QQ登录

只需要一步,快速开始

 注册地址  找回密码
查看: 3204|回复: 9
打印 上一主题 下一主题

虚二次域例两(-5/50)

[复制链接]
字体大小: 正常 放大
lilianjie        

43

主题

4

听众

204

积分

升级  52%

  • TA的每日心情
    开心
    2012-1-13 11:05
  • 签到天数: 15 天

    [LV.4]偶尔看看III

    跳转到指定楼层
    1#
    发表于 2012-1-4 17:41 |只看该作者 |倒序浏览
    |招呼Ta 关注Ta
    本帖最后由 lilianjie 于 2012-1-4 17:54 编辑 - H, d0 l( n* l3 S
    / Y* u: F4 a1 w# j, [  I0 Q( C
    Q5:=QuadraticField(-5) ;
    3 o: {, M6 d4 H! j  E- j! VQ5;( F* n" W: R  ~5 M- z! o
    2 y3 k1 {1 n$ q& F- r
    Q<w> :=PolynomialRing(Q5);Q;3 I: N2 M5 w/ u" o0 _, C1 k  D& J
    EquationOrder(Q5);' j, ]" A- h. x$ [$ I5 u% o
    M:=MaximalOrder(Q5) ;
    ' C. ]- L) p* ]; s" SM;
    5 Q5 V( h* o, P! y8 n. kNumberField(M);4 L0 M$ I# C8 j! z
    S1:=sub< M | 1 >;S2:=sub< M | 2 >;S3:=sub< M | 3 >;S4:=sub< M | 4 >;S5:=sub< M | 5 >;S25:=sub< M | 25 >;S625888888:=sub< M | 625888888 >;S625888888;
    , z" ]( d' A. ^IsQuadratic(Q5);
    8 P8 l( X- B8 Y8 H2 U6 xIsQuadratic(S1);6 @$ Y  a+ e- i3 }2 ]
    IsQuadratic(S4);, I  \5 v# ~4 c! F
    IsQuadratic(S25);
    " @0 q/ [/ p" P, B( `IsQuadratic(S625888888);
    & W; f. I6 ]! K8 y( K8 ^' rFactorization(w^2+5);  ; |$ [1 P4 |1 ~& d- t; G* Z6 ^
    Discriminant(Q5) ;
    - X& R. e4 \5 Y5 j/ l: z) XFundamentalUnit(Q5) ;  q0 S8 ]0 @3 a! R
    FundamentalUnit(M);
    - s- t% x( C! @( U$ R+ V. yConductor(Q5) ;
    ) E6 I- N% e3 a; {0 c9 S/ _$ E8 ]# R) ]& |
    Name(M, -5);1 M8 T& [# H, S: n/ m
    Conductor(M);
    4 D6 G$ R* B1 A# A2 X( `ClassGroup(Q5) ; + S8 K: \' M, S% L: N5 r0 \+ v
    ClassGroup(M);# H  R- @: x* U* Z/ g, e
    ClassNumber(Q5) ;
    1 U/ z6 e. k& WClassNumber(M) ;* H. R1 f% n7 G2 l
    PicardGroup(M) ;4 k( h% z7 M  G+ F# D
    PicardNumber(M) ;" G( p( S& y4 ~8 ~, M, ^) z2 j

    4 C3 ^+ L. O! d( _/ i4 K/ i1 ]QuadraticClassGroupTwoPart(Q5);/ M( k  b8 J" }0 m  q6 C" P
    QuadraticClassGroupTwoPart(M);/ h7 i8 F, A4 K- J' u
    NormEquation(Q5, -5) ;
    : t  I, y2 U2 n8 N9 r- \: @; g) ANormEquation(M, -5) ;
    # Q+ v3 c% Z" LQuadratic Field with defining polynomial $.1^2 + 5 over the Rational Field7 Z7 g# j1 U% S/ A
    Univariate Polynomial Ring in w over Q5. b7 [+ O: _% a% Q; F2 h
    Equation Order of conductor 1 in Q58 G% m# k6 V6 e" n& {8 X
    Maximal Equation Order of Q5" R5 S8 i/ _4 a/ a9 G
    Quadratic Field with defining polynomial $.1^2 + 5 over the Rational Field' v& y9 V0 u/ y4 @, j/ K& _7 ^
    Order of conductor 625888888 in Q5% s- c0 m. g7 v" D* l; ?
    true Quadratic Field with defining polynomial $.1^2 + 5 over the Rational Field
    ' e  m9 w# T. `. H: {true Maximal Equation Order of Q5: U  X1 Z2 J2 R( M
    true Order of conductor 1 in Q5  r# n( W6 I3 \1 q
    true Order of conductor 1 in Q5) d  `0 Z/ p" \+ _+ W  d
    true Order of conductor 1 in Q5
    / ?' C3 r, _) n/ h8 Z- m0 g# V[/ i3 e* h6 K! |4 k$ L
        <w - Q5.1, 1>,0 J5 `; T! d) n1 e
        <w + Q5.1, 1>
    6 e+ E% C: {0 k]) `* D) k% R, e# A4 k  H. B
    -203 q; S% y7 c5 S7 I' t
    9 `2 s( n( l% B' V, K8 G1 C
    >> FundamentalUnit(Q5) ;9 N0 c: C- A/ |0 R& P
                      ^
    , E( t. ~2 a$ E, U8 ~9 ]Runtime error in 'FundamentalUnit': Field must have positive discriminant
    9 F- g$ g" |/ Q5 T: [2 p! t: _0 B/ y  p; J9 d+ @. z7 y  h0 \

    6 P$ B% V+ z, a' w/ _: A>> FundamentalUnit(M);: z' O! F( {: @1 h( O- I
                      ^
    ' ]/ E1 {5 h' @Runtime error in 'FundamentalUnit': Field must have positive discriminant
    2 ]7 k. V8 P% B1 [3 \  W0 m: W* \3 ]  X7 M
    20
    ( T  r% S- [. c* Y* _9 T
    / p! V4 e9 J( U) \6 ~# v) L- h8 B>> Name(M, -5);5 K2 S- @: ~+ }6 u! y2 O
           ^3 A* F+ Y% ~0 [4 C# u8 ~
    Runtime error in 'Name': Argument 2 (-5) should be in the range [1 .. 1]
    % W8 A4 w% z1 p% {3 m6 E- U3 O1 m8 w8 |+ ~
    18 H$ f! Y# E  K. A  O" ^
    Abelian Group isomorphic to Z/2
    4 ^/ ]4 v% @: V7 u0 v# sDefined on 1 generator
    0 `2 c0 W0 [, @Relations:& l4 A  ?" g- D/ p
        2*$.1 = 0& B% B8 y( ~. p! d5 r' D9 d# @
    Mapping from: Abelian Group isomorphic to Z/2
    , P: o1 T4 I8 M5 j( @  h% @Defined on 1 generator* t/ a) Y+ ~6 O: J, _; {
    Relations:$ a1 s. t1 d0 c: i: C
        2*$.1 = 0 to Set of ideals of M! c; g: d) C2 O* f
    Abelian Group isomorphic to Z/2
    ( @' ]0 G5 o) L4 p( k8 y! f* WDefined on 1 generator+ j; x) T: |/ u* P' A% E
    Relations:9 O& ~  H( J9 D! _( g
        2*$.1 = 0
    - m) b6 K! x% g4 b" }8 V( iMapping from: Abelian Group isomorphic to Z/2
    / e- ]5 F' E. q  P$ x" i5 ~Defined on 1 generator  L! }0 O# F) ?/ ~7 ~
    Relations:* K; Z, [. s6 a' r2 d. e
        2*$.1 = 0 to Set of ideals of M
    4 q8 A) m- q8 U' l- m2 ]2; k' ^% {& R- ~+ I1 B+ E" `) Y) p
    2  w8 n; C* U% _2 q
    Abelian Group isomorphic to Z/2" M4 Z; B# @& Y1 C9 x
    Defined on 1 generator; Z" E+ b2 s5 v$ b7 a% a0 g% R
    Relations:
    & i+ O& n" ~) J    2*$.1 = 0
    ! M7 B1 y3 Z8 ]1 QMapping from: Abelian Group isomorphic to Z/2
    . Q8 [% h6 J+ z! u  nDefined on 1 generator* ]. S' P6 K1 Y( u" q& C6 a
    Relations:
    8 I. I0 V* U6 U' |    2*$.1 = 0 to Set of ideals of M given by a rule [no inverse]; ~5 A% T, T- G' m  o
    2" U* ~& K- X; r# c# q; X4 x: i' h
    Abelian Group isomorphic to Z/2, `# E. L7 D" T. o" q# q* Y5 ?4 F: @
    Defined on 1 generator& G' T- P8 c7 N) O1 v! ?
    Relations:# t7 q$ X: h3 X' }/ a
        2*$.1 = 02 V+ F; ?# y. U3 |
    Mapping from: Abelian Group isomorphic to Z/2" h5 d; ?$ v, ^0 ^; s
    Defined on 1 generator6 M5 E: f$ a( D) I( \
    Relations:9 x# W4 T% o  u- x
        2*$.1 = 0 to Binary quadratic forms of discriminant -20 given by a rule [no 5 B$ K8 ~. g6 o' t
    inverse]: J: f# M& N5 q1 Z/ r' k
    Abelian Group isomorphic to Z/2* s' K' J$ a$ x+ n, G
    Defined on 1 generator6 [% t, \7 K+ V5 y/ G
    Relations:
    " [' \. ]6 d' H# ?- W5 D! Z% F    2*$.1 = 0( P& Q4 D" a7 v
    Mapping from: Abelian Group isomorphic to Z/24 G+ V7 }; n( B" l+ L; O. [
    Defined on 1 generator
    # K, T2 y  b5 y0 Q' Z0 o; k* eRelations:
    # ~- J8 B# a: R7 _6 t9 S( N    2*$.1 = 0 to Binary quadratic forms of discriminant -20 given by a rule [no
      A* S( p3 _/ k/ h' Rinverse]2 n) U) l2 ^5 a# f! [1 K
    false3 k4 k: k8 N7 ]' @
    false, o8 T; U2 Q- o4 i3 m
    ==============. W: K: D7 L7 A( z- k# P3 K4 e9 s0 r5 P
    ) d, P9 I" x: u7 l' I6 o7 F' {

    + l& ^; y  D+ Z' d" eQ5:=QuadraticField(-50) ;
    # S; A% c$ {+ K7 {7 q) F3 V/ KQ5;
    ' B9 x5 A7 Z9 |& i( I% F3 {2 R
    + `( i' P& s" {$ qQ<w> :=PolynomialRing(Q5);Q;+ z9 J2 Y5 g# q- C6 \% X7 a3 e
    EquationOrder(Q5);
    9 M! Y) \8 b) T4 @M:=MaximalOrder(Q5) ;
    ( `$ i- z/ {9 y& f3 s$ jM;" g4 U  \: X7 X6 \
    NumberField(M);
      X9 j/ B. U# @0 f- E) kS1:=sub< M | 1 >;S2:=sub< M | 2 >;S3:=sub< M | 3 >;S4:=sub< M | 4 >;S5:=sub< M | 5 >;S25:=sub< M | 25 >;S625888888:=sub< M | 625888888 >;S625888888;
    9 i! Y- ]  A7 lIsQuadratic(Q5);1 T3 i- c4 A9 n' s) k
    IsQuadratic(S1);( K, s/ t6 i7 c9 N6 q2 h
    IsQuadratic(S4);3 U/ h+ K3 u& L- r; W  E1 U/ y. k  Q
    IsQuadratic(S25);5 h, d: W* E9 P& a; u! k
    IsQuadratic(S625888888);6 h" r! [+ t8 f
    Factorization(w^2+50);  
    ! r1 J5 Z0 z: sDiscriminant(Q5) ;
    ! P& g( ?( S) _3 G2 [FundamentalUnit(Q5) ;
    - h5 W8 H/ a. i8 lFundamentalUnit(M);" x! d# Z& `5 i& V: l9 f
    Conductor(Q5) ;
    8 b" q3 a1 \2 H- k1 {5 s1 U
    % n4 r" T& g5 O; dName(M, -50);
    0 l* }" D( w3 |! n- c+ X9 EConductor(M);6 ^6 U( q2 e/ {4 w9 _0 t
    ClassGroup(Q5) ; + T" e3 W, {, M# Z  @0 w5 Z
    ClassGroup(M);
    0 \( T( k/ p3 @; I7 E5 `ClassNumber(Q5) ;
    & n. v# w5 `% B" j% b5 E, kClassNumber(M) ;  x* `' a5 g+ d
    PicardGroup(M) ;/ K1 {$ J1 T/ Z8 e5 g
    PicardNumber(M) ;4 ~# [7 x, u  W6 E% p& B

    ; `6 K6 s- d! l3 N, t9 `2 g, fQuadraticClassGroupTwoPart(Q5);
    , I/ A. V% T% C0 z& UQuadraticClassGroupTwoPart(M);# h6 H/ \& G3 C1 J( Z) b
    NormEquation(Q5, -50) ;
    " P- m1 G' h! U0 Y( X  q- _' ^NormEquation(M, -50) ;
    ' G, q3 y: h( w$ ]& ^: x% v
    ) ?/ K, G( i6 W) sQuadratic Field with defining polynomial $.1^2 + 2 over the Rational Field
      S8 E; j/ e0 T2 FUnivariate Polynomial Ring in w over Q5
    ) t# \* e* F5 V- t8 ?Equation Order of conductor 1 in Q5: ^9 X; h# {% V2 x! u3 d" }
    Maximal Equation Order of Q53 ]5 w% I" ?3 b1 P
    Quadratic Field with defining polynomial $.1^2 + 2 over the Rational Field+ p+ d4 A0 e# _- b
    Order of conductor 625888888 in Q5
    & [! `+ W! o# {0 P; jtrue Quadratic Field with defining polynomial $.1^2 + 2 over the Rational Field
    " J8 a( P1 B8 d& D1 ktrue Maximal Equation Order of Q5
    # e( R' |& j+ {; L& Z& K- Atrue Order of conductor 1 in Q5* Y: i4 p% o0 b% r: H
    true Order of conductor 1 in Q50 M; s; _% i. {9 ~! C* Y
    true Order of conductor 1 in Q5
    : u* M- |  N& d[
    / Z& j8 \: Y6 j- R; f$ C- \9 t    <w - 5*Q5.1, 1>,
    7 S5 X) @8 G! ^# ?& e9 A* w    <w + 5*Q5.1, 1>
    ; }9 T) s! \1 J! K0 P4 B% \6 X]! o- E& v+ g% ]' C8 e8 z
    -8
    + |1 @9 `& ?3 G: X0 {4 v9 j& Q/ @7 e8 ?
    >> FundamentalUnit(Q5) ;2 P* H: f; K7 A( S9 L9 C, B0 N" N
                      ^9 \! z6 M7 @, {9 E& {; r) R
    Runtime error in 'FundamentalUnit': Field must have positive discriminant
    % }! T' f- z) F2 Y
      }9 J  I4 D' f7 s/ M
    . ~: K( e& v1 y* D8 Z+ G' M6 b>> FundamentalUnit(M);$ f+ c8 T: M, t& m5 \
                      ^
    ) L$ D0 U6 k" z) u, X' jRuntime error in 'FundamentalUnit': Field must have positive discriminant0 H' J  u% F" \1 s4 e

    ) i# f+ }/ z% l! v3 F6 E/ U0 ]82 @% s9 O) D$ W2 Y! G

    . P& N+ ]9 I2 d% d* a>> Name(M, -50);
    3 j3 C- G, q2 Y! X; {       ^8 n/ u, D/ A0 t: W! E
    Runtime error in 'Name': Argument 2 (-50) should be in the range [1 .. 1]$ d- b4 A  @; q6 i! p) ~8 j+ |

    & C9 F0 p# X) ?, N% `8 Z1
    5 a) J5 ?/ m/ S5 y! DAbelian Group of order 1' J0 x9 W$ @4 e/ G  v. P
    Mapping from: Abelian Group of order 1 to Set of ideals of M
    / x; R; f. X+ W: @, FAbelian Group of order 1& P# D9 R6 L; u' a
    Mapping from: Abelian Group of order 1 to Set of ideals of M0 _  b" F2 Z, Q* D
    1. j# W; E1 B& \+ v
    1  Z" f, `$ X0 w% `
    Abelian Group of order 16 J3 F* D5 m) v5 o6 x% o
    Mapping from: Abelian Group of order 1 to Set of ideals of M given by a rule [no- E, w. C; l% r5 y8 G& [& p% R+ I
    inverse]' s2 w# h& D& ?* L; K4 ~- Y
    12 ?- i( u4 x- k, q5 [( Z
    Abelian Group of order 1
    % v2 P, |! ~! x0 {: yMapping from: Abelian Group of order 1 to Binary quadratic forms of discriminant" A! \4 ^; |" ]5 H  e+ S" z
    -8 given by a rule [no inverse]; @8 s' u3 h* T# E& d
    Abelian Group of order 1
    - l1 {1 _; w: S8 ?/ {Mapping from: Abelian Group of order 1 to Binary quadratic forms of discriminant/ q4 Z3 ^+ k' e* R% Z5 c2 D# g
    -8 given by a rule [no inverse]
    6 X) i- F" ]! {9 n7 xfalse' i% O+ V& \/ E
    false
    * Y( e" d& m( o5 u% b
    zan
    转播转播0 分享淘帖0 分享分享0 收藏收藏0 支持支持0 反对反对0 微信微信
    lilianjie        

    43

    主题

    4

    听众

    204

    积分

    升级  52%

  • TA的每日心情
    开心
    2012-1-13 11:05
  • 签到天数: 15 天

    [LV.4]偶尔看看III

    看看-1.-3的两种:8 q- i4 ~' [: K; o2 E+ C3 T. I
    * b; M5 G, C, S3 ?& @9 c6 n
    Q5:=QuadraticField(-1) ;8 i5 A' i. T/ f4 K! K# J
    Q5;: l' ~$ l- F% a" F
    ; t) Z+ X/ A& ~) p, r5 I; k
    Q<w> :=PolynomialRing(Q5);Q;' }2 A0 F- A$ O$ S( h4 R
    EquationOrder(Q5);* U5 k4 x4 w: v$ e/ H2 }; t8 Y& G
    M:=MaximalOrder(Q5) ;  X4 l9 V; J6 }$ H
    M;# J, ?7 A# I$ B. Z$ ~6 O
    NumberField(M);" x" q, o% e5 ~! r3 Y: V( b0 u
    S1:=sub< M | 1 >;S2:=sub< M | 2 >;S3:=sub< M | 3 >;S4:=sub< M | 4 >;S5:=sub< M | 5 >;S25:=sub< M | 25 >;S625888888:=sub< M | 625888888 >;S625888888;
    / {5 h) a2 p- F$ h  X* [IsQuadratic(Q5);
    8 L2 M9 Q4 C8 M3 r+ i# uIsQuadratic(S1);1 {# Z: H6 ^$ B7 ]9 i3 }
    IsQuadratic(S4);; n. O, a, k, V, t, Y
    IsQuadratic(S25);( @: C' e2 |4 U; v/ f, s9 c% N& W
    IsQuadratic(S625888888);" [2 S, ]: G2 Y
    Factorization(w^2+1);  
    - [5 @$ X! q% ]Discriminant(Q5) ;
    0 O6 [' K& E. q) l0 u  @FundamentalUnit(Q5) ;7 O* X; z- _) y3 x
    FundamentalUnit(M);
    , ]+ M8 P) ?% A# ~) }- QConductor(Q5) ;
    0 }$ N% g+ K7 u  f/ a1 z& g4 h" w- X- A: g" @, z+ R
    Name(M, -1);! _9 ?  D4 g. ^' `8 d
    Conductor(M);6 b. e, V) [+ j
    ClassGroup(Q5) ;
    ! d( ]% B0 ?* {, e1 y0 _( \& PClassGroup(M);! w3 X; @. E+ a: Z# t
    ClassNumber(Q5) ;" W/ j' b+ T1 L
    ClassNumber(M) ;
    8 P4 w. j- v0 X4 D- OPicardGroup(M) ;0 C* a5 L/ s: Y3 S3 s2 V
    PicardNumber(M) ;7 U# I  u8 w, Z% U; ?7 g

      M4 S# U+ \+ ]' tQuadraticClassGroupTwoPart(Q5);
    ; n# a+ P0 t" q4 CQuadraticClassGroupTwoPart(M);
    - K2 J! w# v/ ]( w% L% t7 t& GNormEquation(Q5, -1) ;% ]8 @& Z% @) k  |+ L
    NormEquation(M, -1) ;- y/ e0 e8 {8 z% C" a
    8 W0 _+ M' I+ X- u
    Quadratic Field with defining polynomial $.1^2 + 1 over the Rational Field
    " @' o- {  n" V- v9 [) k$ IUnivariate Polynomial Ring in w over Q5
    6 T; }* l2 m& r) q2 LEquation Order of conductor 1 in Q5# P6 z# }: x; V1 j
    Maximal Equation Order of Q59 l0 p1 y' L* s( R  M
    Quadratic Field with defining polynomial $.1^2 + 1 over the Rational Field
    ( x* t& E; |& r5 U. zOrder of conductor 625888888 in Q5- a# K  m* c- L, r8 ~
    true Quadratic Field with defining polynomial $.1^2 + 1 over the Rational Field
    % E- j& [" z' L" P7 f& e4 J3 x, ftrue Maximal Equation Order of Q5
    8 ?: [4 v. c0 p" n% Itrue Order of conductor 1 in Q5
    ( x* ~$ y4 ^; F' [5 ltrue Order of conductor 1 in Q5
    2 A' G7 @. Z' o- `& b6 ltrue Order of conductor 1 in Q5
    ) X2 l7 R( F( {% |- G6 O! q[
    2 |3 H8 S6 e& G7 _; P& M    <w - Q5.1, 1>,
    ! C7 K# x' @( @1 k    <w + Q5.1, 1>+ k# j1 U' ]* k. Y8 j
    ]
    8 Z9 ]* L) n$ W2 H5 @5 d-4
    / g4 n: B, D9 u  _
    * U* D* c$ K' e+ K' J; K>> FundamentalUnit(Q5) ;/ o) Q0 l6 W! g; V6 k
                      ^
    0 s5 n6 W! j3 P, T# bRuntime error in 'FundamentalUnit': Field must have positive discriminant
    6 S8 c; P, _5 |7 F8 p* y4 \- f& L( y1 U- U" b$ f4 `

    ( v& r7 B+ y+ i% U6 G6 z; Z* p9 {>> FundamentalUnit(M);- X* V$ B: e' k- `2 f
                      ^1 p  X4 y% B3 |0 P
    Runtime error in 'FundamentalUnit': Field must have positive discriminant
    3 e, U& L2 u5 q6 a0 c3 @2 [2 N* k: Y& K* [. [
    4
    9 X2 w2 n4 L! n* [* n6 T
    ( f7 y" i6 M: d+ I>> Name(M, -1);" U3 ^3 c  ]) Z4 k$ O
           ^
    & |. e- r! y, nRuntime error in 'Name': Argument 2 (-1) should be in the range [1 .. 1]
    & `+ A8 p7 v7 ^: O& ]6 a* Y- C2 V+ ]" X8 N
    1
    % N7 T# `/ {! f0 {4 f+ VAbelian Group of order 13 n$ m3 @* M/ A1 R
    Mapping from: Abelian Group of order 1 to Set of ideals of M- @' f7 @: M- O; \, L4 n$ V, r. X8 L) m
    Abelian Group of order 1/ n3 Z4 m( z; y$ l
    Mapping from: Abelian Group of order 1 to Set of ideals of M
    3 H7 l8 _+ x  ]0 v- n. G" g# [$ d2 q1; ?0 G6 a- e/ L0 y/ R2 W7 z
    18 n% C* X1 h0 R3 W
    Abelian Group of order 1; n3 g% X. W5 T' U0 k  z
    Mapping from: Abelian Group of order 1 to Set of ideals of M given by a rule [no
    ( _. k$ q. M2 P9 G5 y2 b5 r( iinverse]2 `+ T" U4 q/ Y, i
    1
    ) w+ E3 w( A3 H6 LAbelian Group of order 19 n0 r& V4 i$ D5 L( T: m- r( I
    Mapping from: Abelian Group of order 1 to Binary quadratic forms of discriminant, R" D$ k  S4 p
    -4 given by a rule [no inverse]* ]. s; m: ]( |: G$ i
    Abelian Group of order 1; s6 n( g/ ^# `& s+ S3 E' N: V! X2 F
    Mapping from: Abelian Group of order 1 to Binary quadratic forms of discriminant
    8 i& R+ _5 t& n$ Q( V5 w-4 given by a rule [no inverse]
    5 `2 j! Y" j" j/ S2 \false* O  p8 C8 Q8 R* v8 z; b2 L3 I6 r
    false6 p# u/ g4 d* G8 [* g- k9 d% |% N
    ===============
    / \1 P: r9 s  e3 L! G
    ) p) o. I! d) P3 m* EQ5:=QuadraticField(-3) ;
    6 g- o9 V4 u  q3 ?9 {% y6 }Q5;
    6 D0 d3 a  I! N5 u, ]  z+ K
    , }  d$ H9 W" ?* \* y' \Q<w> :=PolynomialRing(Q5);Q;
    ! {4 e. a, \1 _* f; ?$ S6 SEquationOrder(Q5);4 n+ q2 N2 e+ H& d5 e- b; {
    M:=MaximalOrder(Q5) ;% V+ k: u# F* `/ q+ T. |/ d
    M;: f4 I: U$ w( X/ b( \
    NumberField(M);# Z" L0 `# n7 y# I7 k0 N
    S1:=sub< M | 1 >;S2:=sub< M | 2 >;S3:=sub< M | 3 >;S4:=sub< M | 4 >;S5:=sub< M | 5 >;S25:=sub< M | 25 >;S625888888:=sub< M | 625888888 >;S625888888;* n# c. Q6 `$ x4 c3 j
    IsQuadratic(Q5);
    ' i0 v' N9 e% t: n# DIsQuadratic(S1);
    : ]/ x. R1 Y5 F& XIsQuadratic(S4);+ M" s2 K5 F( K1 G% \. W
    IsQuadratic(S25);
    1 u- m0 S8 A; E0 C* wIsQuadratic(S625888888);4 j; P& d+ y# A  q
    Factorization(w^2+3);  
    ' b. R# ~/ b2 L: |+ p' `Discriminant(Q5) ;
    ( e+ {6 }9 z) DFundamentalUnit(Q5) ;) ~& ]4 M! o& X  D6 Z$ {5 [) t
    FundamentalUnit(M);
    6 D: G, m$ n. l9 K: KConductor(Q5) ;
    " U& k6 ~% C* @/ X. d; z1 Q1 {  O2 ?8 O* m! x! E
    Name(M, -3);
    9 f5 f" L' X4 I+ p  j" @3 vConductor(M);* C, h; v, p# ^1 M" m: p
    ClassGroup(Q5) ; 0 f. l( t- t1 A1 d  _: O: g( B# C% e! N
    ClassGroup(M);/ `$ A  ]: A" k% t( ~
    ClassNumber(Q5) ;
    $ i3 @7 H& P& m1 t' @% rClassNumber(M) ;8 E( g. F+ \8 L; ?
    PicardGroup(M) ;( s& x9 ]* D; Y, U
    PicardNumber(M) ;% z" `5 u# ]& o, S

    5 u2 H0 q' e8 l+ Q8 B9 U- mQuadraticClassGroupTwoPart(Q5);& e$ h, ~& I( Y  u% N5 G
    QuadraticClassGroupTwoPart(M);
      f/ s7 G) }4 GNormEquation(Q5, -3) ;
    0 b4 b6 p$ z4 }NormEquation(M, -3) ;
    2 x2 x1 E0 T& w% H
    6 I, u. P5 w3 K" j. NQuadratic Field with defining polynomial $.1^2 + 3 over the Rational Field
    1 d, X, r% w+ c8 jUnivariate Polynomial Ring in w over Q5
    ! c1 E. Q  o1 |( O" d3 X/ r, pEquation Order of conductor 2 in Q5
    0 u& N6 R3 W2 X. D; f; W: B; RMaximal Order of Q5( G& f/ a0 d' u+ B2 J
    Quadratic Field with defining polynomial $.1^2 + 3 over the Rational Field, E- n8 w' F; J. p+ x& g
    Order of conductor 625888888 in Q54 @7 L5 T/ h: W
    true Quadratic Field with defining polynomial $.1^2 + 3 over the Rational Field+ G0 E, h% W% J' R: b
    true Maximal Order of Q5
    # u6 l( y3 L9 a- ^true Order of conductor 16 in Q5
    + t3 \# \( a0 ], m- A% ]. R/ Mtrue Order of conductor 625 in Q5
    ( r' c% w, X; c% E2 Ytrue Order of conductor 391736900121876544 in Q5, V2 A) B0 M, ~, S$ m
    [5 ]" v- Z; F/ {: r6 Y2 }
        <w - Q5.1, 1>,
    7 }- a3 u# q$ m! n    <w + Q5.1, 1>
    $ N. U; W! q4 y+ G5 K2 t]7 h* `) K( J( I7 K7 G
    -3
    ' h! S$ w/ L* Z% L; k, A) n% J: }7 {
    ; |( P4 U7 d* x% F>> FundamentalUnit(Q5) ;8 f6 z- A! Y  [; h, k- c1 t
                      ^5 w0 P1 t/ g1 A  ?% h. \
    Runtime error in 'FundamentalUnit': Field must have positive discriminant
    5 t9 ~2 ~: Y. T  O" _) w! a# i6 t' k  {2 @$ U$ m, d  B$ a" D
    9 V1 C; Z1 f5 A: d6 \# Z7 }
    >> FundamentalUnit(M);
    " D# z1 U' M5 u* n9 {                  ^! ^3 M  G9 D7 s# A) r. u& \
    Runtime error in 'FundamentalUnit': Field must have positive discriminant- d; o- U) ^9 Y% t* e

    * `2 O- K0 R# S! ]3/ D# S' g( t2 o; j9 o( X8 ~
    * j0 o: f; g0 F5 p2 `) c
    >> Name(M, -3);
    7 D% K7 ~8 d- U3 o" ?+ \" N; T% n       ^
    " V( i6 k9 v* {Runtime error in 'Name': Argument 2 (-3) should be in the range [1 .. 1]( I$ ?+ W* C# s1 i7 W( K+ [! t
    8 i7 ]& H/ v/ r4 \6 B
    1$ G  W, b' K3 a& k1 t: B
    Abelian Group of order 1
    - h& t/ o8 z8 x. `& vMapping from: Abelian Group of order 1 to Set of ideals of M6 u% F! z" x! P0 {+ X; Q
    Abelian Group of order 17 Y* a& m" A4 F
    Mapping from: Abelian Group of order 1 to Set of ideals of M  c9 G( Y7 y. G- b2 v$ Y" }4 u
    1
    : v+ I* @9 ~3 y) T1 b1
    8 d2 Q0 f  x8 }3 r, c: [1 h/ gAbelian Group of order 1
    & \9 ~$ M3 b0 YMapping from: Abelian Group of order 1 to Set of ideals of M given by a rule [no
    ( n# c4 B' m! l4 I$ ]inverse]
    9 Y* y: L' U# ^+ M) a1
    3 _% ~+ Q0 l( [- J6 ]% d4 f7 xAbelian Group of order 1+ d2 U9 [' m1 G6 U5 H$ J9 ]
    Mapping from: Abelian Group of order 1 to Binary quadratic forms of discriminant
    " a6 n$ Q: P) u9 G- J4 D; k7 k-3 given by a rule [no inverse]
    3 ]7 J8 q( T; w1 }Abelian Group of order 1
    ( C: T/ R* R9 X, t0 T6 V' E( ~Mapping from: Abelian Group of order 1 to Binary quadratic forms of discriminant
    ! H% c) G( U/ H2 ?% Q, Y, B. H-3 given by a rule [no inverse]
    1 u. s; L8 t' L1 n) Tfalse
    + W! o3 r9 j0 q4 {9 pfalse
    回复

    使用道具 举报

    74

    主题

    6

    听众

    3303

    积分

    升级  43.43%

  • TA的每日心情
    无聊
    2015-9-4 00:52
  • 签到天数: 374 天

    [LV.9]以坛为家II

    社区QQ达人 邮箱绑定达人 发帖功臣 最具活力勋章

    群组数学建摸协会

    群组Matlab讨论组

    群组小草的客厅

    群组数学建模

    群组LINGO

    回复

    使用道具 举报

    lilianjie        

    43

    主题

    4

    听众

    204

    积分

    升级  52%

  • TA的每日心情
    开心
    2012-1-13 11:05
  • 签到天数: 15 天

    [LV.4]偶尔看看III

    本帖最后由 lilianjie 于 2012-1-5 15:20 编辑
      f- a& x, H5 ^$ J$ X3 c0 m5 F
      z6 a' l- s) Z# pDirichlet character
    ( `: U  [% f0 aDirichlet class number formula. w0 e3 \3 w7 k% s' i" z4 N) w
    3 V- T& x! s  R$ C
    虚二次域复点1,实点为0,实二次域复点0,实点为2,实二次域只有两单位根" A$ h/ n0 t5 j& P

    - E- D# K9 P4 [# k% ]# T5 C-1时,4个单位根1,-1, i, -i,w=4,            N=4,互素(1,3),    (Z/4Z)*------->C*      χ(1mod4)=1,χ(3mod4)=-1,h=4/(2*4)*Σ[1*1+(3*(-1)]=1
    8 C4 x1 f7 L( Z/ N6 |: t: R$ b# c2 Y6 a* r6 C0 |/ x, k. W
    -3时  6个单位根                             N=3  互素(1,2),    (Z/3Z)*------->C*         χ(1mod3)=1,χ(2mod3)=-1,
    ) c  s  E1 E4 s2 J6 Y) A/ wh=-6/(2*3)*Σ[1*1+(2*(-1)]=1) ^) c# H' l% k+ A2 Z
    6 K: e$ u* u4 ~5 o0 P: [
    -5时  2个单位根                              N=20   N=3  互素(1,3,7,9,11,13,17,19),    (Z/5Z)*------->C*         χ(1mod20)=1,χ(3mod20)=-1, χ(7mod20)=1, χ(9mod20)=1,χ(11mod20)=1,χ(13mod20)=1,χ(17mod20)=1,χ(19mod20)=1,) v3 b; S! _+ G( c$ N- y: @, [

    ! [) c4 N' t, X! g7 S" Q  N
    8 g7 |* O5 v" w) k
    1 j. L$ d# B% e( R# Bh=2/(2*20)*Σ[1*1-3*1-7*1+9*1-11*1-13*1+17*1+19*1]=2
    1 V: B* w. C6 d6 Y! _0 m1 q9 B( @% O, B$ `% |: h  w8 I7 c6 k
    6 L% q9 Y4 S: A- M5 e
    ; t9 b; `& Y2 H, M
    -50时  个单位根                          N=200; ^" h& W; j' c6 i
    回复

    使用道具 举报

    15

    主题

    4

    听众

    113

    积分

    升级  6.5%

  • TA的每日心情
    开心
    2012-1-13 11:49
  • 签到天数: 9 天

    [LV.3]偶尔看看II

    Dirichlet character

    21.JPG (79.18 KB, 下载次数: 266)

    21.JPG

    11.JPG (74.76 KB, 下载次数: 270)

    11.JPG

    回复

    使用道具 举报

    15

    主题

    4

    听众

    113

    积分

    升级  6.5%

  • TA的每日心情
    开心
    2012-1-13 11:49
  • 签到天数: 9 天

    [LV.3]偶尔看看II

    回复

    使用道具 举报

    lilianjie        

    43

    主题

    4

    听众

    204

    积分

    升级  52%

  • TA的每日心情
    开心
    2012-1-13 11:05
  • 签到天数: 15 天

    [LV.4]偶尔看看III

    本帖最后由 lilianjie 于 2012-1-9 20:30 编辑
    8 ]) o; M) X" n( B1 V' f& ~3 }  Q0 s" J; Q/ a  W3 O0 d- R' L9 p/ y
    F := QuadraticField(NextPrime(5));
    ! ~9 v& w, {: P9 ]) B% O. w# H- ^3 e% C. z, b5 E% J0 B4 p- U2 z. s
    KK := QuadraticField(7);KK;
    . ]. \3 k3 F. o2 DK:=MaximalOrder(KK);
    % T3 A; B. F$ [" IConductor(KK);
      |. D8 Y1 \, A' hClassGroup(KK) ;
    * b+ x; L2 k6 A2 ~/ h' |QuadraticClassGroupTwoPart(KK) ;
    + y0 z9 h8 J* z) ?4 ?NormEquation(F, 7);* X" v! L8 s) I  o- p: K
    A:=K!7;A;
    * W, H2 B. Y) QB:=K!14;B;
    ) E! }; [& d$ K8 y% MDiscriminant(KK)/ k3 ^. \, u2 I; N0 W3 B- \

    % o5 {) R' E4 v5 S. N2 vQuadratic Field with defining polynomial $.1^2 - 7 over the Rational Field$ [7 K, X2 L" m5 o, p2 e' Y
    28
      J% _9 [7 X& ^Abelian Group of order 1& S8 F8 v# I# F9 U, S- W
    Mapping from: Abelian Group of order 1 to Set of ideals of K
    . |, z% r6 _. D* y* ^Abelian Group isomorphic to Z/22 f7 B( l; L7 k8 ?. k0 \
    Defined on 1 generator7 g6 ?+ z- C/ c( t# l
    Relations:
    4 P  q3 ^7 L6 o: f" O/ W    2*$.1 = 0' k: z# y/ H9 C- Q
    Mapping from: Abelian Group isomorphic to Z/2
    . S7 M$ ~. Z  o, qDefined on 1 generator
    6 A& C6 _+ }+ U! L$ ?Relations:! G( J* v! o) U9 ]
        2*$.1 = 0 to Binary quadratic forms of discriminant 28 given by a rule [no
    6 z; p$ Q- d% b$ o5 ]6 W  Y6 e; o- Sinverse]3 N, j8 t+ T2 S
    false! }$ q, ?( L+ K% |& q% \* F
    7$ Q5 Y4 t0 Z8 F6 W9 q
    14
    8 c" l& V2 a. z1 z. ^# x28
    回复

    使用道具 举报

    lilianjie        

    43

    主题

    4

    听众

    204

    积分

    升级  52%

  • TA的每日心情
    开心
    2012-1-13 11:05
  • 签到天数: 15 天

    [LV.4]偶尔看看III

    本帖最后由 lilianjie 于 2012-1-10 11:23 编辑
    8 @, c; o4 q- `* {; U
    9 R$ v; e$ U" Y4 W! _+ m; ?& D 11.JPG   J& W$ ?8 M" b5 J$ f" w
    7 t  h3 S$ \: S: Y4 c2 ^! b* N
    3212.JPG
    8 x0 \/ b9 ~- N
    3 D  c; K* e4 m8 X3 X9 n 123.JPG
    + ~7 `( H" {; }: m5 Y2 H& w; X1 f+ r. c- s  D
    分圆域:
    6 q+ g# @* k3 T6 W9 XC:=CyclotomicField(5);C;
    & p* M8 G+ ?, s0 h" fCyclotomicPolynomial(5);2 ?( [" y$ }9 Q) R5 ?8 z8 N
    C:=CyclotomicField(6);C;6 A& ~: k2 g% y/ v) J$ h
    CyclotomicPolynomial(6);
    + d& {6 N/ t' n% n: k5 u. hCC:=CyclotomicField(7);CC;
    ) \# Q+ [# X" jCyclotomicPolynomial(7);- R/ U3 ]$ g, t9 q
    MinimalField(CC!7) ;8 U2 Y  Z$ u( O; ]* ^+ Y5 D
    MinimalField(CC!8) ;
    ; b7 \9 Q7 \( s' F. sMinimalField(CC!9) ;/ o  Q4 o0 ~9 k6 n
    MinimalCyclotomicField(CC!7) ;
    - H$ K3 m( P' v3 z; _, v# g3 H2 zRootOfUnity(11);RootOfUnity(111);
    * z) s+ u! C8 F+ r$ A( |3 mMinimise(CC!123);. v5 n2 ^+ Q2 B5 D- A4 y
    Conductor(CC) ;5 e0 R: l2 H* s! i& i$ \) e
    CyclotomicOrder(CC) ;: V0 h+ S3 ?6 R4 V8 Z

    ! ^  S: E/ k( e# _  B# iCyclotomicAutomorphismGroup(CC) ;6 X+ B: `- I" D: o
    * A3 A7 {$ Y6 s  Y
    Cyclotomic Field of order 5 and degree 4* V7 f6 a$ f5 r, }1 H% y0 Y
    $.1^4 + $.1^3 + $.1^2 + $.1 + 1- k4 W' s3 b" X: F$ A) t' D
    Cyclotomic Field of order 6 and degree 27 n% H  a' V9 p+ F, H% ?
    $.1^2 - $.1 + 1
    - w7 m, z& g0 D% D. kCyclotomic Field of order 7 and degree 67 _7 t5 V# o( K8 X! R  e0 ~
    $.1^6 + $.1^5 + $.1^4 + $.1^3 + $.1^2 + $.1 + 1
    5 _/ a  a0 a* u% e+ [0 SRational Field  q2 w5 d" x) ?: `! i8 k
    Rational Field
    : j  d+ U( C; H+ hRational Field
      R1 I! V+ G, nRational Field
    1 _- I2 P, z( w. V+ m8 ^7 l) ozeta_11
    8 q3 G2 ^5 y2 qzeta_111
    , X- p7 @0 a9 x$ ]8 x& i123
    ( o0 I* N' N7 Q# ~3 ?8 u4 G7
    ( C1 y* I) Y5 v) b$ P1 w7
      P1 O+ q7 j8 S- F. Q' EPermutation group acting on a set of cardinality 69 W. K' K, {& g- h* X4 C0 U8 v
    Order = 6 = 2 * 3
    : W! b& h. f4 \& Y    (1, 2)(3, 5)(4, 6)6 u6 o" Z: {" f5 y, F
        (1, 3, 6, 2, 5, 4)" D8 [: [/ R5 h' N
    Mapping from: GrpPerm: $, Degree 6, Order 2 * 3 to Set of all automorphisms of
    ( \* r! Z, i% V% s1 A, j9 D* zCC: U9 w) u; C* \2 |2 K
    Composition of Mapping from: GrpPerm: $, Degree 6, Order 2 * 3 to GrpPerm: $,
    ; {7 c) O, K: Y. ~& U6 |1 IDegree 6, Order 2 * 3 and
    7 \4 G$ m+ o7 K: x3 J* QMapping from: GrpPerm: $, Degree 6, Order 2 * 3 to Set of all automorphisms of 7 e: e; G% ~3 {% v! Y% v
    CC
    回复

    使用道具 举报

    lilianjie        

    43

    主题

    4

    听众

    204

    积分

    升级  52%

  • TA的每日心情
    开心
    2012-1-13 11:05
  • 签到天数: 15 天

    [LV.4]偶尔看看III

    本帖最后由 lilianjie 于 2012-1-10 17:41 编辑
    ' T  U0 w6 e' F" n
    lilianjie 发表于 2012-1-9 20:44
    5 m! w1 ]) N: X) K( Q4 x8 ~' L! x分圆域:! o0 V9 z$ ~+ P
    C:=CyclotomicField(5);C;2 O8 p! _2 F. E. a
    CyclotomicPolynomial(5);
    $ ]! j7 W9 k* v: I0 {
    9 P. r& i, ~* [/ M6 z& L+ d( B
    分圆域:
    4 c5 f7 k2 f- L* m' E, k% B分圆域:123
    - B. F0 i1 `+ c5 v: W2 I
    1 y1 Y4 J9 n; [. sR.<x> = Q[]5 j+ j. V4 l: t, }$ [, |
    F8 = factor(x^8 - 1); p- a2 s/ ]- ?
    F85 n+ Y9 `5 O9 K1 U0 y  ^: p
    $ O$ T; X: L1 F; O
    (x - 1) * (x + 1) * (x^2 + 1) * (x^4 + 1)(x - 1) * (x + 1) * (x^2 + 1) * (x^4 + 1)
    1 r" t1 {$ D. q
    & n( h) g! N+ [& o& @* a" FQ<x> := QuadraticField(8);Q;
    + f: l6 z+ p* D4 J3 g. jC:=CyclotomicField(8);C;2 s3 [4 e: b! C1 m
    FF:=CyclotomicPolynomial(8);FF;
    , v( q& t( U  E7 j  N4 M0 t: Z5 f7 c( B0 M
    F := QuadraticField(8);2 j4 |% [6 y' q* W7 f
    F;& [8 H, Z7 w% x3 N$ A
    D:=Factorization(FF) ;D;; r) a: ~5 m; j& F7 I3 T7 b3 N8 t! P
    Quadratic Field with defining polynomial $.1^2 - 2 over the Rational Field
    1 ?1 }- w1 |& |8 l3 M' @( _7 Y+ RCyclotomic Field of order 8 and degree 4
    7 b" A, E0 `1 w( _$.1^4 + 1
    + U& l4 d0 y2 Q+ b4 j0 d0 lQuadratic Field with defining polynomial $.1^2 - 2 over the Rational Field
    ! e( H  b) V/ Y/ L4 I4 G[
    * N+ w# U7 S8 ^, `8 m! a    <$.1^4 + 1, 1>
    1 ^* d, a# p6 V" R: U+ V]
    # q- Q1 i( L" Q0 ]5 ^( w3 b7 X$ m; D2 o3 H
    R.<x> = QQ[]
    - q* J, r& g; ]6 ^* r+ tF6 = factor(x^6 - 1): X% t9 R. u( k7 g3 U. r
    F6% {. B; K7 Q6 K5 s
    - Q9 Q& w' F/ X9 K
    (x - 1) * (x + 1) * (x^2 - x + 1) * (x^2 + x + 1)(x - 1) * (x + 1) * (x^2 - x + 1) * (x^2 + x + 1)
    3 b( g' a/ p9 g: o$ W8 C" k+ @8 [% F) u. F
    Q<x> := QuadraticField(6);Q;$ K) ~8 y7 D/ K6 p- l2 H! |
    C:=CyclotomicField(6);C;
      m6 L7 ^; ~. Q: p2 TFF:=CyclotomicPolynomial(6);FF;
    . x5 ?( o4 X5 U$ t
    ) X) r; I) T) |1 h  t( iF := QuadraticField(6);
    : r. c4 k+ K. o/ kF;
    $ _+ T# k$ r9 ?6 S+ L2 tD:=Factorization(FF) ;D;5 [; T, v8 g' p, K) _0 O9 ?( j
    Quadratic Field with defining polynomial $.1^2 - 6 over the Rational Field
    % R; O% k+ b) Q  nCyclotomic Field of order 6 and degree 2
    * y2 [! @2 \9 `( [5 r4 ]$.1^2 - $.1 + 1
    $ a7 Z% X( K/ M3 l, LQuadratic Field with defining polynomial $.1^2 - 6 over the Rational Field0 [/ K4 C" U! t/ m. C. q$ |
    [
    # T/ P. @% c& g% Y& H, N' _# I  w    <$.1^2 - $.1 + 1, 1>8 F7 V7 R0 E6 D6 H  l0 @
    ]
    2 I' g7 z' [& \; T% m! i$ w% Y" u  o, o+ q6 s3 t4 k6 G) ^
    R.<x> = QQ[]
    + M4 U  j4 u5 TF5 = factor(x^10 - 1)
    $ S, q! @; x2 o3 d( aF5
    9 I0 V. N: u, V7 u(x - 1) * (x + 1) * (x^4 - x^3 + x^2 - x + 1) * (x^4 + x^3 + x^2 + x +
    - q. {4 |' V; m9 Y1)(x - 1) * (x + 1) * (x^4 - x^3 + x^2 - x + 1) * (x^4 + x^3 + x^2 + x + 1)
    " z* ]  C* Z# Y. L8 j' F
    3 D$ x9 {( b+ Q- QQ<x> := QuadraticField(10);Q;1 h" y  C/ N% C
    C:=CyclotomicField(10);C;
    $ w0 x) m% `& Y" {5 l+ OFF:=CyclotomicPolynomial(10);FF;
    5 ?% Q+ I3 }: o& q* T! Q1 p- c' ?' c2 S/ |# @
    F := QuadraticField(10);( R& U0 \2 I+ T; a1 }6 m- V
    F;& ]5 K" d, `" Q- D9 F
    D:=Factorization(FF) ;D;
    ' w+ ~% Y9 Z6 P* uQuadratic Field with defining polynomial $.1^2 - 10 over the Rational Field! P, r& Y, O. I
    Cyclotomic Field of order 10 and degree 4
    : q* e. r' F: T* U1 ?7 H7 E7 a9 e$.1^4 - $.1^3 + $.1^2 - $.1 + 1. O, E7 @, c3 x
    Quadratic Field with defining polynomial $.1^2 - 10 over the Rational Field3 i# {$ p9 T5 Q( ]4 y1 ^3 z
    [
    9 Y6 ^9 u% f8 Q2 k6 v, O4 Z    <$.1^4 - $.1^3 + $.1^2 - $.1 + 1, 1>6 E9 b" J" h1 H* H
    ]

    c.JPG (217.37 KB, 下载次数: 269)

    c.JPG

    aaaa.JPG (98.21 KB, 下载次数: 270)

    aaaa.JPG

    aaa.JPG (157.27 KB, 下载次数: 261)

    aaa.JPG

    aa.JPG (126.91 KB, 下载次数: 263)

    aa.JPG

    a.JPG (242.91 KB, 下载次数: 280)

    a.JPG

    回复

    使用道具 举报

    15

    主题

    4

    听众

    113

    积分

    升级  6.5%

  • TA的每日心情
    开心
    2012-1-13 11:49
  • 签到天数: 9 天

    [LV.3]偶尔看看II

    回复

    使用道具 举报

    您需要登录后才可以回帖 登录 | 注册地址

    qq
    收缩
    • 电话咨询

    • 04714969085
    fastpost

    关于我们| 联系我们| 诚征英才| 对外合作| 产品服务| QQ

    手机版|Archiver| |繁體中文 手机客户端  

    蒙公网安备 15010502000194号

    Powered by Discuz! X2.5   © 2001-2013 数学建模网-数学中国 ( 蒙ICP备14002410号-3 蒙BBS备-0002号 )     论坛法律顾问:王兆丰

    GMT+8, 2026-8-24 07:38 , Processed in 0.528775 second(s), 102 queries .

    回顶部