    ClassNumber(M) ;- v3 v! d( t4 I( A# x" V; J
    PicardGroup(M) ;  u! l* W( t# j  L; S
    PicardNumber(M) ;9 g# r. ?* p/ r2 S

    # E  z) n0 n0 h5 MQuadraticClassGroupTwoPart(Q5);
    ; h" v- S& P' h% m, G, y) zQuadraticClassGroupTwoPart(M);! Q4 Q$ ~! d/ t; C. F7 @: }: Y6 z
    NormEquation(Q5, -50) ;8 V. y3 T  K9 Q' J
    NormEquation(M, -50) ;
    / d5 p. `$ C& S$ @# p6 |$ J& _% Y
    Quadratic Field with defining polynomial $.1^2 + 2 over the Rational Field0 V9 a" d5 k" ]/ C
    Univariate Polynomial Ring in w over Q5
    ) o; A0 o, _: H/ BEquation Order of conductor 1 in Q5/ q" Y+ y: N2 J' Z( S
    Maximal Equation Order of Q55 x, @8 E3 g  R
    Quadratic Field with defining polynomial $.1^2 + 2 over the Rational Field4 K# {+ D7 e: b* D+ u# j6 y
    Order of conductor 625888888 in Q5! }; [! @; G( U/ x2 D  H
    true Quadratic Field with defining polynomial $.1^2 + 2 over the Rational Field
    ) u4 r7 v5 A# F+ t* Itrue Maximal Equation Order of Q5
    2 g5 w5 R/ Z% y6 Z7 Y/ `0 }true Order of conductor 1 in Q5
    2 B, f. h. t' i3 d/ B$ O. A# Qtrue Order of conductor 1 in Q5
    9 _- v7 S, F+ ptrue Order of conductor 1 in Q5
    ! k/ [7 Q% V8 G0 {- Z[
    ! A! H  m9 `/ S: N    <w - 5*Q5.1, 1>,
    - |% J; a4 w) @3 D  B    <w + 5*Q5.1, 1>1 J  l3 J0 Z5 n+ \
    ]
    3 s, S7 _+ }# H6 R) ^* D-8
    1 t1 A0 r: A- ~, [% ?! o. s' f8 b' r* S4 a
    >> FundamentalUnit(Q5) ;+ s9 z3 u3 _1 `! x( K& y+ O
                      ^  u1 S: D5 B; W
    Runtime error in 'FundamentalUnit': Field must have positive discriminant
    , r; H( P% p0 u$ j8 O  I+ ^8 k1 r! [
    1 c3 b! @) T: h5 F1 Q+ S$ @
    ( w. ^$ a( ]1 ]% R>> FundamentalUnit(M);2 Z  @* g9 t* F# r4 n  H
                      ^! ]4 i5 W) N3 t4 F5 @* v
    Runtime error in 'FundamentalUnit': Field must have positive discriminant, y  b: j& \5 U, m# E
    : W: M. J% c; C# Z
    8
    6 Q% w( h1 Y  V! J
    + B& u8 m* y* U>> Name(M, -50);: h  f/ C3 v# r" _; G
           ^
    : Y* Z4 Z! S& H2 z; K4 pRuntime error in 'Name': Argument 2 (-50) should be in the range [1 .. 1]" i  T- G% R( y3 }1 ~! J
    5 I+ O/ z% h. f/ t" ]! t
    1: B9 S, H8 r& z2 l0 R8 u
    Abelian Group of order 1& ~6 M* A; K; A% u  b
    Mapping from: Abelian Group of order 1 to Set of ideals of M
    6 V3 s6 O" ]5 i+ M1 eAbelian Group of order 1
    5 B& O6 s* D2 `) u) T' X1 T4 qMapping from: Abelian Group of order 1 to Set of ideals of M
    3 S- _! E) K  j! S% D  R. n/ b1
    . J6 M8 v; T) R) [& f1
    / \# T5 X5 X3 \3 Q5 KAbelian Group of order 1
    9 ?4 S7 d. C6 }" g2 ^, T; EMapping from: Abelian Group of order 1 to Set of ideals of M given by a rule [no3 t4 Z- ^8 H/ B) K& }3 |* ]% L
    inverse]& z: p) |; @9 e
    1
    ! T; g' `1 J" H; {2 s( u8 nAbelian Group of order 1
    + o5 h, y6 z8 j$ V1 ^Mapping from: Abelian Group of order 1 to Binary quadratic forms of discriminant# C7 g) t+ I2 n4 N# ~, ^
    -8 given by a rule [no inverse]
    . }# `4 A, o9 r4 ~8 o. sAbelian Group of order 1
    * r6 t9 h( j) N. [  HMapping from: Abelian Group of order 1 to Binary quadratic forms of discriminant
    ) @+ J& C/ C6 ~" w* W. b: w/ U-8 given by a rule [no inverse]
    : q6 m9 ^: t' G! q) }false# {1 D# t3 s$ c" A7 |4 g5 N/ y: f
    false
    , E! q/ s7 U( ^; }
    zan
    转播转播0 分享淘帖0 分享分享0 收藏收藏0 支持支持0 反对反对0 微信微信
    lilianjie        

    43

    主题

    4

    听众

    204

    积分

    升级  52%

  • TA的每日心情
    开心
    2012-1-13 11:05
  • 签到天数: 15 天

    [LV.4]偶尔看看III

    看看-1.-3的两种:# e0 b' K; w& A6 r
    ' a" C9 u* ]/ ]7 z8 X9 |
    Q5:=QuadraticField(-1) ;: B8 v* ?" v7 R: C$ E- v* S: u
    Q5;
    . s3 {) D% A( {4 o8 a' b7 {! H, ]8 U& x5 x
    Q<w> :=PolynomialRing(Q5);Q;
    ( y- V  ^* n) yEquationOrder(Q5);
    " A+ L8 F5 k1 |  e( X8 m! rM:=MaximalOrder(Q5) ;2 k8 f. m" @. @) I2 i
    M;
      G; g0 Q& m5 w9 D9 r! E3 [+ XNumberField(M);2 l+ L: q. ?) U. ~# W1 y
    S1:=sub< M | 1 >;S2:=sub< M | 2 >;S3:=sub< M | 3 >;S4:=sub< M | 4 >;S5:=sub< M | 5 >;S25:=sub< M | 25 >;S625888888:=sub< M | 625888888 >;S625888888;
    ) u5 Z! ?# A; Y: Q7 H1 R; S% `$ EIsQuadratic(Q5);
    ) |9 v" z# {, i+ W& LIsQuadratic(S1);" L1 v( K  h( H% f
    IsQuadratic(S4);
    $ N/ T1 q/ N0 }" G. r* I" R4 vIsQuadratic(S25);
    ( f0 L2 G* \6 T  V, ~2 z% ZIsQuadratic(S625888888);
    ) y" q8 t( Y+ Q$ ZFactorization(w^2+1);  
    " s# k' q: m, v) HDiscriminant(Q5) ;
    - i. l3 W. Z& U- J  iFundamentalUnit(Q5) ;
    * y" l4 b; ]' p) aFundamentalUnit(M);+ V  D9 I* }+ j8 E7 ]* A  h
    Conductor(Q5) ;1 B+ J9 e6 d# ^* ]7 v2 O

    0 I% K: V: F$ E: |Name(M, -1);: [, H+ g1 I- `5 A- |& O8 N
    Conductor(M);
    1 X6 D* m( t) u8 a" K# ?2 w" OClassGroup(Q5) ;
    - D* b( p" L) I2 `" V! mClassGroup(M);
    ! L# q& E8 d& b/ e( XClassNumber(Q5) ;
    . [/ e7 O; k) C$ a# qClassNumber(M) ;- g9 s* y5 f0 ]5 d1 r
    PicardGroup(M) ;
    * \: [& A$ v4 Q  N$ I6 K. V+ VPicardNumber(M) ;. G/ Y3 E4 y0 _
    6 O4 n( y, `% |. E6 X% j% P4 f
    QuadraticClassGroupTwoPart(Q5);
    2 G/ s8 a2 h- t6 HQuadraticClassGroupTwoPart(M);
    1 T$ s3 e: l# u! G* f! u1 [NormEquation(Q5, -1) ;8 L8 c+ Q: m' [3 t
    NormEquation(M, -1) ;! x; ~; _& N: @% ?9 O( l% q: ]

    - ]* c) f: C6 ~8 `* R' }Quadratic Field with defining polynomial $.1^2 + 1 over the Rational Field
    ; r- Z4 \3 R" S5 g+ k2 |  f6 I& [Univariate Polynomial Ring in w over Q5+ p: d5 |0 p$ q
    Equation Order of conductor 1 in Q5
    6 |% [0 c) M0 F. KMaximal Equation Order of Q5  Q) Z" x, X& S, D& B
    Quadratic Field with defining polynomial $.1^2 + 1 over the Rational Field( n! V' K+ x9 o7 x, I
    Order of conductor 625888888 in Q5
    8 E7 s  n6 M( Y8 h7 }true Quadratic Field with defining polynomial $.1^2 + 1 over the Rational Field8 I/ E& C9 o2 {6 j( u+ g' i6 d. l5 ?8 W
    true Maximal Equation Order of Q5, P1 I+ f9 i- _- p
    true Order of conductor 1 in Q5
    2 C2 c% I* `# m% S+ ?true Order of conductor 1 in Q5
    ' g6 q8 D0 i/ p* Xtrue Order of conductor 1 in Q5
    ' e* T4 B9 O4 _/ Y[3 q3 V" _/ a5 ?3 g% t7 F  s
        <w - Q5.1, 1>,
    7 |% ]% e! ^/ s# j8 D) `    <w + Q5.1, 1># s- J. z; {2 f$ V! T
    ], A+ o: f: r4 V( q2 g: r5 m
    -4* j2 t  ^1 Y1 R+ B) E& T

    ) p6 |; R. o8 c: |* _3 s>> FundamentalUnit(Q5) ;- L3 d3 {0 r5 X8 R" d* w
                      ^
    8 }0 I% `8 p% {Runtime error in 'FundamentalUnit': Field must have positive discriminant
    6 a+ r! q1 |4 a$ [) |+ Z, i0 M$ V0 x# @( h% M9 L
    & b5 X, k# n& n% S0 ?
    >> FundamentalUnit(M);
    # t% f  Y0 |) c2 X" f. c6 R, ]                  ^
    . i$ P6 l0 m4 s8 ZRuntime error in 'FundamentalUnit': Field must have positive discriminant! m  J+ [+ L6 Y7 e. ]. _

    3 _+ y0 }4 r; r: \, I* q1 e4' w4 \+ l6 @) R, e' i# R
    ( k" P2 a0 w2 }2 {
    >> Name(M, -1);6 h) L+ i; b/ ~: I2 P
           ^7 |# R; p; ^! k+ s& c9 z  v
    Runtime error in 'Name': Argument 2 (-1) should be in the range [1 .. 1]7 @' F1 q- Q1 S6 b

    5 D8 [$ \% N6 e; f, f* U. T) q1( D6 l. l2 ~0 h* `, h! t5 w
    Abelian Group of order 1% N, W: Z0 H. W3 }  K
    Mapping from: Abelian Group of order 1 to Set of ideals of M( @( A5 y9 i: L% g
    Abelian Group of order 14 v! o3 T4 e2 a
    Mapping from: Abelian Group of order 1 to Set of ideals of M
    & ]% \# n3 T& J: ?. x/ P1
    , q" c3 O* ^. M; v& B4 b1
    ) f4 i& k+ c: X1 {( e8 O5 q$ yAbelian Group of order 1/ U! N( Y6 A. d
    Mapping from: Abelian Group of order 1 to Set of ideals of M given by a rule [no% A% g5 g, v9 u( G% e5 Z
    inverse]
    3 E" `! N, P! _1 D1 x9 Y0 n18 ~* z+ b5 j3 n& a
    Abelian Group of order 1
    6 [! k* I4 Y' ZMapping from: Abelian Group of order 1 to Binary quadratic forms of discriminant
    3 b: s' `4 F) Q1 D-4 given by a rule [no inverse]$ a7 ^( k2 c9 ~( p* a# Q! L
    Abelian Group of order 1
    2 c. d; U4 ?: N) H8 ~4 gMapping from: Abelian Group of order 1 to Binary quadratic forms of discriminant! J4 A4 ^4 f, s: {
    -4 given by a rule [no inverse]
    ( ]  V' A3 p) E! O; x: w* h* ifalse5 H0 Q) K# \: ?  z; {
    false  `! l1 b! ?0 w$ d3 L
    ===============) j  N$ X7 i! g4 A) j
    5 L* u( }* r0 l
    Q5:=QuadraticField(-3) ;
    4 g; q; S( J7 jQ5;0 M' I* J" {* w. t* z/ Y& n* j5 @+ M

    5 m5 k% `9 e& E5 \2 T# C5 Z! ?Q<w> :=PolynomialRing(Q5);Q;, {7 p0 x$ r* M1 ]* a" _, Z9 P9 {
    EquationOrder(Q5);% E7 t; v% V4 L, M/ {/ \2 i& H# a' \
    M:=MaximalOrder(Q5) ;( w# _1 i& x4 N  q% E
    M;
    3 U" d2 w; y" v  UNumberField(M);% V8 n# Q, K. M5 K! x/ h+ A
    S1:=sub< M | 1 >;S2:=sub< M | 2 >;S3:=sub< M | 3 >;S4:=sub< M | 4 >;S5:=sub< M | 5 >;S25:=sub< M | 25 >;S625888888:=sub< M | 625888888 >;S625888888;0 h) n, I6 X3 P3 I
    IsQuadratic(Q5);
    . F# r3 u4 W% g9 Z. w) V; I9 ]IsQuadratic(S1);
    " P% d6 J  h6 kIsQuadratic(S4);
    . F9 P% d6 m/ Q  a# ]) n3 N5 r: i  E/ |' rIsQuadratic(S25);
    & i/ b$ B; f1 z+ D/ i, pIsQuadratic(S625888888);, M8 `2 F1 [$ u* x/ w0 T- D
    Factorization(w^2+3);  , S  l" ^% ?- t8 g+ c
    Discriminant(Q5) ;
    1 L- f# g: J! L5 d4 x8 B$ L; |FundamentalUnit(Q5) ;
    : O/ K; o  a) OFundamentalUnit(M);( c+ O5 K- h. N! e
    Conductor(Q5) ;
    5 K% c: E) m; `# R* B0 H0 i* T9 X
    1 v( V( Y/ c" ^9 H# k. V: C& v3 rName(M, -3);0 X# p4 A8 l$ A4 w
    Conductor(M);$ I. Y- ^+ ?6 @1 ^1 X8 H( o4 d
    ClassGroup(Q5) ; & P1 }" s4 u: x' a* _  R. d5 [9 x# L, Q
    ClassGroup(M);5 z1 k. Q+ _6 L9 s
    ClassNumber(Q5) ;
    ( l  A- O5 r$ G; qClassNumber(M) ;; H! }: q0 ^3 ^, S5 ]0 \
    PicardGroup(M) ;
    & `9 M+ c! _* Q7 T9 a( UPicardNumber(M) ;
    9 n9 C0 Q2 |. k4 z- o
    ( R6 t; R% C+ X7 P3 zQuadraticClassGroupTwoPart(Q5);
    % Z1 S- l3 R; AQuadraticClassGroupTwoPart(M);
    6 G9 D4 l/ N5 PNormEquation(Q5, -3) ;
    . C1 O+ ?  `" \/ N* E$ fNormEquation(M, -3) ;
    : J7 |+ f! N: r# V" m2 X0 s# t/ D, m( s$ I
    Quadratic Field with defining polynomial $.1^2 + 3 over the Rational Field, }5 X5 B8 r8 k0 X/ f8 j0 D3 _
    Univariate Polynomial Ring in w over Q5
    - b; U8 x* r5 }3 g' JEquation Order of conductor 2 in Q5. D; o& N0 p7 `. \# V. l3 X2 O
    Maximal Order of Q5+ O$ l# b6 W( V/ @
    Quadratic Field with defining polynomial $.1^2 + 3 over the Rational Field4 c4 q; K& A- G
    Order of conductor 625888888 in Q5
      l9 Z: [2 q! j8 ^true Quadratic Field with defining polynomial $.1^2 + 3 over the Rational Field
    3 ^/ C% j) |! E  ~true Maximal Order of Q5
    4 x8 o4 c' X% m) j7 F7 F/ X2 b  c' atrue Order of conductor 16 in Q5+ l  D: F3 L  S7 t0 c
    true Order of conductor 625 in Q50 Y2 |- x# l: h
    true Order of conductor 391736900121876544 in Q5
    ( p* n, J  R* x( j1 b[$ a5 q& J$ g7 ^& O: y) h
        <w - Q5.1, 1>,! E1 ?' m9 Z, d1 W% x9 h( r
        <w + Q5.1, 1>6 J0 O  ~( m( h- H) y
    ]
    7 B7 R5 c, K" K( c1 e-37 B1 J$ U  ~# r7 w: S

      B" k5 A, q4 i8 M% i- Z4 ^- s>> FundamentalUnit(Q5) ;
    % w$ u0 L" O/ h* \. X                  ^
    % s  x; X0 O' l1 xRuntime error in 'FundamentalUnit': Field must have positive discriminant% ~7 W- T9 N; ]5 I4 R

    6 J6 n$ i9 d5 v/ g4 S* i
    ' N. o8 H# z; b" O>> FundamentalUnit(M);0 o1 @7 C) M* E6 b$ a! R' |
                      ^
    ' b1 E% R2 I1 M2 R/ aRuntime error in 'FundamentalUnit': Field must have positive discriminant$ V4 o  B) x6 D5 W6 Y" u8 P

    % c. D; S) ^! f! y* E" F* Y3+ M/ C/ Z. p, {# Q2 U! h
    1 P/ m: a  X& R& ~7 B6 Z7 v2 W
    >> Name(M, -3);
    / _0 V3 U' P5 B7 o5 S0 n       ^
    4 ~2 q1 H0 r# i  r2 p$ t: G$ @Runtime error in 'Name': Argument 2 (-3) should be in the range [1 .. 1]( h& i' H- i% m8 G2 E0 l7 v3 V

    , g& V4 M, O+ e" `1
    ! _2 i" ^0 F/ X1 W5 Q4 ?* r; aAbelian Group of order 1  N& {9 ^$ N" M
    Mapping from: Abelian Group of order 1 to Set of ideals of M
    + b+ \& }2 Q" k9 R( ?1 S7 z1 e6 XAbelian Group of order 1
    . k  y: [0 {6 }/ W- }1 m1 y  aMapping from: Abelian Group of order 1 to Set of ideals of M
    , S4 [% c! G# u5 i1 D$ f( p# o6 t9 [1/ F6 c( O3 `& ^& x& y# t$ C
    15 U& k( Z; K+ C1 Y
    Abelian Group of order 1
    6 `/ r* C7 X; a: N  W4 f, ~  }/ wMapping from: Abelian Group of order 1 to Set of ideals of M given by a rule [no
    $ C3 J2 }1 z7 e3 B: |9 G1 tinverse]
    # D* a' o& H: d2 p! t11 L% k4 i/ O( |! Q3 W0 l, G
    Abelian Group of order 1$ ^% U6 p8 Y6 s9 `* H
    Mapping from: Abelian Group of order 1 to Binary quadratic forms of discriminant; G  n5 y% ~0 }
    -3 given by a rule [no inverse]* ^$ w: Y: e: N$ |9 L
    Abelian Group of order 1  }* G: \& o& V0 S. |
    Mapping from: Abelian Group of order 1 to Binary quadratic forms of discriminant
    - r/ W9 Z$ B# c$ @+ {" F$ V+ Y-3 given by a rule [no inverse]
    " _! b! k; Y+ X8 R7 O  B/ @false
    9 s! [/ E5 y; Y) K# S$ pfalse
    回复

    使用道具 举报

    74

    主题

    6

    听众

    3283

    积分

    升级  42.77%

  • TA的每日心情
    无聊
    2015-9-4 00:52
  • 签到天数: 374 天

    [LV.9]以坛为家II

    社区QQ达人 邮箱绑定达人 发帖功臣 最具活力勋章

    群组数学建摸协会

    群组Matlab讨论组

    群组小草的客厅

    群组数学建模

    群组LINGO

    回复

    使用道具 举报

    lilianjie        

    43

    主题

    4

    听众

    204

    积分

    升级  52%

  • TA的每日心情
    开心
    2012-1-13 11:05
  • 签到天数: 15 天

    [LV.4]偶尔看看III

    本帖最后由 lilianjie 于 2012-1-5 15:20 编辑 7 M- f" v( b) T! ]
    1 b& h: c; k1 H2 D: A3 D7 g
    Dirichlet character
    * `  }7 e7 g/ wDirichlet class number formula6 }7 n8 x5 H$ z) L
    $ Z* r) C2 i, q6 W, t( A: a* X
    虚二次域复点1,实点为0,实二次域复点0,实点为2,实二次域只有两单位根7 Y; U4 f1 \$ |0 w+ B6 J6 J% W4 a
    ) F) u* r: |5 V( _. x
    -1时,4个单位根1,-1, i, -i,w=4,            N=4,互素(1,3),    (Z/4Z)*------->C*      χ(1mod4)=1,χ(3mod4)=-1,h=4/(2*4)*Σ[1*1+(3*(-1)]=1
      B7 Q$ F( C6 t2 l! x% Z* }' i' ]9 O6 R. A, \% s  o
    -3时  6个单位根                             N=3  互素(1,2),    (Z/3Z)*------->C*         χ(1mod3)=1,χ(2mod3)=-1,
    1 R9 s" @' C& H. ?$ y8 P. uh=-6/(2*3)*Σ[1*1+(2*(-1)]=1/ G: V* ^0 U# U6 S  ^. k% |8 D

    5 M) S: n# P) U  S; R-5时  2个单位根                              N=20   N=3  互素(1,3,7,9,11,13,17,19),    (Z/5Z)*------->C*         χ(1mod20)=1,χ(3mod20)=-1, χ(7mod20)=1, χ(9mod20)=1,χ(11mod20)=1,χ(13mod20)=1,χ(17mod20)=1,χ(19mod20)=1,
    : X+ `0 L  d* q1 j9 f3 w4 ?5 Q; u: W4 ~# C2 D! j" W
    & h+ N1 T$ k2 `/ k0 Z
    , \$ L* J% G( w  [, [$ Y! z
    h=2/(2*20)*Σ[1*1-3*1-7*1+9*1-11*1-13*1+17*1+19*1]=2# l- \5 U, }6 |$ f" v, X

    - b% |$ B) w5 d. d* `
    , Q5 y# A* U# d& a) l9 C# v- q7 }. V0 D% D
    -50时  个单位根                          N=200
    % M4 b9 @( |+ l( Y6 v  e
    回复

    使用道具 举报

    15

    主题

    4

    听众

    113

    积分

    升级  6.5%

  • TA的每日心情
    开心
    2012-1-13 11:49
  • 签到天数: 9 天

    [LV.3]偶尔看看II

    Dirichlet character

    21.JPG (79.18 KB, 下载次数: 180)

    21.JPG

    11.JPG (74.76 KB, 下载次数: 179)

    11.JPG

    回复

    使用道具 举报

    15

    主题

    4

    听众

    113

    积分

    升级  6.5%

  • TA的每日心情
    开心
    2012-1-13 11:49
  • 签到天数: 9 天

    [LV.3]偶尔看看II

    回复

    使用道具 举报

    lilianjie        

    43

    主题

    4

    听众

    204

    积分

    升级  52%

  • TA的每日心情
    开心
    2012-1-13 11:05
  • 签到天数: 15 天

    [LV.4]偶尔看看III

    本帖最后由 lilianjie 于 2012-1-9 20:30 编辑
    , M5 v3 `- R' |: k) b2 W( q. i3 P) i$ k- g( `# m+ o
    F := QuadraticField(NextPrime(5));
    $ p7 D! L1 z, D3 G/ p
    : ?$ h; C: o; L5 B, M* A- fKK := QuadraticField(7);KK;
    , J) A' f5 f$ P7 \7 l( yK:=MaximalOrder(KK);0 R% h6 d5 o' W* ?7 k+ {( b9 N
    Conductor(KK);$ x& L3 X% d! o3 A" w0 @
    ClassGroup(KK) ;
    0 s' _2 [; m& PQuadraticClassGroupTwoPart(KK) ;
    2 U/ d9 `$ s7 A8 z: y1 {NormEquation(F, 7);
    4 F2 S" {0 [3 p5 T5 sA:=K!7;A;
    3 {0 _' ]5 G5 v/ XB:=K!14;B;) l6 p. F/ p5 ~5 ]/ d
    Discriminant(KK), F& r; X% m0 Q' I0 F) c
    0 M4 j9 ]0 U. a% |4 `( u( w
    Quadratic Field with defining polynomial $.1^2 - 7 over the Rational Field) [& h- E7 A% c; U
    28# @& [0 k2 G, j
    Abelian Group of order 1
    ) A$ J: a# v  o; Q4 KMapping from: Abelian Group of order 1 to Set of ideals of K1 w( [3 |" C$ ^5 z
    Abelian Group isomorphic to Z/25 N( s# V& z( T% B& L# k
    Defined on 1 generator; @- i; @- ]6 u% p
    Relations:2 s0 k+ @% ~* ^0 @& h- C. U. \1 e
        2*$.1 = 0
    + x8 S2 A. Q0 F, XMapping from: Abelian Group isomorphic to Z/2
    $ p  H& t* h$ d5 O3 [! RDefined on 1 generator" d) O, r. d3 e- q
    Relations:# S# H" W! R, K& h& ^9 z
        2*$.1 = 0 to Binary quadratic forms of discriminant 28 given by a rule [no # d2 J) q+ v' G7 t! T
    inverse]/ W* o3 x% n3 U, @8 s; I
    false0 }+ L% Y8 e. Q/ s
    76 m  \* n& ]: Q3 Y: K
    14
    ! n: ]( x# E- o" {/ s, L, O28
    回复

    使用道具 举报

    lilianjie        

    43

    主题

    4

    听众

    204

    积分

    升级  52%

  • TA的每日心情
    开心
    2012-1-13 11:05
  • 签到天数: 15 天

    [LV.4]偶尔看看III

    本帖最后由 lilianjie 于 2012-1-10 11:23 编辑 / i' J+ Q. a6 y- T

    ( l, l8 H' \2 s* [! c 11.JPG " V8 _* ^3 k- r) Z: m7 G
    ' O. G9 o2 h- r  X  b0 z0 s
    3212.JPG 0 i1 w: R: f  y0 Z6 T1 I
    . ?; A2 a/ E( ]6 @+ K
    123.JPG
      s  S7 L. h0 \! B, n
    ( n7 x" C: h9 H. s- x* e$ i分圆域:4 ]* i$ X' U+ `6 ~+ j8 \: X
    C:=CyclotomicField(5);C;7 x( C8 j! b3 s1 e' A* S
    CyclotomicPolynomial(5);
    ! p$ a. D+ A9 R: e# M* TC:=CyclotomicField(6);C;# c! \" F! Q$ b2 H+ {# I( q
    CyclotomicPolynomial(6);
    * @9 \' D6 w: e* sCC:=CyclotomicField(7);CC;4 H  o9 q' ]( E( L1 |
    CyclotomicPolynomial(7);0 x1 K  N3 K/ m3 H( q& P5 L7 j
    MinimalField(CC!7) ;
    % F7 m* A# E  Z9 X0 WMinimalField(CC!8) ;3 E. C8 O7 i% U5 V* T& a1 b
    MinimalField(CC!9) ;
    : T0 ^! l- Y! }, [6 F% LMinimalCyclotomicField(CC!7) ;
    % h6 g( i+ Y" h: J5 w0 {RootOfUnity(11);RootOfUnity(111);+ Y- w! z  f& _3 G, o# h4 O" w9 j
    Minimise(CC!123);% B2 h6 l) B" o% k
    Conductor(CC) ;
    % r, j2 w8 u/ r. @( }  MCyclotomicOrder(CC) ;
    $ \& E' Q4 p+ }* f' H* G$ R4 f' l& l6 _% u5 i4 k) b$ J# N" _# S
    CyclotomicAutomorphismGroup(CC) ;
    % I8 I8 s+ g1 ~; R; q: Q1 r  }3 d# E* o4 |- w* `( j3 G$ Z) F
    Cyclotomic Field of order 5 and degree 4
    4 h! [6 u4 q# X- O  U" b$.1^4 + $.1^3 + $.1^2 + $.1 + 18 d% y* `; A! \5 L3 K7 v
    Cyclotomic Field of order 6 and degree 2* s, ?; [# Z: B( @2 ]: e$ v
    $.1^2 - $.1 + 10 l9 B$ f" v) \  @/ e
    Cyclotomic Field of order 7 and degree 6
      {/ x, j# S, H- @/ Y. _4 }9 Y$.1^6 + $.1^5 + $.1^4 + $.1^3 + $.1^2 + $.1 + 1% N0 u  V+ o* b) e/ A: f4 ?! U0 ^
    Rational Field
    # e3 Y4 u3 f  G4 ]2 _) w2 b- ^Rational Field/ o) S' J% E0 u, ]0 ~; |1 P
    Rational Field
    - P, z, h) @& ]. m8 {* NRational Field
    7 W0 [7 A  l8 xzeta_111 ]! V2 D/ W6 A4 ~: ?/ x
    zeta_111/ o; n. p! `- g9 B% l1 k" ~9 S9 x0 v
    123
    ) r1 d8 D+ X1 q4 A7( ]# i" J  y4 d/ {! U  E( l) {
    7
    " I, m% x. h3 ?7 d/ T+ }% j2 A5 A5 T7 PPermutation group acting on a set of cardinality 6+ r2 ^5 o6 r: G2 ~+ L- P
    Order = 6 = 2 * 3
    , X# K) `7 C  S4 @9 o    (1, 2)(3, 5)(4, 6)5 m- X+ y" w, P$ A
        (1, 3, 6, 2, 5, 4)$ s) a6 c; B4 R( f2 n
    Mapping from: GrpPerm: $, Degree 6, Order 2 * 3 to Set of all automorphisms of   ~5 ^! W9 w% |; C6 {) k0 f) l7 o
    CC
    # D5 Q, A& m2 T3 a# ^3 C. QComposition of Mapping from: GrpPerm: $, Degree 6, Order 2 * 3 to GrpPerm: $, + v4 }$ z& L$ Y* h
    Degree 6, Order 2 * 3 and3 z8 |/ U/ U# c5 O9 z$ v  \. f
    Mapping from: GrpPerm: $, Degree 6, Order 2 * 3 to Set of all automorphisms of % N; V6 K! d9 u' ]) W. @2 \0 Z
    CC
    回复

    使用道具 举报

    lilianjie        

    43

    主题

    4

    听众

    204

    积分

    升级  52%

  • TA的每日心情
    开心
    2012-1-13 11:05
  • 签到天数: 15 天

    [LV.4]偶尔看看III

    本帖最后由 lilianjie 于 2012-1-10 17:41 编辑
    8 }, p7 Z* l2 j- l. C
    lilianjie 发表于 2012-1-9 20:44 5 `: X: x4 p8 m2 U0 q7 g
    分圆域:3 e$ d  r3 y1 q0 H; v
    C:=CyclotomicField(5);C;
    / v& @' O0 {8 p' L& T( f$ ?1 bCyclotomicPolynomial(5);

    / v+ i2 R6 ^1 C9 ]8 I' F
    - c9 u( j" w' d+ l0 N/ \分圆域:
    3 Q5 c# y5 n. Q! C分圆域:123
    3 E6 Q# Q/ k" g# [4 |
    " H7 U3 Q! K" j; UR.<x> = Q[]
    6 I1 `7 C4 V. d3 E4 BF8 = factor(x^8 - 1)
    1 w8 f. A. h/ G+ S# e0 \8 [5 G1 {3 _  jF8
    $ `9 r4 q6 x; a5 t
    1 |5 z! b8 E4 S5 C+ U(x - 1) * (x + 1) * (x^2 + 1) * (x^4 + 1)(x - 1) * (x + 1) * (x^2 + 1) * (x^4 + 1)
    ) A3 y& h. \4 k" s% P+ n1 v5 L
    / `3 G: {- m8 z) G6 [Q<x> := QuadraticField(8);Q;
    % u4 A# e2 A; I' R! q6 H( JC:=CyclotomicField(8);C;
    7 Q! ^- U! C3 ]FF:=CyclotomicPolynomial(8);FF;
    1 I* l- z% s  K4 @! D0 Q% P& G
    $ a& n+ r- N7 q2 mF := QuadraticField(8);& C' v1 M) v3 ~; ]$ X
    F;
    & k. W. j/ t/ {D:=Factorization(FF) ;D;
    : B4 W) S9 F$ L& k4 y& Y  DQuadratic Field with defining polynomial $.1^2 - 2 over the Rational Field2 ]: q3 z, o! E" y! @$ i
    Cyclotomic Field of order 8 and degree 4
    ( S3 e, h% b1 S% B2 G1 y$.1^4 + 1! c3 x1 Q; i# O
    Quadratic Field with defining polynomial $.1^2 - 2 over the Rational Field
    % }4 M  Q; o6 \5 Y  `* P; a4 ~! @[
    / \8 k6 V- {. C2 I8 H    <$.1^4 + 1, 1>. L0 Z/ y" r6 y$ d. I3 a
    ]; k! _- d3 U) C. h! T( A! M4 u

    7 L  f; B( M1 X8 VR.<x> = QQ[]
    ( N* E- v9 [7 sF6 = factor(x^6 - 1)- j! [/ x+ x0 c6 l$ ~
    F6
    # r: @- ~0 ^  N7 V+ u
    ' F; D5 D( i. K7 [, V( X/ e(x - 1) * (x + 1) * (x^2 - x + 1) * (x^2 + x + 1)(x - 1) * (x + 1) * (x^2 - x + 1) * (x^2 + x + 1)
      n' u6 a4 E$ V: |+ R7 s7 r" G7 p1 U& O
    Q<x> := QuadraticField(6);Q;
    / {% D+ \5 K+ i! S9 HC:=CyclotomicField(6);C;* k9 \* r1 w1 E  y
    FF:=CyclotomicPolynomial(6);FF;  o. H  X2 l1 @, j- d

    , Z$ e1 {. Z) ?' }1 }' |; BF := QuadraticField(6);  l, ]; [% u. A# {! D
    F;
    5 W' j1 N3 a6 G$ @D:=Factorization(FF) ;D;
    1 e* Z9 J& z# cQuadratic Field with defining polynomial $.1^2 - 6 over the Rational Field, h7 n, f$ Z) _; }+ X$ L- t$ l. [
    Cyclotomic Field of order 6 and degree 2- y0 x0 [4 ]& }# @8 c+ `
    $.1^2 - $.1 + 1- M( f5 L( a! Q( m
    Quadratic Field with defining polynomial $.1^2 - 6 over the Rational Field
    , a' h6 G3 q( D% R( L[7 t' t: B% L% ~" M. h# L. i( F
        <$.1^2 - $.1 + 1, 1>; J7 v: k: ?0 r( U3 ^% }) {' W! ~
    ]6 P7 O3 K7 e# n! g3 s2 q3 E! L
    0 z- a" o$ m4 I* x' T' g
    R.<x> = QQ[]
    3 U* U) k; q# V( q. W! e8 |F5 = factor(x^10 - 1)  q' M4 W% g' s( p6 B) n
    F5
    % G# I+ e! Y! W5 @9 r(x - 1) * (x + 1) * (x^4 - x^3 + x^2 - x + 1) * (x^4 + x^3 + x^2 + x +3 X- b6 A( d& U: j
    1)(x - 1) * (x + 1) * (x^4 - x^3 + x^2 - x + 1) * (x^4 + x^3 + x^2 + x + 1)2 ~4 q9 z5 \% I9 ^. g1 ~* f
      k5 x) j2 y- b# |, D, V- X
    Q<x> := QuadraticField(10);Q;* k# {6 e* h6 }5 A: T5 j
    C:=CyclotomicField(10);C;
    8 D$ v. d) {& e3 l. e7 JFF:=CyclotomicPolynomial(10);FF;& j" q/ f0 [, M8 Y" P

    8 a' g, V0 a  P) O- KF := QuadraticField(10);
    1 n2 v; a' v" Z0 u0 _F;
    ( B, S; Q6 t2 X1 W1 P- m+ q$ XD:=Factorization(FF) ;D;
    " H' a. x/ t+ y' gQuadratic Field with defining polynomial $.1^2 - 10 over the Rational Field
    5 x: d: I, I1 [Cyclotomic Field of order 10 and degree 4
    . L9 J2 r, C0 y$.1^4 - $.1^3 + $.1^2 - $.1 + 14 F& O' X8 q" Z( n
    Quadratic Field with defining polynomial $.1^2 - 10 over the Rational Field1 Z9 Y/ g- z5 c! Q/ T
    [
    0 o+ Y: @5 |3 V$ j9 H% u# ^    <$.1^4 - $.1^3 + $.1^2 - $.1 + 1, 1>
    + N8 P" a) N: ~: r3 ?& U6 F]

    c.JPG (217.37 KB, 下载次数: 184)

    c.JPG

    aaaa.JPG (98.21 KB, 下载次数: 173)

    aaaa.JPG

    aaa.JPG (157.27 KB, 下载次数: 175)

    aaa.JPG

    aa.JPG (126.91 KB, 下载次数: 175)

    aa.JPG

    a.JPG (242.91 KB, 下载次数: 195)

    a.JPG

    回复

    使用道具 举报

    15

    主题

    4

    听众

    113

    积分

    升级  6.5%

  • TA的每日心情
    开心
    2012-1-13 11:49
  • 签到天数: 9 天

    [LV.3]偶尔看看II

    回复

    使用道具 举报

    您需要登录后才可以回帖 登录 | 注册地址

    qq
    收缩
    • 电话咨询

    • 04714969085
    fastpost

    关于我们| 联系我们| 诚征英才| 对外合作| 产品服务| QQ

    手机版|Archiver| |繁體中文 手机客户端  

    蒙公网安备 15010502000194号

    Powered by Discuz! X2.5   © 2001-2013 数学建模网-数学中国 ( 蒙ICP备14002410号-3 蒙BBS备-0002号 )     论坛法律顾问:王兆丰

    GMT+8, 2024-6-17 15:53 , Processed in 0.737808 second(s), 102 queries .

    回顶部