求帮助，关于S1的积分，为什么我的结果带int啊，这是怎么回事。正确的应该怎么办！！

dyd

syms g v aA bA cA zA u  t1 t2;
& B" x+ y3 {; h1 a6 |int(g);
+ x3 _0 T! R" F  J# e3 ?- N, ]int(v);
# q! B: |" Z- n+ ch=0.856;
3 @; G! N) t) H  t* p9 R" U" J& haA=(1+tan(g)*tan(g));
bA=-(2*1.625+2*tan(g)*(h+30*tan(g))-30*tan(g));
2 d; k" k: @) m$ X3 k1 A' z6 WcA=(h+30*tan(g)-15)*(h+30*tan(g)-15);
+ R6 {% t2 J7 ?* CzA=(-bA-sqrt(bA*bA-4*aA*cA))/(2*aA);
& V. G0 d- z- R* B! n0 gya=h+30*tan(g)-tan(g)*zA;
s1=(1.625*1.625-(z-1.625)*(z-1.625))*cos(v)*sqrt(tan(v)*tan(v)+1)*(sin(2*((asin(((h+30*tan(g)-z*tan(g))-15)/(sqrt(1.625*1.625-(z-1.625)*(z-1.625))*sqrt(tan(v)*tan(v)+1))))))/2-sin(2*((asin(-1/(cos(v)*sqrt(tan(v)*tan(v)+1))))))/2+((asin(((h+30*tan(g)-z*tan(g))-15)/(sqrt(1.625*1.625-(z-1.625)*(z-1.625))*sqrt(tan(v)*tan(v)+1)))))+((asin(-1/(cos(v)*sqrt(tan(v)*tan(v)+1))))));
; \) Q6 j; d2 m+ A' I8 `p=1.625-sqrt(1.625^2-((15-ya)/sqrt(tan(v)*tan(v)+1)));
2 c  P7 a% H( C. dH=int(s1,z,p,10);

ealx0yJu

呵呵,打酱油的.

dyd

厚积薄发 发表于 2012-5-9 16:25
* A3 U" o' O2 P7 f) A; Z9 z放个截图看看

" `; R) v# ~1 M6 K/ ]5 ?1 u
6 h1 V, Y% O0 q2 v* ?  b好了···我想得到的是带g v h 但是对s1积分却积分不出来，即使积出来也带int 谢谢了

①不小xin--!

啊啊啊啊啊啊是的的的的飞飞飞

厚积薄发

放个截图看看