: B0 j0 d: {% B3 }) [ Y2 Jc∗τkj=−(xk⃗ −xj⃗ )∗u⃗ c*\tau_{kj} = -(\vec{x_k}-\vec{x_j})*\vec{u}8 N$ n" }: H/ `) A
c∗τ ! L$ M# ~- p2 u" B1 ?& K+ H/ y
kj& L% W' U" x# H1 p
# h+ R$ a2 [* W3 n O
=−( , T& k+ {8 l- \) _( H, X
x 1 a9 {; g+ j9 U* E% d; j9 Mk: X- w" b3 X2 Q: A
H1 T8 S. b5 y9 [& g ) Y% H- v; a5 \( v4 t8 H & z4 q9 x; _# i+ Y0 ~9 s. X − . C( E& y% S8 [; d5 d6 E
x : c" V/ W1 Y8 i9 D
j - ~ f" a0 ]' G! F3 n - ~, d" G7 @# Z 8 V6 w6 D7 v4 I. j5 f! J9 x ( u- x# |6 g9 H7 t) ] )∗ " ]* u$ X4 ]9 m c" lu6 X8 [6 P& Y. n J! |/ ]
% P- D2 Y+ h+ ]+ P/ e8 R & t; _, I5 J9 b# z- _# K这样看起来不够直观,那就代入坐标写成标量形式如下: I. x q2 j0 l# `7 C/ ~1 X @ c$ ?, x( f
c∗τkj=u∗(xk−xj)+v∗(yk−yj)+w∗(zk−zj) c*\tau_{kj}=u*(x_k-x_j)+v*(y_k-y_j)+w*(z_k-z_j) 7 S! S' Y$ F/ N1 Ac∗τ - p7 x9 }& H ?1 o m6 j% t
kj : R: o& O' V8 M . }+ l* @. T' f, b- E8 @
=u∗(x / I! t6 Z' ^9 Q! u' L, X0 V
k * U2 F+ P& Q# s8 |0 \, q% S ! w, M+ O( ~" s/ O+ K* D" t
−x ) |) }! }8 C8 {8 V6 ij / N* M6 E1 J2 ?% H* q 8 v9 H" {& Y& }# N1 K
)+v∗(y ( A$ X! e: \. f# L% k
k * ?4 i% U z6 a: A7 i' B; h# X `) P: h u: b- _* Q −y 0 H* I U: w; L& W& K& J* j3 @7 J
j 8 U+ W1 z6 ~2 o0 Q* A8 |+ p 1 C2 D: h/ {, {% o8 X& l4 g5 M
)+w∗(z ( O* m# g8 {2 d6 r$ s9 N
k. X3 ]! e; t" x" ?8 h$ b
5 {8 K; M- e3 L+ r" x$ [
−z ' i2 h( u$ z& ?6 R& F6 F3 u0 r0 N
j % J. w' @4 {* U) d7 `& M$ [ ' }+ x' \7 u9 U! L, f" c1 S: x ) y; T9 o7 p5 g ]6 s- e4 q. n ! f$ i" s$ d3 X( V1 ~当有多个麦克风时,每两个麦克风就可以得到一组上式,N个麦克风就会有N∗(N−1)/2个等式 N个麦克风就会有N*(N-1)/2个等式N个麦克风就会有N∗(N−1)/2个等式,声源单位传播向量u⃗ =(u,v,w) \vec{u}=(u,v,w) , G2 c1 g' x/ O: \1 ?u) i7 k" h' d/ s1 g6 t- ?1 Q
=(u,v,w) 有三个未知数,因此最少只需要三组等式,也就是三个麦克风就可以计算出声源方向,这里就先假定N=3 N=3N=3,可以得到方程组如下: 0 O P/ E' U% t" m % C$ r# @% Z3 H1 U+ Ec∗τ21=u∗(x2−x1)+v∗(y2−y1)+w∗(z2−z1) c*\tau_{21}=u*(x_2-x_1)+v*(y_2-y_1)+w*(z_2-z_1)c∗τ 1 r9 H' L$ Y# }# `% h% k21 : P. z6 M" Z9 N# C9 H 2 Y/ @0 ?1 b& e; \/ O3 t4 e
=u∗(x * o: z5 U* |) f2 . q- J. k/ L% z" K! M4 X 9 v5 _ H2 _* s: W; J
−x ! k0 Q" q% O# l- j8 W1 & I; s g% h: @& N ' @- p1 J8 d6 S: m1 G
)+v∗(y " ?; V% z7 K4 E2 |
25 {. P* e5 x9 S+ c
2 }, T$ Y: ]8 y7 X5 N
−y # g8 \2 N6 b' E( f; W7 \( Z15 B- m9 X, O1 _/ Q! O7 T
7 Z3 H- O2 m4 o )+w∗(z ( r2 k9 w3 H: X% m, G2 8 Z+ }3 i* a* [ u# d( v , Z0 ~0 g, e, ^6 P5 X8 g
−z ) I1 s8 |! s5 G2 x! X# H& w& f
1 ' ~( ]: f* ^6 ]4 k ! ?6 ~7 A, r6 D5 k* k; q: {$ V )& \: u" u' u+ K3 |! M* u, R7 ^0 ^
c∗τ31=u∗(x3−x1)+v∗(y3−y1)+w∗(z3−z1) c*\tau_{31}=u*(x_3-x_1)+v*(y_3-y_1)+w*(z_3-z_1)c∗τ 9 Z) p' Y! j( s+ J; a$ f
31 - [5 `" u M' D" [# l 7 D: Q X7 K* p1 K: p; [) _6 n; s& i =u∗(x 5 V; N. H0 r# B/ \( d, \
30 e0 p* m3 H$ T }$ q u
7 c+ f# O5 g* g
−x - u+ E( F% \# H
1 $ U# ?; L# X* y% A) I3 V + T+ M _' x. b% E. R
)+v∗(y ( ~9 V9 n8 |* ?- B5 l* K7 R
36 S; J( Y, `8 O( c9 \
" O: X# E) ~+ ]* J; y$ t: L* P
−y 9 e. m6 P- y/ u. m; b& l19 v( ^* C# G+ I$ R7 t8 D1 Y, K
0 H+ Z! h$ e' X, x
)+w∗(z & a$ J3 [, M u' l+ y
3- `" ?1 t: Z7 p. ]0 r
3 t' X& e! j, K −z / E/ ^* D: v1 A/ T
1 5 ]( Q$ E0 V: z; W5 W. C1 l. ^. c ) B) V; a4 M& I5 g) J )" m" m$ A. k; W0 d2 b1 u
c∗τ23=u∗(x2−x3)+v∗(y2−y3)+w∗(z2−z3) c*\tau_{23}=u*(x_2-x_3)+v*(y_2-y_3)+w*(z_2-z_3)c∗τ 8 O: x* M( f0 f23 # a# ?' B5 v* C- Q; O; @: E I u ! S8 `! H& U' r1 n# \4 l, K# X
=u∗(x : S5 k7 V9 T8 U+ x9 Q" e# s# V L
2 - p5 @7 w* q8 t- X ! S# `- N: P3 J( k −x 8 u' W2 @/ \5 p+ n+ \8 Y3' ]2 y- o' M4 n- m" t6 }
+ a" b9 ?2 {0 x6 L
)+v∗(y 6 W" a& V, v# e3 H! p2 4 y3 H" S" B! {7 a. N2 F! v' c ( k1 `" p6 K3 H
−y / t1 S. @; A) j/ `8 y9 J5 p3 s( z: Y
3: s4 H0 x& h8 \
. l5 R: u/ B* @0 D
)+w∗(z / ?8 ~9 M7 t( {5 H7 F% |$ E" C: `
2/ V; p. U, s0 v( p6 F/ d
7 i7 W, X3 @# \0 W% n- W
−z 4 L& r% V4 [0 b2 J9 R3 4 i( k# Y# W1 B+ k$ v. j _ r9 p: q8 D. Y( Y
) 1 I A7 B- h* K. L- R) z% p4 D5 _$ W- @' G; z7 a: o
写成矩阵形式& a/ f2 H* f% U' Y, A5 p
% @ \ v4 q: [: n
9 z5 d5 _9 e7 m) U. W$ \: N# x; R % A: |. `! Y* t* |+ o- A; N- E求出u⃗ =(u,v,w) \vec{u}=(u,v,w) $ t& f+ i1 Z) v
u $ }& u5 L- }6 X% ^! d =(u,v,w) 后,由正余弦关系就有了角度值了 u: F2 D/ @6 m3 D
4 v P" k/ a8 ]! E8 k6 F" @* wθ=acos(1w) \theta=acos(\frac{1}{w})θ=acos( ! P( @+ c) y4 H* i) Yw . @# N3 _! ]5 h$ z' R1+ k* G3 d+ D" p" j. {9 u
9 u" Q7 d% O" | )4 L- d: K$ Q7 u/ T; q- o
8 `, _1 j# H% H# i1 I/ }. j5 ^6 e- _
α=acos(usin(acos(1w))) \alpha=acos(\frac{u}{sin(acos(\frac{1}{w}))})α=acos( 9 d6 p" w4 \4 l0 u* [2 r, ~
sin(acos( % ^. G% \" k. R4 V) k9 [. U
w% `* Y, Y1 B2 A0 _& T
1 7 K4 [; V3 G5 {$ _ - {3 b* p1 }; @4 z u- r D
))* n3 I4 e; W: {) A) c' ~
u : X1 i7 F" e3 U3 g( x - d2 F6 K0 Y- J* c+ {# Y ) ! w% n" T' _3 f; g$ R: g1 x% _4 g) Y' c9 J6 R+ h$ C
当麦克风数量N>3 N>3N>3时,其实所有组合信息对于角度值的计算是有冗余的,这个时候可以求出所有组合的角度值,然后利用最小二乘求出最优解,这样可以利用到所有的麦克风的信息来提高角度估计的稳定性 $ C! y: z8 p3 s2 }! r& g1 \& y7 Z# c1 ]3 W( s
References:$ m0 ?' C7 H1 j+ i B
# b( A8 W: Y K8 ~7 J' t2 nJ. Benesty, J. Chen, and Y. Huang, Microphone Array Signal Processing. Berlin, Germany: Springer-Verlag, 2008. - H& ^) k, `" b! |: v2 o NJ. Dibiase. A High-Accuracy, Low-Latency Technique for Talker Localization in Reverberent Environments using Microphone Arrays. PhD thesis, Brown University, Providence, RI, May 2000.+ _ b4 q7 E4 Q3 z
J.-M. Valin, F. Michaud, J. Rouat, D. Letourneau, Robust Sound Source Localization Using a Microphone Array on a Mobile Robot. Proc. IEEE/RSJ International Conference on Intelligent Robots and Systems (IROS), pp. 1228-1233, 2003.% K1 x! f( r, W7 W4 w
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