lingo建模语言与实例4

longde

目标与约束段
  M- P! x% ?$ k, o4 z. _* T集合段（SETS    ENDSETS）
5 m9 h3 o8 m& u# G2 {5 O+ r) Q6 @数据段（DATA   ENDDATA）
$ H; N) u$ q3 {, c初始段（INIT  ENDINIT）
（计算段 (CALC ENDCALC)）
. K% e- v3 z/ c" x- U% w+ C' z2 nMODEL:
Title Location Problem;
! r+ B. F: a3 m3 F3 n8 `9 R5 tsets:
4 ^" N0 B$ X* U+ D0 g* L/ `6 z    demand/1..6/:a,b,d;
" H) G, C" D, T3 L6 G, b+ V( |) v    supply/1..2/:x,y,e;
    link(demand,supply):c;
) L8 j- t. A* s) f1 j. cendsets
# A  c$ {$ {& V' o5 s( l* R; Cdata:
a=1.25,8.75,0.5,5.75,3,7.25;
b=1.25,0.75,4.75,5,6.5,7.75;
d=3,5,4,7,6,11; e=20,20;
enddata
  k, ?/ f7 c  m7 Finit:
' ^+ L6 \; r# f1 e: P7 H: h! qx,y=5,1,2,7;
1 K! w' N1 A; d$ Zendinit
7 r9 R/ P) H2 [2 Y, C8 g5 amin=@sum(link(i,j):c(i,j)*((x(j)-a(i))^2+(y(j)-b(i))^2)^(1/2));
@for(demand(i)sum(supply(j):c(i,j))=d(i););
@for(supply(i)sum(demand(j):c(j,i))<=e(i););
" v, m! w2 K% b# y; g( ZEND