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(你应该发一个新帖让网友们帮你解答,不要跟我的帖)
) K4 L5 k! e0 {5 O多元回归的代码如下: x=[6744 4536 4893.6 8860.8 7507.2 6782.4 9494.4 6216 6432 8380.8 7375.2]'; z=[6.1 8.5 6.4 5.4 6.3 6.7 5.2 6.6 6.9 5.7 5.9]'; w=[20.95 29.6 21.77 21.38 22.19 24.24 25.93 19.52 19.39 21.54 24.44]'; y=[9460.9 19076.5 13846.7 8342.2 10685.1 11403.1 7384.6 12873.5 10524.5 10446.0 12280.6]'; X=[ones(11,1),x,y,w]; [b,bint,r,rint,s]=regress(y,X,0.5) 得到回归结果: b =
2 o! u W5 G$ ^, n 1.0e+003 * : y4 v; w2 s' D) ]& [' h+ K5 O
7.63365814703216 -0.00125510669136 0.83801013875319 0.32224150099284
7 x0 p7 [% \/ V' A' U( ~( ~' l bint = 5 r+ b/ s; r$ a
1.0e+004 * $ @& \4 S+ D% n# Z
-1.30439270279949 2.83112433220592 -0.00025564588870 0.00000462455043 -0.15661574000751 0.32421776775815 -0.00588755516686 0.07033585536543
; M1 K& D' j" b* L" \ r =
- f) {1 z0 S& P% A! I 1.0e+003 *
9 n& K' X$ T- q# b -1.57113991271872 0.47457119617056 -0.02343040684476 0.41501318324491 0.04377602514276 -1.14372443728898 -1.04594801887843 1.22056403128825 -1.06684456987565 1.61340028960900 1.08376262015110 Z9 ^; P% ~; ^' l9 G& a
rint =
# U4 o6 d6 K1 ^1 |) G Q 1.0e+003 * 8 h9 o* q w8 k* o
-4.18060826996541 1.03832844452798 -0.58713163609601 1.53627402843712 -1.63265383009492 1.58579301640540 -2.41980607307114 3.24983243956095 -3.01244690932543 3.09999895961095 -4.02599379571372 1.73854492113576 -3.03725872250225 0.94536268474539 -1.33675472238316 3.77788278495966 -3.27677184264986 1.14308270289856 -0.92047402141587 4.14727460063388 -1.61182764620170 3.77935288650389
( @, {& X2 H6 _* z s =
: T9 s8 Y9 Z% R2 ?: X6 p7 o 1.0e+006 *
' B6 Q( J' ?; @* s6 j3 d. r! U 0.00000088230440 0.00001749182053 0.00000000124110 1.66800690870350 也就是说,方程为: y=7633.65814703216x-1.25510669136z+838.01013875319w+322.24150099284 ' I/ k7 z/ N. ?. a( k+ L. U
都不是很显著,因为置信区间都过了0点!
$ q K- I( b+ O G[此贴子已经被作者于2008-8-9 13:02:27编辑过] |