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(你应该发一个新帖让网友们帮你解答,不要跟我的帖) 4 [5 X2 H' y: t) g& e2 x9 V
多元回归的代码如下: x=[6744 4536 4893.6 8860.8 7507.2 6782.4 9494.4 6216 6432 8380.8 7375.2]'; z=[6.1 8.5 6.4 5.4 6.3 6.7 5.2 6.6 6.9 5.7 5.9]'; w=[20.95 29.6 21.77 21.38 22.19 24.24 25.93 19.52 19.39 21.54 24.44]'; y=[9460.9 19076.5 13846.7 8342.2 10685.1 11403.1 7384.6 12873.5 10524.5 10446.0 12280.6]'; X=[ones(11,1),x,y,w]; [b,bint,r,rint,s]=regress(y,X,0.5) 得到回归结果: b =
U) K2 `( C) x M7 N0 u5 l 1.0e+003 *
" ~ L; `3 x* y6 r: b 7.63365814703216 -0.00125510669136 0.83801013875319 0.32224150099284 K! B: _5 j: R. s# P5 c) Q
bint =
3 H* ?$ E# u6 Y 1.0e+004 *
' h$ c% W0 k8 Q% U, n! C$ W -1.30439270279949 2.83112433220592 -0.00025564588870 0.00000462455043 -0.15661574000751 0.32421776775815 -0.00588755516686 0.07033585536543
, Y( B% V; ]8 _4 t& }) | r = 0 @1 r' ]: W ~3 b) n
1.0e+003 * 5 U; x |- U, n' i& O4 ?
-1.57113991271872 0.47457119617056 -0.02343040684476 0.41501318324491 0.04377602514276 -1.14372443728898 -1.04594801887843 1.22056403128825 -1.06684456987565 1.61340028960900 1.08376262015110
4 U3 P5 F+ K) q' } rint =
4 x. T% I: q, x* M& w( O 1.0e+003 * 8 G6 p/ Y4 I6 j8 Y1 e$ D) ^7 I
-4.18060826996541 1.03832844452798 -0.58713163609601 1.53627402843712 -1.63265383009492 1.58579301640540 -2.41980607307114 3.24983243956095 -3.01244690932543 3.09999895961095 -4.02599379571372 1.73854492113576 -3.03725872250225 0.94536268474539 -1.33675472238316 3.77788278495966 -3.27677184264986 1.14308270289856 -0.92047402141587 4.14727460063388 -1.61182764620170 3.77935288650389
( ]3 ^7 O& ?* w4 C" F s =
4 r( `3 K2 y; M! h 1.0e+006 *
- t }# L9 }1 z3 N9 j 0.00000088230440 0.00001749182053 0.00000000124110 1.66800690870350 也就是说,方程为: y=7633.65814703216x-1.25510669136z+838.01013875319w+322.24150099284
d! u9 d/ [ Q都不是很显著,因为置信区间都过了0点! 7 E5 \5 {5 \+ y* E, b/ E
[此贴子已经被作者于2008-8-9 13:02:27编辑过] |