函数大全(k开头)

韩冰

< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(k开头)</FONT></B></FONT>
</P>
<><FONT color=#ff0000>函数名: kbhit </FONT>
: W; p$ F* C- ?7 x' X- m功 能: 检查当前按下的键
用 法: int kbhit(void);
程序例: </P>
<><FONT color=#0000ff>#include <CONIO.H></FONT></P>
<><FONT color=#0000ff>int main(void)
{
cprintf("ress any key to continue:");
5 l! z% v) J9 W  }while (!kbhit()) /* do nothing */ ;
% y8 G: p, o5 P4 A! b6 h+ _  Dcprintf("\r\nA key was pressed...\r\n");
return 0;
2 R8 p- N& r7 ^' u2 B+ m. r} </FONT>
</P>
<><FONT color=#ff0000>函数名: keep </FONT>
& p- z6 O; }  |) ?$ A功 能: 退出并继续驻留
用 法: void keep(int status, int size);
0 l* V4 v4 l% J5 I1 v. V程序例: </P>
<><FONT color=#0000ff>/***NOTE:
This is an interrupt service routine. You
can NOT compile this program with Test
8 G: Z: u$ N6 h$ q" hStack Overflow turned on and get an
8 j' b( Z9 M8 z% \executable file which will operate
correctly. Due to the nature of this
function the formula used to compute
the number of paragraphs may not
0 q; w* `: {. k  j% h& m4 X& }* Mnecessarily work in all cases. Use with
: ]( j$ K+ f: Q! f- Z6 E& ycare! Terminate Stay Resident (TSR)
! k& A' F6 g9 \programs are complex and no other support
for them is provided. Refer to the
! i% ^) _% a( w6 P( g! MMS-DOS technical documentation
for more information. */
#include <DOS.H>
/* The clock tick interrupt */
3 U8 H$ m) `& I" d0 c#define INTR 0x1C
$ B( r: k) v0 o4 E% L8 t0 _/* Screen attribute (blue on grey) */
#define ATTR 0x7900 </FONT></P>
<><FONT color=#0000ff>/* reduce heaplength and stacklength
, N, @  A7 w' @6 }# Fto make a smaller program in memory */
+ R: B1 b, o0 d/ O" F$ D# f/ uextern unsigned _heaplen = 1024;
5 ~$ M8 y) p6 Z3 g! wextern unsigned _stklen = 512; </FONT></P>
6 r( o4 Y8 ]" R* f* R<><FONT color=#0000ff>void interrupt ( *oldhandler)(void); </FONT></P>
6 Z6 D! C/ G( Z; t- _3 O<><FONT color=#0000ff>void interrupt handler(void)
9 u6 U1 i6 a- E5 Q* L5 j8 b{
8 D9 `0 w/ l) Y# j( L  t: `# c+ ?unsigned int (far *screen)[80];
static int count; </FONT></P>
4 S! o) U' p: H. A' a- u<><FONT color=#0000ff>/* For a color screen the video memory
/ p$ {0 C2 Z7 U2 Y3 mis at B800:0000. For a monochrome
% S* g# {& C0 |, tsystem use B000:000 */
screen = MK_FP(0xB800,0); </FONT></P>
1 h, p7 ?0 z. B3 G<><FONT color=#0000ff>/* increase the counter and keep it
" ~( C, M( q& p3 M( |& z/ ^within 0 to 9 */
count++;
count %= 10; </FONT></P>
<><FONT color=#0000ff>/* put the number on the screen */
/ R* _5 s+ K7 R( |screen[0][79] = count + '0' + ATTR; </FONT></P>
<><FONT color=#0000ff>/* call the old interrupt handler */
% A% p0 H& Q+ r( _* B7 foldhandler();
} </FONT></P>
4 o4 @6 H0 W0 d' F8 @<><FONT color=#0000ff>int main(void)
- E4 }% d3 u" q4 _! X7 ~{ </FONT></P>
<><FONT color=#0000ff>/* get the address of the current clock
7 k$ q  o# e) d; @) @tick interrupt */
oldhandler = getvect(INTR); </FONT></P>
<><FONT color=#0000ff>/* install the new interrupt handler */
2 T9 W: y" B$ ysetvect(INTR, handler); </FONT></P>
" ~7 B, }. |: N, [& C<><FONT color=#0000ff>/* _psp is the starting address of the
( ?' G) V. }+ Q1 ?3 h9 ~4 uprogram in memory. The top of the stack
/ T1 j; h+ a/ L$ Eis the end of the program. Using _SS and
_SP together we can get the end of the
& T. l$ Q. E% \; Wstack. You may want to allow a bit of
* H- f) u6 V' R& u4 M0 k7 `% vsaftey space to insure that enough room
is being allocated ie:
(_SS + ((_SP + safety space)/16) - _psp)
*/
keep(0, (_SS + (_SP/16) - _psp));
return 0;
9 L" |0 V% r/ h* e) ]: D) D}
+ o8 [! P+ @% s% @& n</FONT></P>

1 |* s- W) X' p+ B/ `% e
3 _3 B  d4 ^1 f: S<><FONT color=#ff0000>函数名: kbhit </FONT>
功 能: 检查当前按下的键
用 法: int kbhit(void);
程序例: </P>
8 m: m* Z2 T5 J; E<><FONT color=#0000ff>#include <CONIO.H></FONT></P>
. {1 C7 }; G; }1 m: y2 `<><FONT color=#0000ff>int main(void)
# Q$ J" m: ?' f% r: w{
cprintf("ress any key to continue:");
" \" `1 X6 t$ e' f* Rwhile (!kbhit()) /* do nothing */ ;
$ ?2 l8 u0 q! m8 Ucprintf("\r\nA key was pressed...\r\n");
# t4 n5 g- o3 n" u9 G5 rreturn 0;
! k& d% B1 g1 }7 p) |}


  {% O& ]/ I) M5 x2 J! m</FONT></P>
* X  Z% w% N- C3 A( m" i7 T, J<><FONT color=#ff0000>函数名: keep </FONT><FONT color=#0000ff>
<FONT color=#000000>功 能: 退出并继续驻留
用 法: void keep(int status, int size);
! L: S+ D: a3 W, m0 m程序例: </FONT></FONT></P>
<><FONT color=#0000ff>/***NOTE:
8 r; V8 ?  }5 f. y" SThis is an interrupt service routine. You
can NOT compile this program with Test
Stack Overflow turned on and get an
) Z: g5 ]! {! e+ \! Yexecutable file which will operate
4 o1 }/ H. m& Z' C/ ?correctly. Due to the nature of this
* ~9 N" J2 N) ~function the formula used to compute
. ~! }+ x  m( k! k4 mthe number of paragraphs may not
necessarily work in all cases. Use with
9 J+ R$ V! ]  W: d: }care! Terminate Stay Resident (TSR)
: W" p4 E* T2 Gprograms are complex and no other support
for them is provided. Refer to the
MS-DOS technical documentation
( X' A8 H" C" k- E6 Wfor more information. */
8 b) s5 ]0 }$ }/ Z#include <DOS.H>
/* The clock tick interrupt */
) ~& D" g$ }& \" i( k  Y7 s#define INTR 0x1C
/* Screen attribute (blue on grey) */
* A# G) C, a) M$ p#define ATTR 0x7900 </FONT></P>
<><FONT color=#0000ff>/* reduce heaplength and stacklength
to make a smaller program in memory */
extern unsigned _heaplen = 1024;
extern unsigned _stklen = 512; </FONT></P>
) S/ T* H. s* A6 h+ p6 n' G) E' e  `<><FONT color=#0000ff>void interrupt ( *oldhandler)(void); </FONT></P>
* M6 y+ d! V9 I2 V& M<><FONT color=#0000ff>void interrupt handler(void)
{
unsigned int (far *screen)[80];
static int count; </FONT></P>
0 C) O8 K- Y/ Z  R# D& n<><FONT color=#0000ff>/* For a color screen the video memory
is at B800:0000. For a monochrome
3 k! B) K9 \$ u9 _  P5 y2 H9 ysystem use B000:000 */
4 e1 Y1 s, Q$ p1 T! i3 ?screen = MK_FP(0xB800,0); </FONT></P>
<><FONT color=#0000ff>/* increase the counter and keep it
within 0 to 9 */
count++;
count %= 10; </FONT></P>
  s6 C& S- G; e  y2 ~<><FONT color=#0000ff>/* put the number on the screen */
screen[0][79] = count + '0' + ATTR; </FONT></P>
<P><FONT color=#0000ff>/* call the old interrupt handler */
oldhandler();
} </FONT></P>
<P><FONT color=#0000ff>int main(void)
6 u! g2 V3 C/ J, o! w! ]{ </FONT></P>
<P><FONT color=#0000ff>/* get the address of the current clock
tick interrupt */
8 C9 q2 C, H) Xoldhandler = getvect(INTR); </FONT></P>
<P><FONT color=#0000ff>/* install the new interrupt handler */
setvect(INTR, handler); </FONT></P>
. `+ b: c  K+ {" f. C! {<P><FONT color=#0000ff>/* _psp is the starting address of the
program in memory. The top of the stack
; H, E8 n. g  q1 S6 ^" Lis the end of the program. Using _SS and
_SP together we can get the end of the
6 {4 ^  T$ y" |3 s# e0 \# jstack. You may want to allow a bit of
0 Z7 Y9 m1 j  g% G+ Y) C. \7 qsaftey space to insure that enough room
9 S  K+ n5 N# ~4 Z% ]- nis being allocated ie:
0 D1 s$ x+ K5 B$ A* r; s(_SS + ((_SP + safety space)/16) - _psp)
+ e" h2 u8 W) [( j2 I; F" Z7 _*/
2 C  U  T7 @. i: I7 wkeep(0, (_SS + (_SP/16) - _psp));
2 j$ _' n' r' H. breturn 0;
( _8 {8 [  L4 O}</FONT></P>