- 在线时间
- 0 小时
- 最后登录
- 2007-9-23
- 注册时间
- 2004-9-10
- 听众数
- 3
- 收听数
- 0
- 能力
- 0 分
- 体力
- 9975 点
- 威望
- 7 点
- 阅读权限
- 150
- 积分
- 4048
- 相册
- 0
- 日志
- 0
- 记录
- 0
- 帖子
- 1893
- 主题
- 823
- 精华
- 2
- 分享
- 0
- 好友
- 0

我的地盘我做主
该用户从未签到
 |
< ><FONT color=#ff0000>函数名: ultoa </FONT>; S) Y0 H" l$ b' a% r- X" |
功 能: 转换一个无符号长整型数为字符串 ! G9 B; y+ h; ^) |+ M
用 法: char *ultoa(unsigned long value, char *string, int radix); & ?6 {# a% i: d
程序例: </P>
% E" z8 l. S9 D8 o6 A' ?; I< ><FONT color=#0000ff>#include <STDLIB.H>
, g6 r) K+ [* G0 V) v8 t#include <STDIO.H></FONT></P>+ Q, ~7 [* A$ p% D _5 Q
< ><FONT color=#0000ff>int main( void ) , |; u6 g# Q4 o# R1 {& k
{ + Z; b! b B6 c G2 D: C3 @
unsigned long lnumber = 3123456789L; ! W/ b v: ]' u: q
char string[25]; </FONT></P>0 F1 W5 F x, @
< ><FONT color=#0000ff>ultoa(lnumber,string,10);
, a5 Z9 C Z- Y3 b3 @( s( jprintf("string = %s unsigned long = %lu\n",string,lnumber); </FONT></P>8 x* B* O" G' E2 O! Q! P B
< ><FONT color=#0000ff>return 0; ! x/ M+ k& L; q5 N, Y3 ]7 \
} 8 a; V# d& j `+ v8 n2 c
</FONT>
6 H) c6 A# \. v. l2 {
* e3 X. q2 V" C- q. ?: D9 D</P>
# i( K; s# p$ m9 J# g< ><FONT color=#ff0000>函数名: ungetc </FONT>" h3 u- d, x4 h$ a9 X. H' X8 ^
功 能: 把一个字符退回到输入流中 * v+ ? g- h/ q1 }
用 法: int ungetc(char c, FILE *stream); # ~$ x [ t. K% M) A& [" I' G
程序例: </P>6 ]7 b7 R7 T6 H- B7 p
< ><FONT color=#0000ff>#include <STDIO.H>0 h3 |7 w% ?; h) j6 g) t0 t
#include <CTYPE.H></FONT></P>
) m5 Y* w2 I* E2 }' Q< ><FONT color=#0000ff>int main( void ) 9 c2 D+ I' L& T, h& Y$ V
{ $ ?# H: y( `" A
int i=0;
( D4 [- Y3 v; k# X4 O7 jchar ch; </FONT></P>+ ?# @. `/ I! X/ C& }3 r
< ><FONT color=#0000ff>puts("Input an integer followed by a char:"); </FONT></P># u6 D) W5 Z( r
< ><FONT color=#0000ff>/* read chars until non digit or EOF */ 1 @9 u( j B' H0 A) @. A
while((ch = getchar()) != EOF && isdigit(ch)) 7 B* F& O! ~( X) M3 e7 a
i = 10 * i + ch - 48; /* convert ASCII into int value */ </FONT></P>
; e8 j0 m: ^; M; {% Q m8 i7 V& m' j< ><FONT color=#0000ff>/* if non digit char was read, push it back into input buffer */
) O- i! l$ J0 Sif (ch != EOF)
# Q& y2 H4 g' y& m) p, sungetc(ch, stdin); </FONT></P>* Y. O' ~4 V- Q* E7 s `
< ><FONT color=#0000ff>printf("i = %d, next char in buffer = %c\n", i, getchar()); - k; C0 a" e5 v- G K3 B; Q+ A8 J, \, `
return 0;
[) {$ ]. P* [' @8 G5 v7 M; L9 `} </FONT>7 P: T' h: i. N! r) q2 w
7 X/ A6 G+ n g0 G% T9 E. D! K7 W# n: S* u( q
</P>: I s- @4 |5 }, j% z
< ><FONT color=#ff0000>函数名: ungetch </FONT>( ~7 h, [, E5 a1 W% r1 Q2 U1 b# P/ d
功 能: 把一个字符退回到键盘缓冲区中 5 N ]6 H' a. `
用 法: int ungetch(int c);
0 ~8 E2 e8 }; S! q3 ^程序例: </P>
1 \1 }4 J0 i8 H6 ]9 W+ ^7 p< ><FONT color=#0000ff>#include <STDIO.H>
5 ^6 K. F# Z, l$ h* u* h; t#include <CTYPE.H>! R/ l4 n6 x& X" O+ H! E9 @' M
#include <CONIO.H></FONT></P>
2 m% U& C; D6 s8 I/ e( _8 q1 J2 Q< ><FONT color=#0000ff>int main( void )
, U& B) i1 H6 @/ t% A$ _; M{ $ K9 G% m& m5 h9 o, h: B
int i=0; $ q1 ^# L( {$ @5 e
char ch; </FONT></P>1 d& h# E) F% b$ x8 L6 h) g
< ><FONT color=#0000ff>puts("Input an integer followed by a char:"); </FONT></P>- w/ T8 G8 M' K! l( f
< ><FONT color=#0000ff>/* read chars until non digit or EOF */
4 H8 Z. y: t6 ]" B+ e2 Twhile((ch = getche()) != EOF && isdigit(ch))
& w1 |5 T. T L- S( Ci = 10 * i + ch - 48; /* convert ASCII into int value */ </FONT></P>
- g( A( `* D. |: \9 \# `< ><FONT color=#0000ff>/* if non digit char was read, push it back into input buffer */ # {4 ~7 m4 }4 m
if (ch != EOF)
/ |9 y+ N: @3 {+ }$ r; xungetch(ch); </FONT></P>
+ e6 L* |$ X* D y Q2 q+ U4 U; w< ><FONT color=#0000ff>printf("\n\ni = %d, next char in buffer = %c\n", i, getch()); / g6 o/ H3 l. z
return 0;
+ Z/ Y# |1 B) U5 M8 N& W( U} - S- e# `- p! G' V
+ G. u: w" n' [ J* Z6 I9 Y% v' k
$ }6 G- Y+ [. p$ y) B# J, B
</FONT></P>
r7 m# X/ W* S# T4 {$ l< ><FONT color=#ff0000>函数名: unixtodos </FONT>
f' H9 Q- U& Z功 能: 把日期和时间转换成DOS格式
$ y! {$ _4 [ U% E: ~用 法: void unixtodos(long utime, struct date *dateptr,
6 X8 J* F. j% k% R. }struct time *timeptr);
. t5 W2 Z3 N' F程序例: </P>, ^( d \; [# {7 [( K7 n
< ><FONT color=#0000ff>#include <STDIO.H>! t5 x( ^* T! Q3 c' C
#include <DOS.H></FONT></P>
. H( |" ~8 N% Z! K< ><FONT color=#0000ff>char *month[] = {"---", "Jan", "Feb", "Mar", "Apr", "May", "Jun",
* M4 X" N; I/ u$ N$ b) L"Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}; </FONT></P>1 o3 n, a Y0 A: Y4 @( e* J, O
< ><FONT color=#0000ff>#define SECONDS_PER_DAY 86400L /* the number of seconds in one day */ </FONT></P>5 u O: p; p$ p* H, m% J# `: i- q
< ><FONT color=#0000ff>struct date dt; " [% P8 w2 M+ H) ^: @
struct time tm; </FONT></P>
`" x1 s/ D! U8 _; ^, a< ><FONT color=#0000ff>int main(void)
% h" ^. ~4 A9 D: P. ^$ O{ # R+ y# I. B" j; ~
unsigned long val; </FONT></P>
( e& V! o0 Z% S+ b< ><FONT color=#0000ff>/* get today's date and time */ 1 k: i. A( R) N, q8 d
getdate(&dt); , b. j6 e. t( J( G n4 K1 m
gettime(&tm); 6 A8 U2 u1 ?2 v( c' y
printf("today is %d %s %d\n", dt.da_day, month[dt.da_mon], dt.da_year); </FONT></P>& W0 y: Q9 c8 F7 E- @
< ><FONT color=#0000ff>/* convert date and time to unix format (number of seconds since Jan 1, 1970 */ 8 f6 D' O/ G5 y3 _+ c
val = dostounix(&dt, &tm); 7 k, D. x' m& N8 X! Q; g: |/ L6 P
/* subtract 42 days worth of seconds */ / P5 r8 v' V% i( P3 X
val -= (SECONDS_PER_DAY * 42); </FONT></P>
3 Y: E1 y# k- ?% H# T# p< ><FONT color=#0000ff>/* convert back to dos time and date */
3 H& c2 T% i% V- a k9 z* uunixtodos(val, &dt, &tm); . y% A% Z# |# _% p. T7 H- K' @
printf("42 days ago it was %d %s %d\n",
7 x8 M- B3 Y b6 [7 w: D; v- jdt.da_day, month[dt.da_mon], dt.da_year); & L, G3 S' a; D8 y
return 0;
; z+ r4 W2 ?" c} + o6 J1 i; B0 v% W$ N3 R4 m+ i
6 U4 N9 M z& y- J' R
- G7 ^% x: ^: P8 j. D8 j</FONT></P>& F, p0 F7 J7 r8 ]/ L
< ><FONT color=#ff0000>函数名: unlink </FONT>
: L ^8 X5 d; W功 能: 删掉一个文件
1 _5 Q: n+ n* D7 J+ u1 X) }# ^/ a% ~用 法: int unlink(char *filename);
0 H* J* t( A2 b' \: W: V程序例: </P>
& C8 P N) }0 ?/ C" I+ G< ><FONT color=#0000ff>#include <STDIO.H>2 N1 I! _4 t5 q( v
#include <IO.H></FONT></P>5 @; ~7 W- b) P1 |, |- w, [: m) G- X# Q
<P><FONT color=#0000ff>int main(void) ! Y3 d/ f. r6 @0 b
{ 6 Z. }: e3 E0 g- i
FILE *fp = fopen("junk.jnk","w"); 1 R. r0 K: g* f& X+ x0 N6 u
int status; </FONT></P>
7 q1 m# Q- e: V. E4 ~- v0 P* }<P><FONT color=#0000ff>fprintf(fp,"junk"); </FONT></P>
_* F) m, E4 p) c<P><FONT color=#0000ff>status = access("junk.jnk",0); , } `3 h! T% C; Q6 r- f# W
if (status == 0)
7 J8 O; t$ Q% \ \; aprintf("File exists\n");
7 ]; H% O, X: aelse
9 A Q# w% ~6 ^2 a9 Fprintf("File doesn't exist\n"); </FONT></P>0 M! n$ M% v7 b! O
<P><FONT color=#0000ff>fclose(fp);
|# I, u. y& x# q+ ?7 @: tunlink("junk.jnk");
1 A$ _( D4 k/ r; u9 Istatus = access("junk.jnk",0); . G1 p9 I: N* b" }3 u- k0 n/ C
if (status == 0)
4 F5 z5 Z0 ]7 a1 zprintf("File exists\n"); 3 s/ {; |3 Y* t2 H7 a
else . U+ h3 ?; `/ J! r, z
printf("File doesn't exist\n");
% H6 v9 f1 E2 N+ Z' c( {</FONT></P>
7 {! \4 ~/ F+ V/ w<P><FONT color=#0000ff>return 0;
' A8 c, F+ F/ Y2 j9 \} # o8 C0 @: |0 f( k
0 M$ F8 V* e5 g5 e% U" n. v</FONT>% u; p7 r' `) I3 g2 f
</P>
! ^( x& e5 d3 g/ |8 W& f<P><FONT color=#0000ff>函数名: unlock </FONT>6 q+ M, X( e* c3 k( R
功 能: 解除文件共享锁 9 _1 h2 n! K" F. B$ Y3 y
用 法: int unlock(int handle, long offset, long length); / s! @0 Y0 O1 T0 i s
程序例: </P>
1 p J/ F& K) }0 [<P><FONT color=#0000ff>#include <IO.H> o# v4 Q9 \9 s; s7 v: K+ r
#include <FCNTL.H>
6 N' `! e9 Q. }# B/ {0 T a" X#include <SYS\STAT.H>! T* V: f* @* {+ p4 F
#include <PROCESS.H>
5 m2 T4 E$ w$ g: q, {#include <SHARE.H>
5 \! y6 b9 c" B6 e; A#include <STDIO.H></FONT></P>4 I! M9 `7 s# o; s! l `
<P><FONT color=#0000ff>int main(void)
3 X2 N: @; Z3 S" X6 s2 b{ 7 A% w9 Z) c: _6 A" `
int handle, status;
! C) i# e: g, W$ k/ `7 C: Tlong length; </FONT></P>
3 I5 u# T" y, S- J<P><FONT color=#0000ff>handle = sopen("c:\\autoexec.bat",O_RDONLY,SH_DENYNO,S_IREAD); </FONT></P>
L: D' C G1 d. c! v<P><FONT color=#0000ff>if (handle < 0)
4 E5 o9 _1 U' q+ A* k8 x{
5 b) M5 q$ _. jprintf("sopen failed\n"); % i" \ b( c1 }8 g1 M2 }5 \: _4 Q
exit(1); ! [2 q8 X1 v. ~( B2 J
} </FONT></P> B" t* q) w* X" L
<P><FONT color=#0000ff>length = filelength(handle);
J2 g% R# V6 t, lstatus = lock(handle,0L,length/2); </FONT></P>$ A6 x# j% S% B6 Y5 M
<P><FONT color=#0000ff>if (status == 0) 5 k: \9 V8 k2 j7 H+ k1 b, x% q
printf("lock succeeded\n"); , J2 V6 K% \% L$ F% t
else
' b' i( `: b6 w6 Oprintf("lock failed\n"); </FONT></P># w9 @7 J8 t8 `
<P><FONT color=#0000ff>status = unlock(handle,0L,length/2); </FONT></P>! ~2 O$ o: ~, x
<P><FONT color=#0000ff>if (status == 0) + N; H4 s4 ]7 `$ x+ F3 } u, \. i
printf("unlock succeeded\n");
6 ]! M. L( x/ jelse 9 ~9 Y* ~ m% B9 z" W- x' m
printf("unlock failed\n"); </FONT></P>+ F- f W0 `5 `- F3 o" b
<P><FONT color=#0000ff>close(handle); 9 R; U7 {9 G6 ?5 B
return 0; ) Q# |0 V: @) S$ v( K
} </FONT></P> |
zan
|