求帮助，关于S1的积分，为什么我的结果带int啊，这是怎么回事。正确的应该怎么办！！

dyd

syms g v aA bA cA zA u  t1 t2;
int(g);
int(v);
( ~3 Y6 X3 o' Z5 Ah=0.856;
$ ^# `: P& _4 Y3 ?2 `" YaA=(1+tan(g)*tan(g));
8 Z# r' Y% r- ?bA=-(2*1.625+2*tan(g)*(h+30*tan(g))-30*tan(g));
cA=(h+30*tan(g)-15)*(h+30*tan(g)-15);
$ A/ v7 i3 Q) B7 I7 ~/ E, FzA=(-bA-sqrt(bA*bA-4*aA*cA))/(2*aA);
* n6 v- i9 V8 {ya=h+30*tan(g)-tan(g)*zA;
2 c! z) L$ X0 w6 Q0 Bs1=(1.625*1.625-(z-1.625)*(z-1.625))*cos(v)*sqrt(tan(v)*tan(v)+1)*(sin(2*((asin(((h+30*tan(g)-z*tan(g))-15)/(sqrt(1.625*1.625-(z-1.625)*(z-1.625))*sqrt(tan(v)*tan(v)+1))))))/2-sin(2*((asin(-1/(cos(v)*sqrt(tan(v)*tan(v)+1))))))/2+((asin(((h+30*tan(g)-z*tan(g))-15)/(sqrt(1.625*1.625-(z-1.625)*(z-1.625))*sqrt(tan(v)*tan(v)+1)))))+((asin(-1/(cos(v)*sqrt(tan(v)*tan(v)+1))))));
) h( O! Y5 ?9 D1 Wp=1.625-sqrt(1.625^2-((15-ya)/sqrt(tan(v)*tan(v)+1)));
H=int(s1,z,p,10);

厚积薄发

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①不小xin--!

啊啊啊啊啊啊是的的的的飞飞飞

dyd

厚积薄发 发表于 2012-5-9 16:25
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6 L9 \' A( ]  P
0 K& c3 q2 T. }$ O: D好了···我想得到的是带g v h 但是对s1积分却积分不出来，即使积出来也带int 谢谢了

ealx0yJu

呵呵,打酱油的.