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求fh3函数在[0.001 0.01]和[0.003 0.1]之间的最小值,估计在1至5之间。 5 B1 g J" [( Z6 a
function f=fh3(n), F0 T+ h1 N! G! J. a! ?" `
g2=2^0.5-1;
& b+ z% G% O1 [7 ~! lmu0=4*pi*10^(-7);/ p0 n" Y- h- ^* |9 V- {
gaf=7.8*10^3;
; u0 y# s' L+ @* Y/ Y' {4 V# cgacu=8.9*10^3;: r6 f( h/ R: p' o5 J( [
gat=4.5*10^3;
: L7 l. A0 z! n# X* |' zgaa=2.7*10^3;
/ a: }3 B5 n( ~5 `$ c/ L8 Zp=2.7*10^4;
" {: a9 v9 |4 g+ d' r) B8 Aq=3*10^(-5);+ B6 s( F6 t2 V" V
rou=0.7;* f9 L+ H$ d2 o' I, A% \
kb=0.9;
6 q+ t! N7 W" C) x) o%j0=8*10^6;
! `7 ^( n+ x( W6 A \- Yj0=2*10^6;" D6 r: u) Z$ w3 J# U
kd=3;
% T3 d6 \8 }# g# f9 Pbm=2;/ n- _/ f7 ]9 |: U/ u; _
ht=2*10^(-3);
4 W# O' z* [( q: z. omu1=10^8/1.75;
9 t# V) B1 ~# b: } x3 Ukt1=2*pi*gat*ht;
9 Q4 b/ c& d: I8 w1 B. c3 bkt2=2*pi*gaa*ht;
& V: j3 c" P* I y4 ikr=1.02;, b; v1 u% r1 J% W" X/ Y# m* H
ku=(mu0/2/bm)^0.5;
; N1 F8 e5 w0 k+ |4 V! w2 Zkx=mu0^0.5*kb*kd^2*j0;- I. ~7 W7 W2 M: C1 T
kp=(2*q/pi/p)^0.5;7 X/ u* U {: ]8 c5 O# _3 L
kg=mu0^0.5*kb*kd*j0*g2;! m4 M- E* P. \9 W9 l) t! }
rx=ku*kx-kp*kg;
2 z( M# i- n) h2 Fra=ku*kg;
( i0 |) N0 H. X& m9 xrc=kp*kx;
1 O: ]. U, E3 A. Dkj=mu0*kb*kd*j0;: h- A! F7 C0 ~$ x
kj=kj/kx;
6 {" ^1 \8 w1 p. d( bh0=3*ht;
6 i1 ~) W l2 C7 N" Bh1=2*(1+1/rou)*q/pi;
; G& E: X0 D9 ~- C' }' O7 eh2=2*(kd-1);- |8 P0 f* ?+ u; O0 G
h3=1/bm*(mu0*p*q/(2*pi))^0.5;) ?; e. j: o4 F0 b, A S
h4=1/kj*(mu0*p*q/(2*pi))^0.5;
* f: n/ B) q `1 i, T! c5 shg=2*pi*kr*ht;' ]* |! F. X1 g0 {, x- Y& ]# T
w1=gaf/bm*(pi*p*q*mu0/2)^0.5;) J: i. E% W7 c$ t
w1p=8*g2*kd*w1;
% V! Y. a" g# ]. |. p* J! \w2=2*kd^2*gaf*(2*pi*mu0*p*q)^0.5/kj;
+ r7 [7 w+ \5 g5 g$ {4 E9 _w3p=2*g2*gacu/kj*(2*pi*p*q*mu0)^0.5;+ S- s( o$ r5 A& C; z
w3pp=hg*h3;0 t: W% f: m/ S/ k# m* l9 e# r
w3=w3p+w3pp;+ J: i& E( X( H) O0 ]
w4=2*kd*gacu/kj*(2*pi*p*q*mu0);
: v( A9 D8 R" }: m3 O H, Gw5=5*pi*ht*gat;; k- X; r" ^) j7 `* A1 Y% e; T
w6=hg*h0*gat;
5 X# d- j% ?% \- Hw7=hg*h1*gat;2 x4 \. T# K! Z9 j6 j9 u+ s$ G/ c
w8=hg*h0*gat;. {& w' E6 O- H/ R* {' ^0 e
w9=hg*h4*gat;
4 V6 N" z4 r" G' i6 b; T7 ef=w1p*r*x^0.5+w2*x^1.5/(g2*r-kd*x)+w3*r*x^(-0.5)+w4*x^0.5+w5*r^2+w6*r+w7/r+w8*r*x+w9*r*x^(-0.5)/(g2*r-kd*x);$ Z# V' G6 K! B# K# o g* s @
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