lingo建模语言与实例4

longde

目标与约束段
4 I$ I0 {+ U  y) O+ `+ j5 K! K" |8 u集合段（SETS    ENDSETS）
" [" y( W* Z9 N8 R/ A* {& r: i% o数据段（DATA   ENDDATA）
& [2 a& K% @! ^4 M初始段（INIT  ENDINIT）
（计算段 (CALC ENDCALC)）
! I8 w% w0 n, xMODEL:
. F* T# }. y  x4 O0 M6 x+ sTitle Location Problem;
, O* u2 t: T" O& @7 r6 F" Ksets:
. z( `* G$ B& A" M! |    demand/1..6/:a,b,d;
    supply/1..2/:x,y,e;
  F; i  t& E, G/ h    link(demand,supply):c;
endsets
data:
a=1.25,8.75,0.5,5.75,3,7.25;
b=1.25,0.75,4.75,5,6.5,7.75;
d=3,5,4,7,6,11; e=20,20;
enddata
/ B2 @- p& J4 V( B4 Binit:
x,y=5,1,2,7;
" z) e/ ?( W! m2 `1 J) n( w2 `, L# ~endinit
1 s9 ?4 F/ j! {. }' V" Q, n6 lmin=@sum(link(i,j):c(i,j)*((x(j)-a(i))^2+(y(j)-b(i))^2)^(1/2));
@for(demand(i)sum(supply(j):c(i,j))=d(i););
@for(supply(i)sum(demand(j):c(j,i))<=e(i););
- l% t" j7 F1 x# w0 t0 J/ Q3 {: ZEND