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< ><FONT color=#ff0000>函数名: ultoa </FONT>& @$ `0 d: \2 \* s% z" @
功 能: 转换一个无符号长整型数为字符串
: v& ^( T2 l7 ^* a" `8 s用 法: char *ultoa(unsigned long value, char *string, int radix);
" N9 F" l0 `; y; s* P. w' n程序例: </P>7 V* {) E+ X& u7 B6 i+ h+ _; e6 W
< ><FONT color=#0000ff>#include <STDLIB.H>) B6 t8 ]0 k! [8 ?, m" D+ g
#include <STDIO.H></FONT></P>
: I i3 ?$ m, {) a+ o$ K1 ?< ><FONT color=#0000ff>int main( void ) " d z; v$ g" Z9 W* \* K
{ ! W/ k% P1 g, f5 T( Z, U
unsigned long lnumber = 3123456789L; 0 }: p+ _% T9 {
char string[25]; </FONT></P>2 {: L; Z: u' n8 t1 P+ q
< ><FONT color=#0000ff>ultoa(lnumber,string,10); 2 v) a4 z" s2 k4 F% H4 m0 J; A
printf("string = %s unsigned long = %lu\n",string,lnumber); </FONT></P>8 M$ A, k. e( z% s
< ><FONT color=#0000ff>return 0;
: X& a2 y, X$ F7 C. }$ l} 9 D8 l5 _; k C4 V! z1 p
</FONT>
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1 ^4 `( W9 ?+ ^6 M</P>* P2 E6 K6 j2 ]2 c+ O
< ><FONT color=#ff0000>函数名: ungetc </FONT>
- g' K5 N1 E* o$ E功 能: 把一个字符退回到输入流中 + M x9 d1 c0 w) I& n1 I
用 法: int ungetc(char c, FILE *stream);
7 l1 O5 T* [8 b. S. m程序例: </P>6 w: p8 z. F" \" \* a) m; C' h
< ><FONT color=#0000ff>#include <STDIO.H>
, N& u* i- |& s7 j#include <CTYPE.H></FONT></P>
: b+ R- I/ f7 N1 f< ><FONT color=#0000ff>int main( void ) 7 F. C# w0 b; f; f( U O
{
$ q. A, x" F; k6 X" A2 P: a: Vint i=0;
6 b9 g Q3 U+ b7 B* O$ ^char ch; </FONT></P>0 y& O k' z N. H, X( o/ l
< ><FONT color=#0000ff>puts("Input an integer followed by a char:"); </FONT></P>( x% w4 b8 H( d( a# b
< ><FONT color=#0000ff>/* read chars until non digit or EOF */ ( D* R: Y" y' N1 A5 E
while((ch = getchar()) != EOF && isdigit(ch))
$ v, ~4 n9 r9 a' H% m# ni = 10 * i + ch - 48; /* convert ASCII into int value */ </FONT></P>
% S3 \% e; U- |& }# k& I) T2 q< ><FONT color=#0000ff>/* if non digit char was read, push it back into input buffer */ ( b# O# e+ _! r) S- |' {
if (ch != EOF) $ S$ b) C; @6 V
ungetc(ch, stdin); </FONT></P>) J. p& V+ P) b# K
< ><FONT color=#0000ff>printf("i = %d, next char in buffer = %c\n", i, getchar()); $ d, e3 S6 c4 ?9 Z
return 0; ' O- `: Z$ l) i/ l/ B5 T& b
} </FONT>; }+ m) e" L8 A# q4 X; `& t
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</P>
( e( G; S& d8 R! H1 d+ i) j& e( o< ><FONT color=#ff0000>函数名: ungetch </FONT>
$ O7 |* b" }6 c! `& x, @5 [5 {功 能: 把一个字符退回到键盘缓冲区中 # w# m1 G9 b% b+ R% _8 O% Q+ f: u
用 法: int ungetch(int c); 2 o; a# C8 x* l6 e9 f
程序例: </P>& ]0 o' l$ ?6 T
< ><FONT color=#0000ff>#include <STDIO.H>8 s- C, H0 ]8 O3 R- h" L
#include <CTYPE.H>5 X: \+ u$ Y6 k8 @( D- {$ G: N
#include <CONIO.H></FONT></P>
- X8 g0 Y! {0 R' o- v< ><FONT color=#0000ff>int main( void ) + N( [% \5 e% I6 e. I0 I4 e# j
{ - j }6 j1 I3 U1 U- m0 e
int i=0;
9 V4 e( k$ Y o7 i6 u' ]4 G, J! jchar ch; </FONT></P>9 g6 K1 h/ S; V0 S) R/ \
< ><FONT color=#0000ff>puts("Input an integer followed by a char:"); </FONT></P>" _4 e+ E/ q' x3 {) x. V
< ><FONT color=#0000ff>/* read chars until non digit or EOF */
: Z U0 I. P, }0 b% t7 Zwhile((ch = getche()) != EOF && isdigit(ch)) , o' z; a' y4 \5 v! _+ ]/ I
i = 10 * i + ch - 48; /* convert ASCII into int value */ </FONT></P>
: Q9 `& ^9 R1 p" B8 t, l# k< ><FONT color=#0000ff>/* if non digit char was read, push it back into input buffer */ ; i$ y. {" w+ R, c6 l4 l1 c
if (ch != EOF) # ?, a& X( W2 b
ungetch(ch); </FONT></P>
! }0 H2 g& B' X$ ?: N& ^< ><FONT color=#0000ff>printf("\n\ni = %d, next char in buffer = %c\n", i, getch()); / @* K( o& O# h& r$ C6 h
return 0; , \" p0 |) W& r' L/ V/ l
} ( e Y6 u# _: z$ Z9 }9 ]( F/ ?
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</FONT></P>2 o8 s7 ^. d2 o6 d/ q0 s! |7 h
< ><FONT color=#ff0000>函数名: unixtodos </FONT>
3 I, `) L* A* {" e功 能: 把日期和时间转换成DOS格式 % o6 d7 `$ `4 l( c9 h! }& i
用 法: void unixtodos(long utime, struct date *dateptr, 3 |" T0 Y% M$ q/ h
struct time *timeptr); 7 }8 m- E C( d4 M
程序例: </P>
6 U3 Z- D: k& K" R) { j6 `5 q< ><FONT color=#0000ff>#include <STDIO.H>
; o/ a/ e9 f% J2 | r7 j& S6 M#include <DOS.H></FONT></P> W8 a0 N( O4 t' s
< ><FONT color=#0000ff>char *month[] = {"---", "Jan", "Feb", "Mar", "Apr", "May", "Jun",
) P* x0 J; _3 n6 s& R# Y, l# }"Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}; </FONT></P>
4 J+ Y' Y3 A4 V0 c1 E, r< ><FONT color=#0000ff>#define SECONDS_PER_DAY 86400L /* the number of seconds in one day */ </FONT></P>
+ `- ]4 v* |0 h% H# M< ><FONT color=#0000ff>struct date dt;
9 `# R, N6 O9 p: N7 R r$ o% F7 ystruct time tm; </FONT></P>
% a( G/ a- F9 |2 C< ><FONT color=#0000ff>int main(void)
. x7 S' _& s/ I6 V# W( l{
3 A/ f& i+ f# _2 a4 \unsigned long val; </FONT></P>
- o% M2 U+ x Y4 q6 w( o< ><FONT color=#0000ff>/* get today's date and time */ ; U' L6 K& Y3 a' ~: y2 \& t `
getdate(&dt);
4 Z3 L8 S% y! w4 \/ p+ H* m7 C/ Rgettime(&tm); . z: @; ~9 h7 x: T1 I! T3 z
printf("today is %d %s %d\n", dt.da_day, month[dt.da_mon], dt.da_year); </FONT></P>
! T1 c; H* L" P _< ><FONT color=#0000ff>/* convert date and time to unix format (number of seconds since Jan 1, 1970 */
0 P: ^+ L7 r/ h) v+ z, J! hval = dostounix(&dt, &tm); $ g+ k) Z0 r! O' A, Y7 n" E' b
/* subtract 42 days worth of seconds */
- A5 `: U$ l1 g- `; R. [" l, Gval -= (SECONDS_PER_DAY * 42); </FONT></P>
! B+ d7 G6 m m9 D< ><FONT color=#0000ff>/* convert back to dos time and date */ # f; p0 u; [. Q4 r: _
unixtodos(val, &dt, &tm);
/ M7 i% x% l+ Q `printf("42 days ago it was %d %s %d\n",
6 Z6 L ^" Y6 l0 K( H7 a/ r5 {dt.da_day, month[dt.da_mon], dt.da_year);
: a2 d% b' l9 u: F6 `return 0;
! i+ f0 X% k4 G}
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* m1 X) B& S" x! o; e9 q6 [
$ h* j% ?4 ^' K4 ~1 a</FONT></P>
9 l2 h& a0 V! h7 Q2 z5 b I< ><FONT color=#ff0000>函数名: unlink </FONT>' A( |% L% F2 H8 h* s( u
功 能: 删掉一个文件
6 r% V1 g: w1 G/ p% u用 法: int unlink(char *filename); 6 O5 f9 z0 ~9 A6 H h
程序例: </P>+ _- ]/ }3 w' s) V( W6 x2 k
< ><FONT color=#0000ff>#include <STDIO.H>
6 a* u9 V r1 C N( r4 ^: C6 O#include <IO.H></FONT></P>
' j7 J5 P/ ~/ g" y, K<P><FONT color=#0000ff>int main(void) * S( b) T% S8 d' x. s
{ ; H( Q9 M3 h/ e8 {/ u# J! a- S
FILE *fp = fopen("junk.jnk","w"); 6 @' z1 S# q2 D/ s" ^ l* K: k1 q
int status; </FONT></P>
( R. o, q, q/ Z% u<P><FONT color=#0000ff>fprintf(fp,"junk"); </FONT></P>
g, e. a- u; P8 }<P><FONT color=#0000ff>status = access("junk.jnk",0);
. J3 i# w9 j4 K7 d3 j( Yif (status == 0)
$ e- H2 o: B7 x0 P, b B$ M; ~printf("File exists\n");
% X' b, Q, ~1 E2 Melse ! y% Z5 ^# r2 D9 E3 [
printf("File doesn't exist\n"); </FONT></P>. H2 L$ d0 w; [. H+ o; F) F* q; t
<P><FONT color=#0000ff>fclose(fp); ' G8 c1 ?( a2 s
unlink("junk.jnk");
3 ^. `" e6 j; `status = access("junk.jnk",0); ( k) D( ~2 p0 h5 `
if (status == 0) 2 a E6 {# x2 R7 E/ z+ i5 H( C
printf("File exists\n"); ) q# X% d5 P, z# Y$ {$ ?7 t B
else
, _9 x. F% B, D7 g1 ?printf("File doesn't exist\n"); 6 f+ {# ]) g' w* E$ e! N9 h7 ^
</FONT></P>! V: I3 g! V F8 `0 O7 M
<P><FONT color=#0000ff>return 0; , @) g6 A4 d+ f5 W8 I, @
}
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! ?: R/ @7 Y6 x8 K</FONT>
6 f" a, f" L0 ]$ d w7 g, \9 d</P>. r; F$ r; y- ^
<P><FONT color=#0000ff>函数名: unlock </FONT>
' A; R( j& S" y' R! s* y$ W3 E功 能: 解除文件共享锁 & t' G6 k) }8 G2 @- B; n
用 法: int unlock(int handle, long offset, long length); 5 d" G7 N3 ]0 I+ K V1 u( [
程序例: </P>
! Z" } _# X) g' A o<P><FONT color=#0000ff>#include <IO.H>- V3 M1 u9 I5 x+ `( j" [, n0 w
#include <FCNTL.H>
! ]' H' G$ ^6 i#include <SYS\STAT.H>) S, r ]3 \/ f
#include <PROCESS.H>
6 G# ~: k* d! k. k B" O( M#include <SHARE.H>/ Y! N+ u+ k; h) Q
#include <STDIO.H></FONT></P>
7 Y: b3 J3 Q m/ C0 A( j( I<P><FONT color=#0000ff>int main(void)
) Y1 W$ b7 h5 K# N& Q( E6 f{
# U3 P9 y5 {: E( Gint handle, status;
7 A% `; e- X r m( [long length; </FONT></P>
+ |. ~+ n# E9 E3 W8 r<P><FONT color=#0000ff>handle = sopen("c:\\autoexec.bat",O_RDONLY,SH_DENYNO,S_IREAD); </FONT></P>
# Q& T- A8 \7 x<P><FONT color=#0000ff>if (handle < 0)
& W( t) R4 m4 |, }& Q( g{
, ?/ ^, O. ^* [' b& ~+ J$ }printf("sopen failed\n"); 5 X) s, D* d+ @6 m+ \
exit(1); 9 F2 z' E; q+ Y2 R7 h
} </FONT></P>
) B2 |/ p6 X9 F! P! F% Z2 I<P><FONT color=#0000ff>length = filelength(handle);
# T& D, e# S' G8 s$ p% Wstatus = lock(handle,0L,length/2); </FONT></P>
) J' Z) [3 G' ?& f<P><FONT color=#0000ff>if (status == 0) # w( {3 N3 e9 B
printf("lock succeeded\n"); / R* Y, l# O/ c
else 3 a+ r- L" r/ X5 }
printf("lock failed\n"); </FONT></P>3 a4 W9 M- j% _$ Z( h. |7 y, H) l' Q
<P><FONT color=#0000ff>status = unlock(handle,0L,length/2); </FONT></P>0 n" K$ A" g$ N
<P><FONT color=#0000ff>if (status == 0)
! a* c4 A4 M; ?! Cprintf("unlock succeeded\n"); ; M0 s! e* F, A1 t4 W) L0 U
else
, h7 }) ~/ W2 a2 I( J3 Cprintf("unlock failed\n"); </FONT></P>
) Z: ^ f5 ^/ g2 X* z, n<P><FONT color=#0000ff>close(handle);
0 T' C/ L1 |8 d# ]. M3 k P+ k% N% rreturn 0;
* `# n* i1 J; k2 _7 y} </FONT></P> |
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